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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 8901. |
Collinear points means |
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Answer» Collinear means they all are lie in the same line means in the straight lines . Points that follow, to form a straight line are collinear points.Their relation is like:-AB+BC=AC Any 2 parts of the line together make a straight line. A point that lies on another point |
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| 8902. |
The pair of linear equation 3x-5y=7 , 6x-10y=7 has how many solution |
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Answer» No solution The conditions for each of the solutions is given by;\tIf\xa0, then there is a unique solution for the pair of linear equations.\tIf\xa0, then there are infinitely many solutions for the pair of linear equations.\tIf\xa0, then there is no solution for the pair of linear equations.\xa0So, according to our question;\xa0SO,\xa0Here, the third condition is satisfying that; \xa0which means\xa0.Therefore, the given pair of linear equations has no solution. |
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| 8903. |
The pair of linear equation x-2y=5 , 2x-4y=1 will have how many solution? |
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Answer» It have no solutions a1/a2 = 1/2b1/b2= 2/4 = 1/2c1/c2 = 5/1No solution as a1/a2 = b1/b2 but not equal to c1/c2 so no solution to the above system of equation. |
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| 8904. |
Pythagora |
| Answer» Pythagoras of Samos was an ancient Ionian Greek philosopher and the eponymous founder of Pythagoreanism. His political and religious teachings were well known in Magna Graecia and influenced the philosophies of Plato, Aristotle, and, through them, Western philosophy. | |
| 8905. |
Express 0.7 bar in the form of p/q also find the prime factorization of q when p and q are Co-prime |
| Answer» 0.7 bar means 0.77777777...Letx = 0.777......... ----(I)10x = 7.77........ ----(II)Subtract (II) from (I)\t10x - x = 7.777.... + 0.777...\t9x = 7\tx = 7/90.7 bar can be expressed as 7/9 | |
| 8906. |
Prove that 4+5√3 is irrational, given that √3 is irrational. |
| Answer» let 4+ 5√3 be a rational number.4 + 5√3= a/b where a and b are co primes\xa05√3=a/b-4\xa05√3=a-4b/ba-4b/b- 5=√3But this contradiction is wrong therefore 4+5√3 is a irrational number. | |
| 8907. |
If the pth term of an ap is q and the qth term of an ap is p, show that it\'s nth term is (p+q-n). |
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| 8908. |
If anybody can help me with hindu medium of CBSE maths sample papers 2020-21.. Please |
| Answer» First Pal you can give me sample paper of 10th class in Hindi PDF form SST ka then I can send you my paper in Hindi | |
| 8909. |
Maths chapter 8 main kon se exercise cut h |
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Answer» Ex 8.3 8.3 |
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| 8910. |
Find the area of quadrant of a circle whose circumference is 22 cm |
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Answer» Circumference of circle = 22 2πr = 22 2× 22/7 ×r = 22 r= 7/2Area of quadrant = theta/ 360 ×πr2 90/360× 22/7 × 7/2 ×7/2 = 77/8 |
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| 8911. |
p(-1,1)is the point on the line segment joining A(2,-2) and B(3,7 ) then find the ratio of division. |
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| 8912. |
If one root is negative to other of equation 4x2–8xk–9=0 .find the value of K . |
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Answer» Comparing f(x) = 4x2\xa0- 8kx - 9 with ax2+bx+c we geta=4; b=-8k and c=-9.Since one root is the negative of the other, let us assume that the roots are p an -p.Sum of the roots, a+(-a)=-b/a= - (-8k) / 40=2kk=0 Hey how r i |
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| 8913. |
9 sec square A - 9 tan square A = |
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Answer» 9sec²A-9tan²A=9 A n s w e rThe value of 9sec²A-9tan²A =9Step-by-step explanation:The\xa0value\xa0of\xa09sec²A-9tan²A=\xa09(sec²A-tan²A)/*\xa0By\xa0Trigonometric\xa0identity:\xa0=\xa09\xa0×1=\xa09Therefore,.The\xa0value\xa0of\xa09sec²A-9tan²A\xa0=9 |
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| 8914. |
What is elinimation method? |
