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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 8551. |
1+4+7+10+....+x=287 find x |
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Answer» a=1. d=3. Sn= 287. an=?Sn= n/2[2a+(n-1)d]287=n/2[2×1 +(n-1)3]287= n/2[2+3(n-1)]287= n/2[2+3n-3]287= n/2[3n-1]287×2 =n(3n-1)574= 3n^2 - n3n^2 - n - 574 =0Now,I hope you would solve. We need to find nHere,a=1 d=3 a n=287 n=?Therefore,An = a+(n-1)d287= 1+(n-1)3286=3n-3289=3n279/3=n93=n ANSWER |
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| 8552. |
(sin 30°+cos30°)-(sin60°+cos60°) |
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Answer» 0 =(1/2+root3/2)-(root3/2-1/2)=1/2+root3/2-root3/2-1/2=0 0 = Sin30°+ Cos30° - { Cos(90°-60)+Sin(90°-60°)}= Sin30° + Cos 30° - Cos30° - Sin30°= 0 |
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| 8553. |
If any by the following points and give reason for your answer1) (-1,-2) ,(1,0),(-1,2),(-3,0) |
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| 8554. |
Proof all triangle theorems |
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| 8555. |
.Find the zeros of thepolynomial and verify themwith coefficient of quadraticpolynomialax² + bx +c |
| Answer» Pagal | |
| 8556. |
4x*2-6-8x |
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Answer» X= (2+√10)/2 or x=(2-√10)/2 -6 |
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| 8557. |
-3y-4y= |
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Answer» -7y -7y -7y |
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| 8558. |
Yeh mathematics kisne banayi thii???? Mujhe mil jaye vo kahii ?? |
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Answer» ??? ??? ??? |
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| 8559. |
Find the root root of quadratic equation X square - 4 x + 2 is equal to zero using quadratic formula |
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| 8560. |
✓5 is irrational |
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Answer» Let us assume that √5 is a rational number.Sp it t can be expressed in the form p/q where p,q are co-prime integers and q≠0⇒√5=p/qOn squaring both the sides we get,⇒5=p²/q²⇒5q²=p² —————–(i)p²/5= q²So 5 divides pp is a multiple of 5⇒p=5m⇒p²=25m² ————-(ii)From equations (i) and (ii), we get,5q²=25m²⇒q²=5m²⇒q² is a multiple of 5⇒q is a multiple of 5Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number√5 is an irrational number ✓5=a/b ✓5=a/b |
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| 8561. |
What is the area of the triangle |
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Answer» 1/2 x base x height Area of the triangle =1/2 ×base×height Area of equilateral triangle =√3/4 a^2 Area of the triangle =1/2 ×base×heightArea of equilateral triangle =√3/4 a^2Heron\'s formula = √s(s-a)(s-b)(s-c) |
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| 8562. |
Ch 3 class 10 all word problems |
| Answer» Himani....All questions are ur doubt? | |
| 8563. |
State and prove phytagoras theorem |
| Answer» Pythagoras Theorem is Easyonly U have to Step According Basic propnality Theorem | |
| 8564. |
In an A.P. if S21 = 1250, S20 = 1200, find a21• |
| Answer» 50 | |
| 8565. |
How to solve equation by shri daracharyas method |
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| 8566. |
Find sum of zeroes of the quadratic polynomial 3x²+2x-5. |
| Answer» 3x^2 +5x - 3x - 5X(3x+5)-1(3x+5)(X-1) (3x+5)X=1, X= -5/3 | |
| 8567. |
Show that the system of linear equations 4x+3y=6 and 12x+9y=8 has infinitely solutions. |
| Answer» It will not have infinite solutions | |
| 8568. |
What is the H.C.F of two coprime numbers..? |
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Answer» 6 1 1 1 1 |
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| 8569. |
Write a quadratic polynomial sum of zeroes is 5 and product is 6. |
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Answer» x2-5x+6 x^2+(a-b)x+(ab)X^2+(-5)x+(6)X^2-5x+6 x²-5x+6 |
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| 8570. |
Sum of the 2 numbers is 16 and sum of their reciprocal is 1by3 find the number |
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Answer» 12 and 4 is the ans https://youtu.be/gESQXM3MFtUBest formula sheet of CHAPER 5 CLASS 10 MATHS MUST WATCH IT |
