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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 8201. |
A rational number between 3/5 nd 4/5 is |
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Answer» 8/10 10/15, 11/15, etc... 19/30 , 20/30 , 21/30 , 22/30 , 23/30 7/10 is correct answer 3¼,3⅔ etc. |
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| 8202. |
Which of the following is not a zero of the polynomial x^3 - 6x^2 + 11x -6 .A) 1B) 2C) 3D) 0 |
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Answer» D)0 D) 0. |
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| 8203. |
6+√5is a irrational number prove |
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Answer» Prove √5 is irrational (in short steps). Then, as sum of rational number (6) and irrational number (√5) is always irrational, 6 + √5 is also irrational. Hlo Sakshi singh Hlo If possible let 6+√5 is a rational number...... Let 6+√5 =a/b {a and b is co- prime number } # 6+√5 a/b # √5 = a/b - 6 # √5 = a -6b / b # products of rational is always rational # a- 6b is a rational number # √5 is a rational number # But we know that √5 is an irrational number # so it contradict the fact so our is asumalt is wrong...... ................ Aakash Anand ? |
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| 8204. |
Find the value of a and b if x⁴+x³+8x²+ax+b is divisible by x²+1....please give a whole solution |
| Answer» x²+1) x⁴+x³+8x²+ax+b(x²+x+7 X⁴+ +x² _______________ 0 +x³ + 7x²+ ax+b +x³ + + x __________________ 0 +7x²+a +b +7x² +1 ________________ 0 a +b | |
| 8205. |
First equation X + 2 Y is equal to 12 second equation x minus Y is equal to 4 |
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| 8206. |
Using Euclid\'s Division Algorithm Prove that 847,2160 are co-prime number |
| Answer» Co-primes are 2 numbers which have only one as a common factor.a = 2160b = 847By Euclid\'s lemma a=bq+r, 0≤r | |
| 8207. |
(2567)² |
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Answer» 6589489 6589489 (2567)² = 2567 x 2567 = 6,589,489 Ans is 6589489 |
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| 8208. |
(26) |
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Answer» Yes I have remember 26/11??? Kay bro (26) .? |
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| 8209. |
Solve (2√2)² |
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Answer» 4×2=8 2×✓2×✓2=2×2=4 (2√2)²=(2×2×√2×√2)=(4×2)=8 8 answer 4×2= 8 |
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| 8210. |
Express 59/2raises4× 5raises3 |
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Answer» Can you please get the answer of my question. I am sorry. I didn\'t know about it. Anyways, hi avni What do u think should boards be cancelled or not.... If any other person is reading this question comment down⤵⬇ About their choice regarding cancellation of boards... Thank you? Me too ?sorry Sorry I don\'t know ? |
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| 8211. |
Explain why 6 x 5 x 4 x 3 x 2 x1 +1 is a composite number. |
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Answer» 721 6×5×4×3×2+1=721721=7×103Hence it is a composite no . Give equation have not more then two factor then it is not composite number ? Composite number more then two factor ? 1(6×5×4×3×2+1) Thus , it has more than one factor .Therefore, it is a composite number. |
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| 8212. |
Explain why 6 x 5 x 4 x 3 x 2 x1 +1 is not a composite number. |
| Answer» #1(6×5×4×3×2) 1 × 720 ...... ........ Give equation have not more than two factor then it is not a composite number? | |
| 8213. |
12-9 |
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Answer» 3.0000000000000000000000000000 3 3 3? 3 |
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| 8214. |
40-45 45-50 50-55 55-60 60-70 frequency 4 6 16 20 30 24 |
| Answer» Please ask question with complete information. | |
| 8215. |
Find the ratio between the L.C.M and H.C.F of 5,15,20 |
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Answer» LCM ( 5,15,20) = 60 and HCF (5,15, 20)= 5 . Therefore ratio is equal to 60/5 that is 12:1 ❤5= 5×1❤15=3×5×1❤20=2×2×5×1 ?HCF = 5 ? LCM=2×2×3×5= 60 ?❤ Ratio = LCM/HCF = 60/5 ?12/1 ..... Ratio =12:1 .answer ........... Aakash Anand ?❤ |
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| 8216. |
For what value of an unnatural number 24th is divisible by 8 |
| Answer» Yeah | |
| 8217. |
Find the area of the sector of a circle with radius 6cm if angle of sector is 60 degree |
