Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 5351. |
Show that any positive integer is of the form 3 m or (3m + 1)or 3m +2) for some integer m |
| Answer» Ncert question | |
| 5352. |
What\'s the Formula of (a+b)³ and (a-b)³? |
| Answer» ( a+b)^3 = a^3 +b^3 +3 ab (a+b | |
| 5353. |
5555833%56789 |
| Answer» | |
| 5354. |
Find the sum of first term of ap x-8,x-2,x+4... |
| Answer» | |
| 5355. |
Prove root7+root5 is an irrational |
|
Answer» first assume that it is rationalise in the form of p/q where p and q are co prime nos.root 5+rot7=p/qwhole square both side...12+2root35=(p/q)whole sqaretherefore root 35=(p square-12q square)/q squarelhs= irrational no.rhs=rational no.this contradicts our assumption that root5+root7 is rational..therefore it is irrational no. Let √7+√5 be rational and its simplest form be a/b where a and b are co primes.Then √7+√5=a/bSquaring on both sides12+2√35=a square/b square2√35=a square /b square -12√35=a square -12b square/2b squareSince the number on the rhs is a non zero integer Therefore it is a rational numberThen √35 is also a rational numberBut this contradicts the fact that √35 is an irrational number Therefore our supposition is wrongHence √7+√5 is an irrational number This* Thai is an ncert ques see in ncert question |
|
| 5356. |
I face very difficulty to solve u like my boards have what can i do |
| Answer» Take comp. Rest.... Don\'t take tension.... Focusing on regular studies... ???? | |
| 5357. |
Is Shiv Das\'s sample papers good to practice?? |
|
Answer» yeah osswal is really best? It is best u like sample papers Arihant is good........ Bt oswal is best?? Btaoo Arihant? Navdeep app kaha se ho Every sample paper is best.....but truth i have nt listen about this... I heard this name first time... |
|
| 5358. |
What is the angle subtended at the centre of a circle radius 10cm by arc of 5 pie |
|
Answer» 90 My coming 18 |
|
| 5359. |
What is the common difference of an AP in which a21-a7. 84 |
| Answer» Let {tex}a{/tex} be first term and {tex}d {/tex} be the common difference.{tex}a_{21} - a_{7} = 84{/tex}{tex}a + (21 - 1)d - a + (7 - 1)d = 84{/tex}{tex}a + 20d - a - 6d = 84{/tex}{tex}14d = 84{/tex}{tex}d = 6{/tex}Therefore, common difference is 6. | |
| 5360. |
If a11 exceed a4 by 14 find d |
| Answer» | |
| 5361. |
If tanA + cotA=2 then find the value of tan2A + cot2A |
|
Answer» Square hai Please reply... Are yar isme tan square A hai ya tan 2A =0 2 |
|
| 5362. |
if a and b are the zeros of the quadratic polynomial p(x)=x2-k(x+1)-a and if (a+1)(b+1)=0,find a |
| Answer» | |
| 5363. |
28542zs |
| Answer» | |
| 5364. |
Find the 10th term from the end of the AP -4,9,14,.........254. |
|
Answer» 209 218.. 137 234 X |
|
| 5365. |
If AD is bisector of BC. Prove that ABD is similar to ADC |
| Answer» | |
| 5366. |
100-100/100-100=2 prove that |
| Answer» | |
| 5367. |
Define an acute angle. |
|
Answer» Acute angle is an angle which is between 0° and 90°>. Angle less than 90 is called acute angle |
|
| 5368. |
Friends what is the rule to identity the rhs criteria is use or not |
|
Answer» (Hypo)^2 = ( height)^2 + (base)^2 1. A right angle equal2. Hypotenuse equal3. Any other side equal No |
|
| 5369. |
