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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 8801. |
Check whether (5,-2) , (6,-4) and (7,-2) are coordinates of an isosceles triangle |
| Answer» Let a be (5,_2)&b be (6,_4)and c (7,_2).Distance between A and B=root under (6_5)^2+(_4+2)^2Root under1+4=root under5.Distance between A and C=root under (7_5)^2+(_2+2)^2=root under4=2.Distance between B and C=root under (7_6)^2+(_2+4)^2= root under1+ 4= root under5.Hence distance of AB=distance of BC=root 5 | |
| 8802. |
Whatever is hemisphere |
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Answer» A hemisphere is a 3D geometric figure that is half of a\xa0sphere\xa0(hemi- means half).I hope it will help you Hemisphere is the half of sphere. Just like semicircle which is half of circle |
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| 8803. |
Tan(A+B)=√3, tan (A-B)=1/√3, |
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Answer» Tan (A +B)=root 3=(A+B)=60 (1)TAN (A_B)=1/ROOT 3=(A_B)=30 (2)solving 1 and 2 we get2a=90A=45degree. Put the value of a in eq (1) 45+b=60B=15degree Tan( A+B ) = √3. A+B = 60⁰ - (i) (∵tan 60⁰= √3) tan (A-B)=1/√3. A-B = 30⁰ -(ii) (∵tan 30⁰ = 1/√3) Add equation (i) and (ii) (A+B=60⁰) + ( A-B = 30⁰) 2A = 90⁰ A = 90⁰/2 A = 45⁰ Put A = 45⁰ in equation (i) A + B = 60⁰ 45⁰ + B = 60⁰ B = 60⁰ - 45⁰ B = 15⁰ |
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| 8804. |
Chapter 11 construction main say kon se exercise delete ho gaye h |
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Answer» exercise nahi theorem delete hua hai - to construct a triangle similar to a given triangle as per given scale factor. Yaa... Right... Himanshu.. Bcoz mere preboard mein deleted syllabus bhi aya tha |
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| 8805. |
Solve x^-4=0 |
| Answer» X²-4=0X²=4X=√4X=2 | |
| 8806. |
Draw a circle of radius |
| Answer» Nargish can u write ur question clearly? .this is not clear ? | |
| 8807. |
What is GCD |
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Answer» Greatest common divisor Greatest Great common divisor |
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| 8808. |
Anshika, yes my problem is solved .......now my teacher don\'t talk to me from last 3 days. ???? |
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Answer» ???? My teacher do not talk to me ???? this is soo funny for me bcz ,,,, as the mistake is of my teacher, bt my teacher blamed me to that,,,, and after allll she herself stop talking to me and ask9 questions from me ??????????????? My study is going very well there is 4 mnts for study now and my target is to complete my syllabus in 2mnts and in remaining 2 mnts i will solve sample papers and revise the whole syllabus 2-3 time ....... thats my target ............. And how is it study going on Oh that\'s nice☺️☺️ and how is it your study dear, and thanks to call me in Anshika☺️☺️ |
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| 8809. |
Can anyone help me??I want to know the deleted exercise & Question number of class 10th Mathematics. |
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Answer» check \'Maths teacher \' channel on you tube That\'s my pleasure, agar phir bhi nhi aye to bata dena I will send you vedio ? name again☺️☺️ Ok I will check..Thank you for your help...☺️☺️☺️? App you tube par brainy trainy ke naam se channel hai uss par dekhi sayad samj aa jaye nahi to infero classses se |
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| 8810. |
Find the 10th term of ap 2,7,12... |
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Answer» a=2d=7-2=5an=a+(n-1)dan=2+(10-1)5a10=2+9×5a10=2+45a10=47 47 an=a+(n-1)d=2+9(5)=2+45=47 47 |
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| 8811. |
Secant 30 degree + cosec 30 degrees |
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Answer» sec30°+cosec30° = 2/√3 + 2 =2+2√3/√3 =2+2√3/√3 x √3/ √3 =2√3+6/3 =2√3+2 Sec30°= 1/2Cosec30°= 2So,Sec30° + Cosec30°=1/2 + 2=1/2 + 2/1=1 + 4/2=5/2 |
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| 8812. |
Find a Quadratic polynomial whose zeroes are 2- ? and 2+ ? |
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Answer» Sum of zeroes= (2-3)+(2+3)= 2+2=4........ Product of zeros=(2-3)(2+3)= 4+6-6-9 = -5 .......Using formula, x^2+(Sum of zeroes× x) + (product of zeroes) = x^2+4x-5 x^2 - 4x +1 |
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| 8813. |
Find a Quadratic polynomial whose zeroes are 2- ? and 2+ ? 2 |
| Answer» answer is x2-33x-22 | |
| 8814. |
Find the point on the x-axis which is equidistant from (2,-5) and (-2, 9) |
