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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 10301. |
Find the value of p for which one root of the quadratic equation px2 |
| Answer» equation to batao | |
| 10302. |
2x+3y=0 3x+4y=5 |
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Answer» X=15 y= -10 Apna naam maths rakhe ho or bna nhi pate ho |
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| 10303. |
area of an quadrilateral |
| Answer» Which types of quad...? | |
| 10304. |
If sinA+cosA=root3 then prove that tanA+cotA=1 |
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Answer» Lhs or rhs dono ka solution kro Solve it we got 1 Tan=sin/cos cot = cos/sin Sin A . Cos A =1 |
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| 10305. |
What is 3/5 is irrational number |
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Answer» Root 3/5 is irrational no. but 3/5 is rational no. 3/5 is always rational no. No it is rational number |
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| 10306. |
Why is argon bigger than chlorine? |
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Answer» Argon is bigger than chlorine because it have larger molecules than chlorine Because it has more no. of molecules |
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| 10307. |
Sina(90-a)= |
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Answer» Cos a Hm |
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| 10308. |
If tanA=ntanB and sinA=msinB then prove thatcos2A=m2-1/n2-1 |
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| 10309. |
Prove that root 2 is irrational and root 2 square is rational |
| Answer» | |
| 10310. |
Sample question paper 2018 class 10 maths |
| Answer» I have also not have this | |
| 10311. |
Will math ncert sufficient for get good marks in board exam of class 10 |
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Answer» Yes mere hisab we pehle to ncert hi karni chahiye aur phir kuch sample paper agar time hai to Concept is essential Ya |
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| 10312. |
If n is a natural number, then by which number 9 2n - 3 2n is always divisible |
| Answer» | |
| 10313. |
If sin alpha and cos alpha are the roots of the equation ax2+ bx+ c = 0, then find b2. |
| Answer» a2+2ac | |
| 10314. |
If the sum of the roots of the equation x2 -x = lamda(2x-1) is zero, then find lamda |
| Answer» {tex}\\frac{{ - 1}}{2}{/tex} | |
| 10315. |
Is here any mathematician who has guts to answer my question |
| Answer» No | |
| 10316. |
Exam time table |
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Answer» 12 English On 8 computer On 6 march hindi |
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| 10317. |
Find the root of the equation ×2-×-p(p+1) |
| Answer» -p, -(p+1) | |
| 10318. |
The HCF of 45 and 105 is 15 . Write their LCM |
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Answer» 45=15×3105=15×7HCF is 15 because it is common in both LCM=HCF×7×3LCM=15×7×3LCM=315So the LCM is 315 ❤❤❤❤❤ Hcf×lcm=product of numbers15×lcm=45×105Lcm=45×105/15Lcm=45×7Lcm=315 First number × second number = LCM × HCF then find it 315 |
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| 10319. |
(1+cotA-cosecA) (1+tanA+secA)=2 |
| Answer» Hello the answer is too long to type so to solve the question you have to first convert the given ratios into sin and Cos and then open the bracket and you will get the answer | |
| 10320. |
What would be the value of n for n²-1 divisible by 8. |
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Answer» Ty 7 Any odd no. |
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| 10321. |
CosA+SinA-1÷cosA-sinA+1=cosecA+cotA |
| Answer» | |
| 10322. |
find two numbers whose sum is 27 and product is 187 |