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Answer» πr² thetha /360°=22/7×6×6×60°/360°= 22/7×6=132/7=18.8 cm². Put the value in the formulas πr^2× theta upon 360 we get 132/7 which is 18.857 cm square |
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| 8218. |
Sides of triangle are given below. Determine whether it is right triangle or not 13,12,5 |
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Answer» By converse of Pythagoras theorem we get 12 square plus 5 square = 13 square . Therefore it is a right angled traingle . Yes the gives sides can form right angle |
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| 8219. |
Sides of a two similar triangle are the ratio 4:9 . Find the areas of the triangle in the ratio |
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Answer» 16/81 Given: the ratio of sides is 4:9Solution:Let there are two triangles ABC and PQR similar to each otherWhere AB/PQ=4/9According to theorem 6.6 which states that the ratio of areas of similar triangles is equal to the square of the ratio of their sidesHence,ar(ABC)/ar(PQR)=(AB/PQ)² =(4/9)² =(16/81)Therefore, the ratio of the areas of given triangles is 16:81Hope this helps u!!!One more thing this(theorem 6.6) is deleted from the syllabus od 2020-2021 as 30percent syllabus is reduced??? 16/81 |
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| 8220. |
What is an , l, n and nth term |
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Answer» Okay thank you Here l is the last term of the ap. And n is term of any no. In ap. And nth term is usually denotes to the whole ap sequence. |
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| 8221. |
Find the values of k for given quadric equation, so that have equal roots : 2x^2+is+3 =0 |
| Answer» Please ask question with complete information. | |
| 8222. |
If 2 and -3 are the zeroes of the quadric polynomial x^2+(a+1)x+b then values of a and b |
| Answer» Putting 2 as p(2) as 2 is a zero of this quadratic polynomial.we get 2a +b = -6 as first equation. Put -3 as p(-3) as -3 is another zero of this quadratic polynomial.we get 3a - b = 6 as second equation. Adding these equations we get a= 0 and after that put a in first we get b= -6 | |
| 8223. |
Find discriminant of x^2 -3x+1=0 |
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Answer» 5 is Answer Discrimant=5 Discriminant = b² -4ac. => (-3)² - (4×1×1). => 9 - 4. => 5 Answer. |
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| 8224. |
Find the zeros of the quadratic polynomial- x²-2x-8 |
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Answer» what did the author do to make mini get rid of her false fear # x² -4x-8 # x²-4x+2x -8# x(x-4) +2(x-4) #(x+2) (x-4) For zeros # (x+2) (x-4) =0 # x+2=0 and x-4=0 # x=-2 and x= 4 ..... Zeros of polynomial X=-4;X=-2 |
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| 8225. |
867 and 225 euclid hcf |
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Answer» HCF of 867 and 225 is 3 Stomach contains gastric gland which secrets gastric juicesThese juices are HCL Pepsinand mucusHcl kills the germs and make ingested food acidic so as to Pepsin can work in easily.Pepsin breaks down protein into simpler substance i.e., peptones.Mucus helps in protecting of inner wall of stomach from its own secretion of hcl what is the role of stomach in our digestive system |
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| 8226. |
Solve for x : root 6x+7 - (2x-7) = 0 |
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Answer» 6x+7-2x+7=0. 4x+14=0. 4x=-14. x=-7/2 6x+7-(2x-7)=0Soln:6x+7-2x+7 =04x+14=04x=-14x=-14/4Therefore, x=-7/2. |
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| 8227. |
If cosec A - sin A = a^3, sec A - cos A = b^, prove that a^2b^2(a^2+b^2) = 1 |
| Answer» We use\xa0{tex}\\theta{/tex} = A | |
| 8228. |
Write down the decimal expansion of 29 upon 343 |
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Answer» 29/343 Prime factors of 343 = 7×7×7 The denominator is not in the form of 2 and 5 so there Will be no Terminating decimal expansion................. 0.845 0.0670.. |
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| 8229. |
Show that any odd positive integer in the form of 6q+1, 6q+3, or 6q+5 |
