Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 7501. |
I want cbse sample papers .but I am not getting it |
| Answer» | |
| 7502. |
If aabb is a four digit number and also a perfect square , then find the value of a+b. |
| Answer» 11 | |
| 7503. |
A mango is there of rupees 30 find the other product |
| Answer» | |
| 7504. |
sin square theta + cos square theta + 3 sin square theta cos square theta equal to 1 |
| Answer» Yes first you change sin into cos | |
| 7505. |
Determine the AP whose fourth term is 18 and difference of ninth term from fifteenth term is 30 |
| Answer» A4=A+3D=18A9=A+8DA15=A+14DA15-A9=A+14D-A-8D=6D=30(GIVEN) D=5,A=3A.P.=3,8,13,18,23,28,33,......... | |
| 7506. |
s5+s7=167s10=235Find a.pWhere sn denotes the sum of its first n terms |
| Answer» A. P. =1,6,11,16,21,... | |
| 7507. |
2+2_78 |
| Answer» | |
| 7508. |
For what value of n 2^n*5^n ends in 5 |
| Answer» Not any value will satisfy this | |
| 7509. |
15+14=192,15+10=552,25+16=914,Then find the value of 10+8=? |
| Answer» Answer=218First subtract get2 then add get 18 reverse it and get 81.Then answer is 218.You can check this logic in the given. | |
| 7510. |
New pattern of exam |
| Answer» | |
| 7511. |
CosA = 1-sinA1+sinA CosA |
| Answer» | |
| 7512. |
What is maths? |
| Answer» | |
| 7513. |
X²+4x-9=0 |
| Answer» | |
| 7514. |
Calculate 3/8 in decimal form |
| Answer» Answer is 0.375 | |
| 7515. |
What is area of hexagon |
|
Answer» 6 * area of triangle 3root3/2 ×side square |
|
| 7516. |
How we know where we use section formula and mid point formula |
| Answer» | |
| 7517. |
Cot A+tanB upon cotB+tanA=cotAtanB prove |
| Answer» 1/tan a+ tan b upon 1/tan b+ tan a1/tan a*tan b upon tan A upon 1+ tan a*tan b upon tan b1/tan a ➗ 1/tan b1/ tan a*tan bCot a*tan b | |
| 7518. |
2k, 3k-1,8 what are the value of k |
| Answer» 2.5 or 5/2 | |
| 7519. |
why sin x is always less than 1 or equal to zero |
| Answer» sinx=perpendicular/hypotenuse =\'p\' is always less than by \'h\'So the value will not exceed 1 | |
| 7520. |
Tsa of sphere |
| Answer» 4*pi *r square | |
| 7521. |
Prove that sinx-cosx+1/sinx+cosx-1=1/secx-tanx |
| Answer» sinx-cosx+1/sinx+cosx -1=(sinx-cosx+1)x(sinx +cosx +1) / (sinx+cosx - 1)x(sinx +cosx +1)=(sinx +1)sq. - (cosx)sq./ (sinx +cosx) sq. - (1)sq.=sinsq.x+2sinx+1-cossq.x/ sinsq.x+cossq.x+2sinxcosx-1=2sinsq.x+2sinx/ 2sinxcosx=2sinx(sinx +1)/ 2sinxcosx=sinx+1/cosx=(1+sinx)x(1-sinx)/ (cosx) x(1-sinx)=cosx/(1-sinx) (dividing num. and den. by cosx) =1/secx-tanx PROVED BY SIDDHARTH THE | |
| 7522. |
solve the following equation by completing method 3 x square _ 5x+ 2=0 |
| Answer» Ans : x=1 and x=2/3 | |
| 7523. |
If the last term of an AP is 119 and the 8th term from the end is 91 there common difference is |
| Answer» -4 | |
| 7524. |
If 2x,x+10,3x+2 are in AP, find the value of x |
|
Answer» X=6 X=6 |
|
| 7525. |
Any easy way for learning formula of area of triangle |
|
Answer» Triangle is half of the rectangle Area=0.5(length x breadth) Length×breath×height Ye to khud itna easy formula hai 1/2basexhight |
