Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 7451. |
which book will be suitable for preparation for 2018 board examination |
| Answer» Now arihant is in trend but personally I suggest oswal question bank | |
| 7452. |
sin A, cos A |
| Answer» | |
| 7453. |
If p, q are zeroes of polynomial p(x) = 2x2-7x+3, find the value of p2 + q2. |
| Answer» According to the question,\xa0p and q are the zeroes of polynomial f(x) = 2x2 - 7x + 3,\xa0f(x) = 2x2\xa0-7x + 3Sum of roots = p + q =\xa0{tex}- \\frac { \\text { Coefficient of } x } { \\text { Coefficient of } x ^ { 2 } }{/tex}{tex}= - \\left( \\frac { - 7 } { 2 } \\right) = \\frac { 7 } { 2 }{/tex}Product of roots= pq\xa0{tex}= \\frac { \\text { Constant term } } { \\text { Coefficient of } x ^ { 2 } } = \\frac { 3 } { 2 }{/tex}Since, (p + q)2\xa0=p2 + q2 + 2pqSo, p2 + q2 = (p + q)2 - 2pq{tex}= \\left( \\frac { 7 } { 2 } \\right) ^ { 2 } - 3 = \\frac { 49 } { 4 } - \\frac { 3 } { 1 } = \\frac { 37 } { 4 }{/tex}Hence, the value of p2+ q2={tex}\\frac{37}{4}{/tex} | |
| 7454. |
When will you provide new sample papers on the app |
| Answer» | |
| 7455. |
if hcf(n,32)=4 and lcm(n,32)=96 then find the value of n |
|
Answer» We know that,LCM×HCF = product of no. 96×4 = n×32384 = n ×32384÷32 = n12 =n n =12 how 12 |
|
| 7456. |
If 24 cotA-7,find value of sin A |
| Answer» 7/25 | |
| 7457. |
What is ogive |
| Answer» | |
| 7458. |
If a, (a-2) and 3a are in ap than value of a is |
| Answer» 3 | |
| 7459. |
X²+2x+8 |
| Answer» X square + 4 x + 2 X + 8X(x+4)+2(x+4)(X+4)(x+2)_4,_2 | |
| 7460. |
Prove that CosA/1 - (tanA-sin^2A/cosA-sinA)=cosA+sinA |
| Answer» | |
| 7461. |
Prove that tangents at the ends of a diameter of a circle are parallel. |
| Answer» Given: PQ is a diameter of a circle with centre O.The lines AB and CD are the tangents at P and Q respectively.To Prove: AB {tex}\\parallel{/tex} CDProof: Since AB is a tangent to the circle at P and OP is the radius through the point of contact.{tex}\\therefore{/tex}{tex}\\angle{/tex}OPA = 90o ........ (i)[The tangent at any point of a circle is\xa0{tex}\\perp{/tex} to the radius through the point of contact]{tex}\\because{/tex}\xa0CD is a tangent to the circle at Q and OQ is the radius through the point of contact.{tex}\\therefore{/tex}{tex}\\angle{/tex}OQD = 90o ........ (ii)[The tangent at any point of a circle is {tex}\\perp{/tex} to the radius through the point of contact]From eq. (i) and (ii), {tex}\\angle{/tex}OPA = {tex}\\angle{/tex}OQDBut these form a pair of equal alternate angles also,{tex}\\therefore{/tex}\xa0AB {tex}\\parallel{/tex} CD | |
| 7462. |
Happy Diwali frndzzz ?????? |
| Answer» | |
| 7463. |
Important formulas of real numbers |
| Answer» Check formulae in notes :\xa0https://mycbseguide.com/cbse-revision-notes.html | |
| 7464. |
Sum of |
| Answer» | |
| 7465. |
Solve for x 2x/x-3 + 1/2x+3 + 3x+9/(x-3)(2x+3)=0, x is not equal to the 3, - 3/2 |
