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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 5401. |
LCM kaise lata ha |
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Answer» By doing prime factorisation of given number and from that series take product of highest power no.. Included in the prime factorisation series By which do u wanna learn Factors karke LCM ata h Happy ⚘⚘⚘⚘⚘⚘ ?????? day all of you |
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| 5402. |
Of x=25^1/3-5^1/3+1,then find (6-x/x)^9 |
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| 5403. |
The sum of first terms of an ap is given by sn= 2nsquare + 3n find the 16 term of the ap |
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| 5404. |
Prove that bx=ay |
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Answer» ?? Hii praveen |
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| 5405. |
Is saal se board ho gya hai toh pass ho ne ke liye kiase study kroon main abh please any one else |
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Answer» Lekin self study or hardwork dono hi bahoot jyaada karna padega agar tum hardwork karoge toh ab bhi kuch kar sakte ho Aab toh kuch nhi ho sekta time toh nikel gya. Padhai ni ki kya |
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| 5406. |
If the mode of a distribution is 8 and its mean is also 8 then what is median ? |
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Answer» 3median=mode + mean 3median=8+163median =24Hence median =8 Sona raj..... Kya tum Yogender hoo?? |
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| 5407. |
Solve 99x +101y = 1499101x + 99y =1501 |
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Answer» Once add the equations and once subtract the equations. You will get two simplified equations then solve them x=8,y=7 |
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| 5408. |
What is the volume of cylinder |
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Answer» πr^2h Pi r²h |
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| 5409. |
Hum pre bord ma 2 subject ma fail h |
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Answer» So sad It\'s ok ,aage mhnet krna ? |
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| 5410. |
Is - 150is a term of ap 11,8,5,2,......?why? |
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Answer» Yes, 55th term No |
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| 5411. |
Prove that root 3 is an irrational |
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Answer» IET root3 be rational and let its simplest form be a/b then aAnd b are integers having no common factor other than 1 and( b not equal to 0) now,√3= a/b=3=asquare/bsquare,•=3bsquare=asquare,3dividea[3 is prime and 3divides a square=3,divides a] let a=3c(putting a=3c in(1) we get 3b square=9c square=b square=3c square,=3divides b square [3divides 3c square]=3 divides b[3 is prime and 3 divides b square = 3divides b],3 is a common factor of a AND b see ncert text book for d same |
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| 5412. |
2+7 |
| Answer» I don\'t know 9 | |
| 5413. |
Pythagores theorem hence proved |
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| 5414. |
Tum log ka pass 5 year back questions ha |
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Answer» Ya tumne aap se baat kar sakte ho wase he question paper dekh lo 2 ya 3 toh ha Google pe pe search karo aur vedantu website par milegA Is app pe milega |
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| 5415. |
Prove that 3/2 |
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| 5416. |
Can (x-7 ) be the remainder on division of a polynomial p(x) by (7x+2) ? Justify your answer |
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| 5417. |
P term of ap is 1/q ,q term of ap is 1/p .then prove that p*q is 1 |
| Answer» Aap kaha se ho | |
| 5418. |
If a and b are zeroes of polynomial x\'2-(k+6)X+()2k-1 |
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Answer» Kon m Aap kaha se ho |
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| 5419. |
How many hours we should practice maths if you are weak in maths |