| Answer» Now, the point is on x-axis, so the value \'y\' of the given point will be zero.Let, the value of the \'x\' value of the given point = x[Assume,x as a variable to do the further mathematical calculations.]So,the point is = (x,0)As mentioned in the question,the two points are equidistant from (x,0).So,Distance between (x,0) and (2,-5)= ✓(x-2)²+(0+5)²Distance between (x,0) and (-2,9).=✓(x+2)²+(0-9)²Now,the points are equidistant.So,✓(x-2)²+(0+5)² = ✓(x+2)²+(0-9)²(x-2)²+(0+5)² = (x+2)²+(0-9)²x²-4x+4+25 = x²+4x+4+81x²-4x-x²-4x = 4+81-4-25-8x = 56x = -7 | |
| 8815. |
Prove that 5 - ? is irrational given that ? is irrational |
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Answer» Let as assume that 5-√3 is rational no. 5-√3 =a/b ( a and b is coprime no. & Integers &q≠0)5-a/b = √3 √3= 5b-a/ bSince a and b are integers ,we get 5-a/ b is rational no. But √3 is irrational no.So, our assumption was wrong .Hence 5-√3 is irrational no. Lets us assume that 5 is rational!So, subtraction of rational with irration results as irrational, so, 5-3 is irrational |
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| 8816. |
Prove the following Identity?????+????+ ?+????????= ?????3 |
| Answer» Given cosA/(1+sinA) +(1+sinA)/cosAOn taking the LCM we get,={cos²A +(1+sinA)²}/cosA.(1+sinA)Combining the like terms and adding and also we know that,use sin²A+cos²A =1=(1+1+2sinA)/cosA(1+sinA)=2(1+sinA)/cosA(1+sinA)=2/cosA=2secA | |
| 8817. |
n an equilateral ABC, D is a point on side BC such that BD =??BC prove that 9AD2= 7AB |
| Answer» ABC is an equilateral triangle , where D point on side BC in such a way that BD = BC/3 . Let E is the point on side BC in such a way that AE⊥BC .Now, ∆ABE and ∆AEC∠AEB = ∠ACE = 90°AE is common side of both triangles ,AB = AC [ all sides of equilateral triangle are equal ]From R - H - S congruence rule ,∆ABE ≡ ∆ACE∴ BE = EC = BC/2Now, from Pythagoras theorem,∆ADE is right angle triangle ∴ AD² = AE² + DE² ------(1)∆ABE is also a right angle triangle ∴ AB² = BE² + AE² ------(2)From equation (1) and (2)AB² - AD² = BE² - DE²= (BC/2)² - (BE - BD)²= BC²/4 - {(BC/2) - (BC/3)}²= BC²/4 - (BC/6)²= BC²/4 - BC²/36 = 8BC²/36 = 2BC²/9∵AB = BC = CASo, AB² = AD² + 2AB²/99AB² - 2AB² = 9AD²Hence, 9AD² = 7AB² | |
| 8818. |
Solve 2x + 3y = 11 and 2x – 4y = -24 and hence find the value of m for which y = mx + 3 |
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Answer» Let,P(x)=2x+3y=11-(1)P(x)=2x-4y=-24-(2)Now solving 1 and 2 we get7y=35Y=5Now putting the value of y in 1 we getX=-2Now,given y=MX+35=m(-2)+3M=-1 2x + 3y = 11 (1)2x - 4y = -24 (2)Subtracting both the equations7y = 35y = 5Putting y = 5 in 1 we get2x + 15 = 112x = -4x = -2y = mx + 35 = m(-2) + 32 = -2m-1 = m |
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| 8819. |
1/2a+b+2x = 1/2a +1/b +1/2x find the roots |
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| 8820. |
Ex 8.3 cut ho gyi h kya |
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Answer» Haa Therefore, my prediction was rightThank you all for answering!!! Yes, but only in 2021 in our exam. Ha Haa |
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| 8821. |
2×0 |
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Answer» 0 0 0 0 0 |
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| 8822. |
What is 1-sin square Q |
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Answer» Cos square Q Cos square Q Yaha par Q kya hai Cos squareQ |
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| 8823. |
Find the HCF & LCM of 404 & 96 |
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Answer» HCF = 4LCM = 9696 HCF IS 4AND LCM IS 9696 |
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| 8824. |
Find the greatest 6 digit number divisible by 3,5 and 7 each |
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| 8825. |
How to find upper model class? |
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| 8826. |
Formulas of ch 13 |
| Answer» | |
| 8827. |
Ad not equal to bc ( A2 - b2)X2 +2(ac+bd)x +(C2+D2)=0 has no real roots. |
| Answer» CosQ | |
| 8828. |
Solve for x : x-1/2x+1 + 2x+1/x-1 =2 , where x not equal to-1/2 ,1 |
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Answer» Value of x =-2 -2 |
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| 8829. |
1/(x-1) (x-2) + 1/(x-2) (x-3) = 2/3. Find roots of it |
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Answer» Only 4 How❓❓ 2 ,4 and 8 |
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| 8830. |
Case study problem of all subject |
| Answer» No | |
| 8831. |
For what value of n,are the nth terms of two APs:63,65,67..........and 3,10, 17........equal ? |