| Answer» Given, {tex}\\frac{2x}{x-3}+\\frac{1}{2x+3}+\\frac{3x+9}{(x-3)(2x+3)}=0{/tex}{tex}\\Rightarrow\\frac{{2x(2x + 3) + x - 3 + 3x + 9}}{{(x - 3)(2x + 3)}} = 0{/tex}{tex} \\Rightarrow \\frac{{4{x^2} + 6x + x - 3 + 3x + 9}}{{2{x^2} + 3x - 6x - 9}} = 0{/tex}{tex} \\Rightarrow \\frac{4{x^2} + 10x +6 }{{2{x^2} - 3x - 9}} = 0{/tex}Cross multiplying equation , we get ,{tex} \\Rightarrow 4{x^2} + 10x +6 = 0{/tex}{tex} \\Rightarrow 4{x^2} + 6x+4x +6 = 0{/tex}{tex} \\Rightarrow x(4{x} + 6)+1(4x +6) = 0{/tex}{tex}\\Rightarrow(x+1)=0{/tex} or {tex} (4x+6)=0{/tex}{tex}\\Rightarrow x=-1{/tex}{tex}\\Rightarrow x=-\\frac{3}{2}{/tex}Hence , the roots of the given quadratic equation are -1 and {tex}-\\frac{3}{2}{/tex} | |
| 7466. |
What is life stable |
| Answer» | |
| 7467. |
The difference of two no. Is 4 if the difference of their reciprocal is 4/21 find the no. |
| Answer» Let first number be x.Then,\xa0second number = x + 4\xa0According to the question ,{tex}\\frac{1}{x} - \\frac{1}{x+4} =\\frac{4}{21}{/tex}{tex}\\begin{array}{l}\\frac{x\\;+\\;4\\;-\\;x\\;}{x(x+4)}=\\;\\;\\frac4{21}\\\\\\frac{\\;4}{x^2\\;+4\\;x}=\\;\\;\\frac4{21}\\\\4(x^2\\;+\\;4x)\\;=\\;84\\end{array}{/tex}⇒ 4x2 + 16x - 84 = 0⇒4(x2 +4 x - 21) = 0⇒ (x2 +4 x - 21) = 0⇒(x +7) (x -3) = 0⇒ x +7 = 0 or x - 3 = 0⇒ x = -7 or x = 3Therefore, the two numbers are 3 and 7 or -7 and -3 | |
| 7468. |
Explain why 47*19*11+19is a composite no |
|
Answer» 19 (47*1*11+1)=19 (517+1)=19 (518)=98429842 cannot be factor further .Therefore,the given expression has 19 and 518 as its factor . Hence it is composit number Because it has two factor 19(47×11+1) =19×518 composite no have maximum two factor hence this is composite no |
|
| 7469. |
what is theorem 6.6 |
| Answer» | |
| 7470. |
SecQ+tanQ-1/tanQ-secQ+1=cosQ/1-sinQ |
| Answer» | |
| 7471. |
Polinomal |
| Answer» | |
| 7472. |
What is substitution method |
| Answer» Sis bo | |
| 7473. |
10*5 |
| Answer» 50 | |
| 7474. |
if (3y-1),(3y+5)and(5y+1)are three consecutive term of an AP then find the value of y |
| Answer» 3y+5 -3y+1=5y+1-3y-5as difference is eqal in ap6=2y-42y=10y=5 | |
| 7475. |
Sin45°+cos45° |
|
Answer» Under root 2 Root 2 Square root of 2 |
|
| 7476. |
! what does it |
| Answer» | |
| 7477. |
(5To the power 4x)- 3*5to the power 2x+1 =250 solve this |
| Answer» | |
| 7479. |
3/8 in decimal form. |
| Answer» {tex}{3 \\over 8 }=0.375{/tex} | |
| 7480. |
what is split up sllybus |
| Answer» | |
| 7481. |
costita +sintita=√2costita then show that costita-sintita=√2sintita |
| Answer» | |
| 7482. |
How many term are there in AP 6,10,14,18------,174 |
| Answer» 43 terms ate in AP | |
| 7483. |
What is the relation b/w mean,mode and median? |
| Answer» Mean =3median-2mode | |
| 7484. |
What is dev |
| Answer» | |
| 7485. |
What is formula of euclidean division lemma |
|
Answer» a=bq+r where 0 a«bq+r |
|
| 7486. |
A man standing on the top of vbuildi |
| Answer» | |
| 7487. |
