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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 8251. |
√33 |
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Answer» 5.74 Write full questions |
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| 8252. |
Show that square of any positive integer is of the form 9m Or 9m+1. |
| Answer» You can take the no 3Then all no can be represented in the form 3q,3q+1,3q+2.Then you show by sqaring all of them one by one.For eg- (3q^2)=9q^2 or 9q(q) Where q is any integers | |
| 8253. |
Show that cube of any positive integer is of the form of 16q Or 16q+1 ? |
| Answer» | |
| 8254. |
Chapter 4 ex 4.1 question 2(2) |
| Answer» Let the two integer be x, x+1X(x+1) =306X square+x=306X square+x-306=0This is the required quadratic equation. | |
| 8255. |
P(x)=x4-5x+6, g(x)2-x2 |
| Answer» Please ask question with complete information. | |
| 8256. |
Use Euclid division algorithm to find HCF of196 and 38220 |
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Answer» 38220= 196*195+0So , the HCF of ( 38220,196)= 195. Ok I will you on whatsapp |
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| 8257. |
Find the median of the first 10 prime numbers |
| Answer» 12. | |
| 8258. |
KI EXERCISE 6.4 AUR 6.5 AAENGI KYA EXAM MEIN IS SAAL?? |
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Answer» Yes Ha koi doubt h kya Yes Yes |
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| 8259. |
KOI TOH BATADO YAAR PLEASE YAARKL PRE BOARD HAI MERA??? |
| Answer» Bhai mera bhi h ??? | |
| 8260. |
proove that 5 + 2√5 is irrational |
| Answer» Let 5+2√5 be a rational number = p/qWhere p and q are coprime numbers & q≠0So 5+2√5 = p/q2√5 = (p-5q)/q=> √5 = (p-5q)/(2q)Since RHS is a rational number => √5 is a rational numberBut it contradicts the fact i.e.√5 is irrational numberTherefore our assumption was incorrect=> 5+2√5 is an irrational numberHence proved | |
| 8261. |
BATADO YAAR ??? |
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Answer» Yes Kya That Will EXERCISE 6.4 and 6.5 aaengi exam mein? Kya bataung .. |
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| 8262. |
find the real roots of the quadratic equation 3x2 – 5x – 2 = 0 |
| Answer» | |
| 8263. |
chaper 2 Ex 2.10 |
| Answer» https://mycbseguide.com/course/cbse-class-10-mathematics/1202/ | |
| 8264. |
SORRY..... EXERCISE 6.5* AA RAHI HAI KYA IS SAAL?? |
| Answer» Nhi h | |
| 8265. |
EXERCISE 6.6 AA RAHI HAI KYA ??IS SAAL |
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Answer» CBSE board me to aa rahi h Rajasthan Kyu Tum kha se ho |
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| 8266. |
EXERCISE 6.4 AA RHI HAI KYA??IS SAAL |
| Answer» | |
| 8267. |
What is HCF of 8 and 6 |
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Answer» 2 HCF of 8 and 6 is 2 2 8}6 by encluid division lemon method a=pq +r 8= 6×1+ 2 = 86= 6×1+0= 6 2 |
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| 8268. |
2√45+3√20-10√125/2√5 |
| Answer» This can also be written as :- 2√9*5 + 3√4*5 - 10√25*5 / 2√5 = 2*3√5 + 3*2√5 - 10*5√5 / 2√5 = 6√5 + 6√5 - 50√5 / 2√5 = (6 + 6 -50)√5 / 2√5 = -38√5 / 2√5 = -19//. | |
| 8269. |
What is area of cube |
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Answer» 6a^2 (a)^3 6 × side^2 |
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| 8270. |
If α and β are the zeros of the Polynomial f(x)=x2-5x+k such that α-β=1 find the value of K? |
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Answer» a-b=1 and a+b=5 By solving itWe will get a=3 and b = 2So ,k = ab = 3×2 = 6Hence, k=6 a=1, b=-5, c=kWe r doing this formula D =b2 - 4ac (-5)2 -4*1*k 25 - 4k = 0 -4k = -25 subtract sin se subtract sin cancel we get4k =25 K = 25/4 |
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| 8271. |
Find the roots of the equation 2x² - 5x + 3 = 0, by factorisation. |
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Answer» Middle term splitting 2 x square- 3x - 2x plus 3 |
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| 8272. |
Solve the following pair of linear equations :(I) 152x - 378y = -74 and -378x +152y = -604 |