| Answer» According to Euclid’s Division Lemma if we have two positive integers a and b, then there exist unique integers\xa0q\xa0and\xa0r\xa0which satisfies the condition\xa0a = bq + r\xa0where 0\xa0≤ r < b.Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.According to Euclid’s division lemmaa = bq + ra = 6q + r………………….(1)where, (0\xa0≤ r\xa0< 6)So r can be either 0, 1, 2, 3, 4 and 5.Case 1:If r = 1, then equation (1) becomesa = 6q + 1The Above equation will be always as an odd integer.Case 2:\xa0If r = 3, then equation (1) becomesa = 6q + 3The Above equation will be always as an odd integer.Case 3:\xa0If r = 5, then equation (1) becomesa = 6q + 5The above equation will be always as an odd integer.∴ Any odd integer is of the form 6q + 1 or 6q + 3 or 6q + 5.Hence proved. | |
| 8230. |
Square root of 5 |
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Answer» 9 2.2360....... √5 = 2.2360… |
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| 8231. |
4÷8=? |
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Answer» 0.5 0.5 Half of 1 0.5 ^_^ 1/2 = 0.5 |
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| 8232. |
x1,y1=-3,-1x2,y2=2,4find the answer using distance formula |
| Answer» 5√2 is the answer | |
| 8233. |
Draw the graph of following equation2x - 3y + 6 = 02x + 3y - 18 = 0y - 2 = 0 |
| Answer» Sorry I can\'t answer thi | |
| 8234. |
Find the difference between the points P(-6,3)and Q(-1,-4) |
| Answer» Answer is 74 we transfer into roots 2 Root 34 | |
| 8235. |
CBSE ka exam postponed ho ga kayaa |
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Answer» Aur kitna time Chahiye No never Nhiiii jiiiii Noooo |
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| 8236. |
Prove (1+cota +tana) (sina-cosa) = sina tana-cota cosa |
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Answer» (coseca.seca) Take L. H. S change cot and tan into sin and cos Then take R. H. S change cot and tan into sin and cosBoth side come (coseca.cota)(sina-cosa) |
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| 8237. |
if alpha and beta are the zeros of the polynomial x2-3x+5 then find the value of 1/alpha+1/beta |
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Answer» α+β=3αβ=51/α + 1/β = (β+α)/αβ = 3/5 α+β= 3αβ= 51 1 β+α 3-- + -- = ------ = ---- . Ansα β αβ 5 |
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| 8238. |
A mall is constructing in the city Jaipur |
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Answer» hii Please ask question with complete information. |
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| 8239. |
Anyone can give me imp questions of chapter 9,10 in maths |
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Answer» Whole ncert chapter ?plz |
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| 8240. |
Can I get all forums of all lessons |
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Answer» 9482953992 send on this number on watsaap I have written in a page How send photo in these appI don\'t know |
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| 8241. |
find the point on y axis which is equidistant from the point (5 -2) and (-3 2) |
| Answer» -3/5 | |
| 8242. |
Use Euclid division algorithm to find the HCF of :135 and 225 |
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Answer» 45 45 HCF IS 45 |
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| 8243. |
Sin × cos |
| Answer» sincos | |
| 8244. |
Cofficient of X+1 |
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Answer» Coefficient is 1 Cofficient is 1 |
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| 8245. |
x2+1700x-1500 Middle term split? |
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Answer» -1700.88 0.58 |
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| 8246. |
Ap question 3 part no. 3 |
| Answer» Bolo | |
| 8247. |
Use euclid\'s division algorithem to find the H.C.F. of:i) 867 and 225 |
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Answer» The HCF of 867 and 225 is 3 Hi brother I hope I can help you with this Answer must be like https://drive.google.com/file/d/1lHqm1aKBl5is881bNt__sg5OJ3kPYn3X/view?usp=drivesdkPlz open the drive you will be getting the answerI hope you will get it.. |
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| 8248. |
If x is equal to 0.7 bar find 2x |
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Answer» Given a12 =37D=3 find a s12 1.5555.... |
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| 8249. |
Find the value of cos30,cos45,cos60,cos90 |
| Answer» Cos30° = root 3/ 2Cos60° = 1/2 Cos90° = 0 | |
| 8250. |
if the system of equations 6x+2y=3 and kx+y=2 has a unique solution find the value of k |
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Answer» K is not equal to 3 K=3 K=3 K =/= 3. (a1/a2 =/= b1/b2) K=3 |
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