Can I get marks around 80% in maths by practising ncert book? |
|
Answer» Yaaa absolutely ,if u work hard then definitely you get 80% Definitely yes.but u should know how to solve because the numbers and questions may differ Yes, but example must compulsory and read theory |
|
| 7488. |
A person observed the angle of elevation of the top of a tower as 30 |
| Answer» Let height of the tower be DC = h m and BC = x m AC = (50 + x) mIn\xa0{tex}\\triangle {/tex}DBC,\xa0{tex}\\frac { h } { x } = \\tan 60 ^ { \\circ } = \\sqrt { 3 }{/tex}\xa0{tex}\\Rightarrow \\quad h = \\sqrt { 3 } x{/tex} ..(i)\xa0In\xa0{tex}\\triangle {/tex}DAC,\xa0{tex}\\frac { h } { x + 50 } = \\tan 30 ^ { \\circ } = \\frac { 1 } { \\sqrt { 3 } }{/tex},\xa0{tex}\\Rightarrow \\quad \\sqrt { 3 } h = x + 50{/tex}\xa0...(ii)Substituting the value of h from (i) in (ii), we get3x = x + 50or, 3x - x = 50\xa0{tex}\\Rightarrow {/tex}\xa02x = 50{tex}\\Rightarrow {/tex} x = 25 m{tex}h = 25 \\sqrt { 3 } = 25 \\times 1 \\cdot 732 \\mathrm { m }{/tex}\xa0= 43.3 mHence, Height of tower = 43.3 m. | |
| 7489. |
Prove that the points(3,0),(6,4)and(-1,3) are vertices of right angled isosceles triangle......... |
| Answer» Given A(3, 0), B(6, 4) and C(-1, 3)AB2\xa0= (3 - 6)2\xa0+ (0 - 4)2\xa0= 9 + 16 = 25BC2\xa0= (6 + 1)2\xa0+ (4 - 3)2\xa0= 49 + 1 = 50CA2\xa0= (-1 - 3)2\xa0+ (3 - 0)2\xa0= 16 + 9 = 25AB2\xa0= CA2\xa0or, AB = CATriangle is isocelesAlso, 25 + 25 = 50or, AB2\xa0+ CA2\xa0= BC2Since, pythagoras theorem is verified, therefore triangle is right-angled triangle. | |
| 7490. |
Find 3 is irrational |
| Answer» No 3 is not irrational | |
| 7491. |
Sir mid term exam ke solution jaldi daal do 10th class ke ok.... |
| Answer» | |
| 7492. |
Find pairs of natural numbers whose least common multiple is 78 and the greatest divisor is 13 |
| Answer» Least common factor (LCM) = 78Greatest divisor is also a HCF = 13As, we know , HCF {tex}\\times{/tex} LCM = a {tex}\\times{/tex} b ( a and b are two natural no. of which LCM and HCF is given)Therefore, required product of no. = 13 {tex}\\times{/tex} 78 = a {tex}\\times{/tex} b =1014 or 2{tex}\\times{/tex}3{tex}\\times{/tex}13{tex}\\times{/tex}13Since 13 is common in both no. as its HCF is 13Required no.= 13{tex}\\times{/tex}3 = 39 and 13 {tex}\\times{/tex}2 = 26{tex}\\therefore{/tex}\xa0Pairs of natural numbers are 78 and 13 or 26 and 39. | |
| 7493. |
why sin Rita always less than 1 |
| Answer» | |
| 7494. |
√4+2√2 |
| Answer» 2(1+√2) | |
| 7495. |
If the common difference of an ap is 3 than find the a20 and a15 |
| Answer» a+19d and a+14d , where d is the common difference. | |
| 7496. |
What is a slope |
| Answer» | |
| 7497. |
Find the roots of quadratic equation 3 X square + 5 root 5 x minus 10 equals to zero |
|
Answer» (-5+✓145)/6 and( -5-✓145)/6 Root 5 upon 3 and -2root5 |
|
| 7498. |
L |
| Answer» | |
| 7499. |
(2x+4y)=0 |
| Answer» | |
| 7500. |
Give the first whole no |
|
Answer» 0,1,2,3,3 0 0,1,2,3,4 |
|
