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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 7751. |
Can I get the cbse guidelines |
| Answer» | |
| 7752. |
When are the boards for class ten starting? |
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Answer» 9th Feb????I thought it was in march!! May I plz know ur source of information about the same. Maybe from 9th feb |
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| 7753. |
R(cube)=16.3 find value of r |
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| 7754. |
Prove that 0-0=2 |
| Answer» Let 0 equal 4 and other 0 equal 2 | |
| 7755. |
111111111+33333 |
| Answer» 111144444 | |
| 7756. |
The mid point of the line segment joining (2a, 4)and (-2,3b) is (1,2a+1). The value of a and b is |
| Answer» C(1, 2a + 1) is the midpoint of A(2a, 4) and B(-2, 3b){tex}x = \\frac { x _ { 2 } + x _ { 1 } } { 2 }{/tex}and\xa0{tex}y = \\frac { y _ { 2 } - y _ { 1 } } { 2 }{/tex}{tex}1 = \\frac { - 2 + 2 a } { 2 }{/tex}and\xa0{tex}2 a + 1 = \\frac { 3 b + 4 } { 2 }{/tex}2 = -2 + 2a and 4a + 2 = 3b + 4 ...(1)a = 2 ...(2)Putting a = 2 in (1), we get4\xa0{tex}\\times{/tex}2 + 2= 3b\xa0{tex}\\Rightarrow{/tex}\xa010 - 4 =3b{tex}\\Rightarrow{/tex}\xa03b = 6\xa0{tex}\\Rightarrow{/tex}{tex}b = \\frac { 6 } { 3 } = 2{/tex}Hence, a = 2 and b = 2 | |
| 7757. |
a=50 b=80 find ab |
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Answer» 4000 4000 |
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| 7758. |
I want to know that how marks questions will come from each chapter according to latest |
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| 7759. |
Exponents and powers |
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| 7760. |
Best ? of luck for ntse exam to all |
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| 7761. |
Formulas of sav |
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| 7762. |
Cosec+sec=2 then. Cosec^2 + sec^2? |
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| 7763. |
A die is thrown. Find probability given. (1) a prime number (2) 2 or 4 (3) a multiple of 2 or 3 |
| Answer» 1) 3 2) 1/3. 3)2/3 | |
| 7764. |
PQ is a tangent to the circle at A. If angle PAB=58°, find angle ABQ and angle AQB |
| Answer» Join OA.\xa0clearly, OA {tex}\\perp{/tex}\xa0PAQ.{tex}\\therefore{/tex}\xa0{tex}\\angle{/tex}OAP = 90°{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}1 + 58° = 90°{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}1 = 90° - 58° = 32°In {tex}\\triangle{/tex}BOA,OA = OB. [radius of circle]\xa0Now,\xa0{tex}\\angle{/tex}PAB={tex}\\angle {/tex}ARB={tex}58^\\circ{/tex}[alternate\xa0angles are equal]{tex}\\angle{/tex}ABQ = 32° [as AO=OB,angles opposite to them must be equal]{tex}\\angle{/tex}PAB + {tex}\\angle{/tex}BAQ = 180°{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}BAQ = 180° - 58°= 122°In {tex}\\triangle{/tex}ABQ,{tex}\\angle{/tex}ABQ + {tex}\\angle{/tex}BAQ + {tex}\\angle{/tex}AQB = 180°\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}{tex}AQB = 180° - 122° - 32° = 26°{/tex} | |
| 7765. |
Tell me about permutation and combination and please do hurry |
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| 7766. |
Which term of the AP:3,8,13,18,......,is 78 |
| Answer» 16th term | |
| 7767. |
If sintheta =tan theta then value of cos theta is |
| Answer» 60degree | |
| 7768. |
If a mean of the following frequency distribution is 24 find the value of p |
| Answer» | |
| 7769. |
A protractor it\'s circumference 22 cm find radius |
| Answer» √7 | |
| 7770. |
Which type of questions come in bord examination |
| Answer» Check last year papers :\xa0https://mycbseguide.com/cbse-question-papers.html | |
| 7771. |
4,4,4,4 and 8 numbers used and plus, minus, divide and multiplied used make 100 |
| Answer» 4+4+4*8+4=100 | |
| 7772. |
Number 4,4,4,4 and 8 used and +, /,*, _ |
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| 7773. |
If PQ and PR are two tangents to a circle with centre o .if angleQPR=46 find angle OQR |
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| 7774. |
Find the circumference of circle whose Area is 16 times the area of the circle with diameter 7 can? |
| Answer» Area of Circle with diameter 7 units =\xa0{tex}\\pi \\times \\frac{7}{2}^2{/tex}=\xa0{tex}\\frac{49}{4}\\pi{/tex}\xa0sq unitsArea of Bigger Circle =\xa0{tex}16 \\times\\frac{49}{4}\\pi^2{/tex}=\xa0{tex}4 \\times 49 \\pi{/tex}sq unitsNow, to find radius of bigger circle,Area of Bigger Circle =\xa0{tex}4 \\times 49 \\pi{/tex}sq units{tex}\\pi{/tex}R2\xa0=\xa0{tex}4 \\times 49 \\pi{/tex}R2\xa0= 4 x 49R = 2 x 7 = 14 unitsTherefore, Circumference of Bigger Circle = 2{tex}\\pi{/tex}R = 2{tex}\\pi{/tex}(14) = 28{tex}\\pi{/tex} units | |