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Answer» How many hours i should practice sst if i m weak in sst?? Anyway Atleast 3 hours daily Thanks my friends With break Ans anybo 6- hours if you week in maths➕➖✖➗✔✅❎ About 3 hrs |
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| 5420. |
Easy to hard |
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Answer» Hi play boy Hello payal???? Hi payal |
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| 5421. |
What is the difference between homolgus and analogas |
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Answer» Welcome? Thnx everyone ◆Homologous organ are those organs which have same structure but different function whereas ◆Analogous organs refer to those organs with same function but different structure. Organs which have same body structure but perform different functions is called homologous. Those which perform similar function but have different structure called analogous Homologous organs have similar structure but different functions while analogous organs have different structure but similar functions. |
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| 5422. |
(1-tanA +1-cotA) ^2 =tan^2 AProve it |
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| 5423. |
Find the root of the quadratic equation √3xsq-2x-√3 |
| Answer» Check r.s aggarwal examples | |
| 5424. |
any guess papers for 2018 board exams are avilable...? |
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Answer» Thik h bol dunga Go to jagranjosh.com ok latest sample papers and ncert book is enough to score gud marks in all sub naa ??? Sample paper Just see latest smaple paper by cbse |
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| 5425. |
Solve for x 12abxsquare_(9a square _8b square) x_6ab=0 |
| Answer» 12 abx2 - (9a2 - 8b2)x - 6ab = 0Comparing with Ax2 + Bx + C = 0, we getA = 12 ab, B = -(9a2 - 8b2), C = -6 abUsing the quadratic formula, {tex}\\mathrm { x } = \\frac { - \\mathrm { B } \\pm \\sqrt { \\mathrm { B } ^ { 2 } - 4 \\mathrm { AC } } } { 2 \\mathrm { A } }{/tex}we get {tex}\\Rightarrow x = - \\left( - \\left( 9 a ^ { 2 } - 8 b ^ { 2 } \\right) \\right\\}{/tex}{tex}\\frac { \\pm \\sqrt { \\left( - \\left( 9 a ^ { 2 } - 8 b ^ { 2 } \\right) \\right) ^ { 2 } - 4 ( 12 a b ) ( - 6 a b ) } } { 2 ( 12 a b ) }{/tex}{tex}= \\frac { 9 a ^ { 2 } - 8 b ^ { 2 } \\pm \\sqrt { 81 a ^ { 4 } + 64 b ^ { 4 } - 144 a ^ { 2 } b ^ { 2 } + 288 a ^ { 2 } b ^ { 2 } } } { 24 a h }{/tex}{tex}= \\frac { 9 a ^ { 2 } - 8 b ^ { 2 } \\pm \\sqrt { \\left( 9 a ^ { 2 } + 8 b ^ { 2 } \\right) ^ { 2 } } } { 24 a b }{/tex}{tex}= \\frac { 9 a ^ { 2 } - 8 b ^ { 2 } \\pm \\left( 9 a ^ { 2 } + 8 b ^ { 2 } \\right) } { 24 a b }{/tex}{tex}= \\frac { 9 a ^ { 2 } - 8 b ^ { 2 } + 9 a ^ { 2 } + 8 b ^ { 2 } } { 24 a b }{/tex}{tex}= \\frac { 9 a ^ { 2 } - 8 b ^ { 2 } - 9 a ^ { 2 } - 8 b ^ { 2 } } { 24 a b }{/tex}{tex}= \\frac { 18 a ^ { 2 } } { 24 a b } , \\frac { - 16 b ^ { 2 } } { 24 a b } = \\frac { 3 a } { 4 b } , \\frac { - 2 b } { 3 a }{/tex}{tex}\\therefore{/tex} the solution of the given equation are\xa0{tex}\\frac { 3 a } { 4 b } \\text { and } \\frac { - 2 b } { 3 a }{/tex}. | |
| 5426. |
Probability of 53 sunay ina year |
| Answer» total no of day in a year=365 no of days in a week=7 thus no of weeks in a year=365%7=52weeks and 1 day now,it is clear that the no of sunday in a year =52 the remaining 1 day could be monday,tuesday,wednesday,thrusday ,friday, saturday and sunday. Now probability of getting sunday=1/7. Therefore probability of getting 53 sunday=1/7. | |
| 5427. |
If de is parallel to bc,ad=2,ab=5,ae=1.5 the find ec |
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| 5428. |
√5x+1-√2x-5=3 |
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| 5429. |
If sin∆=cos∆ then find the value of ∆. |
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Answer» Sin∆/cos∆=1So,tan∆=1Also,tan45°=1Hence,∆=45° sin∆=cos∆sin∆/cos∆=1tan∆=1∆=45° (tan∆=45°) |
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| 5430. |
Binduo A(0;0) Ar B (36; 15) ke bich ki duri gyat kare |
| Answer» 39 | |
| 5431. |
√5x+2=√2x-5 |
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| 5432. |
Find the least common denominator by division method 5 |
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| 5433. |
