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9301.

What is first four consecutive positive terms of an AP

Answer»
9302.

Activities for class 8

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9303.

If alpha and beta are zeroes of polynomail 4xcube +3x -7

Answer»
9304.

Prove that cos45- sin45=0

Answer» We know that cos 45=1/√2 and sin 45=1/√2Therefore 1/√2-1/√2=0Hence it is proved
9305.

Prove that root 2 is an irrational no

Answer» Let √2 is an irrational numberLet √2=p/q (where p and q are integers and q is not equal to 0) -1Let a/b is the lowest form of p/q So,p/q=a/b (where a and b are co- prime numbers)Putting in 1√2=a/bSquarring both side(√2)^2 = (a/b)^22=a^2/b^2a^2 = 5b^2So,2 is the factor of a^2also 2 is the factor of aLet a=2m( where m is some integer) (2m)^2= 2b^24b^2=2b^2 4b^2/2 = b^2 2b^2 = b^2b^2=2b^2 So,2 is the factor of b^2also 2 is the factor of bHere,2 is the factor of both a and b .This contradict our supposition that √2 is an rational number is wrong. Hence ,√2 is an irrational number
9306.

If p, q are prime positive integers, prove that √p + √q is an irrational number.10.

Answer» Please tell the answer
9307.

65m-113n

Answer»
9308.

(x-3)^2=(2x-5)(3-x) check whether it is a quadratic equation

Answer»
9309.

126 HcF

Answer» 126-2,3,3,7HCF=3×2×7 =42ans
HCF = Highest Common Factor. Factors of 126=2,3,3,7So, H.C.F= 3
9310.

0 is a real number but why

Answer»
9311.

A number when divided by 61gives 27 as quotient and 32 as remainder find the number

Answer» Answer is 1679solution :61×27 + (32)=1647+32=1679
9312.

Prove that √5 is an irrational number.

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9313.

Prove that (5+2root5) hole square 2 is irrational

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9314.

2y^2 + 12y - 432

Answer» 2y ×2y+12y-4324y+12y-43216y=432y=432÷16y=27
9315.

Check whether 4n can end with the digit 0 for any natural number

Answer» If the 4n is end with zero it has 5 and 0 as a prime factorisation but it 2 and 2 as a prime factor so it is end with digit zero
9316.

Find the value of Alpha / beta + beta upon Alpha if in the polynomial X square + bx + c

Answer» Take LCM of alpha and beta LCM will be alpha betaBeta and beta will be cancelled then put + sign then alpha and alpha will be cancelledEquation: alpha + beta divide by (/) alpha betaThen apply sum of zeros and product of zeros Then a and a will be cancelled remaining -b/c And answer will be -b/c
9317.

Show that the following numbers are irrational (i) 3/(2√5) (ii) 4 +√2\u200b

Answer» Because
9318.

Show that the following number is irrational 3/(2√5)

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9319.

[a+b] [a+b]

Answer» (a+b)^2=a^2-b^2+2ab
(a+b)² =a²+ b²+ 2ab
a²+b²+2ab
a²+b²
a²+b²
9320.

√2x²-3x-2√2 splitting middle term

Answer» ✓2x²+4x-1x-2√2√2(x-2√2)+1(x-2√2)(X-2√2). (√2x+1)
9321.

Solve the following for x and y ax/b - by/a = a+b ax-by=2ab

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9322.

Hlo sir

Answer» Hlo
9323.

Find the sum of first twelve 2- digit number which are multiple of 6

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9324.

5 is one of the zeroes of the polynomial p(x)=2x³-5x²-13x+30. true or false

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9325.

History of pie

Answer» The value of pie is not defined
9326.

If tan (A-B) = 1/2 and cos (A+B) =1/2, 0°

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9327.

a^m^n =[a^m]^n

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9328.

75/455 is terminating or non terminating decimal expansion

Answer» Terminating
9329.

Simplify 2+2√13/8

Answer» 2.90138781887
9330.

The sum of two numbers is 84 and their HCF is 4 total number of such pairs of number

Answer» 84
9331.

Linear combination of 13

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9332.

Show that 2√ 3- 5 is an irrational number

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9333.

The number of polynomial has zeros as - 2 and 5 is

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9334.

All the best all of you my friends for sst exam 🤞🤞🤞

Answer» Same
9335.

Write0.333.... in the form of p/q

Answer» Hii
0.333 = 333/1000
Let x = 0.33333..... ..1Multiplying eq. 1 with 10So, 10x = 3.33..... ..2Subtracting eq.2 from 1So, 10x - x = 3 9x = 3 x = 3/9 x = 1/3Thus 0.333...=1/3
9336.

The site of food made and him what does he suggested

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9337.

(sin A + cosec A ) ^ 2 * (cos A + sec A ) ^ 2 = 7 + tan 2 A + cot 2 A

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9338.

Root 3x²+10x+7root3=0

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9339.

show that only one of the numbers n , n+2 , n+4 is divisible by 3

Answer» Case-I: When n = 3qIn this case, we haven= 3q, which is divisible by 3Now, n = 3qn+2 = 3q+2n+2 leaves remainder 2 when divided by 3Again, n = 3qn+4 = 3q+4=3(q+1)+1n+4 leaves remainder 1 when divided by 3n+4 is not divisible by 3.Thus, n is divisible by 3 but n+2 and n+4 are not divisible by 3. Case-II: when n = 3q+1In this case, we haven= 3q+1,n leaves remainder 1 when divided by 3.n is divisible by 3Now, n = 3q+1n+2 = (3q+1)+2=3(q+1)n+2 is divisible by 3.Again, n = 3q+1n+4 = 3q+1+4=3q+5=3(q+1)+2n+4 leaves remainder 2 when divided by 3n+4 is not divisible by 3.Thus, n+2 is divisible by 3 but n and n+4 are not divisible by 3. Case-III: When n + 3q+2In this case, we haven= 3q+2n leaves remainder 2 when divided by 3.n is not divisible by 3.Now, n = 3q+2n+2 = 3q+2+2=3(q+1)+1n+2 leaves remainder 1 when divided by 3n+2 is not divisible by 3.Again, n = 3q+2n+4 = 3q+2+4=3(q+2)n+4 is divisible by 3.Thus, n+4 is divisible by 3 but n and n+2 are not divisible 3.
9340.

Show that 21n cannot end with the digits 0, 2, 4, 6 and 8 for any natural number n.

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9341.

Three prime number Pqr statify the following condition = P + Q = R and 1< P

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9342.

Ex 2B 11question rs Aggarwal

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9343.

Ex,2a

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9344.

Exercise 6.3 question number 4 solution

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9345.

polynomials ex 2.2 ans

Answer» And x=2
X=4
9346.

Six x equal minust three minus seven

Answer» look at maths chapter 2 polynomial and find NCERT solutions you will get ans .
9347.

if in board exams I don\'t take vale of √3 as 1.73 if give, then are marks deducted?

Answer» Yess
Yes
Yes
9348.

Find the value of Sin ^2 30 cos^2 45+4tan^2 30+1/2 sin ^2 90-2cos 90 +1/2

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9349.

All the best guys for Maths board exam don\'t get tension write happily

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9350.

(4,7)and(10,-1)

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