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5701.

What is composite number?with examples

Answer» Aur kon kon se no. Puchoge
Composite number is a positive integer it can be formed by multiplying to smallest positive integer
5702.

Use euclid divisor algorithm to find the hcf of

Answer» a=bq+r, 0=r or 0
Incomplete q
5703.

What is integer?Give examples

Answer» All positive negative natural numbers are integers.ex.-1,-2,-3,-4......1,2,3,4.....
-10,-9,-8...0...1,2,3
In a number line the left side no. Are negative and right side no. Are positive
5704.

What is whole number?Give examples

Answer» All natural numbers including 0 are whole numbers.eg. 0,1,2,3,4,5,6,7,8,9.
0,1,2..
The no. Which are starting from 0
5705.

What is real number?Give with examples

Answer» A collection of rational or irrational numbers are called real numbers
5706.

What is a real number?Give defination with examples

Answer» Real numbers are nothing but a set of rational and irrational numbers Hope it Will help!!
123......
Numbers which we can express in a number line are called real number
5707.

Solve the following pair of linear equation by the substituting method. 2x+3y=103x+y=8

Answer» Its wrong but thanks for solving it anuska
X=8-2/3,x=6/3,x=2
Put the value of y in eq 2
2x + 3y=10----(1),3x + y=8,3x =8-y,x=8-y/3,put eq 2in eq 1,2(8-y/3)+3y=10,16-2y/3 +3y=10,16-2y+9y=30,7y=30-16,y=14/7Y=2
5708.

35+35

Answer» 70
70
70
5709.

Kis kis ne roje rakhe hai

Answer» Sab na
Maine nhi rakha hai
5710.

19530 Prime factor

Answer» 5736
2×3×3×5×7×31
5711.

19530

Answer» 2×3×3×5×7×31१
Ch 1 real number Prime factor of 19530
5712.

What is imperial equation

Answer» Tumne bataya ni ki tumhara center kaha pada tha
5713.

Rs agrawl

Answer» Irrational
Pai ki value rational ya irrational hoti hai
Ex 2A5)5x^2-4-8x
Prefer ncert only
Accji book ha questions b accha ha
5714.

Find all zeros of x⁴-7x³+10x²-14x-24 if two zeros are√2 & -√2

Answer»
5715.

√2-√5

Answer» 66
5716.

(x-4)(x+2)=0

Answer» x=4,x=-2
5717.

The smallest composite number is

Answer» 4
4
4
4
5718.

What is the probability of a red card or a queen?

Answer» P(getting a red card or queen)=16/52=> 6/13
Total outcomes=52 and favourable outcomes=16
5719.

7575ka hcf

Answer» HCF sirf do numbers ka nikal sakta hai and you have mentioned only one number ?that is 7575!!! It is not possible?!!...
5720.

Probability of an event E+probability of the event \' not E \' ____________

Answer» 1
1
1
1
Not more one
5721.

If 1 and - 2are the two zeros of POLYNOMIAL (x3-4x2-7x+10)find its third zero

Answer» Third zero is 5
5722.

Write the prime factorization of 31250. What are its factor ?

Answer» 2×5 ki power 6
5723.

Defination of arithmetic prigression (AP)

Answer» An arithmetic progression (A.P) is a progression in which the difference between two consecutive terms is constant.Example: 2,5,8,11,14…. is an arithmetic progression.
5724.

If Hcf(336, 54) =6, find lcm(336, 54)

Answer» HCF × LCM=Product of the two numbersNow,=>6 × LCM = 336 × 54=>LCM = 336 × 54/6=>LCM = 56 × 54Therefore,LCM=3024
3204
3024
3024
5725.

Kon sa app best hai byjuss or vedantu??

Answer» Vedantu
Extramarks
Byjus
Byjus have more defined study step by step
Show that any positive odd integer is of the form 6q+1,or6q+3,or 6q +5 ,where q is some integer
5726.

4u(u+2)=0 ????

Answer» Here 4u(u+2)=0Therefore 4u=0 and u+2=0So u=0 or - 2
4u2+8u even u can take 4u as common
U=0 and U=-2
U=√-2 or 2i
5727.

Hfhfjfjfjfnj

Answer» Hhhnjnsnsk
5728.

Product of three number is not equal to the product of their HCF and LCF

Answer» Cvcif
Right
5729.

Ten third of 100 will be

Answer» 333.33
5730.

How can we make series of 1st 20 prime numbers

Answer» But here how can we find discriminant
2, 3, 5, 7, 11, 13, 17 19 23 29 29 29 3137
5731.

Alafa × bita × gama = - d/a

Answer» Right
5732.

Cos - sin + 1 ÷ cos + sin - 1 = 1+cos/sin

Answer» Divide numerator and denominator by sin. And try to solve . It help to make ur question easy and simple
5733.

Can anyone construct the angle of 100 degrees?

Answer» Lo
Yes
ya by using constructor
5734.

Check whether 6" can end with the digit 0 for any natural number n

Answer» No because the prime factorisation of 6 contains 2 but not 5.
5735.

Find HCF •4,19•420,130•867,255•144,198•32,616•336,54

Answer»
5736.

Stastics

Answer»
5737.

Define equally likely outcomes ? In deep..

Answer»
5738.

Find the product of a roots of a quadratic equation 2x^2+7x-4=0

Answer» a.b=c/a=-4/2=-2
5739.

If the remainder on division x^3+2x^2+kx+3 by

Answer»
5740.

Which book is very best for board exam

Answer» Mtg, paractise all question from itTo get 99%
Science togeter with
NCERT is best practice it thorolly.
For maths only RD Sharma
Ncert and rd
5741.

When the app have all chapters r.d Sharma solutions

Answer»
5742.

Give the proper answer of Father of the geomatry?

Answer» Euclid
5743.

What is Euclids algorithm?

Answer» The Euclid\'s alogorithm is a=bq+r
a=bq+r
5744.

What is Euclid\'s algorithm?

Answer» ATQ euclids algorithm dividend =divisor ×qoutient +remainder
The set of the statements a=bq+r
5745.

Who is the Father of geomatry

Answer» Aryabhatta
Euclid
5746.

Any army country went off 616 members is to to March behind any army in

Answer» What\'s app
5747.

Use euclid,s division algorithim to find the HCF of 135 and 225

Answer» 225=135×1+90135=90×1+45 90=45×2+0This implies that HCF is 45
Since 225>135 , We divided 225 by135 225÷135=90 .Since remainder is not 0 ,We divided 135 by 90 135÷90=45 .Since remainder is not 0,We divided 90 by 4590÷45=0, Since the remainder is 0 .So as using the euclids division algorithim the H.C.F is 45
5748.

Find the least positive integers which when diminsed by 5 is exactly divisible by 36&54

Answer» For the solution of this question we have to find L.C.M of 36 and 54.L.C.M. of 36 and 54 = 2×2×3×3×3 = 108Now,The least number = (L.C.M. of 36 and 54) + 5⇒ 108+5 = 113Hence 113 is the least positive integer which on diminished by 5 is exactly divisible by 36 and 54.
5749.

The pair of linear eq.ax+3y=a-3,12x+ay =a has no solution find a

Answer» a=+or-6
5750.

8x+5y+=9:3x+2y=4

Answer» By elimination method :8x+5y = 9---------(1) ×23x+2y = 4 -----(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)...8×-2 +5y = 9-16+5y = 95y = 9+165y = 25y = 25/5y = 5