| 7775. |
If x=a sec theta+b tan theta ,y=a tan theta +b sec theta prove that x 2 -y \u200b2 =a 2 -b 2 |
| Answer» Given: x = a sec\xa0{tex}\\theta{/tex} + b tan\xa0{tex}\\theta{/tex}\xa0and y = a tan\xa0{tex}\\theta{/tex}\xa0+ b sec\xa0{tex}\\theta{/tex}ATQx2 - y2 = (a sec\xa0{tex}\\theta{/tex}\xa0+ b tan\xa0{tex}\\theta{/tex})2 - (a tan\xa0{tex}\\theta{/tex}\xa0+ b sec\xa0{tex}\\theta{/tex})2\xa0= a2 sec2\xa0{tex}\\theta{/tex}\xa0+ b2 tan2\xa0{tex}\\theta{/tex}\xa0+ 2ab sec\xa0{tex}\\theta{/tex}\xa0tan\xa0{tex}\\theta{/tex}\xa0- (a2 tan2\xa0{tex}\\theta{/tex}\xa0+ b2 sec2\xa0{tex}\\theta{/tex}\xa0+ 2ab tan\xa0{tex}\\theta{/tex}\xa0sec\xa0{tex}\\theta{/tex})=a2 (sec2\xa0{tex}\\theta{/tex}\xa0- tan2\xa0{tex}\\theta{/tex}) - b2 (sec2\xa0{tex}\\theta{/tex}\xa0- tan2\xa0{tex}\\theta{/tex})= a2 - b2Hence proved. | |
| 7776. |
Check whether 5×7+7×3+3 |
| Answer» | |
| 7777. |
फाइंड थे साइन 30 |
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Answer» Ha ha silly question sin30° =1/2 |
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| 7778. |
Check whether 5*7+7*3+3 is a composite number and justify |
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| 7779. |
a=5 c=6 find b |
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Answer» Can u prove that the answer is 5.5 5.5 |
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| 7780. |
How was ntse paper |
| Answer» Maharashtra mein paper hone ka hai | |
| 7781. |
Trigonometric identites |
| Answer» Trigonometric identities are equations involving the trigonometric functions that are true for every value of the variables involved. Some of the most commonly used trigonometric identities are derived from the Pythagorean Theorem , like the following: sin2(x)+cos2(x)=1. 1+tan2(x)=sec2(x). | |
| 7782. |
Isme diya important question kya board exam me aayega |
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| 7783. |
The 8th term of an appointment is 37 and it\'s 12th term is 57 find ap |
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Answer» a8=a+7d=37 ........ ia12=a+11d=57 ...... iifrom i and ii\xa04d=20 d=5a+35=37a=2AP is 2 , 7, 12. 17\xa0........... 2,7,12,17,22,27,32,37,42,47 |
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| 7784. |
Two hemisphere in half of circle find area of shaded region whose diameter is 36cm |
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| 7785. |
Who like maths |
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Answer» Science teri jaan h tua maths meri jaan h or jaan se bhi badkar Mujhe maths apne pyaar se bhi jyada pas and h. Science meri jaan hai ushe mujhse koi juda nahi ker sakta maths bhi nahi ager hum maths ko padte hainntab badi calculations per calculator kun udhate hain whyyyyyy???????? Only science science science |
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| 7786. |
Activity 5 math NCERT |
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| 7787. |
Where do we get solutions of important question |
| Answer» Internet | |
| 7788. |
Kitne log god me believe kerte hain mein to kerta hon |
| Answer» | |
| 7789. |
Find the value of p so that the quadratic Equation px( x-3)+9=0 has two equal roots |
| Answer» we have,{tex}px^2 - 3px + 9 = 0\xa0{/tex}put a = p , b = -3p, c = 9 in\xa0{tex}b^{2}-4 ac{/tex}{tex}b^2 - 4ac = (-3p)^2 - 4(p)(9){/tex}{tex}= 9p^2 - 36p{/tex}for having equal roots\xa0{tex}b^2 - 4ac = 9p^2 - 36p = 0\xa0{/tex}{tex}9p^2 - 36p = 0\xa0{/tex}9p(p - 4)\xa0= 0\xa09p = 0 or p - 4 = 0\xa0p = 0 or p = 4 | |
| 7790. |
Objective |
| Answer» | |
| 7791. |
Distancebetween the point (0,0)and(36,19)can we find the distance between the two towns A B |
| Answer» You have to use distance formula of ncert 10 textbook to solve this question. | |
| 7792. |
If 3x+7y=-1,4y-5x+14=0 find the value of 3x-8y |
| Answer» Do it yourself? | |
| 7793. |
Is 184 is the term of the A . P 3,7,11 |
| Answer» 735 | |
| 7794. |
Cos theta + sin theta = P 1/cos theta + 1/sin theta = V . Then find the value of V |
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| 7795. |
Formula of chapter 12 |
| Answer» Check it in your book | |
| 7796. |
If 6/5 a 4 are in ap find value of a |
| Answer» There is no answer of this question | |
| 7797. |
Sir mathematics ka NCERT solutions hindi me upload Kar do please........ |
| Answer» To whom do you say sir??? | |
| 7798. |
TanA |
| Answer» | |
| 7799. |
how to do easy calculations in math |
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| 7800. |
Tan¤\\sec+1+cot¤\\cosec¤+1= cosec¤+sec¤/-cosec¤sec¤ |
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