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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6751. |
What is the altitude of an equilateral triangle of each side 6cm? |
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Answer» let ABC be an equilateral triangle and AD is the altitude from A to BC and BD=1/2 BC i.e. BD=3 cmThen in the\xa0right angled triangle\xa0ADB AB2 = BD2 +\xa0AD262\xa0= 32+ AD2AD=36 - 9= root\xa027= 3 root3 cm Altitude of equilateral triangle=√3/2*side =√3/2*6 =3√3cm |
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| 6752. |
Determine vertically the vertices of the triangle formed y=x 3y=x x+y=8 |
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| 6753. |
In board Geometry will come from ncert or it can come from other refreshers ... |
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| 6754. |
In triangle PQR right angled at Q,PQ+QR=25.Determine the value of Sin P,CosP and TanP. |
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| 6755. |
2xm+3x |
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| 6756. |
To prove:√1+SinA/1-SinA=SecA+TanA |
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| 6757. |
√3x^2-8x+4√3 |
| Answer» √3x^2-6x-2x+4√3=√3x(x-2√3)-2(x-2√3)=(x-2√3)(√3x-2) | |
| 6758. |
Root 2 prove |
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| 6759. |
Real root of 5 |
| Answer» 2.2306 | |
| 6760. |
Prove that cube√2 is irrational |
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| 6761. |
Which term of the AP 3,10,17..... will be 84 more than its 13th term? |
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Answer» Given that a = 3 , d = 7 A13 = 3 + 12*7A13= 87Now 87+84 = 171171 = 3 + (n-1)7168 = 7n - 7175 = 7nn = 25Ans = 25th 25th term is the answer |
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| 6762. |
Calculate the hcf of 3*3*3*5 and 3*3*5*5 |
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Answer» Sorry it\'s 45 Hcf is 40 |
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| 6763. |
TanA + cot a =2 find tan2a + 1/cot2 a |
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| 6764. |
TanA +cotA =2 find Tan2 A + 1/cot2a |
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| 6765. |
Write the value of bracket 256 square 0.25 |
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Answer» 4 4 is the answer. (256)^0.25=(256)^25/100=(256)^1/4=4 as 4×4×4×4=256 |
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| 6766. |
Prove that 3 is rational number |
| Answer» is that root 3 or simple 3 | |
| 6767. |
What is ap |
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Answer» Arithmetic progression Arthmatic progession three formulas these chapters Arithmetic Progressions. |
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| 6768. |
Triangle ABC is right angles at B and D is mid point of BC. prove that square AC EQUAL 4AD -AB |
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| 6769. |
Their w |
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| 6770. |
Marking scheme latest |
| Answer» Please answer | |
| 6771. |
show that the four points (0,1),(6,7),(-2,3)&(8,3) are the vertices of rectangle |
| Answer» Let A (0 - 1), B (6, 7), C (-2, 3) and D (8, 3) be the given points. Then,AD =\xa0{tex} \\sqrt { ( 8 - 0 ) ^ { 2 } + ( 3 + 1 ) ^ { 2 } } = \\sqrt { 64 + 16 } = 4 \\sqrt { 5 }{/tex}BC =\xa0{tex} \\sqrt { ( 6 + 2 ) ^ { 2 } + ( 7 - 3 ) ^ { 2 } } = \\sqrt { 64 + 16 } = 4 \\sqrt { 5 }{/tex}AC =\xa0{tex} \\sqrt { ( - 2 - 0 ) ^ { 2 } + ( 3 + 1 ) ^ { 2 } } = \\sqrt { 4 + 16 } = 2 \\sqrt { 5 }{/tex}and, BD =\xa0{tex} \\sqrt { ( 8 - 6 ) ^ { 2 } + ( 3 - 7 ) ^ { 2 } } = \\sqrt { 4 + 16 } = 2 \\sqrt { 5 }{/tex}Therefore, AD = BC and AC = BDSo, ADBC is a parallelogramNow, AB =\xa0{tex} \\sqrt { ( 6 - 0 ) ^ { 2 } + ( 7 + 1 ) ^ { 2 } } = \\sqrt { 36 + 64 }{/tex}= 10and, CD =\xa0{tex} \\sqrt { ( 8 + 2 ) ^ { 2 } + ( 3 - 3 ) ^ { 2 } }{/tex}= 10Clearly, AB2\xa0= AD2\xa0+ DB2\xa0and CD2\xa0= CB2\xa0+ BD2Hence, ADBC is a rectangle.Area of rectangle ADBC =\xa0{tex} A D \\times D B = ( 4 \\sqrt { 5 } \\times 2 \\sqrt { 5 } ){/tex}sq. units = 40 sq. units. | |
| 6772. |
CH 8 ex 8.4 question 5 |
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| 6773. |
π is a irrational no. While 22/7 is a rational |
| Answer» 22/7 is not the exact value of π {it is approximate} | |
| 6774. |
Root6+root6+root6+....... |
| Answer» Let x=√6+√6+√6........x^2=6 +√6+√6........x^2=6+xx^2-6-x=0 and solve it | |