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Answer» Thank u Let first equation be (1) and second equation be (2). Now, do (1) - (2) to get (A). Then, do (1) + (2) to get (B). Solve equations (A) and (B) to get required answer. Hope it helps you. Thank you for sharing the question. ? |
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| 8273. |
X+y=12 and xy= 27 then x3 + y3 is |
| Answer» x³ + y³=(x + y)(x² + y² - xy)=12(x² + y² + 2xy - 2xy - xy)=12{(x + y)² - 3xy}=12{(12)² - 3 × 27}=12{144 - 81}=12 × 63=756 (Ans.) | |
| 8274. |
Which chapter is hardest chapter in class 10 math |
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Answer» Triangle Triangles No trigonometry Triangles |
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| 8275. |
1/x+1/x-16=1/15 |
| Answer» x=6,x=40 | |
| 8276. |
Show that root 2 is an irrational number. |
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Answer» Let us assume that {tex}\\sqrt2{/tex} is a rational number.So it can be expressed in the form p/q where p, q are co-prime integers and q {tex}\\ne{/tex} 0{tex}\\sqrt2{/tex} = p/qHere p and q are coprime numbers and q {tex}\\ne{/tex}\xa00Solving{tex}\\sqrt2{/tex}\xa0= p/qOn squaring both the side we get,{tex}\\Rightarrow{/tex}\xa02 = (p/q)2{tex}\\Rightarrow{/tex}\xa02q2\xa0= p2\xa0.. (1)p2/2 = q2So 2 divides p and p is a multiple of 2.{tex}\\Rightarrow{/tex}\xa0p = 2m{tex}\\Rightarrow{/tex}\xa0p2\xa0= 4m2\xa0..(2)From equations (1) and (2), we get,2q2\xa0= 4m2{tex}\\Rightarrow{/tex}\xa0q2\xa0= 2m2{tex}\\Rightarrow{/tex}\xa0q2\xa0is a multiple of 2{tex}\\Rightarrow{/tex}\xa0q is a multiple of 2Hence, p, q have a common factor 2. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number{tex}\\sqrt2{/tex}\xa0is an irrational number. Let us assume that ✓2 is a rational number.So it can be expressed in the form p/q where p, q are co-prime integers and q 0 = p/qHere p and q are coprime numbers and q 0Solving = p/qOn squaring both the side we get, 2 = (p/q)2 2q2 = p2 .. (1)p2/2 = q2So 2 divides p and p is a multiple of 2. p = 2m p2 = 4m2 ..(2)From equations (1) and (2), we get,2q2 = 4m2 q2 = 2m2 q2 is a multiple of 2 q is a multiple of 2Hence, p, q have a common factor 2. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number Hence it is proved that ✓2 is irrational number |
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| 8277. |
If a(6 -1) and c(k 8) are three points such that ab=bc find the value of k. |
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Answer» GivenA(6,−1),B(1,3) and C(k,8) Using distance formula AB 2 =BC 2 ⇒(6−1) 2 +(−1−3) 2 =(k−1) 2 +(8−3) 2 ⇒25+16=k 2 +1−2k+25 ⇒k 2 −2k−15=0 ⇒k 2 −5k+3k−15=0 ⇒k(k−5)+3(k−5)=0 ⇒(k−5)(k+3)=0 k−5=0⇒k=5 k+3=0⇒k=−3 GivenA(6,−1),B(1,3) and C(k,8)Using distance formulaAB 2 =BC 2 ⇒(6−1) 2 +(−1−3) 2 =(k−1) 2 +(8−3) 2 ⇒25+16=k 2 +1−2k+25⇒k 2 −2k−15=0⇒k 2 −5k+3k−15=0⇒k(k−5)+3(k−5)=0⇒(k−5)(k+3)=0k−5=0⇒k=5k+3=0⇒k=−3 You haven\'t given b(1,3 ) in your question Wait i am answering Didn\'t understand question |
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| 8278. |
factorise 25x^2 -36y^2 |
| Answer» 25x2 - 36y2= (5x)2 - (6y)2= (5x + 6y) (5x - 6y) | |
| 8279. |
√5 is a irrational |
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Answer» We prove by contradiction method.Let assume that √5 is rational.√5=p/q ---eq......1P and q are co prime integer with common factor 1.Squaring both side equation 15=p²/q²:. q²=p²/5 eq...2It means p² have factor 5 so p would also have sector 5.p=5xsquaring both sidep²=25x²Puting this value of p² in equation 2q²=25x²/5q²=5x²q²/5=x²This means q² have factor 5.But our assumption says p and q have common factor 1.So our assumption was wrong√5 is irrational number. yes √ 5 is an irrational no. Let\xa05\u200b\xa0be a rational number.then it must be in form of qp\u200b where, q\ue020=0 (\xa0p\xa0and\xa0q\xa0are co-prime)5\u200b=qp\u200b5\u200b×q=pSuaring on both sides,5q2=p2 --------------(1)p2\xa0is divisible by\xa05.So,\xa0p\xa0is divisible by\xa05.p=5cSuaring on both sides,p2=25c2 --------------(2)Put\xa0p2\xa0in eqn.(1)5q2=25(c)2q2=5c2So,\xa0q\xa0is divisible by\xa05..Thus\xa0p\xa0and\xa0q\xa0have a common factor of\xa05.So, there is a contradiction as per our assumption.We have assumed\xa0p\xa0and\xa0q\xa0are co-prime but here they a common factor of\xa05.The above statement contradicts our assumption.Therefore,\xa05\u200b\xa0is an irrational number. √5 =p/q Let us assume that√5 is rational |
