InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 901. |
Chapter 14.3 question no. 3 |
| Answer» available on this app.. | |
| 902. |
Solution of chapter 2,exercise 2.2 only |
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Answer» Sorry galat type ho gya but m ye kahna chahti hoon ki aapko exercise 2.2.ke solutions es app se aasani se mil sakte hai....... Bro you can easily get this from thid available on this app... |
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| 903. |
If the first term of an ap is -5 and the common difference is 2 then the sum of its first 6 term |
| Answer» | |
| 904. |
Where do you all belong fron? |
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Answer» Maharashtra Maharashtra Madhya Pradesh Haryana |
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| 905. |
Kya aap sabhi 10th class mein hai? |
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Answer» Thanks ,I just want to confirm that are there only 10th class students or anyone else. Hu Ok Haa Yaa |
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| 906. |
Ex: 2.1 question 5 |
| Answer» The no. Of zeros are 4 as the line touches the x axis 4 times. | |
| 907. |
If the HCF of the polynomials x²+px+q and x²+ax+b is x+l.Find their LCM |
| Answer» | |
| 908. |
X-2y=3. 2x-y=1(using geometrical method) |
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| 909. |
Sir, why 22/7 is a rational no but 3.14 is a irrational no? |
| Answer» \tAs you know that π is a irrational number as it\'s decimal expension is non- terminating & Non- repeating.\tBut these statements are actually true because we have assumed the APPROPRIATE value of π as 22/7 to make calculation easier.\tIf you divide 22/7 then it\'s decimal expension will come 3.14... which as approximately value equal to π. | |
| 910. |
bx+ay-ab(a+b)=0b^2x+a^2y-2a^2b^2 |
| Answer» The system of linear equations with variables x and y are given to be⇒ b³x - a³y = a²b²(a + b) .......... (1)⇒ b³x - a³y = a³b² + a²b³ ........... (2)And, the other equation isb²x - a²y = 2a²b² ............ (3)⇒ b³x - a²by = 2a²b³ ............ (4)Now, solving equations (2) and (4) we get,a²by - a³y = a³b² + a²b³ - 2a²b³ = a³b² - a²b³⇒ a²(b - a)y = a²b²(a - b)⇒\xa0y = - b²Now, from equation (3) we getb²x - (-b²)a² = 2a²b²⇒ b²x = a²b²⇒\xa0x = a²Therefore, the solution for x is x = a². (Answer) | |
| 911. |
To kaise h aap log |
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Answer» Thik h? Badiaya Koi to bolo |
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| 912. |
Kal result hai best of luck sab ko.result accha aayga sab ka. |
| Answer» | |
| 913. |
The first term of an ap is -5 and the the common difference is -2 then the sum of first 6 team is |
| Answer» Given a =-5 and d=-2 , n= 6To find 6th terrm so here we will use Sn formula :Sn=n/2{a+(n-1)d}Putting the given values on this formula:Sn =6/2{-5+(6-1)-2}S6= 3{-5+(5×(-2)}S6=3(-5-10)S6=3×(-15)S6=-45 | |
| 914. |
If the product of the zeroes of x2 – 3kx + 2k2 – 1 is 7, then values of k are ___ and ___. |
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Answer» 2 K=2 |
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| 915. |
Find the 10th term and the 20th term of the AP 5,1,-3,-7 |
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Answer» Corect answer is -71 Wrong answer a10 = a + 9d = 5+9(-4) = 5-36 = -31A11= a + 10 d = 5+10(-4) = 5-40 = -35 |
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| 916. |
Show that :-tan48°tan23°tan42°tan67°=1 |
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Answer» tan48°×tan23°×tan42°×tan67°=1L.H.S.=>tan(90°-48°)×tan(90°-23°) ×tan42°×tan67°=> 1/tan42°× 1/tan67°× tan42°× tan67°=> 1=1 HENCE PROVEDHOPE IT WILL HELP YOU.... Hii Haj tan 48° tan 23° tan 42° tan 67° = tan (90° - 42°) tan (90° - 67°) tan 42° tan 67° = cot 42° cot 67° tan 42° tan 67° = (cot 42° tan 42°) (cot 67° tan 67°)= 1×1= 1 |
