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6601.

A die is thrown. Find three probability of getting (a) an even prime number (b) number 5

Answer» (a).an even prime number=1/6(b).a number 5=1/6
6602.

Prove Root 2 +root 3 whole square is irrational

Answer» (√2+√3)^2=2+3+2√5 =5+2√5Let us first prove that √5 is an irrational,Let us assume that √5 is a rational numberSo, √5=p/q,where q≠0,HCF(p,q)=0 (√5)^2=(p/q)^2,squaring on both the sides 5=p^2/q^2 5q^2=p^2 ......eqn 1q^2 is a multiple of 5;p^2 is also a multiple of 5;Therefore,even p is a multiple of 5;Let p=5r where r is a positive integer, 5q^2=(5r)^2......by eqn 1 5q^2=25r^2 q^2=5r^2r^2 is a multiple of 5q^2 is also a multiple of 5Therefore,even q is a multiple of 5 By this we come to know that the HCF is not 1.This contradiction arised due to our wrong assumption that √5 is a rational number.Therefore,√5 is an irrational number.Now,let us assume that (5+2√5) is a rational number, So, (5+2√5)=a/b,where b≠0,HCF(a,b)=1 2√5=a-5b/b √5=a-5b/2b Irrational≠integer/integer=rationalThis contradiction arised due to our wrong assumption that (5+2√5) is a rational number.Therefore,(5+2√5) is a irrational number.i.e;(√2+√3)^2 is a irrational number .Hence,proved
6603.

Which probability of dice in even no.

Answer»
6604.

965355/888558

Answer»
6605.

I m having maths exam this Monday wish me luck and plz give any suggestions to prepare☺

Answer» all the very best for your exam dear . Few tips that could help you would be :*first of all try to do easier and simple questions so that u boost up your confidence level* secondly before revising the questions , learn and revise all the formulaes of whatever chapter u r going revise. *do complete ncert first *then try to do some other book like exam idea , r.d sharma , r.s agarwal etc*when u are comple with ur book exercise take many sample papers and solve questions according to each chapter while revising *after this take 3-4 sample papers n sit for 3 Hrs and do it . From this u ll be able to get to know whether u can solve the whole paper in 3 hrs time limit or not . hope these tips would help u to get good marks in ur exam . DO UR BEST AND BEST OF LUCK!!!!
6606.

The angles of a quadrilateral are in AP whose common difference is 10° .Find the angles.

Answer» 75,85,95,105
6607.

Make an equation who\'s zeroes are-3 and 5

Answer» K(x\'2-2x-15
x^2+2x+15
6608.

If nth term of an ap is m and mth term is n then find pth tern

Answer» K is pth term of this ap
6609.

Find the hcf of 96 and404 by using euclids division algorithm

Answer»
6610.

Please create for hindi medium

Answer»
6611.

If a = tan60°-1 b = cot 45°+2Prove that a*b=0

Answer»
6612.

How solve 2x

Answer» Put 2x=0 and then X=0/2=0
6613.

All formula of mathematics 1st term please

Answer» S¡=A+[N_1]D
6614.

In triangle Abc if DE PARALLEL BC AND AE IS 8 CM AND EC IS 2 CM AND BC IS 6 CM THEN FIND DE.

Answer» DE II BCLB = LD and LC = LEThus triangles ABC and ADE are similar (AA Rule)DE/BC = AE/ACDE/6 = 8/10DE = 6 X 8/10 = 4.8 cm
4.8cm
6615.

Given=SinA+2cosA =1To prove=2sinA-cosA=2

Answer»
6616.

a_b

Answer»
6617.

Please provide syllabus mathematics of SA1 for class 10th

Answer» the case pattern is changed by 2017-18 now the exams will held annually
6618.

If 3 tanA = 4 find the value of (5 sinA - 3 cosA)/ (5 sinA + 2 cosA)

Answer» given: 3tanA = 4 tan A = 4/3 P/B = 4/3 BC/AB = 4/3 (LET A TRIANGLE RIGHT ANGLED AT B BASE AB AND PERPENDICULAR BC AND HYPOTENUSE AC.) BC = 4K AND AB =3KUSING PYTHAGORAS THEOEMAC = 5KSIN A = 4/5COS A = 3/5NOW,(5 sinA - 3 cosA)/(5 sinA + 2 cosA)(4-9/5)/(4+6/5)(11/5)/(26/5)11/26 is the answer
6619.

