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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6401. |
Guys kya aap me se koi dear sir ke video\'s dekhta hai |
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Answer» Bakwaas.......dear sir Me Ha yaar I Koi nhi ☹️☹️ I am huge fan of dear sir |
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| 6402. |
Root five is rational number prove |
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Answer» It is a irrational no. Kabhi prove nhi hoga kyuki root 5irrational h na ki rational. Check your question? Abe oyee yai yaha kya puch raha h bai likhte likhte haath dard ho jayenge or vese bhi tune exam mai yai questions to chodke aana hi h ???? Root 5 is not rational no. but it is irrational no. |
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| 6403. |
What is the area of the largest square that can be inscribed in a circle of radius 12cm? |
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Answer» Radius = 12 cmDiameter = diagnol of square(h)=24 cmHence area of square = (a)(a)ApplyingPythagoras theorem(h)(h)=(a)(a)+(a)(a)576=2(a)(a)288=(a)(a)Hence area of sq is 288 sq.cm Please check your answer I think 72 cm square 576cm squate |
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| 6404. |
Important chapter in maths |
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Answer» Most important chapters are Trigonometry, Triangle.Volume and surface area, Area related to circles,circles and construction All chapters I think Are this the markings kavya??? Subject. No. in board question 1. Real number= 62. Polynomial= 33. Pair of linear equation two variable= 24. Quadratic equation=85. Arithmetic progression= 76. Triangle= 87. Coordinate geometry= 68. Introduction of trigonometry= 89. Some application of trigonometry= 410. Circle= 311. Construction= 412. Area related to circle= 313. Surface area & volume= 714. Statistics= 715. Probability= 4 Waise important to sbb h btt meri nzr me.. Trigonometry,geometry,mensuration,statistics nd probability.. Surface area and area related to circle much guestion is ask from these chapter Ohk I think algebra and geometry . Yaar kya yaar All chapters are important ???? |
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| 6405. |
Pass hone ke liye kotbe percent chahiye honge Pls reply |
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Answer» 33 I think 33 % Full percent kitne chahiye hoge |
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| 6406. |
244 hours into day and hour |
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Answer» 10 days and 4 hours Gjiffgv 10 and a half day and hours is 244 |
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| 6407. |
244 hours iN to day and hours |
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| 6408. |
14.3 last sum 7 |
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Answer» Can\'t able to understand your question Hi |
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| 6409. |
The sum of n,2n,3n terms of an AP are s1,s2,s3 respectively. Then prove that s3={s2-s1}3 . |
| Answer» S1 = n/2 (2a + (n-1)d) ;S2 = n(2a + (2n-1)d) ;S3 = 3n/2(2a+(3n/2-1)d) ;3(S2 -S1)= 3( 2an +2n^2d -dn -an -n^2d/2 +nd/2)= 3( an +3dn^2 /2 -nd/2)= 3n/2 (2a + (3n/2 -1) d)= S3Hence, proved | |
| 6410. |
Is completing square method involve in cbse board exams |
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Answer» This method is in ncert but not in syllabus Yes, its given in ncert. So it is in syllabus. No Shayad nhi ?but boards h to risk mat lo...ek bar padh lena ? |
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| 6411. |
Find the distance point (2,3) and (7,10) |
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Answer» Root 74 √74 units... |
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| 6412. |
2+2-4/5*4 |
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Answer» 0.8 4/5 0.8 |
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| 6413. |
Evaluate 10*1- cot*cot/1+sin*sin |
| Answer» 10/cot² | |
| 6414. |
Prime factor of 140 |
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Answer» 2 , 5 and 7 2*7*2*5 |
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| 6415. |
Find sum of 1st 15 multiples of 8 |
| Answer» The sum of 1st 15 multiples of 8 is 960 | |
| 6416. |
If triangle ABC is right angled at C then value of cosec(A+B) is |
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Answer» Answer is 1 angles*? sorry by mistake i wrote √2... becoz in any triangle sum of all the sides = 180 ....since one angle is 90 ... therefore the sum of remaining two angle will also be 90....A+B =90...and cosec 90=1...sorry 1 i think answer is √2 |
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| 6417. |
Show that the points (5,5),(h, 0), and (0,k)are collinear if 1/h +1/k =1/5. |
| Answer» first of all k ki value find out kro....in terms of h value ayegi .....and then 3 points mil jayenge...area of triangle formula ka use kro....area of triangle=0...becoz the points are collinear | |
| 6418. |
AB is the diameter of the circle with the center O if PAB=55 PBQ =25 And ABR=50 find PBA BPQ and BAR |
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| 6419. |
Find HCF of 398and 456 |
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Answer» Answer is 2 2 |
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| 6420. |
How i can solve trignometry sums like that of exercise 8.4 ?? |
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Answer» Also understand the methods used to solve different types of questionsExample if the question consists √ then method is rationalisation Practice more questions from question bank Only need to learn the formula and basic concept of trigonometry |
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| 6421. |
Wk bahut bada confusion hai mI abhi kya padhun |
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Answer» Kon maths mai Bhai tu NCERT , RD aur ,RS CHAT JA Tere sb complete hogaua Ooh Hindi is there Hmm Everything Tumhare mai hindi hai English mai kya Do English Soch toh raha hun but kya padhun samj ni a rah hai English Ek* can anybody suggest me |