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| 917. |
Give answer for the riddle below |
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Answer» Hii??? Hii Hii |
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| 918. |
Koi zinda hai abhi bhi......ya bus me hi ek oolo hu |
| Answer» ha bolo, I\'m also alive. | |
| 919. |
Factorization x2-2x-8 |
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Answer» X= -2,4 is the answer X2-2x-8By spliting the middle termSo,x*8=88 can be splitted as -4*2-4x+2x=-2xX2+2x-4x-8=0X(x+2)-4(x+2)=0(X+2)(x-4)=0(X+2)=0X=-2(X-4)=0X=4Therefore x=-2,4 x= -2,4 x2-2x-8 :By splitting methodx2-4x+2x-8 x(x-4)+2(x-4) (x-4)(x+2). x2+2x-8=0x2+4x-2x-8=0\xa0x(x+4)-2(x+4)=0(x-2) (x+4)=0\xa0x=2 or x= -4 |
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| 920. |
Prove that √p+√q is irrational ,if p and q are prime numbers . Explain it with easy method |
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Answer» Search ResultsFeatured snippet from the webNow x, x², p, q and 2 are all rational, and rational numbers are closed under subtraction and division. So (x² - p - q) / 2 is rational. But since p and q are both primes, then pq is not a perfect square and therefore √(pq) is not rational. But this is a contradiction. lets assume that √p is rational,⇒ √p = a/b ( where \'a\' and \'b\' are co primes, meaning they don\'t have any common factors except for 1)From squaring both sides,p = a²/b²⇒pb² = a²⇒ b² = a²/pSince \'p\' divides a², it also divides \'a\' meaning \'a\' has a factor of pLet \'a\' = pm (where m is a positive integer) ⇒ a² = p²m²Now, pb² = a²pb² = p²m²pb²/p²= m²b²/p =m²∴ \'p\' divides \'b\' ⇒ \'b\' also has a factor \'p\'∴ \'a\' and \'b\' are not co primes and our assumption was wrong⇒ √p is irrationalSimilarly √q is irrational∴⇒ √p + √q is irrational Let us suppose that\xa0√p + √q\xa0is rational.\xa0Let\xa0√p + √q\xa0= a, where a is rational.\xa0=\xa0√q\xa0= a –\xa0√p\xa0Squaring on both sides, we get\xa0q = a2\xa0+ p -\xa02a√p=>\xa0√p\xa0= (a2\xa0+ p - q)/2a, which is a contradiction as the right hand side is rational number, while√p\xa0is irrational.\xa0Hence,\xa0√p + √q\xa0is irrational. |
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| 921. |
Can anyone explain me trigonometric ratios |
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Answer» No This chapter is done in your school?.......anyways thank you The trigonometric ratios are special measurements of a right triangle (a triangle with one angle measuring 90° ). ... There are three basic trigonometric ratios: sine , cosine , and tangent . Given a right triangle, you can find the sine (or cosine, or tangent) of either of the non- 90° angles. |
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| 922. |
chapter4 |
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Answer» It is quadratic equations It is written ...... mathematics Subject |
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| 923. |
The primeter of the quadrant of a circle is 25 cm .find its area |
| Answer» Let radius = rPerimeter = radius + radius + length of arcPerimeter of quadrant = r + r + angle/360 * 2 * pi * r = 252r + [1/4 * 2 * 22/7 * r] = 2525/7 * r = 25r = 7Area = angle/ 360 * pi * r * r1/4 * 22/7 * 7 * 7 = 38.5 sq.cm | |
| 924. |
One of the zeros of the polynomial 2x square +7x-4 |
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Answer» Yogita thanku 2x2+7x -4=02x2+8x -x -4=02x(x+4)-1(x+4)=0(X+4)(2x -1)=0X+4=0X=-42x-1=0X=1/2The zeroes of the polynomial 2x²+7x-4 are -4 , and 1/2. -4 will we the zeroes of this polynomial |