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| 8280. |
Find zeros of tsq-15 |
| Answer» First, write the equation,t2\xa0- 15 = 0Now, we shift the (-15) to RHS,t2 = 15So, t = - {tex}\\sqrt {15}{/tex} = -3.87 or + {tex}\\sqrt {15}{/tex} = + 3.87 | |
| 8281. |
225 का 35% कितना होगा |
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Answer» = 78.75 78.75 225÷100*35 = 78.75 |
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| 8282. |
Aaplog maths ke liye ncert ke alawa koi side book use krte ho kya?? |
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Answer» yes i use exemplar Right Aman Are phela ncert fir rd What pyq No After solving ncert i prefer to solve pyq |
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| 8283. |
Cos thetha=0.6, show that (5sin thetha-3tan thetha) =0. |
| Answer» Given=cosA=0.6CosA=B/H0.6=B/H6/10=B/HBase=6Hypo.=10then by using pythagoras theorem Perpendicular =8Prove:5sinA-3tanA=05×P/H-3×P/B=05×8/10-3×8/6=04-4=00=0Hence proved | |
| 8284. |
Sec thetha=5/4, verify that tan thetha/(1+tansquare thetha) =sin thetha/sec thetha |
| Answer» | |
| 8285. |
Prove that 5+3√2 is irrational |
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Answer» Google ko poocha hame kya poochta hai ???? If we will post over here it will be very confusing for uhh bcuz it is little lenthy soo just google it as Manas said. Search on Google |
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| 8286. |
225 का 40% कितना होता है |
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Answer» Ok... 225/100*40= 90% 90 |
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| 8287. |
(7/8) का square karenge to 4/6 kese aayega aapne hi ex 8.1me karaya |
| Answer» | |
| 8288. |
Find the sum of the following APs:(1) 2,7,12.....,10terms. |
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Answer» Sn=n/2[2a+(n-1)d]S10=10/2[2*2+(10-1)5] =5(4+45) =5(49)S10=245 245 245 |
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| 8289. |
The different of two natural no.of three and the difference reciprocal 3/28. Find the no. |
| Answer» Y=-7 or y=4 | |
| 8290. |
Is √2 is rational |
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Answer» Yes Yes √2 is Irrational Yes yes |
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| 8291. |
Find the number of decimal place in the decimal expansion of 73 by 2,000 |
| Answer» Decimal expansion = 73/2000 = 0.0365my whatsapp - 8405050980 | |
| 8292. |
If the mode of the data 2,3,3,5,7,7,6,5,x and 8 is 3 then what is the value of x. |
| Answer» X = 3 | |
| 8293. |
Can anyone help me to factorise 2x^2-5x+7 as I am unable to get solution |
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Answer» D=b^2-4ac =25-28=-3As D<0 there are no real roots for this eq. So it can not be factories. X=1 X=7/2 (X=-1) (X=7/2) |
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| 8294. |
For what value of n, are the nth terms of two APs 60, 62, 64......and -10, -3, 4, 11.....are equal? |
| Answer» AP1 AP2A=60 & D=2 a=-10 & d=7Now equate the nth term for which both terms are same60+(n-1)2= -10+(n-1)7Solving for n we getn=15 | |
| 8295. |
If a and b are two positive integers such that a=14b. Find the HCF of a and b. |
| Answer» HCF = 1 | |
| 8296. |
t square +15 |
| Answer» -root 15 , root 15 | |
| 8297. |
Evn |
| Answer» | |
| 8298. |
What is Bernoulli number |
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Answer» This is out from our syllabus but just I want to know about it ....? |
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| 8299. |
8744944 |
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Answer» Please post reasonable question and not stupid one It\'s the number |
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| 8300. |
If 1+sin2=3sincos than prove that tan=1ir1/2 |
| Answer» | |