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Answer» The\xa0elimination method\xa0is used to solve linear equations in two variables, where one of the variables is removed or eliminated. This method is sometimes more comfortable and convenient than the\xa0substitution method. Here are the notes provided with the complete steps to solve such linear equations where two variables are used.In another classification, there are three different algebraic methods to solve simultaneous linear equations. These methods are namely:\tSubstitution method\tElimination method\tCross-multiplication methodThere are many situations which can be mathematically described by two equations that are not in the linear form. But we alter them so that they are reduced to a pair of linear equations. In this article, you will learn how to solve linear equations using the elimination method. Sonu Elimination method? |
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| 8915. |
What is substitution method? |
| Answer» The\xa0substitution method\xa0is the algebraic method to solve simultaneous linear equations. As the word says, in this method, the value of one variable from one equation is substituted in the other equation. In this way, a pair of the linear equation gets transformed into one linear equation with only one variable, which can then easily be solved. Before moving to solve the linear equations using the substitution method, get an idea on what the algebraic method and graphical method is. | |
| 8916. |
Rita |
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Answer» ?\u200d❤️\u200d?\u200d??\u200d❤️\u200d?\u200d??\u200d❤️\u200d?\u200d? Sonu |
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| 8917. |
Bhi koi hamko social science ka delete portion batao to |
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Answer» Thanks Bro Google pai jao aur type kro social science delete syllabus 1st website pai hi hai sab khuch |
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| 8918. |
Bhi koi hamko science ka reduced syllabus to btao |
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Answer» Bahi koi hindi me bej de yaar notes science ke Ok HRD Minister Ramesh Nishank announced a major CBSE syllabus reduction for the new academic year 2020-21 on July 7 which was soon followed by an official notification by CBSE on the same.Considering the loss of classroom teaching time due to the Covid-19 pandemic and lockdown, CBSE reduced the syllabus of classes 9 to 12 with the help of suggestions from NCERT.The CBSE syllabus has been rationalized keeping intact the learning outcomes so that the core concepts of students can be retained.Deleted syllabus of CBSE Class 10 Science\xa0\xa0 Find for reduced syllabus on Google Aapko reduce syllabus Google par mil gayega |
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| 8919. |
Reduce syllabus of NCERT maths book? |
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Answer» Yes HRD Minister Ramesh Nishank announced a major CBSE syllabus reduction for the new academic year 2020-21 on July 7 which was soon followed by an official notification by CBSE on the same.Considering the loss of classroom teaching time due to the Covid-19 pandemic and lockdown, CBSE reduced the syllabus of classes 9 to 12 with the help of suggestions from NCERT.The CBSE syllabus has been rationalized keeping intact the learning outcomes so that the core concepts of students can be retained.Deleted syllabus of CBSE Class 10 Mathematics\xa0 |
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| 8920. |
Koi hamko bahut saare math ke difficult question bhejo kisi bhi chapter ka math only.ok |
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Answer» The sum of n terms of an A.P is 5(nsquare)-3n then, find the first term and d Bah Prove 2+2 =4 ? |
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| 8921. |
1 2 ekad biopest samikaran gyat Kijiye Jiska 0 3 aur 4 Hain |
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| 8922. |
Ek Dui Ghat samikaran gyat karo Jiska 0 ank 3 aur 4 Hain |
| Answer» x=3 , x=4(x-3) (x-4)(x)^2 -7x +12 =0 | |
| 8923. |
Coss 3O +SIN601+SIN30 +coss60 |
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Answer» Elimination method fraction equation 5root 3/2 5root3 by 2 |
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| 8924. |
Define ohm\'s law? |
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Answer» Potential difference =current*resistanceV=IR It states that current flowing through the conductor is directly proportional to the potential difference across the ends of the conductor when physical conditions like temperature , pressure etc remains same. V=IR According to Ohms ,At constant temperature the electric current is directly proportional to the potential difference. |