(1+n)x 2 mcx + c - a = 0

Answer»
6620.

What is the full form of sss

Answer» Side side side it is a criteria of similarty
Side side side criterion of similar triangles!!
6621.

If P(E)=0.07.what will be the probability of `not E\'?

Answer» 0.93
1 - 0.07 = 0.93
P(e)+p(not E) =1
0.93
0.93
6622.

In triangle PQR S andT are points on PQ and PR respectively. Ps =4 pq =9 and PR =4.5

Answer»
6623.

n2 - 8 is divisible by 8 if n is??

Answer» n=8Now,proof:-=8×8-8/8=64-8/8=56/8=7Hence,n=8; is the value required..
6624.

a2_b2 +2ab

Answer» (a+b)(a+b)-2b2
(a+b)(a+b)
6625.

Chapter-6, theorem - 6.7

Answer»
6626.

x2 + 99x + 127 find zeroes of the polynomial??

Answer» it is of polynomial chapter how can I use this formula
Use -b+✓b²-4ac /2a
6627.

Theorem 6.7

Answer»
6628.

2+3

Answer»
6629.

How to find mean

Answer» a+fidi/xi
MethodsFirst -Sigmafi×xi /fi SecondA+ sigmafi×di /fi Third- A+ h×Sigmafi×ui /fi
Three methods for mean direct method, assuming method and step deviations
6630.

Given that sin☆+2cos☆ = 1 , then prove that 2sin☆ - cos☆ = 2.

Answer» Write cos in the form of sin then take LCM and solve it
6631.

Tan x= 20/21 then 1-sinx+cosx/1+sinx+cosx =

Answer» Sin / cos = tan Use this formula
6632.

If one of the zeroes of xcube-3xsquare-13x+15is1, find the remaining zeroes

Answer» -3 and 5 are other two zeroesAs 1 is zero so,x-1 is a factor divide it by x-1 the ans got split it u will get other 2 zeroes
6633.

6/3=

Answer» 2
6/3=2.
6634.

If x+1/x=6 find x square+ 1/x square

Answer» {tex}x+{1\\over x}=6\\\\Squaring \\ both\\ sides, \\ we\\ get\\\\=>x^2+{1\\over x^2}+2x\\times {1\\over x}=36\\\\=>x^2+{1\\over x^2}+2=36\\\\=>x^2+{1\\over x^2}=34{/tex}
34
6635.

Exercise 6.6 question no.3

Answer»
6636.

What is trignometry

Answer» Trigonometry is the branch of mathematics dealing with the relations of the sides and angles of triangles and with the relevant functions of any angles.
Measurement of triangles
Trigonometry means measurement of angle of a right angled triangle
6637.

NCERT EXERCISE 8.1 OUESTION NUMBER 6

Answer»
6638.

Solve the following quadratic equation for x. X square - 4ax - b square +4a square = 0

Answer» We have,x2 - 4ax + 4a2 - b2\xa0= 0{tex}\\Rightarrow{/tex}(x -2a)2\xa0- b\u200b\u200b\u200b\u200b\u200b\u200b2\xa0= 0{tex}\\Rightarrow{/tex}(x - 2a + b)(x- 2a- b) = 0{tex}\\Rightarrow{/tex}x -2a + b = 0 and x -2a - b = 0{tex}{/tex}{tex}\\Rightarrow{/tex}\xa0x = 2a - b or 2a + b
6639.

A19=47 find a

Answer» 2.473684211
a=3
6640.

Please provide me marking scheme of SA-1 with chapter weightage.

Answer»
6641.

Prove that sin0-cos0+1/sin0+cos0-1=1/sec0-tan0

Answer» i want solution of this qus
6642.

1/5of180

Answer» 36
6643.

Proof of SAS and SSS criteria rule

Answer»
6644.

B.p.t

Answer» Basic proportionately theorem
6645.

A (-3,2)B (-2,-1)C (0,0) are points on circle find radius of circle

Answer»
6646.

1+2+3+4+5×1+2+4(3-8)×0

Answer» 17
0
45
6647.

If cosA =√4-x.x/2 find the value of secA.tanA

Answer»
6648.

What is dependable consistent

Answer»
6649.

In which questions we put the formula how we know it

Answer» By practicing more and more questions...................................... ...... ..............
6650.

Fegj

Answer»