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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 10101. |
Check whether 75/455 is terminating or non terminating decimal expansive |
| Answer» Simplify 75/455When u will divide 75/455 = 15/91 you\'ll get this.So deniminatior is 91 And it\'s factors are 91= 7×13 75/455 now, see 455 it contains its prime factors 7 and 13 but not 2 and 5So it\'s an non terminating decimal expansion. | |
| 10102. |
value of sin x equal to 4 by 5 find the value of 10 x 90 - x |
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| 10103. |
If value of sin x equal to 4 by 5 find the value of 10 x 90 - x |
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| 10104. |
Find the quadratic polynomial whose sum and products of zeroes are -2/3 , 3/2 |
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| 10105. |
Factorise - 4x^2-115x+375 |
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| 10106. |
Prove that one of every 3 consecutive positive integers is divisible by 3. |
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| 10107. |
Solve *x4 6i*π€cx |
| Answer» Please ask question with complete information. | |
| 10108. |
Show that one and only one out of n, n+2, n+4 is divisible by 3, where n is any positive integer. |
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Answer» We know that any positive integer is of the form 3q or 3q + 1 or 3q + 2 for some integer q & one and only one of these possibilities can occurCase I : When n = 3qIn this case, we have,n = 3q, which is divisible by 3n = 3q= adding 2 on both sidesn + 2 = 3q + 2n + 2 leaves a remainder 2 when divided by 3Therefore, n + 2 is not divisible by 3n = 3qn + 4 = 3q + 4 = 3(q + 1) + 1n + 4 leaves a remainder 1 when divided by 3n + 4 is not divisible by 3Thus, n is divisible by 3 but n + 2 and n + 4 are not divisible by 3Case II : When n = 3q + 1In this case, we haven = 3q +1n leaves a reaminder 1 when divided by 3n is not divisible by 3n = 3q + 1n + 2 = (3q + 1) + 2 = 3(q + 1)n + 2 is divisible by 3n = 3q + 1n + 4 = 3q + 1 + 4 = 3q + 5 = 3(q + 1) + 2n + 4 leaves a remainder 2 when divided by 3n + 4 is not divisible by 3Thus, n + 2 is divisible by 3 but n and n + 4 are not divisible by 3Case III : When n = 3q + 2In this case, we haven = 3q + 2n leaves remainder 2 when divided by 3n is not divisible by 3n = 3q + 2n + 2 = 3q + 2 + 2 = 3(q + 1) + 1n + 2 leaves remainder 1 when divided by 3n + 2 is not divsible by 3n = 3q + 2n + 4 = 3q + 2 + 4 = 3(q + 2)n + 4 is divisible by 3Thus, n + 4 is divisible by 3 but n and n + 2 are not divisible by 3 . Thanks I HOPE YOU UNDERSTAND? We know that any positive integer is of the form 3q or 3q + 1 or 3q + 2 for some integer q & one and only one of these possibilities can occurCase I :\xa0When n = 3qIn this case, we have,n = 3q, which is divisible by 3n = 3q= adding 2 on both sidesn + 2 = 3q + 2n + 2 leaves a remainder 2 when divided by 3Therefore, n + 2 is not divisible by 3n = 3qn + 4 = 3q + 4 = 3(q + 1) + 1n + 4 leaves a remainder 1 when divided by 3n + 4 is not divisible by 3Thus, n is divisible by 3 but n + 2 and n + 4 are not divisible by 3Case II :\xa0When n = 3q + 1In this case, we haven = 3q +1n leaves a reaminder 1 when divided by 3n is not divisible by 3n = 3q + 1n + 2 = (3q + 1) + 2 = 3(q + 1)n + 2 is divisible by 3n = 3q + 1n + 4 = 3q + 1 + 4 = 3q + 5 = 3(q + 1) + 2n + 4 leaves a remainder 2 when divided by 3n + 4 is not divisible by 3Thus, n + 2 is divisible by 3 but n and n + 4 are not divisible by 3Case III :\xa0When n = 3q + 2In this case, we haven = 3q + 2n leaves remainder 2 when divided by 3n is not divisible by 3n = 3q + 2n + 2 = 3q + 2 + 2 = 3(q + 1) + 1n + 2 leaves remainder 1 when divided by 3n + 2 is not divsible by 3n = 3q + 2n + 4 = 3q + 2 + 4 = 3(q + 2)n + 4 is divisible by 3Thus, n + 4 is divisible by 3 but n and n + 2 are not divisible by 3 .\xa0 |
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| 10109. |
1 +1 |
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Answer» 2 2 2 2 2 |
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| 10110. |
In a∆ ABC , right angle triangle at B ,AB=24cm , BC=7Cm . Determine : sin A ,cosA |
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Answer» Hypotenuse Similarly of cosA also First we will find AC by Pythagoras theorem then put value of sinA that is Perpendicular-------------------Hypotenuse |