| Answer» Let the two numbers be x, 27 - x.According to the questionx (27 - x) =182{tex}\\implies{/tex}27x - x2\xa0-182 = 0{tex}\\implies{/tex}x2 - 27x + 182 = 0{tex}\\implies{/tex}\xa0x2 - 13x -14x + 182 = 0{tex}\\implies{/tex}x (x-13) - 14 (x-13) = 0{tex}\\implies{/tex}(x-13) (x-14) = 0Either x-13 = 0 or x - 14 = 0{tex}\\implies{/tex}x = 13, 14Hence, the required numbers are 13, 14 | |
| 10323. |
If alpha &beta are the roots of axsquare-bx+c=0then calculated alpha and vita |
| Answer» | |
| 10324. |
For what value of k k+9 , 2k-1 and 2k+7 are consecutive terms of an AP?? |
| Answer» {tex}mx - ny = m^2 + n^2{/tex} ...(i){tex}x + y = 2m{/tex} ...(ii)Multiplying equation (ii) by m and subtracting from (i), we get{tex}y = \\frac { n ^ { 2 } - m ^ { 2 } } { - ( m + n ) }{/tex}\xa0= -\xa0{tex}\\frac { ( n - m ) ( n + m ) } { m + n }{/tex}y = m - nPutting value of y in (i), we get{tex}mx - n(m - n) = m^2 + n^2{/tex}{tex}mx - nm + n^2 = m^2 + n^2\xa0{/tex}{tex}mx = m^2 + nm ={/tex}\xa0{tex}\\frac{m(m + n)}{m}{/tex}{tex}x = m + n{/tex} | |
| 10325. |
Prove that the square of any positive integer is the form of 4q or 4q+1 for same integer q |
| Answer» Yrrrr ncert question h ye | |
| 10326. |
What are the constituents of the alloy constantan? |
| Answer» Copper and nickel | |
| 10327. |
Ok next question. What are the constituents of the alloy constantan? |
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Answer» Yes right Nickel and copper Copper and nickel |
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| 10328. |
Ok ready for the next question. What is the other name of calcium hydride |
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Answer» Calcium bihydride maybe I also don\'t know Ok The answer is hydrolith. Sabhi q and ans ko note kar lena. Chemistry is not too good I don\'t know the answer Khu akhe you have to answer very quickly |
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| 10329. |
LCM of 5926 |
| Answer» | |
| 10330. |
10th |
| Answer» | |
| 10331. |
What happened khu akhe . Where is your answer |
| Answer» I was late. Look down | |
| 10332. |
If sec 4A = cosec (A -20),where 4A is an acute angle, find the value of A |
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Answer» since sec(90-theta)=cosec thetasec[90-(A-20)]=sec4Aon comparing 90+20-A=4A110=5AA=22 A= 22 22 |
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| 10333. |
If sn denotes the sum of the first n terms of an A. P., prove that s12=3(s8-s4) |
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Answer» See in oswaal answer sheet 2 question 17 Rs aggarwal |
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| 10334. |
Solve for x and yMx-ny =m2 +n2 x+y =2m |
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Answer» {tex}mx - ny = m^2 + n^2{/tex} ...(i){tex}x + y = 2m{/tex} ...(ii)Multiplying equation (ii) by m and subtracting from (i), we get{tex}y = \\frac { n ^ { 2 } - m ^ { 2 } } { - ( m + n ) }{/tex}\xa0= -\xa0{tex}\\frac { ( n - m ) ( n + m ) } { m + n }{/tex}y = m - nPutting value of y in (i), we get{tex}mx - n(m - n) = m^2 + n^2{/tex}{tex}mx - nm + n^2 = m^2 + n^2\xa0{/tex}{tex}mx = m^2 + nm ={/tex}\xa0{tex}\\frac{m(m + n)}{m}{/tex}{tex}x = m + n{/tex} {tex}mx - ny = m^2 + n^2{/tex} ...(i){tex}x + y = 2m{/tex} ...(ii)Multiplying equation (ii) by m and subtracting from (i), we get{tex}y = \\frac { n ^ { 2 } - m ^ { 2 } } { - ( m + n ) }{/tex}\xa0= -\xa0{tex}\\frac { ( n - m ) ( n + m ) } { m + n }{/tex}y = m - nPutting value of y in (i), we get{tex}mx - n(m - n) = m^2 + n^2{/tex}{tex}mx - nm + n^2 = m^2 + n^2\xa0{/tex}{tex}mx = m^2 + nm ={/tex}\xa0{tex}\\frac{m(m + n)}{m}{/tex}{tex}x = m + n{/tex} |
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| 10335. |
Solve For X And YMx-ny=m2 +n2 X+y=2m |
| Answer» {tex}mx - ny = m^2 + n^2{/tex} ...(i){tex}x + y = 2m{/tex} ...(ii)Multiplying equation (ii) by m and subtracting from (i), we get{tex}y = \\frac { n ^ { 2 } - m ^ { 2 } } { - ( m + n ) }{/tex}\xa0= -\xa0{tex}\\frac { ( n - m ) ( n + m ) } { m + n }{/tex}y = m - nPutting value of y in (i), we get{tex}mx - n(m - n) = m^2 + n^2{/tex}{tex}mx - nm + n^2 = m^2 + n^2\xa0{/tex}{tex}mx = m^2 + nm ={/tex}\xa0{tex}\\frac{m(m + n)}{m}{/tex}{tex}x = m + n{/tex} | |