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| 8925. |
How many theories are there in real number chapter |
| Answer» Bro its in book read it? | |
| 8926. |
Types of polynomial explain with examples? Also define it ? |
| Answer» Types Of PolynomialsPolynomials can be classified based on:a) Number of termsb) Degree of the polynomial.Types of polynomials based on the number of termsa) Monomial – A polynomial with just one term. Example: 2x, 6x2, 9xyb) Binomial – A polynomial with two terms. Example: 4x2+x, 5x+4a) Trinomial – A polynomial with three terms. Example: x2+3x+4Types of Polynomials based on DegreeLinear PolynomialA polynomial whose degree is one is called a linear polynomial.For example, 2x+1 is a linear polynomial.Quadratic PolynomialA polynomial of degree two is called a quadratic polynomialCubic PolynomialA polynomial of degree three is called a\xa0cubic polynomial.For example, 2x3+5x2+9x+15 is a cubic polynomial. | |
| 8927. |
Define algebra? |
| Answer» Polynomial | |
| 8928. |
Show that there exists no rational number whose square is 5 |
| Answer» Given,Prove that there is no rational number whose square is\xa0Let\'s assume that\xa0, where\xa0\xa0and\xa0\xa0and\xa0are co-prime.Then we have,So,⇒\xa0This implies that\xa0\xa0is even.Then,So,⇒\xa0⇒Thus,⇒⇒Then,∴\xa0which contradicts\xa0\xa0and\xa0\xa0being co-prime.Therefore,\xa0\xa0is irrational. | |
| 8929. |
matchmatics techer of a school look her |
| Answer» Sincere | |
| 8930. |
Online rehna frnds plz |
| Answer» | |
| 8931. |
Gaurav seth तुमसे चेक का परिभाषा पूछा था तुमने उसका विवरण क्यों दिया |
| Answer» एक चेक एक कागज होता है जो बैंक को उस व्यक्ति के खाते से उस व्यक्ति को एक विशिष्ट राशि का भुगतान करने का निर्देश देता है जिसके नाम पर चेक बनाया गया हैA cheque is a paper instructing the bank to pay a specific amount from the person’s account to the person in whose name the cheque has been made.\xa0 | |
| 8932. |
Find the coordinates if the po points of trisection of the line segment joining (4,-1) and (-2,-3) |
| Answer» first let the points beA(4,-1),B(-2,-3)first let us take the ratio as 1:2 and later 2:1 since its trisection .let the point joining A and B be P(x,y)Step-by-step explanation:P = (1*-2+2*4/1+2 , 1*-3+2*-1/1+2) = (-2+8/3 , -3-2/3) = (6/3 , -5/3)P = (2 , -5/3)now let ratio be 2:1P = (2*-2+1*4/3 , 2*-3+1*-1/3) = (-4+4/3 , -6-1/3) = (0/3 , -7/3)P = (0 , -7/3) | |
| 8933. |
If tan A=1,and sinB=1/2, find the value of cos(A+B) where A and B are both acute angles. |
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| 8934. |
Exercise 14.1 |
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Answer» In order to find the mean value, we will use direct method because the numerical value of fi\xa0and xi\xa0are small.Find the midpoint of the given interval using the formula.Midpoint (xi) = (upper limit + lower limit)/2\tNo. of plants (Class interval)No. of houses Frequency (fi)Mid-point (xi)fixi0-21112-42364-61556-857358-10695410-122112212-1431339\xa0Sum fi\xa0= 20\xa0Sum fixi\xa0= 162\tThe formula to find the mean is:Mean = x̄ = ∑fi\xa0xi\xa0/∑fi\xa0= 162/20= 8.1Therefore, the mean number of plants per house is 8.1\xa0Click for more:NCERT Solutions for Class 10 Maths Exercise 14.1 ... In e |
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| 8935. |
the sum of the squares of three consecutive integers is 110 then the smallest positive integer is |
| Answer» Consecutive numbers\xa0are numbers that follows each other in order.\xa0Define the numbers:\xa0Find the sum of the squares of these 3 number:\xa0Given that the sum is equal to 110:\xa0Find the numbers:\xa0\xa0\xa0Answer: The smallest positive integer is 5. | |
| 8936. |
If sin (A-B) =12, cos (A+B)=12 0° < ? + ? ≤ 90°, A> ?, Find A and B |
| Answer» A+B=120 .................[1 ]A-B =12...................... [2]___________2A = 108A= 108/2A= 54Value of A in eq 2A-B=1254-B = 12-B = 12-54-B = - 42 - cancelled So B = 42So value of A =54 B = 42 | |
| 8937. |
Find the distance of point (-3,4) from the x-axis |
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Answer» The distance of point (-3, 4) from x-axis is 4units i.e.ordinate. Clearly, the distance of the point P(-3, 4) from x -axis is 4 units. |
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| 8938. |
hamko koi hcf lcm ka word problem solve karne ka tarika to bta do |
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| 8939. |