What type of solution (s) the pair of equation x+2y+5=0 and 3y-6y+1=0 |
|
Answer» Unique solution Que...sudharo A unique solutions |
|
| 5370. |
Find sum of first n terms of an ap if nth term is 2-3n ? |
|
Answer» Your answer is wrong (-3n^2+n)/2 |
|
| 5371. |
Prove that √3 is an irrational no. |
|
Answer» It\'s in text book See in NCERT |
|
| 5372. |
Find a quadratic polynomial whose zeroes are 5+√2and5-√2 |
|
Answer» X2-10x+23 Maybe x^2+24 |
|
| 5373. |
Manas |
| Answer» Hi | |
| 5374. |
The perpendicular from A on side BC of triangle ABC intersect at D such that DB=CD .prove that 2AB |
| Answer» Given: The perpendicular from A on side BC of an{tex}\\vartriangle {/tex} ABC intersect BC at Such that BC = 3CDTo prove:2AB2 = 2AC2 + BC2\xa0Proof:In right triangle ADB,AB2 = AD2 + BC2 (1).......[By Pythagoras theorem]In right triangle ADC,AC2 = AD2 + CD2 (2).....[By Pythagoras theorem]Subtracting (2) from (1), we getAB2 - AC2 = BD2 - CD2= (BD + CD)(BD - CD)= (BC)(3CD - CD) ........ {tex}\\because {/tex} BD = 3CD(given)= (BC)(2CD) = 2(BC)(CD)=2(BC){tex}\\left( {\\frac{1}{4}BC} \\right){/tex}DB = 3CD{tex} \\Rightarrow \\frac{{BD}}{{CD}} = 3{/tex}{tex} \\Rightarrow \\frac{{DB}}{{CD}} + 1{/tex}= 3 + 1{tex} \\Rightarrow \\frac{{DB + CD}}{{CD}}=4{/tex}{tex}\\Rightarrow \\frac{{BC}}{{CD}} = 4{/tex}{tex}\\Rightarrow CD = \\frac{1}{4}BC = B{C^2}{/tex}{tex}\\Rightarrow {/tex} 2(AB2 - AC2) = BC2{tex}\\Rightarrow {/tex} 2AB2 - 2AC2 = BC2{tex}\\Rightarrow {/tex} 2AB2 = 2AC2 + BC2 | |
| 5375. |
How many questions would be there in final exam 2018 |
|
Answer» 29 in maths In maths About 27to 28 questions. 30 No, 29 It\'s 30 28 |
|
| 5376. |
if the sum of n terms of AP is same as it\'s m terms .show that the sum of its m+n term is 0 |
| Answer» Either correctly explain the question or the question is wrong there will be m-n | |
| 5377. |
If A+B=90degree and secA=5/3 then find the value of cosecB |
|
Answer» Pr kaise 5/3 |
|
| 5378. |
Why 13233343563715 is a composite number |
|
Answer» Mai hi batau kya composite number A number which more than two factor Which have factor more than 2 or more Which have factor what complete this Which have factor Tell me what is composite number Bcoz it have factor Yes right It is a composite number bro No It have a factor 5 |
|
| 5379. |
X^2 + 2x - 45 = 0 by completing square method |
| Answer» | |
| 5380. |
If A(-3,5),B(-2,-7),C(1,-8)andD(6,3) are the vetice of a quadrilateral abcd find it\'s area |
| Answer» It is clear from figure, thatArea of quadrilateral ABCD= Area of\xa0{tex}\\Delta{/tex}ACB + Area of\xa0{tex}\\Delta{/tex}ACD= {tex}\\frac{1}{2}{/tex}[-3( -8 - 7 ) + 1(7 - 5 ) + (-2)(5 - (-8)) ]+ {tex}\\frac{1}{2}{/tex}[-3( -8 - 3 ) + 1(3 - 5) + 6(5 - (-8)) ]= {tex}\\frac{1}{2}{/tex}\xa0[ 45 + 2 - 26 ] + {tex}\\frac{1}{2}{/tex}\xa0[ 33 - 2 + 78 |=\xa0{tex}\\frac {1} {2}{/tex}\xa0[ 21 + 109 ] = 65 units. | |
| 5381. |
Find tha value of K for which the difference between the root of the equation x×x+kx+8=0is 2 |
| Answer» | |
| 5382. |
What is the main format of cards being used in gamble games |
| Answer» | |
| 5383. |
How to see sample paper |
| Answer» | |
| 5384. |
The diameter of a wheel is 1.26m find out the distance covered in 500 revolution |
|
Answer» Please give solution 126 |