| 10336. |
Previous question ka molecular structure bana? |
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Answer» -- means double bond CH3 is not coming in second place sry but Maine sahi kiya hai CH3-CH-CH--CH3 CH3 CH3-CH-CH--CH3 CH3 Tripti you can\'t understand answer the above question I will try but 80 percent not possible What Then cl me tomorrow I can make you understand very clearly Ask some other question pls Filhaal nahi Khu akhe structure bana? |
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| 10337. |
What do you understand by efflorescence? |
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Answer» Na2CO3 .10H2O is water of crystalization Wrong shalu Loosing of water molecule from water of crystalization Removal or evaporation of 9 molecules of H20 from Na2C03.10H20 |
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| 10338. |
Look down my question |
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Answer» Whatever but fine Sorry vo to main joking Post office mein joking kar raha tha par bura mat manna Okk Look down Itna majak chalta hai kyu? Acha? The day before yesterday was not anybody at home? |
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| 10339. |
Which sample for maths is nice???????????? |
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Answer» Together with Oswal???????????? Final Exam wala??? |
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| 10340. |
Easy tricks to solve surface volume |
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Answer» L earn formula simple Learn formula and apply |
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| 10341. |
What is copra?, when it was introduced ?? |
| Answer» Consumer Protection Act it was introduced in 1986 | |
| 10342. |
Why was States reorganization commission formed ?? |
| Answer» | |
| 10343. |
Describe jhumming cultivation in one sentence |
| Answer» | |
| 10344. |
Sin30.cos30 |
| Answer» Sin 30 = 1/2 and Cos 30 = √3/2so Sin 30 x Cos 30 = 1/2 x √3/2 = √ 3/4 | |
| 10345. |
2×3+4= |
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Answer» Swaggy apni brainly wali id ek baar chek kar lo mere liye...plzzz 10 |
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| 10346. |
2+3/5 |
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Answer» Hello I know 2.6 Hiiii Yes I am Hiiii is anyone online |
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| 10347. |
chapter 12 ex 12.1 question no 3 |
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Answer» the area of gold region =22/7×21/2×21/2=346.5 The width of the gold one is 10.5 then the width of another will increase by 10.5 ! It\'s big Wait |
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| 10348. |
The sides of a triangle are in the ratio 3:5:6find the all threee angles of te triangle |
| Answer» Let sides be 3x,5x,6x A+B+C=180°3x+5x+6x=180°14x=180°X=180/14 X=25.23x=3*25.2=75.65x=5*25.2=1266x=6*25.2=151.2 | |
| 10349. |
Hey I have one ques that maths ka paper saare NCERT mai se aayega? |
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Answer» Koi meko bhi btana? Yess 90%bt 10%NCERT based aayega |
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| 10350. |
Let d be the hcf of 24 and 36 .find two numbers a and d such that d =24a + 36b. |
| Answer» Let d be the HCF of 24 and 36.24 = 23{tex}\\times{/tex}336 = 22{tex}\\times{/tex}32HCF = 22{tex}\\times{/tex}3 = 12{tex}\\Rightarrow{/tex}{tex}d = 12{/tex}Now {tex}d = 24a + 36b{/tex}{tex}12 = 24a + 36b{/tex}When\xa0{tex} a = -1{/tex} and {tex}b = 1{/tex}, we get12 = 24{tex}\\times{/tex}(-1) + 36{tex}\\times{/tex}(1)= -24 + 3612 = 12So, a = -1 , b = 1 satisfy the equation d = 24a + 36b{tex}\\therefore{/tex} One possible value of a and b is -1 and 1. | |