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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

8851.

Find the 10 th term of the AP whose sum of n term is given by 2n^2 +3n

Answer» ANSWERS n\u200b =2n 2 +3nWe know that nth term of AP is given bya n\u200b =S n\u200b −S n−1\u200b ⟹a n\u200b =2n 2 +3n−2(n−1) 2 −3(n−1)⟹a n\u200b =4n+1Tenth term=a 10\u200b =4×10+1⟹a 10\u200b =41
A=S1= 2×1^2+3×1=5A2 = S2-S1 =( 2×2^2+3×2)-5=14-5=9 ..........d=a2 - a1 = 9-5=4a10= a + (n-1)d........5+(10-1)×4.........5+9×4=5+36=41 A10 =41
Sn=2n²+3n, we know An=Sn-Sn-1(n is at foot and - 1 is from n)....... A10 =S10 - S9........ A10 =2×10²+3×10 - 2×9-3×9........... An=200+30-18-27........ An=185
Discussion
8852.

Kon sa book accha hoga ncert chodh k frnd

Answer» RD sharma Exemplerxamidea.....
Modern book
Xam idea
CBSE EXAMPLER
Maths ka
Discussion
8853.

Solve for xx-2/x-4 + x-6/x-8= 6 2/3

Answer» Hello
56x²-684x+1960=0.do solve this and give us the answer
Is eq equal to 62/3 or there should be something else
Khud se try kiya??
Discussion
8854.

Find the value of x and y by elimination method 2x+y=5, 2x+3y=7

Answer» By elimination method 2x+y=5 ----------------equation 12x+3y=7-----------equation 2 Subtract eq 1&2 2x+y=52x+3y=7 - - -(sin change)--------------------------2y=-2 Y=2/2y=1Put the value of y in equation 1 2x+y=5 Y=1 2x+1=52x= 5-1 2x=4X=4/2 x=2So, x=2 and y=1
Discussion
8855.

13/1000 decimal expansion will terminates

Answer» 0.013
0.013
Discussion
8856.

5x+y=26x-3y=1Solution

Answer» By elimination method 5x+y=2 ––––––equation 16x-3y=1--------------equation 2 Multiply by 3 in equation 1 3(5x+y=2)15x+3y=6 ----------------equation 3 Add equation 3&2 15x+3y=66x-3y =1--------------- 21x=7 X=7/21 x=1/3 Put tha value of x in equation 2 .......6x-3y=1 6×1/3 -3y=1 2-3y=1 -3y =1-2 -3y= -1 Y=1/3So ,x=1/3 and y= 1/3
Discussion
8857.

4X + 5Y =14 , 2X+5Y=12

Answer» By elimination method -4x + 5y = 14-------12x + 5y = 12-------2By subtracting eq 1 and 22x = 2 X = 2/2 x = 1Putting x=1 in eq 22(1) + 5y = 12Y = 12 - 2 / 5Y = 10/ 2Y = 5
Discussion
8858.

Find the roots of the quadratic equations 2x^2+x+4.

Answer» 2x^2 + x + 4D = b^2 - 4acD = (1)^2 - 4(2)(4)D = 1 - 32 D = -31 < 0 So it has not real roots
Discussion
8859.

Case study questions for 10th

Answer» CBSE has introduced the Case Study Questions in class 10 and class 12 this year. The annual examination of 2021 will have case-based questions in almost all major subjects. This article will help you to find sample questions based on case studies and\xa0model question papers\xa0for CBSE Board Exams 2021.Case Study Question in MathematicsHere is an example of a case study based question for class 10 Mathematics. To get more questions and model question papers for the 2021 examination, download\xa0myCBSEguide Mobile App.
1st row 3 jars, 2nd row 6 jars.....
Discussion
8860.

2 or 2 4 kyu ho tai ha

Answer» How could it be fluorine?
The is wrong, it would be like 2 and 2.2 and 2=22 and (1+1)+(1+1)=4
Fluorine
22
?
Discussion
8861.

A box contains 30 cards out of which Y cards are blue if one

Answer» What is the question complete the question
Discussion
8862.

Write a quadratic polynomial the sum of whose zeroes is -3 and product is -10.