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| 10111. |
The hcf of 45 and 105 is 15 find the LCM |
| Answer» HCF * LCM = ab (where a and b are numbers). 15 * LCM = 45 * 105. LCM = 45 * 105 / 15 = 105 * 3 = 315.// | |
| 10112. |
Find the quadratic polynomial whose sum of zeroes and product of zeroes are. √22+1 and 1/√2+1 |
| Answer» Given, s = √22 + 1 and p = 1/√2 + 1 = 1 + √2 / √2. Therefore, p(x) = k (x^2 - sx + p) = k (x^2 - (√22 + 1)x + (1 + √2) / √2). | |
| 10113. |
(3+2 root 5)^2 |
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| 10114. |
Find the HCF of (2²×3³×5²),(3²×5²×7³) and (2×3×5³×7²) |
| Answer» hcf=7350 | |
| 10115. |
What is HCF of pair of Co prime |
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Answer» 1 1 1 1 When two numbers (they may not be prime) do not have any common factor other than 1 between them they are called co-primeAs the definition suggest , the HCF of a co-prime number will always be 1. |
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| 10116. |
7×-2y=9 and 4x+6y=15 |
| Answer» we have to find the value of x and y so by using elimination method7x-2y=9----------------eq1we have to multiply eq1 by 3 to make the variable y same(7x-2y=9)*321x-6y=27-----------eq14x+6y=15------------eq2by elimination method by adding the eq1 and eq221x-6y=274x+6y=15the -6y and +6y get canclledso24x=42x=42/24the value of x is 7/4 putting the value of x in eq24x+6y=154*7/4+6y=154 and 4 get canclled 7+6y=156y=15-76y=8y=8/6 that is 4/3the value of x=7/4the value of y=4/3 | |
| 10117. |
Prove underroot 3+underroot 5 is irrational |
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Answer» Answer to prove se start hai unlock 35 lakh questionsWhat\'s your doubt?10th>Maths>Real Numbers>Revisiting Irrational Numbers>Prove that √(3) + √(5) is...MathsBookmarkProve that 3\u200b + 5\u200b is irrational.EasyshareShareAnswerTo prove : 3\u200b + 5\u200b is irrational.Let us assume it to be a rational number. Rational numbers are the ones that can be expressed in qp\u200b form where p,q are integers and q isn\'t equal to zero.3\u200b + 5\u200b = qp\u200b 3\u200b = qp\u200b − 5\u200b squaring on both sides, 3= q 2 p 2 \u200b −2. 5\u200b ( qp\u200b )+5⇒ q(2 5\u200b p)\u200b =5−3+( q 2 p 2 \u200b ) ⇒ q(2 5\u200b p)\u200b = q 2 2q 2 −p 2 \u200b ⇒ 5\u200b = q 2 2q 2 −p 2 \u200b . 2pq\u200b ⇒ 5\u200b = 2pq(2q 2 −p 2 )\u200b As p and q are integers RHS is also rational.As RHS is rational LHS is also rational i.e 5\u200b is rational.But this contradicts the fact that 5\u200b is irrational.This contradiction arose because of our false assumption.so, 3\u200b + 5\u200b irrational. |
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| 10118. |
Show that n² - 1 is divisible by 8, if \'n\' is a odd positive integer |
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| 10119. |
2x-y=4 |
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Answer» X | 0 | 2 | 4 --------------------------------------Y | -4 | 0 | 4 2x-y=4Let\'s X=3 and Y=2 Putting 3&4 to the eq. =2(3)-2=4=6-2=4=4=4Hence,x=3,y=2 x=3y=42x-y=42*3-4=6 |
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| 10120. |
Prove that n^2-n can be divisible by 2, where n is an odd number ??? |
| Answer» n^2 - n can also be written as n (n - 1) where n is an odd number. So, naturally (n - 1) becomes an even number. Thus, since any number, along with an even number, can give an EVEN product, n^2 - n is also divisible by 2. | |
| 10121. |
In the given figure, if AB ||CD, then |
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Answer» Ch 1 Ex 1.1 1 part 196 and 2978 Please ask question with complete information. |
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| 10122. |
Which stream is best in 11 |
| Answer» All are best...... But u have to think that which stream is comfortable for you to achieve ur goals and what u want to become in future. | |
| 10123. |
if 274 is of the form 5q+4 for an inteer q then find the value of q |
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Answer» Given = 5q+4= 274 => 5q = 274-4 => q = 270/5 => q = 54 Therefore the value of q is 54 274-4/5=270/5=54Thus value of q is 54 Q=54 |
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| 10124. |