Case study suresh is having a garden near delhi |
| Answer» Suresh is having a garden near Delhi. In the garden, there are different types of trees and flower plants. One day due to heavy rain and storm one of the trees got broken as shown in the figure.The height of the unbroken part is 15 m and the broken part of the tree has fallen at 20 m away from\xa0the base of the tree.Using the Pythagoras answer the following questions:\tWhat is the length of the broken part?\t15 m20 m25 m30 m\t\t\tWhat was the height of the full tree?\t40 m50 m35 m30 m\t\t\tIn the formed right-angle triangle what is the length of the hypotenuse?\t15 m20 m25 m30m\t\t\tWhat is the area of the formed right angle triangle?\t100 m2200 m260 m2150 m2\t\t\tWhat is the perimeter of the formed triangle?\t60 m50 m45 m100 m\t\tAnswer:1)C2)A3)C4)D5)A\xa0 | |
| 8940. |
If p and q are the zero of x^2 + px + q then find the value of p and q |
| Answer» Given equation\xa0x2+px+qAlso, given\xa0p,q\xa0are the roots of the equation.p+q=−p 2p=−q .....(1)And pq=qq(p−1)=0⇒q=0\xa0or\xa0p=1So, by\xa0(1),\xa0q=0⇒p=0 Hence, the values of\xa0p\xa0are\xa00,1. | |
| 8941. |
If sin alpha =0.2 and cos beta=0.2. Find sin( alpha + beta) |
| Answer» Here,Sin α = cos β = 0.2 •°• sinα = cos β Now, according to complementary angle ratios... Cosβ = sin(90-β) so by applying this concept... Sinα = sin(90-β)•°• α = 90-β •°• α+β=90 ----(1) We have to find Sin(α+β) so now according to (1).... Sin(α+β) = Sin(90) and the value of Sin90 = [1]// | |
| 8942. |
find the sum of (-5)+(-8)+(-11)+......+(-230) |
| Answer» (−5) + (−8)+ (−11) + ... + (−230) .Common difference of the A.P. (d) = a2\xa0- a1\xa0=-8-(-5)=-8+5=-3So here,First term (a) = −5Last term (l) = −230Common difference (d) = −3So, here the first step is to find the total number of terms. Let us take the number of terms as\xa0n.Now, as we know,an\xa0= a + (n-1) dSo, for the last term, - 230 = -5 + ( n-1) (-3)\xa0 - 230 = -5-3n + 3-23 +2 = -3n-228-3=n n = 76Now, using the formula for the sum of\xa0n\xa0terms, we getSn=762[2(-5)+(76-1)(-3)] = 38 [-10+(75)(-3)] =38 (-10-225) = 38(-235) = -8930Therefore, the sum of the A.P is Sn\xa0= -8930\xa0 | |
| 8943. |
Express 156 is the product of co prime |
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Answer» \xa0156=13×3×22 Bzhz Express 156 as the product of prime |
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| 8944. |
Value of sin90 |
| Answer» 1 | |
| 8945. |
Find the 10th term of A.P 2, 7, 12......... |
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Answer» Given ap= 2,7,12....A=2Common difference=12-7=5N term an=a+(n-1)dAn10=2+(10-1)5=2+9×510th term=47 Given A.P. 2, 7, 12, ….. First term a = 2 Common difference d = 7 – 2 = 5 nth\xa0term an\xa0= a + (n – 1)d ∴ a10\xa0= 2 + (10 – 1) × 5 = 2 + 9 × 5 = 2 + 45 = 47 Hence, 10th\xa0term of given series is 47 Given A.P. 2, 7, 12, …..First term a = 2Common difference d = 7 – 2 = 5nth term an = a + (n – 1)d∴ a10 = 2 + (10 – 1) × 5= 2 + 9 × 5= 2 + 45= 47Hence, 10th term of given series 47. |
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| 8946. |
Ap 2 7 12 17 23 ..... find 240th term |
| Answer» the given AP2,7,12,17.........\xa0the first term(a) =2common difference = 5\xa0the nth term = a+(n-1)d=2+(n-1)5=2+5n-5=5n-3therefore 5n - 3 is the nth term of the given APNow T240\xa0\xa0= 5 x (240) - 3therefore 240th term is 1197 | |
| 8947. |
The central value of the set of observation is calledModeMedianMean AM |
| Answer» Median | |
| 8948. |
What is the probability that a no. Selected from the numbers 1,2,3....,15 is a multiple of 4 |
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Answer» The series is\xa01, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15The multiples of 4 in the above series is\xa04, 8, 12 = 3 termsThe probability of selecting a multiple of 4 =\xa0or = 0.2 From Number1,2,3,4,5,6,7,8,9,10,11,12,13,14,15From 1 to 15, Multiples of 4 are 4, 8, 12 onlySo Probability= Count\xa0of\xa0No.\xa0which\xa0are\xa0multiple\xa0of\xa04\u200b/Total\xa0Number\xa0givenProb.=3/15 \u200b= 1/5 |
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| 8949. |
घन की सतह ...........के आकार की होती है। |
| Answer» Box | |
| 8950. |
ऊपरी सीमा और निम्न सीमा के अंतर को ...........कहते है । |
| Answer» माप, साइज या चौड़ाईकिसी वर्ग अंतराल का ऊपर का मान उस वर्ग अंतराल की उपरि वर्ग सीमा कहलाता है तथा उसका नीचे का मान उसकी निम्न वर्ग सीमा कहलाता है। किसी वर्ग की उपरि वर्ग सीमा और निम्न वर्ग सीमा का अंतर उस वर्ग की माप, साइज या चौड़ाई कहलाता है। | |