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| 925. |
what is euclid division lema |
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Answer» This is deleted from the syllabus 2020 For a pair of given positive integers ‘a’ and ‘b’, there exist unique integers ‘q’ and ‘r’ such thata=bq+ra=bq+r, where\xa00≤r | |
| 926. |
Prove that√6 is irrational |
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Answer» Let √6 be a rational number , then √6 = p÷q , where p,q are integers , q not = 0 and p,q have no common factors ( except 1 )=> 6 = p² ÷ q² => p² = 2q² ................(i)As 2 divides 6q² , so 2 divides p² but 2 is a prime number > 2 divides p.....Let p = 2m , where m is an integer .......Substituting this value of p in (i) , we get ,......(2m)² = 6q² .......=> 2m² = 3q² .......As 2 divides 2m² , 2 divides 3q² .......=> 2 divides 3 or 2 divide q² ......But 2 does not divide 3 , therefore , 2 divides q²........=> 2 divides q .......Thus , p and q have a common factor 2 . This contradicts that p and q have no common factors ( except 1 ).......Hence , our supposition is wrong . Therefore , √6 is an irrational number.... Square root hai cube root hai Assume cube root 6 is rational. Then let cube root 6 = a/b ( a & b are co-prime and b not = 0)\xa0Cubing both sides : 6=a^3/b^3\xa0a^3 = 6b^3\xa0a^3 = 2(3b^3)\xa0Therefore, 2 divides a^3 or a^2 * a . By Euclid\'s Lemma if a prime number\xa0divides the product of two integers then it must divide one of the two integers\xa0Since all the terms here are the same we conclude that 2 divides a.\xa0Now there exists an integer k such that a=2k\xa0Substituting 2k in the above equation\xa08k^3 = 6b^3\xa0b^3 = 2{(2k^3) / 3)}\xa0Therefore, 2 divides b^3. Using the same logic as above. 2 divides b.\xa0Hence 2 is common factor of both a & b. But this is a contradiction of the fact that a & b are co-prime. Therefore, the initial assumption is wrong.\xa0cube root 6 is irrational. |
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| 927. |
π is dash number |
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Answer» Pi(π) is an irrational number but we use π = 22/7 or 3.14 3.1415926535 Irrational number. Irrational no. π (Pi) is irrational number.We cannot write down a simple fraction that equals\xa0Pi. The popular approximation of\xa022/7\xa0= 3.1428571428571... is close but not accurate. Another clue is that the decimal goes on forever without repeating. |
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| 928. |
And where are you from |
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Answer» Ok by Ok, chalo bye Maharashtra Sorry....... And from where are you |
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| 929. |
Mene chatting padhi thiSo don\'t worry mujhe aisa nhi lagta h |
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Answer» I am from ambala Koi bhi aise hi apna no. Nhi deta h Aap kahq se ho.. Mene apki aur priyanshu ki chatting padhi thi...... Mujhe pata h aapne apna no. Nhi diya Hmm? |
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| 930. |
Pehle aap kisi priyanshu ke sath bhi chat karte the na, me har din padta tha |
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Answer» So, what are your favorite subjects Shayd aapko lag raha hai ki mai priyanshu bhaiya se what\'s app pr chat krti hu , but this is not true mai kabhi bhi apna no. Kisi ko nhi diya But as a brother and sister baat krte thee ham Ha , |
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| 931. |
Ab koi mujhse bhi baat kar lo |
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Answer» Me too I am fine and what above u Kaise ho Hii Hiii |
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| 932. |