Answer» X^2 + 3x -10
Sum of zero = _3Products of zero =_10Then the quadratic polynomial =x^2_( a+b )x+abX^2+3_10
Sum of the zeroes = -3 Product of the zeroes = -10 X2 -(sum of the zeroes)x+(product of the zeroes)x2-(-3)x+(-10)X2 + 3x-10
Hope this helps uX^2-x(sum of zeros )+product of zeroX^2-x(-3)+(-10)X^2+3X-10 is required qudatric polynomial
Discussion
8863.

Sample paper 2020-21 solution

Answer» This year, CBSE has made too many changes in the question paper pattern. As per the revised curriculum document issued by CBSE for session 2020-21, there will be 50% MCQ and objective type questions. The unseen passages in CBSE Class 10 English Sample Paper 2020-21 will have only MCQs. In the same way, there are many other segments in CBSE model question papers for class 10 English that have been completely changed. So, it is very important to understand the class 10 English question paper 2020-21 pattern and prepare for exams accordingly.Click on the given link for paper and answer:Class X 2020-2021 SQP and MS - CBSE | Academics Unit
Discussion
8864.

Case studies question

Answer» Practice the questions of case study from sample paper
Discussion
8865.

An AP consists of 50terms of which 3rd term is 12 and the last term is 106. Find the 29th term.

Answer» Let a , d are first term and commondifference of an A.Pnth term = Last term = a + ( n - 1 )dan = a + ( n - 1 )dNow ,It is given that ,Third term = 12a + 2d = 12 ------( 1 )Last term = 106a + 49d = 106 ---( 2 )Subtract ( 1 ) from ( 2 ) , we get47d = 94d = 2Substitute d value in equation ( 1 ) ,We geta + 2 × 2 = 12a = 12 - 4a = 829th term = a + 28da29 = 8 + 28 × 2= 8 + 56= 64
n=50 a+2d=12 - - - - 1 a49d106 - - - - - 2 by 2-1 we get, a+47d-a-2d= 106-12 47d=94 D=94/47 d=2 then a=8 a+(n-1)d=nth term 8+28×2=64
Discussion
8866.

Solve 2cosec2 45° + cot2 30°- sin2 60

Answer» 2×(root2)^2+(root3)^2_(root 3/2)^22×2+3_3/47_3/4=28_3/4=25/4 ans.
2×(3½)²+(3½)²-(3½/2)² _______________________ 2×2+3-3/4=(28-3)/4=25/4
Discussion
8867.

Find the zeroes of quadratic polynomials (i) 5u2 +10u

Answer» 5u^2+10u=05u (u+2)=05u=0 or,u=0(U+2)=0u=-2
5u²+10u=0 then 5u(u+2)=0 either 5u =0 or u+2=0 so u=1/5 or - 2
Discussion
8868.

Find the value of k such that the polynomial x2 - k + 6

Answer» Question
Complete your qestion
Discussion
8869.

Surface of cube

Answer» TSA of cube = 6a ^ 2
T.S.A. of cube=6a^2
A=6a^2
Discussion
8870.

X-1=8(y-1),x=y^2 solve for value of x and y

Answer» Then x=y^2X=(1)^2X=1
X_1=8y_8 (1) ,x=y^2Put the value of x^2 in eq (1)Y^2_1=8y_8 Y^2_8y+7=0Y^2_7y_y+7=0Y (y_7) _1 (y_7)=0(Y_7) (y_1)=0Y=7 ,y=1
x - 1 = 8(y - 1)y^2 - 1 = 8y - 8 (∵x=y^2)y^2 - 8y -1 +8 = 0y^2 - 8y +7 = 0y^2 - y -7y + 7 = 0y (y-1) -7(y-1) = 0(y -7) (y-1) = 0∴ either (y-7) =0 OR (y-1) = 0∴ y = 7 OR y= 1i) If y= 7 , then x = y^2 = (7)^2 = 49ii) If y = 1, then x = y^2 = (1)^2 = 1
Discussion
8871.

X^2+46x+62 find factors

Answer»
Discussion
8872.