|
| 5385. |
Sir,which book should be followed for maths board 10 class exam |
|
Answer» Oswal question bank NCERT of class 10th Rd sharma better I think |
|
| 5386. |
If x+y+z = π Then prove that Cot x/2 +cot y/2 + cot z/2 = cot x/2 × cot y/2 × cot z/2. |
| Answer» | |
| 5387. |
The first term of ap are 3y-1,3y+5 and 5y+1 respectively. |
| Answer» {tex}3y - 1,3y + 5{/tex} and {tex}5y + 1{/tex} in A.P.{tex}(3y + 5 ) - ( 3 y - 1) = (5y + 1) - (3y + 5){/tex}or, {tex}3y + 5 - 3y + 1 = 5y + 1 - 3y - 5{/tex}or, {tex}6 = 2y - 4{/tex}or, {tex}2y = 6 + 4{/tex}or, {tex}2y = 10{/tex}or, y =\xa0{tex}\\frac{10}{2}{/tex}{tex}y = 5{/tex} | |
| 5388. |
Hy can I get my answers of maths question |
|
Answer» Yes Yeah why not |
|
| 5389. |
Express the trigonometric ratio of secA and tanA in terms of sinA |
|
Answer» Seca= 1/√1- sin^2a What u mean ayush that sin a is answer TanA=sinA/cosA SinA is ans So easy seca = 1/cosa and tana = sina/cosa |
|
| 5390. |
How can I learn trigonometry |
|
Answer» By learning formulas Not learn just understand and think over how to use formula and wher apply 9ooooOoo |
|
| 5391. |
volume of sphere?? |
|
Answer» H 4/3πr3 |
|
| 5392. |
Find the of the segment ayb show in fig. 12.9 if radius of the circle 21 cm and / sob |
|
Answer» Incomplete que ???? |
|
| 5393. |
If. SinA+SinB+SinC=3 then CosA+CosB+CosC=? |
| Answer» | |
| 5394. |
Prove that the lengths of two tangents drawn from external points to circle are equal |
|
Answer» Pg no.211 of maths book U can refer to ncert.... |
|
| 5395. |
Tips for triangle |
|
Answer» Complete all the theorems 1st Then move on extras Just first complete ncert of triangles.... |
|
| 5396. |
What is mean mode median |
| Answer» Mean:\xa0The "average" number; found by adding all data points and dividing by the number of data points.Example: The mean of\xa0444,\xa0111, and\xa0777\xa0is\xa0(4+1+7)/3 = 12/3 = 4(4+1+7)/3=12/3=4left parenthesis, 4, plus, 1, plus, 7, right parenthesis, slash, 3, equals, 12, slash, 3, equals, 4.Median:\xa0The middle number; found by ordering all data points and picking out the one in the middle (or if there are two middle numbers, taking the mean of those two numbers).Example: The median of\xa0444,\xa0111, and\xa0777\xa0is\xa0444\xa0because when the numbers are put in order\xa0(1(1left parenthesis, 1,\xa0444,\xa07)7)7, right parenthesis, the number\xa0444\xa0is in the middle.Mode:\xa0The most frequent number—that is, the number that occurs the highest number of times.Example: The mode of\xa0\\{4{4left brace, 4,\xa0222,\xa0444,\xa0333,\xa0222,\xa02\\}2}2, right brace\xa0is\xa0222\xa0because it occurs three times, which is more than any other number. | |
| 5397. |
in mathematics the hardness level would be of ncert or more hard |
| Answer» Y | |
| 5398. |
Which type exam paper for this year |
| Answer» From whole syllabus...?? | |
| 5399. |
What is remainder theorem |
| Answer» Remainder is always less than divisor or greaterthan/equal to 0 | |
| 5400. |
Is infinite equals to 0 |
|
Answer» Thank you guys for your answer Ya we can say it also Boundless is infinite Or darshana can\'t ewe say that the countless is infinite No Infinity means something which never end No Countless is infinite No |
|