8-0.123456789=, this question was reported by someone |
| Answer» I not getting ur question | |
| 933. |
Yaha par maths ke question puchne ate h log Aur ye ashish aur khushi?\u200d♂️?\u200d♂️ |
| Answer» Don\'t take it seriously.......I was just kiding | |
| 934. |
a die is thrown once what is the probability of getting a no. Lying between 2 and 5 |
| Answer» The no. Is 3and4And probability is 2/6=1/3 | |
| 935. |
Draw a line segment ab of length 5.5cm find a point p on it such that ap=2/3pb |
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| 936. |
Ohk,bye gn khushi |
| Answer» Gm khushi | |
| 937. |
Hlw,khushi |
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Answer» Bolo Aachi chal rhi h aur aapki |
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| 938. |
Hlw,shivani |
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Answer» Khusi ,aap kha se ho Ohkk aap aapna name kyu nhi likhi h |
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| 939. |
Factorization x2+4x+6 |
| Answer» I think your question is wrong check the question | |
| 940. |
Example of trigonometric ratios of complementary angle from ncert book |
| Answer» | |
| 941. |
If the roots of quadratic equation (b-c)x2+(c-a)x+(a-b) are equal, prove that 2b=a+c |
| Answer» (b-c)x²+(c-a)x+(a-b)=0Comparing with quadratic equationAx²+Bx+C=0A=(b-c),B=c-a,C=a-bDiscriminate when roots are equalD=B²-4AC=0D=(c-a)²−4(b-c)(a-b)=0D=(c²+a²−2ac)-4(ba-ac-b²+bc)=0D=c²+a²−2ac-4ab+4ac+4b²-4bc=0c²+a²+2ac-4b(a+c)+4b²=0(a+c)²-4b(a+c)+4b²=0[(a+c)-2b]²=0a+c=2b\xa0 | |
| 942. |
How to write a quadratic equation which is having -2 and 1 as the root |
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Answer» X2 + x -2 ={X^2 - (alpha + beta ) x +(alpha×beta ) = x^2 - (-2+1)x + (-2×1)=x^2 + x - 2 X²-2x+1 |
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| 943. |
Real number 1.2 answer |
| Answer» Kiya❓ | |
| 944. |
Solve: 4x^2 - 4ax+ (a^2-b^2) = 0 |
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Answer» But my answer is right Ok. No problem! Sorry j my answer has a mistake.so my answer is wrong 4x²-4ax+(a²-b²) 4x²-4ax+(a+b)(a-b)=0m²-n² =(m+n)(m-n) Splitting the middle term, we get=> 4x² -2(a+b)x-2(a-b)x +(a+b)(a-b)=0=> 2x[2x-(a+b)]-(a-b)[2x-(a+b)]=0=> [2x-(a+b)][2x-(a-b)]=0=> 2x-(a+b)=0 Or 2x-(a-b)=0=> 2x = a+b Or 2x = a-b Then x=a+b/2,x=a-b/2 4x²-2(a+b)x-2(a-b)x+(a²-b²) => 2x{x-(a+b)}-2(a-b){x-(a+b)} => (2x-2a+2b)(x-a-b) => x=a--b or a+b |
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| 945. |
Can anyone tell me which topics are removed from maths syllabus?? |
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Answer» Okay in short form. What do u mean by kk? Ess app par jab tum cbse syllabus par click karoge to app ko mil jayega pdf Kk! Iss app par available hai |
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| 946. |
Mathematics is the father of all subject |
| Answer» Yes | |
| 947. |
What is aperture |
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Answer» Aperture is the portion of the mirror from which the reflection of light actually takes place. Thank you piyush The diameter of a mirror( like concave or convex )is called aperture |
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| 948. |
If h is hcf of 609 and 957 find x and y satisfying 609x plus 957y |
| Answer» Euclid division algorithms 135and225 | |
| 949. |
Even zeros of the polynomial F(x) =(k2+4)xs square |
| Answer» | |
| 950. |
Hi,guys r here someone who like to do friendship with me |
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Answer» He is my bro? U r lavanya then who is sumesh pandit Ya i want hey myself Lavanya ? |
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