9AD^2=7AB^2

Answer» In an equilateral ABC, D is a point on side BC such that BD equals 1 third BC. Prove that 9AD2 = 7AB2. Given : An equilateral triangle ABC such that To Prove : 9AD2 = 7ABGiven : An equilateral triangle ABC such that BD equals 1 third BC.To Prove : 9AD2 = 7AB2Const: Draw AE ⊥ BC.Proof: In right triangles ABE and ACE, we haveAE = AE [common]∠AEB = ∠AEC [90°]and AB = AC[∆ABC is an equilateral]Therefore, by using RHS congruent condition space space increment ABE approximately equal to increment ACErightwards double arrow BE = CE [by CPCT]rightwards double arrow BE equals CE equals 1 half BCIn right triangle ADE, we have space AD squared space equals space AE squared plus DE squaredrightwards double arrow AD squared space equals space AE squared plus left parenthesis BE minus BD right parenthesis squaredrightwards double arrow space space space AD squared equals AE squared plus BE squared plus BD squared minus 2 BD. BErightwards double arrow AD squared space equals space left parenthesis AE squared plus BE squared right parenthesis plus BD squared minus 2 BD. BE open square brackets because space space BD equals 1 third BC space and space BE space equals space CE space equals space 1 half BC close square bracketsrightwards double arrow space space space AD squared space equals space AB squared plus open parentheses 1 third BC close parentheses squared minus 2 cross times 1 third BC cross times 1 half BCrightwards double arrow space space space AD squared space equals space AB squared plus 1 over 9 BC squared minus BC squared over 3rightwards double arrow AD squared equals fraction numerator 9 AB squared plus BC squared minus 3 BC squared over denominator 9 end fractionrightwards double arrow 9 AD squared space equals space 9 AB squared minus 2 BC squaredBut AB = BC = CArightwards double arrow 
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rightwards double arrow 
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In an equilateral ABC, D is a point on side BC such that\xa0\xa0Prove that\xa09AD2\xa0= 7AB2.\xa0
Given : An equilateral triangle ABC such that\xa0To Prove : 9AD2\xa0= 7AB2Const: Draw AE ⊥ BC.Proof: In right triangles ABE and ACE, we haveAE = AE [common]∠AEB = ∠AEC [90°]and AB = AC[∆ABC is an equilateral]Therefore, by using RHS congruent condition BE = CE [by CPCT]In right triangle ADE, we haveBut AB = BC = CA\xa0
Discussion
8873.

Case study base question as per New pattern introduction by CBSE

Answer»
Discussion
8874.

Cos2A-3CosA+2/Sin2A=1

Answer» Sorry cosA=1Proved
Cos2A_3CosA+2=2sin2ACos2A_3cosA+2=2 (1_cos2A)Cos2A_3cos +2=2_2cos2A3cos2A_3cosA=03cosA (cosA_1)=0CosA_1=0CosA=0L.H.S=R.H.S
Discussion
8875.

Chapter 9 exercise 9.1 m say kon sa question cut h . Please tell me

Answer» Nothing is deleted in Chapter-9(Maths)
Kuch bhi cut nhi hua
Koi nhi Hua Hai cut
Discussion
8876.

Happy new year to all.https://www.tenor.co/buUF0.gif

Answer» Sm2u ???
Same to you ?
Same to you
Hi
Discussion
8877.

Please tell which exercise have been deducted from maths

Answer»
Discussion
8878.

Ncert exercise 1.1 exam me aayega ki na

Answer» No
No
Thanks
No
Discussion
8879.

P(x)3x2+x-2

Answer» 3x^2 +x -23x^2 +3x -2x -23x(x-1) - 2(x+1) (3x-2) (x-1) So, Either x= 2/3 Or x= 1
Ask the question properly we are unable to understand
Discussion
8880.

Advanced happy new year my dear friend ??

Answer» Crafty Queen mein aapki maid nahi hun so don\'t be so rude And Maine aapko yeh hi kaha tha ki aap apni stories mat share karo because its not allowed.You can check the guidelines.Also tell me how can I help you???*For eg*-I live in Punjab and youlive in Uttar Pradesh Should I come to your place,request your teacher not to force you or call your teacher??You are wasting your as well as our time.Only your parents and Principal can help you. We are helpless.If they don\'t support you its not our fault.We feel bad for u but we are helpless.Thanks Jai Shri Krishna
Same to u
Same to you☺
You to ?
Same to u
Discussion
8881.

The sum of 2 number is 8 and the sum of their reciprocal is 8/15. Find the numbers.

Answer» Let one number be X. The other number be\xa0Y.GIVEN,x+y=8x=8-y ---------------(1)1/x+1/y=8/15BY SIMPLIFING 1/x+1/y=8/15 WE GET,(x+y)/xy=8/15FROM (1) WE GET,8/8y-y2=8/15y2-8y+15=0(y - 3)(y - 5) = 0y = 3 or 5WE KNOW THAT x+y=8When y=5, x=3When y = 3, x = 5
Discussion
8882.