Find the HCF of two numbers experimentally based on euclid\'s division lemma (Make a flowchart) |
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| 10125. |
If HCF of 480 and 685 is expressed in the form of 480 x minus 475 find x |
| Answer» The HCF of 480 and 685 is 5 so480x-475=5480x=5+475480x=480x=1the value of x is 1 | |
| 10126. |
Find the ratio of the sum and product of the roots of the equation 3x²+12-13x |
| Answer» The given quadratic equation is ;3x² + 12 - 13x = 0.The given quadratic equation can be rewritten as ; 3x² - 13x + 12 = 0.Now,Comparing the above equation with the general quadratic equation ax² + bx + c = 0,We have;a = 3b = -13c = 12Thus,The ratio of sum and product of the roots of given quadratic equation will be -b/c-b/c = -(-13)/12 = 13/12. | |
| 10127. |
Find the lcm of 1/3 , 5/6 , 5/9 |
| Answer» Lcm:- 18 | |
| 10128. |
√2,1/3 |
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Answer» A Plz type whole question.. |
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| 10129. |
1/(x-1)(x-2)+1/(×-2)(×-3)=2/3 |
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| 10130. |
Is cosA equals to 1/sinA |
| Answer» No cosA = 1/ sec A | |
| 10131. |
The sequence 27,23,18,15,11___ is an AP? true or false |
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Answer» False as a2-a1=-4 and a3-a2=-5 False False the sequence is not an A.P.As 23-27=-4 18-23=-5 15-18=-3 11-15=-4Therefore, common difference is not equal in all cases. Therefore it is not anA. P. |
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| 10132. |
Prove the fundamental theorum of arithmetic. |
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| 10133. |
If one root of the polynomial f(x) =5x2 +13 x + k is reciprocal to other find |
| Answer» P(x) =5x2+13x+kAlpha =1/bitaAlpha×bita=1c/a=1k/5=1Hence, k=5Yours, Krishna, Bihar | |
| 10134. |
.If the product of zeroes of the polynomial p(x)=ax3-6x2+11x-6 is 4, the a= |
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| 10135. |
What is ecliss lema |
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Answer» Euclid lemma is a proven statement which helps to prove another statement. Euclids lima is a proven statement |
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| 10136. |
Is polynomial y^4+ 4y^2+5 have zeroes or not? |
| Answer» Yes | |
| 10137. |
Exercise 1.1 class 10 |
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| 10138. |
what is miscellaneous exercise in cbse class 10 maths (ncert book) |
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| 10139. |
Explain why (7×9×11×13+11×14) is a composite number. |
| Answer» Because it has more than one factors | |
| 10140. |
Find quadratic polynomial whose zeros are 1 and -3 |
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Answer» x²-2x-3 is he polynomial x²-2x-3 |
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| 10141. |
bx+cy= a+bax(1/a-b-1/a+b) +cy(1/b-a-1/b+a)=2a/a+b |
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| 10142. |
4x + py +8=02x + 2y + 2 = 0 |
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| 10143. |
Cos72. |
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| 10144. |
Tan26. |
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| 10145. |
Sin18. |
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| 10146. |
What is the cover drive shot who invntd it |
| Answer» So technically, azhar was the original\xa0inventor\xa0of those wristy effortless\xa0cover drives\xa0which we remember laxman for and he was also one of the most delicate and most alluring batsman India ever got to see. | |
| 10147. |
If 278/2^3m has a terminating decimal expansion and m is a positive integer such that 2 |
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| 10148. |
What is the square root of 44 |
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Answer» The square root of 44 is 6.633 2√11 is the square root of 44 Square root of 44 = 1936 12 |
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| 10149. |
If sum of square of zeros of the quadratic polynomial f(x)=x²-8x+k is 40, find the value of k |
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| 10150. |
How many square meters of one hector |
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Answer» 10000 square metres 10,000 square metres |
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