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| 8571. |
Find the cubic polynomial whose zeroes are 1/2, 1, -2 |
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| 8572. |
Neha borrowed Rs.7300 at the rate of 8% p.a for 225 days .find the interest and amount she paid |
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| 8573. |
The condition of the equation ax2+bx+c=0 has one positive and other negative root is |
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Answer» Have u got the answer Let the positive root be x and the negative be -x. Sum of roots=-( coefficient of x/coefficient of x*2) 0= -b/a, o = b/a, b= 0 is the required condition |
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| 8574. |
Sin theta +sin theta =1 , if theta1=30 , find value of theta |
| Answer» https://www.google.com/url?sa=t&source=web&rct=j&url=http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsStandard_SQP.pdf&ved=2ahUKEwjnybOVi-TuAhVVXSsKHfQRDX0QFjAAegQIBBAC&usg=AOvVaw1bwd9hxAWzKsEk_BbwmTXQ&cshid=1613124052073 | |
| 8575. |
If the diameter of the base of cone is 10cm and it\'s height is 12cm find curved surface area |
| Answer» Csa=204.29 | |
| 8576. |
2+2÷8 |
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Answer» 9/4 1/4 9/4 2.25 2+2÷2 |
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| 8577. |
Solve graphically x+y=10 and x-y=4 |
| Answer» X+y= 10.............(i)X-y= 4................(ii)Taking IX + y = 10X =10-yLet, y=5So, x=10-yX=10-5X=5Let, y =4So, x=10-4X=6Let y =6So, x=10-6X=4Now taking equation. (ii)X-y=4X=4+yLet ,y=1So, x=4+1X=5Let, y=0So, x=4+0X=4Let, y =2So, x=4+2X=6Here the coordinates for equation (i) are A(5,5) ;B(6,4) ; C(4,6) Here the coordinates for equation (ii)areA(5,1);B(4,0);C(6,2). Draw the coordinates on graph .I cannot send the pic of graph. | |
| 8578. |
How many multiples of 4 lies between 10 and 250 |
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Answer» 62 60 |
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| 8579. |
Tan A = root 2 - 1 , show that SinA ×CosA = root 2/4 |
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Answer» Samajh mein aya bro TanA. = √2-1, tan*2A=(√2-1)*2,tan^2A=2+1-2√2, 1+tan^2A= 4-2√2, sec^2A= 4-2√2, cos^A= 1/4-2√2,. Cos^2A= 4+2√2/8,. Sin^2A= 1-cos^2A, sin^2A= 4-2√2/8,. Sin^2A×cos^2A= (4-2√2)×(4+2√2)/8×8. (SinAcosA)^2= 8/64,. (SinAcosA)^2= 2/16,. SinAcosA= √2/4 proved |
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| 8580. |
How i will know that 1231 is a prime number or not.( i.e- 3457 |
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Answer» Prime factorisation se pata kar sakte ho Firstly make factors of it |
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| 8581. |
Probe that √5 is irrational |
| Answer» Let us assume that √5 is a rational number.Sp it t can be expressed in the form p/q where p,q are co-prime integers and q≠0⇒√5=p/qOn squaring both the sides we get,⇒5=p²/q²⇒5q²=p² —————–(i)p²/5= q²So 5 divides pp is a multiple of 5⇒p=5m⇒p²=25m² ————-(ii)From equations (i) and (ii), we get,5q²=25m²⇒q²=5m²⇒q² is a multiple of 5⇒q is a multiple of 5Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number√5 is an irrational numberHence proved???? | |
| 8582. |
Pythogarsas theorem |
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Answer» It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides. In a right angle triangle the square of hypotenuse is equal to the the sum of squares of of other two sides |
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| 8583. |
Rajan is having a garden near Delhi |
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| 8584. |
Derive phytagoras theorem |
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Answer» 6362784415 send me It\'s too long give me ur whatsapp number I will sent u |
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| 8585. |
Find the values of x and y if the. Distences of point (x,y) from (--3,0)as well as from (3,0) are 4 |
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| 8586. |
Find zeroes of the 6x²-3-7x and verify the relationship between the zeroes and co efficient |
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| 8587. |
