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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 9551. |
I want PT 2 question paper of class 10th |
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| 9552. |
A2 + b2 |
| Answer» Ab² | |
| 9553. |
Check whether the following is a equation or not. (x²+1)(x+1)= (x+3)² |
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Answer» X(x²+1)+1(x²+1)=||+X³+X+x²+1=(x+3)²=||As it is=x²+3³+2(x)(3)=|| ""=X²+9+6xX³+X+x²+1==X²+9+6x{x² cancel by x²}__{+1-9=-8}_{x-6x=-5x}Then the left equation will beX³-5x-8=0And degree of equations is highest power of equationsAnd here the highest power is 3 ,so it is cubic equations not quadratic equations No, because xcube -5x -8 |
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| 9554. |
Can you get me term 2 sample papers, please |
| Answer» Please send term 2 sample paper | |
| 9555. |
Find the value(s) of z if z^ 2 + 1 z^ 2 =2,z not equal to 0 |
| Answer» Z²+z²= 2z =\\ 0Z²+z²-2z=0Put z=00²+0²-2(0)=0 | |
| 9556. |
Sum of n term |
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Answer» It is equal to n divided by 2 times the sum of twice the first term – \'a\' and the product of the difference between second and first term-\'d\' also known as common difference, and (n-1), where n is numbers of terms to be added. Sum of n terms of AP = n/2[2a + (n – 1)d] N/2{2a+(n-1)d}=SñSñ= n/2{a+añ} |
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| 9557. |
2x^2+ 2X+6=0 |
| Answer» use quadratic formula | |
| 9558. |
Express each number as a product of its prime number 5005 and 7429 |
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| 9559. |
Work out 3 digit number divisible by 5,11,3,8 ? |
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| 9560. |
3√5x^2+25x-10√5=0 |
| Answer» 3root5x^2+30x-25x-10root5=03x(root5x+10)-5root5(root5x-10) (3x-5root5) (root5x-10)X=5root5/3,10/root5 | |
| 9561. |
Radies =0.35It revolve =450 |
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| 9562. |
If 5*0=0, and 7*0=0 then 5*0=7*0 is not 5=7 |
| Answer» No 5 is not equal to 7 | |
| 9563. |
Unfair means matlab What impact on result |
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| 9564. |
How can I find roots of quadratic equations by quadratic formula? |
| Answer» First Find Discriminant D=b^2-4acThen put the value of D in Given FormulaX= -b plus or minus √D upon 2a | |
| 9565. |
I need chapter 14.1and 2 3 solution |
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| 9566. |
How to solve quadratic equations by complete square |
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| 9567. |
Find the value of 7 sec square B -7 tan square B |
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Answer» 7 7sec*2 - 7tan*2=7(sev*2 -tan*2)=7 7 |
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| 9568. |
Prove that the trangets drawn at the ends of a diameter of a circle are parallel |
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Answer» Ab by ao=bo, oa=ob=Ab oa and ob are perpendicular to tangents so tangents are parallel AB diameterA-o-BOA=OB=ABOA andOB are perpendicular to tangents So tangents are parallel |
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| 9569. |
FIND THE H.C.F OF 120÷168 EUCLID LEMMA |
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Answer» 168/120=1+48. 120/48=2+24.48/24=2+0Hcf is 24. A+B square 168/120=1+48120/48=2+2448/24=2+0Then the HCF is 24Hence proved!!! |
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| 9570. |
Have you any doubt in any question |
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Answer» N0 Nai What is ph |
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| 9571. |
When cbse released term 1 marks class 10 |
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Answer» 14 March After term 2 examination 15 days after term 1 2Sept |
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| 9572. |
Kis kisko kaunsa QUESTION PAPER CODE mila share kare |
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Answer» 030/1/4 03014 very hard 030/1/4 |
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| 9573. |
what was the value of tan (60-30 ° |
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Answer» 1/√3 Cot30 1/root 3 Shivani singh |
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| 9574. |
If i got 10 marks in class 10 term 1 then i will pass or not ? Help |
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Answer» Thanks bhai no It\'s just marks. Term 1 and 2 marks will be added to declare the result. So no worry. Concentrate on Term 2 No No |
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| 9575. |
The perimeter of a sector of radius 5.2 cm is 16.4 cm, the area of the sector is |
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Answer» 15.6 15.6 |
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| 9576. |
All formulas of ratios,square etc and important question of lesson triangle ,of cbse term 1. |
| Answer» You will check out in google . | |
| 9577. |
A line represented by 4x-3y=9 intersects the y axis at |
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Answer» (0,-3) Tere ghand pe intersect hata hai #please lile #?? 0,-3 (0,-3) (0,-3) |
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| 9578. |