The graph shown in figure is of which type of polynomial

Answer»
Discussion
8883.

Find the co-ordinate of center of a circle passing through the points (6,-6) , (3,-7) & (3,3)

Answer» Let O (x, y) is the point of the circleif three given points A (3,-7) B (3,3) and C (6,-6)we know distance between circumference and center is always same. i.e radius .now,{tex}OA^2=OB^2=OC^2{/tex}{tex}OA^2=OB^2{/tex}{tex}=>(x-3)^2+(y+7)^2=(x-3)^2+(y-3)^2{/tex}{tex}=>(x-3)^2-(x-3)^2=(y-3)^2-(y+7)^2{/tex}{tex}=> 0=(2y+4)(3){/tex}{tex}=> y= -2{/tex}now again ,{tex}OB^2=OC^2{/tex}{tex}(x-3)^2+(y-3)^2=(x-6)^2+(y+6)^2{/tex}put y=-2{tex}=>(x-3)^2+(-2-3)^2=(x-6)^2+(-2+6)^2{/tex}{tex}=>(x-3)^2-(x-6)^2=16-25{/tex}{tex}=>(2x-9)(3)=-9{/tex}{tex}=> 2x= -3+9=6{/tex}=> x=3hence center co-ordinate is (3,-2)
Discussion
8884.

exercise 1.1 is coming in exam ??

Answer» Euclid\'s Division Lemma is not a part of our syllabus.As per the 30%reduced syllabus by CBSE
No
No
Discussion
8885.

Solve 2x+3y=11 and 2x-4y=-24 and hence find the value of m for which y=mx+3 .

Answer» Hi
Fbgne
Hi yogita thanks for your solution I have miscalculated the value of x and m
By using elimination method we can easily get y=5, x=1/3, m=6
Given equations are\xa02x+3y=11−−−−(1)2x−4y=−24−−−−(2)Form (1)2x+3y=11\xa0⇒2x=11−3y⇒x=211−3y\u200b−−−(3)substituting x in(2)2x−4y=−24\xa0⇒2(211−3y\u200b)−4y=−24⇒11−3y−4y=−24⇒11−7y=−24⇒7y=35⇒y=35/7⇒y=5.putting y = 5 in (3)\xa0x=[11−3(5)\u200b]/2⇒x=[11−15\u200b]/2⇒x=−4/2∴x=−2.Hence x = -2 and y = 5 is the solution of the\xa0equation.Now, we have to find my=mx+3 ∴m=−15=3(−2)+35−3=−2m⇒−2m=2⇒m=−2/x=−1
Discussion
8886.

Prove that 2+ root 3 ÷ 5 is irrational

Answer» Please ask question with complete information.
Discussion
8887.

Find the cordinate of the mid point of the line segment joining the points (a,b)and (-a,-b)

Answer» O, O
Discussion
8888.

the next root of the ap root 7, root 28, root 63 ,........

Answer» A=root 7D=root 7Hence the next A.p is root 112
Discussion
8889.

2ax-2by+a+4b=02bx+2ay+b-4a=0

Answer»
Discussion
8890.

If the zeros of the polynomial f(x)= x^3-3x^2+x+1 are (a-b), a and (a+b), find a & b.

Answer» Prakash 13:33Hey, glad to know that you\'re learning from BYJU\'S. For more help you may chat here.Student 13:33If the zeros of the polynomial f(x)= x^3-3x^2+x+1 are (a-b), a and (a+b), find a & b.ReadNew messagePrakash 13:34Kindly allow me a minute or two to check for relevant answers to your question. Please be online.Prakash 13:35ANSWERa−b,a,a+b are zeroes of x3−3x2+x+1⇒a−b+a+a+b= sum of zeroes = 3⇒3a=3⇒a=1(a−b)(a)(a+b)= product of zeroes =−1⇒(1−b)(1+b)=−1⇒1−b2=−1⇒b2=2⇒b=±2\u200b
sum of the zeroes = (a-b) + (a+b) + a = 3a i.e. 3a = - b/a or 3a=3 or a=1product of the zeroes = (a-b)*(a+b)*a= a3-ab2 i.e. 1 - b2\xa0= c/a (by putting the value a=1) or b2\xa0=2 or b = +-root2
Discussion
8891.