| 6775. |
What is Pythagoras theorm |
| Answer» (H)2=(B)2+(P)2that is not two that is sqare | |
| 6776. |
Find sum of first 11 terms of an a.p. whose middle term is 60 |
| Answer» n=11(a1+a11) / 2 =60a1+a11=120sum of AP = n/2 (a1+a11)\xa0 = 11/2 x 120 = 660\xa0 | |
| 6777. |
Solve ax+by=a-bbx-ay=a+b |
| Answer» ax + by = a - b multiply by abx - ay = a + b multiply by b{tex}\\Rightarrow{/tex} x = 1{tex}\\therefore{/tex} a + by = a - bby = -by = -1{tex}\\therefore{/tex} x = 1y = -1 | |
| 6778. |
Prove that root 5 is irrational |
| Answer» let root 5 be rationalthen it must in the form of p/q [q is not equal to 0][p and q are co-prime]root 5=p/q=> root 5 * q = psquaring on both sides=> 5*q*q = p*p ------> 1p*p is divisible by 5p is divisible by 5p = 5c [c is a positive integer] [squaring on both sides ]p*p = 25c*c --------- > 2sub p*p in 15*q*q = 25*c*cq*q = 5*c*c=> q is divisble by 5thus q and p have a common factor 5there is a contradictionas our assumsion p &q are co prime but it has a common factorso\xa0√5 is an irrational | |
| 6779. |
2x+y=0 find there zeros? |
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| 6780. |
Factorize: a^2+b^2-2 (ab-bc-ca) |
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| 6781. |
Find2tan30°÷1+tan230° |
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Answer» 2*1/√3/1+(1/√3)²=2/√3/1+1/3=2/√3/3+1/3=2/√3÷4/3=2/√3×3/4=√3/2 = 2×1/^3 ÷1+1/3=2/^3+1/3=2^3+1/3Note:^=square root |
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| 6782. |
Sintheeta by cos theeta |
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Answer» Tan theeta TanΘ tantheeta |
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| 6783. |
Hey there r 10 members of the group that i wanted to make now our group is ready.... |
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| 6784. |
How many two digit number are divisible by 3 |
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Answer» numbers divisible by 3 = 3,6,9,12,.....................the least\xa02 digit number\xa0divisible by 3 is 12the largest 2 digit number divisible by 3 is 99so we get 12 , 15, 18, ..... 99 are in ApWe have to find n\xa0last term is 99an = 99a1=12d=3an = a1 +(n-1)399=12+3n-33n=90n=30\xa0\xa0 12, 15,18,......,99 |
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| 6785. |
Value Of root 6 |
| Answer» Root of 6 is 2.449 | |
| 6786. |
If sum of q terms of an AP is 162 and a=2d then find the value of a |
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| 6787. |
state and prove pythgorus |
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| 6788. |
Hob l. |
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| 6789. |
In a acute angled triangle abc if sin (a+b-c)=1/2 and cos (b+c-a)=1/root 2 find angles a b and c |
| Answer» Since sin 45 degree equal to 1 by 2 and Cos 60 degree equal to one by root 2 so show a + b + C is equal to 60 degree and a + b + c equal to 45 degree so adding Season 1 and 2 we get that a and c is cancelled out and we get the value of B and putting the value of the input the equations will get that all the values up a b and c | |
| 6790. |
X-Y-2y 4-g |
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| 6791. |
SMS from home as an ap is equal to n s on |
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| 6792. |
Ifind mth tex) |
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| 6793. |
proove of pythagoras theorm |
| Answer» H^2=p^2+b^2 | |
| 6794. |
How many of you play mini militia game?I suggest u this addictive game.DOWNLOAD NOW! |
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Answer» Join my lobby \'prateek kingdom\' from battlezone india.good luck? Good I play mini militia game. |
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| 6795. |
√2+4×√6 |
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Answer» 10 √2+4√6? |
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| 6796. |
find the value of A, If CosA/1-SinA+CosA/1+SinA=4,A=Less than or equal to 90 |
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| 6797. |
Fund value of x |
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| 6798. |
5power (x-1)+5power (2-x)=5power 3 +1 |
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| 6799. |
Why quadratic equation is so complicated and its have some simplest method please give me answee |
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| 6800. |
President Name |
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