100xsquare--20x+1=0 |
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Answer» x=1/10 (1-10x)^2 |
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| 8588. |
roots of quadratic equation x square - 7 x is equal to zero is |
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Answer» X=0 and X=7 At first find D.D = b² - 4acD = (-7)² - 4×1×0D = 49 - 0Hence , D = 49Here, D > 0Therefore Roots are real and unequal.Roots are 7 and 0. x=7 |
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| 8589. |
prove 7√5 irrational |
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Answer» Assume that √5 is rational, so it has of the form √5=a/b, where a and b are coprimes (both numbers have only common factor as1) √5 =a/b square both sides then 5=a^2/b^2 ie a^2 =5b^2 let it be eq1 a^2 /5=b^2 now a^2is divisible by 5 therefore a is divisible by 5 now take a=5c from eq1 we get 25c^2 =5b^2 ,5c^2 =b^2 Now c^2 =b^2/5 now b^2 is divisible by 5 by theorem 1.3 a and b have a common factor as 5 so our assumption is wrong √5 is irrational Now we have to prove 7√5 is irrational we already proved √5 is irrational Now assume 7√5 is irrational therefore 7√5 =a/b we know √5 is irrational so 7√5=a/b √5=a/7b where √5 is irrational and a/7b is rational So it is contradiction to our assumption therefore our assumption is wrong 7√5 is irrational Assume that √5 is rational, so it has of the form √5=a/b, where a and b are coprimes (both numbers have only common factor as1) √5 =a/b square both sides then 5=a^2/b^2 ie a^2 =5b^2 let it be eq1 a^2 /5=b^2 now a^2is divisible by 5 therefore a is divisible by 5 now take a=5c from eq1 we get 25c^2 =5b^2 ,5c^2 =b^2 Now c^2 =b^2/5 now b^2 is divisible by 5 by theorem 1.3 a and b have a common factor as 5 so our assumption is wrong √5 is irrationalNow we have to prove 7√5 is irrational we already proved √5 is irrationalNow assume 7√5 is irrational therefore 7√5 =a/b we know √5 is irrational so7√5=a/b√5=a/7b where √5 is irrational and a/7b is rationalSo it is contradiction to our assumption therefore our assumption is wrong7√5 is irrational |
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| 8590. |
Xsquare-2x-8 |
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Answer» x^2- 2x-8=0x^2-4x+2x-8=0x(x-4)+2(x-4)=0(x+2)(x-4)=0x+2=0x=-2. Ans.And x-4=0 x=4. Ans. Xsquare-4x+2x-8Xsquare+2x-4x-8X(x-2)+4(x-2)(X+4)(x-2)X=-4,2 |
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| 8591. |
2 square into minus 3 X + 5 equal to zero |
| Answer» 2x^2-3x=02x- 5x + 2x+5=0x(2x-5)-1(2x-5)=0(x-1)(2x-5)=0x-1=0x = 1 Ans.2x-5=02x = 5x=5/2 Ans. | |
| 8592. |
Find the nature of the roots of the following quadratic equations if the real roots exist find them |
| Answer» R u Amman from IT? | |
| 8593. |
5+76544422 |
| Answer» the total value of 5+76544422 is:-76544427 | |
| 8594. |
312+852 |
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Answer» 1164 312852 1164 |
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| 8595. |
Case study based questions in standard Page no 80 |
| Answer» What is this | |
| 8596. |
What is the distance between the points A (Sin theta- Cos theta,0 ) and B(0,Sin theta+Cos theta)? |
| Answer» = whole root (0 - sin theta + cos theta)^2 + (sin theta + cos theta - 0)^2 = whole root sin ^2 theta + cos^2 theta + sin ^2 theta + cos ^2 theta = whole root 2sin ^2 theta + 2cos ^2 theta= whole root 2(sin ^2 theta + cos ^2 theta )= whole root 2(1) [since sin^2 theta + cos^2 theta =1]= therefore root 2Distance is root 2 | |
| 8597. |
Write all the other trigonometric ratios of |
| Answer» Ratios of??? | |
| 8598. |
solve for x 36x^2-12ax+(a^2-b^2)=0 |
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Answer» 36x2−12ax+(a2−b2)=0Ax2+Bx+C=0\xa0from,A=36 B=−12a C=(a2−b2)Roots of quadratic equation formula :x=2A−B±B2−4AC\u200b\u200b=2×3612a±144a2−144(a2−b2)\u200b\u200b=7212a±144b2\u200b\u200b=7212a±12b\u200b=6a±b\u200b⇒x=6a+b\u200b\xa0or\xa06a−b\u200b pls reply |
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| 8599. |
Make a pie chart on the languages of nagaland |
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| 8600. |
Make a pie chart on nagaland languages |
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