Exercise 5.3 cut ho gyi h kya

Answer» Thank you all!!!
Nhi question 15 to 20 delete ho gay
Yup Q 15 to Q 20 is deleted from arithmetic
CBSE Class 10 Mathematics (041) - Deleted portion:\tUNIT I-NUMBER SYSTEMS ChapterTopicsREAL NUMBERSEuclid’s division lemmaUNIT II-ALGEBRA ChapterTopicsPOLYNOMIALSStatement and simple problems on division algorithm for polynomials with real coefficients.PAIR OF LINEAR EQUATIONS IN TWO VARIABLEScross multiplication methodQUADRATIC EQUATIONSSituational problems based on equations reducible to quadratic equationsARITHMETIC PROGRESSIONSApplication in solving daily life problems based on sum to n termsUNIT III-COORDINATE GEOMETRY ChapterTopicsCOORDINATE GEOMETRYArea of a triangleUNIT IV-GEOMETRY ChapterTopicsTRIANGLESProof of the following theorems are deleted · The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides. · In a triangle, if the square on one side is equal to sumof the squares on the other two sides, the angle opposite to the first side is a right angle.CIRCLESNo DeletionCONSTRUCTIONSConstruction of a triangle similar to a given triangle.UNIT V- TRIGONOMETRY\xa0 ChapterTopicsINTRODUCTION TO TRIGONOMETRYMotivate the ratios whichever are defined at 0o\xa0and 90oTRIGONOMETRIC IDENTITIESTrigonometric ratios of complementary anglesHEIGHTS AND DISTANCESNo deletionUNIT VI-MENSURATION\xa0AREAS RELATED TO CIRCLESProblems on central angle of 120°SURFACE AREAS AND VOLUMESFrustum of a coneUNIT VI-STATISTICS & PROBABILITY ChapterTopicsSTATISTICS· Step deviation Method for finding the mean · Cumulative Frequency graphPROBABILITYNo deletion\t
Pls answer
Discussion
8892.

1) find the zeores of the polynomial 4x²-9 graphically

Answer» => 4x²- 9 = 0=> 4x² = 9=> x² = 9/4=> x = ± ⅔
Discussion
8893.

Prove that 3+2root5 is irrational

Answer» Letus assume that 3 + 2√5 is a rational number.Soit can be written in the form a/b3 + 2√5 = a/bHere a and b are coprime numbers and b ≠ 0Solving3 + 2√5 = a/b we get,=>2√5 = a/b – 3=>2√5 = (a-3b)/b=>√5 = (a-3b)/2bThis shows (a-3b)/2b is a rational number. But we know that But √5 is an irrational number.so it contradictsour assumption.Our assumption of3 + 2√5 is a rational number is incorrect.3 + 2√5 is an irrational numberHence proved
Our Assumation is wrong, it\'s irrational numbers.
Discussion
8894.

Prove sum of A triangle =180

Answer»
Discussion
8895.

What are the aspects of modem

Answer» Yogita Ingle thanku for typing so much but the fact is that I wanted to ask about the development which you have already answered but in my mind there is modem so I miss intendedly typed modem
A modem is a hardware device which means modulator-demodulator.modems are used to transfer data from one computer network to another computer network through telephone lines.the computer network works in digital mode, while analog technology is used for carrying messages across phone lines.the modulator converts information from digital mode to analog mode at the transmitting end and demodulator converts the same from analog to digital at receiving end.
Discussion
8896.

What is the value of tita

Answer» Thetha is an assuming symbol like x alphbet it has not its own value
Value of tita is depend upon the given numerical ..
He is asking about tita not tan tita
Value of tita is perpendicular upon base
Discussion
8897.

Send 25 degree cos 65 degree + cos 25 February science 35 degree

Answer» What is this?You can ° rather than writing degree
Discussion
8898.

How to find the number of zeroes in a polynomial ( graph )

Answer» No. of zeroes is equal to the no. of points cut at x . axis .
Just see how many times does the line intersects with x axis
Discussion
8899.

sin (90-A)=

Answer» Cos A
cos A because cos A and sinA are complementary angles of each other .
COS A
Discussion
8900.

, sin theta + cos theta the whole square equal to 1 + 2 Sin Theta into cos theta

Answer»
Discussion