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Answer» Thanks? 13 13 |
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| 8832. |
Evaluate :Tan 40°× tan 50° |
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Answer» Sorry isske equal 1 nahi h muje laga ki 1 isske equal m de rkha h...........so..tan(90°-50°)×tan50°..... cot50°tan50°.....1 Tan(90°-50°)×Tan50°=1Cot50°×tan50°=1 1=1Hence proved Khud try karka dekho aasan h nikal jayga |
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| 8833. |
Using quadratic formula, solve the following quadratic equation for x: p2x2+(p2-q2)x-q2=0 |
| Answer» | |
| 8834. |
Prove that (1+Cos2A)sin2A=1 |
| Answer» Ye que shi h kya...? | |
| 8835. |
Check whether 307 is a term of the list numbers 6,13,20,27 |
| Answer» a=6d=13-6=7n=?an=307an=a+(n-1)d307=6+(n-1)7307=6+7n-7307=7n-1307+1=7n308=7nn=308/7n=44therefore, 307 term will come on 44th in number in A.P. | |
| 8836. |
Cos alpha divide by cos beta= m cos alpha / sin beta= n |
| Answer» This is a rong questio | |
| 8837. |
Prove that 2_ |
| Answer» | |
| 8838. |
If 2x²+bx+8=0 to have non real roots -8 |
| Answer» | |
| 8839. |
Best channel in youtube for maths |
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Answer» Dear sir Maths teacher Dear sir Mathematics analysis!! Pathshala channel |
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| 8840. |
Ncert ka exercise 2.3 aaega exam me |
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Answer» No it is removed Yes Thanks Yes ... Offcourse Yes |
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| 8841. |
Prove that the sum of the square of the diagonals of the llgm is equal to the sum of its side |
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| 8842. |
How to make our basic strong in Maths ? |
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Answer» Practice se☺️☺️ Just practice and don\'t take it as a worry you must enjoy and if you start enjoying solving it your basic will be already strong |
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| 8843. |
Frnds |
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Answer» Hii richa,, i m sumaila ,, i know this is reading platform if u see my question is also a reading related questions not about any other things,,,, and. And agr tumhe isse problem bhi h to tum mt padho in question ko kisi ne aapko force ni kiya h ye padhne ke liye ,, and by the way if anyone have any problems then plzz do not see my question bcz tunhe answer to dena hota ni h bt ulta seedha bolne ke liye pehle aa jaate ho soo plzz agr problem h to aap hmare question ko mt dekha karo kisi ne aapko force ni kiya h ki tum mere question dekhoo ....... And plzz stop to suggest me these useless ideas..... Have a nice day dear ,,, take care of ur self from covid-19,,, byee The student who had chosen the french and german they will solve your problem.Because the 1st page or in home screen you can go in subject option of french and german.By the way Crafty queen don\'t post these thingsThis is a reading plateform Frnds ,,, plzzz aap sare subject ko choose kijiye q ki kuch log french or German mei bhi interested h or agr unhe kuch puchna hota h to vo kaise piche q ki kisi ne vo subject le hi ni rkhe soo plzz un subject ko bhi le lo .??? |
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| 8844. |
find the distance point -3 , 4 from x axis |
| Answer» | |
| 8845. |
Yadi X barabar 1 hai tu vah pad ka man gyat kijiye |
| Answer» | |
| 8846. |
Three no are in the ratio 3:4:5 nd their LCM is 1200 . Then, their HCF is |
| Answer» Let us rewrite the 3 no.s as 3x 4x and 5x. Their LCM =1200. It means x is their HCF. LCM=HCF ×uncommon factors i.e x×5×4×3............ 1200=60x ............... x=20 | |
| 8847. |
Find the probability :(a) Either red or king (b) red and a king |
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Answer» a) red cards(including 2 kings)=26 Kings =4-2=2 P(E)=26+2/52=28/52=7/13 The angle of elevation ofthe top of the tower from points an the ground which is 22.5 m.from the foot of the tower is 30 m and height of the tower A) red cards =13 king=4, 2 red and 2 black. ie 13 already includes 2 king so, 13+2/52=15/52 |
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| 8848. |
Chapter 12 |
| Answer» Please ask question with complete information. | |
| 8849. |
8×2 |
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Answer» 16 16 16 16 |
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| 8850. |
Please answer Q1 of NCERT Exemplar (class 10) solution of unit 2 and exercise 2.4 |
| Answer» | |