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| 6422. |
Sin³Q+cos³Q/sinQ+cosQ +sinQcosQ |
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| 6423. |
Prove it √3-5 |
| Answer» Let √3-5 is a rational and =a/b and a and b are rationalSo,√3=a/b+5Then,a/b+5is rational But √3 is irrational (by contradiction)So,√3-5 is irrational | |
| 6424. |
A|BC is an isoceles right triangle right angles at prove that AB^2 =2AC^2 |
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| 6425. |
Prove that 1÷(3-2^5) is an irrational number |
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Answer» It is rational number Let this number is rational and it is equal to a/b |
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| 6426. |
Find a quadratic polynomial with 3 and 2 as the sum nd ptoduct of its zeroes respectivel |
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Answer» X^² - 3x + 2 α+β =3 αβ=2 X^2-(α+β)x+αβX^2-3x+2 |
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| 6427. |
ABC is a right angled triangle AB=3cm , BC=5cm and AC=4cm, then the inradius of the circle is? |
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| 6428. |
(sin 72 + cos 18) (sin 72 - cos 18) |
| Answer» \xa0(sin72° +\xa0cos18°)(sin72° −\xa0cos18°).= (sin2\xa072° –\xa0cos2\xa018°)= (sin2\xa072° –\xa0cos2\xa0(90° –\xa072°)\xa0=\xa0sin2\xa072° –\xa0sin2\xa072°= 0 | |
| 6429. |
If sinA = 0 then fimd value of A. |
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Answer» sin A=0A=0 SinA = 0SinA = Sin0°A = 0° SinA = 0SinA =sin90°A = 90° |
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| 6430. |
X^1/2+y^1/2=[18+6*5^1/2]^1/2 |
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| 6431. |
Trigonometry ouestions |
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| 6432. |
I am practicing old book of rs agarwal of 2004 of class10 .is it right to do? |
| Answer» No problem bro .but u can also use xam idea | |
| 6433. |
From where do we get the name of trigonometric ratios |
| Answer» It\'s easiest to think of the trig functions on a circle- this is how they were constructed before calculators.\tSine is from the Latin for bay and/or the Arabic for bowstring. Picture the chord (segment from A-B) and the circle A-D-B as a bow. If you measure the length of A-C and divide by the radius of the circle (O-A) you get the sine of the angle theta\tCosine is from "complement sin". It\'s the complement to the angle, so if you measure the distance from the centre to the chord (O-C) and divide by the radius you get the cos of the angle.\tTangent is from the Latin for touch. A tangent is a line that touches the circle once. By definition this meets a line to the centre at right angle, so you always have a right angle triangle and so an easy definition of the tan of the angle.\tSecant is from cut (Latin again). It cuts the tangent from O-E cosecant,\tCotangent etc are like cosine, the complements to their respective functions, but unless you do a lot of maths you probably won\'t meet them | |
| 6434. |
Solve the equation 2x -3y=-10 |
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Answer» Let x be 2 2*2-3y=-104-3y=-10-3y=6y=6/-3-1/2 2x=3y - 10x=(3y-10) / 23y=2x+10y = 2(x+5) / 3 |
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| 6435. |
what is exact value of π? |
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Answer» 44/14 or 22/7 = 3.14 approximately The number π is a mathematical constant, the ratio of a circle\'s circumference to its diameter. It is approximately equal to 3.14159. It has been represented by the Greek letter "π" since the mid-18th century, though it is also sometimes spelled out as "pi". |
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| 6436. |
(1-sin45°+sin30°)(1+cos45°+cos60°) |
| Answer» Put the values of degree then the answer will come OK | |
| 6437. |
What type of questions are put in trigonometry |
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| 6438. |
X2+x_ (p+1)=0 |
| Answer» p _(p_1) | |
| 6439. |
For class 10th board exam idea Mathematics book for exam preparation this book is good or not |
| Answer» FIRSTLY WE HAVE TO PREPARE FOR NCERT AND XAM IDEA IS ALSO GOOD | |
| 6440. |
expreess cos A in terms of cotA |
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Answer» CotA =1/tanA1/TanA=cosA/SinASinA =cosA*tanACosA=SinA*1/TanA""""""= SinA*cotA cosA=1/1+√cot^2A |
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| 6441. |
If n times n th term is equal to m times m th term.prove that m+n th term is zero. |
| Answer» mam = nanm[a + (m - 1)d] = n [a + (n - 1)d]{tex} \\Rightarrow {/tex}\xa0ma + m2d - md = na + n2d - nd{tex} \\Rightarrow {/tex}\xa0a(m - n) + (m2 - n2)d - md + nd = 0{tex} \\Rightarrow {/tex}\xa0a(m - n) + (m - n) (m + n)d - (m - n)d = 0{tex} \\Rightarrow {/tex}\xa0(m - n) [a + (m + n - 1)d] = 0{tex} \\Rightarrow {/tex}\xa0a + (m + n - 1)d = 0{tex} \\Rightarrow {/tex}\xa0am+n = 0Hence proved. | |
| 6442. |
If sec theta = x+1/4x, prove sec theta + tan theta = 2x or 1/2x |
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| 6443. |
What is 2+2? |
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Answer» It\'s answer is 4 it is so easy 4 Are itna bhi nhi pta kya 4 hota h |
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| 6444. |
x^(2/3log x to the base 2 - 1) |
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| 6445. |
In trigonometry who discover sin cos tan cosec sec cot |
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| 6446. |
Rd sharma (trigonometric identities ex.16) |
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| 6447. |
How to solve linear equations in 2 variables |
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| 6448. |
2555-(-265) |
| Answer» 2820 | |
| 6449. |
A swimming pool |
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Answer» Beta has mat For swimming?? |
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| 6450. |
If tan thita = root 2-1 then find sin thita * cos thita |
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Answer» Very good question Sorry i cant tell ? |
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