What is altitude |
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Answer» Height of traingle Attitude in triangle is like drawing a line from one vertex (vertex mean corner of triangle)of triangle to it\'s opposite side .I think it\'s also called as median of triangle which divides triangle in two equal parts . I think its height of a triangle |
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| 9579. |
cocecutive no of HCF |
| Answer» 1 | |
| 9580. |
The number of revolutions made by a circular wheel of radius 0.7 m in rolling a distance of 176 m is |
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Answer» 40 40 |
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| 9581. |
Tan theeta / sec theeta-1 + tan theeta / sec theeta+1 is equal to |
| Answer» 2 sec theeta | |
| 9582. |
The solution of 7^x+y=343= and 343^x-y=7= is |
| Answer» x=5/3 and y=4/3 | |
| 9583. |
The solution of 7 343 x y += and 343 7 x y -= i |
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Answer» I don\'t know 7 x-y=3437x-y=7^3x-y=37x+y=24017x+y=7^4x=7/2=3.5 and y =0.5x/y=3.5/0.5=7 |
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| 9584. |
What are factors of 8 |
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Answer» 2*3 1,2,4,8 and common factor of 8 is 1 2x2x2 2^2 2×2×2 |
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| 9585. |
How to learn areas related to circle formula easily |
| Answer» Learn from sample paper of Dapeeak the formulas of area related to circle and do the sample paper question | |
| 9586. |
In the given figure the value of x is |
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Answer» question uncomplete Why was Rashid unlucky 118 |
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| 9587. |
If b tan theta is equals to a find the value of cos theta + sin theta by cos theta minus sin theta |
| Answer» B+A/B-A is the answer | |
| 9588. |
The probability expressed as a persrcentage of a occurrence can never be |
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Answer» 0 less than 0 and greater than 1 Probability can never be negative and greater than 1. |
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| 9589. |
Centroid of a triangle |
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Answer» Centroid = (x1+x2+x3whole divide by 3 , y1+y2+y3whole divide by 3) Centroid of a triangle is a intersection point of its medians. |
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| 9590. |
Ch 3 ex 3.5 Q.4 |
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Answer» Go on youtube and search these questions you will get answer Hi |
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| 9591. |
7/9,11/18,5/12,17/36Convert the following unlike fraction into like fraction |
| Answer» Take lcm then solve it and the answer will be 28/36, 22/36, 15/36, 17/36 | |
| 9592. |
Unlike fraction to like fraction |
| Answer» Those pairs/group of fraction have same denominators is called like fraction.ex.1/2,3/2,4/2,5/2.Those pairs of fraction have not same denominator is called unlike fraction. 4/3,5/6,8/7,5/7. | |
| 9593. |
1.√(a+3)²+(1)²=Please give full explanation of your answer.................. |
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Answer» Sin^X+sin^4X=1then cosX+cos^X=1 Sin^X+sin^4X=1,then cosX+cos^X=? |
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| 9594. |
Ch.5 ex 5.3 |
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Answer» Which question Which subject |
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| 9595. |
mid point q. |
| Answer» To find a mid point ? a+b/2 | |
| 9596. |
Find the values of y for which the distance between the points p(2, -3) and Q(10,y) is 10 units. |
| Answer» y = 3, -9 | |
| 9597. |
How to find the radius of circle inscribed inside the right angled triangle... |
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Answer» Even a shorter method ( if you want only the answer and not the procedure ) ; find the shortest side of the right-angled triangle (let it be x). If x is an odd number , the maximum radius will be (x-1)/2 units and if x is an even number , the maximum radius will be (x/2)-1 units . Hope it helps . The way is, first draw the radius on all 3 sides it will be perpendicular to all 3 After that the right angled triangle gets divided into 3 triangles find the area of all three triangles and sum of 3 triangles will be equal to right angle triangle from there you will get an equation and after solving it you will get the radius |
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| 9598. |
867 hcf 225 |
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Answer» Is 3 867 hcf 225 |
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| 9599. |
If root 3 tan square theta minus 3 is equal to zero then theta |
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Answer» ∅= 60⁰ √3 tan theta - 3 = 0 √3tan theta =3Tan theta = 3/√3Tan theta = √3*√3/3Tan theta= √3In tan √3 comes when theta is 60.So theta = 60 |
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| 9600. |
Cos^2x+sec^2x=? |
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Answer» 1 Answer is 1 sin²x+cos²x is a trignometric identity... The answer is 1 1 |
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