|
| 7526. |
Find the value of m . So that the quadratic eqation mx(x-7)+49=0 ,has 2 equal roots |
| Answer» M=4 | |
| 7527. |
Find the number of pairs of parallel planes that a regular hexagon possesses. |
| Answer» 3 | |
| 7528. |
If sec4 A=cosec(A-20),where 4A is an acute angle. Find the value of A |
|
Answer» A=22 22 |
|
| 7529. |
Prove 2+2=5 |
| Answer» | |
| 7530. |
Prove pythogoras thoerm |
| Answer» | |
| 7531. |
Prove 0/0=2 |
| Answer» | |
| 7532. |
Define radian? |
| Answer» | |
| 7533. |
Sin2A=2SinA is true when A =? |
| Answer» 0 | |
| 7534. |
Find the point on the x-axis which is equidistant from the point (2,-5)and (-2,9). |
| Answer» Let the point of x-axis be P(x, 0)Given A(2, -5) and B(-2, 9) are equidistant from PThat is PA = PBHence PA2\xa0= PB2 → (1)Distance between two points is\xa0{tex}\\sqrt{[(x_2\xa0- x_1)^2\xa0+\xa0(y_2\xa0- y_1)^2]}{/tex}PA =\xa0{tex}\\sqrt{[(2\xa0- x)^2\xa0+\xa0(-5\xa0- 0)^2]}{/tex}PA2\xa0= 4 - 4x +x2\xa0+ 25=\xa0x2\xa0- 4x + 29Similarly,\xa0PB2\xa0=\xa0x2\xa0+ 4x + 85Equation (1) becomesx2\xa0- 4x + 29 =\xa0x2\xa0+ 4x + 85- 8x = 56x = -7Hence the point on x-axis is (-7, 0) | |
| 7535. |
Mental ability questions available |
| Answer» | |
| 7536. |
Find ap 23 |
| Answer» | |
| 7537. |
Why trigonometric ratios are 6? Why not 12, 16 |
| Answer» Because there can be only 6 ratios made by perpendicular,base&hypotenuse. | |
| 7538. |
Prove that 1+secA÷secA=sin^2A÷1-cosA |
| Answer» (1+secA)/secA=1/secA+1=cosA +1=(1+cosA)(1-cosA)/ 1-cosA=1-cossq. A/1-cosA =sinsq.A/1-cosA | |
| 7539. |
what is the smallest number that,when divided by 35,56and 91 leaves remainders of 7 in each case. |
| Answer» 3647 | |
| 7540. |
Find the value of p , if the number x,2x+p,3x+p are three consecutive terms of an AP |
|
Answer» P=0 4 |
|
| 7541. |
tanA/1-cotA+cotA/1-tanA=(1+secA.cosecA)prove |
| Answer» tanA/(1-1/tanA)+cotA(1-tanA)=-tansq.A/(1-tanA)+1/tanA(1-tanA)=1-tancubeA/tanA(1-tanA)=(1-tanA)(1+tansq.A+tanA)/ tanA(1-tanA)=1+tansq.A+tanA/ tanA=cotA+tanA+1=cosA/sinA+sinA/cosA+1=(cossq.A+sinsq.A+cosAsinA)/cosAsinA=(1+sinAcosA)/sinAcosA=1+secAcosecA Proved | |
| 7542. |
1+1+1+1+1×0-1+1+1=kya hoga |
|
Answer» Acc. To bodmass answer is5 2 5 5 5 or -3 1 3 5 is the answer\xa0 |
|
| 7543. |
I want cbse sample paper with marking scheme for 2018 exam |
| Answer» Check sample papers here :\xa0https://mycbseguide.com/cbse-sample-papers.html | |
| 7544. |
What is imaginary number |
|
Answer» Which don\'t exist. They are represented by "i" e.g. √-1 Which does not exist |
|
| 7545. |
Why is the value of pie( ) considered 180° in trigonometry |
| Answer» | |
| 7546. |
{2×2×2×x-1} +10÷21=98 |
| Answer» | |
| 7547. |
Can anybody give me the important questions of chapter 1and 2 ? |
| Answer» | |
| 7548. |
Solve the following pair of linear equations for X and Y b/a y=a^2 +b^2 ; x+ y = 2ab |
| Answer» | |
| 7549. |
2x/(x-4) + (2x-5)/(x-3)=25/3 |
| Answer» | |
| 7550. |
Construct a rhombus DAME with its diagonal DM=10cm and AE=7cm |
| Answer» | |