If P (e)=0.5. |
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| 5434. |
A speed car |
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| 5435. |
What is no. |
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Answer» Human??? Undisputed one आप kon ho |
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| 5436. |
X power 4 +3xpower 3- xsquare -9x -6 ÷ xsquare -3 |
| Answer» The given polynomial f(x) = x4 - 3x3 - x2 + 9x - 6Since, two of the zeroes of polynomial are {tex}- \\sqrt 3{/tex}\xa0and {tex}\\sqrt 3{/tex}hence (x+{tex}\\sqrt 3{/tex})(x-{tex}\\sqrt 3{/tex})=x2-3 is a factor of f(x)Now on long division of f(x) by\xa0x2-3So, f(x) = x4 - 3x3\xa0- x2 + 9x - 6 = (x2 - 3)(x2 - 3x + 2)= (x + {tex}\\sqrt 3{/tex})(x - {tex}\\sqrt 3{/tex})(x2 - 2x - 1x\xa0+ 2)= (x + {tex}\\sqrt 3{/tex})(x - {tex}\\sqrt 3{/tex})(x - 1)(x - 2)f(x)=0 if x=-{tex}\\sqrt 3{/tex}\xa0or x={tex}\\sqrt 3{/tex}\xa0or x=1 or x=2Therefore, the zeroes of the polynomial are {tex}-\\sqrt 3{/tex}, {tex}\\sqrt 3{/tex}, 1, 2. | |
| 5437. |
Can (x-7) be the remainder on division of a polynomial p(x) by (7x+2) ? Justify your answer. |
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Answer» No because degree of remainder is always less than divisor no because the degree of r(x) < degree of divisor { g(x) } |
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| 5438. |
Show that there is no positive integer n for which &√n-1 +√n+1 is rational |
| Answer» check rd | |
| 5439. |
Check whether - 150 is a term of the AP:11,8,5,2...? |
| Answer» Find it by using nth term formula | |
| 5440. |
If p (E)=0.05,what is the probability of \'not E\'. |
| Answer» P(E) + p not e = 10.05 + p not e = 1P not e = 1.00 - 0.05P not e = .95 | |
| 5441. |
How can we prove section formula |
| Answer» Consider any two points A (x 1, y 1) and B (x 2, y 2) and assume that P (x, y) divides AB internally in the ratio m : n i.e. PA: PB = m : nDraw AR, PS and BT perpendicular to the x-axis. Draw AQ and PC perpendiculars to PS and BT respectively.In ∆PAQ and ∆BPC∠PAQ = ∠BPC (pair of corresponding angles)∠PQA = ∠BCP (90 °)Hence, ∆PAQ ∼ ∆BPC (AA similarity criterion)∴ PA BP = AQ PC = PQ BC (Corresponding sides of similar triangle are proportional)⇒ m n = x - x 1 x 2 - x = y - y 1 y 2 - y Taking m n = x - x 1 x 2 - x , we getm x 2 - mx = nx - n x 1 ⇒ (m+n)x = m x 2 + n x 1 ⇒ x = m x 2 + n x 1 m + n Similarly taking m n = y - y 1 y 2 - y , we get y = my 2 + n y 1 m + n The coordinates of the points P(x, y) which divides the line segment joining the points A( x 1 , y 1 ) and B( x 2 , y 2 ), internally, in ratio m : n are m x 2 + n x 1 m+n , m y 2 + n y 1 m+n. Hope this helps uh!!! | |
| 5442. |
Ex 3.7 questions 7 ,3part by elimination method |
| Answer» Its easy | |
| 5443. |
2cosA/sin²A |
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Answer» Abhishek answer kardo reply kardo Rajput ma Bhaduriya Abhishek answer do please RAJPUT ko to SB phchan jate h? 2cosA/sinA*1/sinA=2cotAcosecA Rathore Plzz add answer Aap konse राजपूत हो भाटी tanwar rarhore I am also What youre mean Pta chal gya tha I am also RAJPUT Abhishek आप rajputo Mein konse ho |
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| 5444. |
Show that root 6 is irrational |
| Answer» Hii | |
| 5445. |
Sara question open kar digia mere pass paise nahi hai |
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| 5446. |
Tan60°+cos60° = |
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Answer» Root 3 + 1/2 = (2root3 + 1) / 2 ? |
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| 5447. |
Numbers |
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| 5448. |
Formula of trapezium |
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Answer» B×H to parallelogram ka hota h 1/2 × h ( sum of parallel sides ) Formulae hota h pr mujhe yaad nhi h 1/2×sum of parallel sides×height There is no formula of trapezium B*h |
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| 5449. |
Prove of BPT |
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Answer» Thanx Nice ans Open your book it will be more helpful to you |
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| 5450. |
Who is solving rd sharma here? |
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