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10351.

Anyone having blue print of marking schreme of maths...

Answer» I hv
That is given in sample paper
Lol..marking scheme
10352.

Middle term of A.p

Answer» For even = (n/2) (n/2+1)
N+1/2
Middle term =n+18/2
Formula to find middle term (n+1/2) th term
Hum nikalte hai middle term
A.P to de
10353.

Middle term of ap

Answer»
10354.

Which chapter

Answer»
10355.

SinA=24÷25 then find value of cos A

Answer» Koi bat nhi....bhai...hota hai
Ohhh.....sorry..bhai
Mr..lovely ka
Bhai....aapka...wrong hai
CosA=7÷25
Cos A = 7/24
Cos A = 7/24
7/25
Use pytha. Formulae
10356.

The decimal expansion of 3\\2power 15×5power 10is

Answer» Answer
10357.

What are fossils

Answer» Fossils are dead remains of past animals
Fossils are the remain part of any living organism,or their impressions,that lived in distant past, preserved in the rocks
10358.

If cos(Alfa+bita),then find the value of sin(Alfa+bita)

Answer»
10359.

Ncert ch 5 qes 10

Answer» Give answers
10360.

What is CSA of hemisphere

Answer» 2πrsquare
2πr²
10361.

If secA=x+1/4x,prove that secA+tanA =2xor 1/2x

Answer»
10362.

If the mth term of an ap is 1/n and nth term is 1/m then show that (m*n) th term is 1

Answer» Let a and d be the first term and common difference respectively of the given A.P. Thenan = a + (n - 1)d{tex}\\frac { 1 } { n } ={/tex}\xa0mth term\xa0{tex}\\Rightarrow \\frac { 1 } { n } {/tex}= a + ( m - 1 ) d\xa0...(i){tex}\\frac { 1 } { m }{/tex}= nth term{tex}\\Rightarrow \\frac { 1 } { m } {/tex}= a + ( n - 1 ) d\xa0...(ii)On subtracting equation (ii) from equation (i), we get{tex}\\frac { 1 } { n } - \\frac { 1 } { m } = {/tex} [a+ (m-1) d] -[ a+ (n -1)d]= a + md - d - a - nd + d{tex}= ( m - n ) d{/tex}{tex} \\Rightarrow \\frac { m - n } { m n } = ( m - n ) d {/tex}{tex}\\Rightarrow d = \\frac { 1 } { m n }{/tex}Putting d = {tex}\\frac { 1 } { m n }{/tex}\xa0in equation (i), we get{tex}\\frac { 1 } { n } = a + \\frac { ( m - 1 ) } { m n } {/tex}{tex}\\Rightarrow \\frac { 1 } { n } = a + \\frac { 1 } { n } - \\frac { 1 } { m n } {/tex}{tex}\\Rightarrow a = \\frac { 1 } { m n }{/tex}{tex}\\therefore{/tex}\xa0(mn)th term = a + (mn - 1) d=\xa0{tex}\\frac { 1 } { m n } + ( m n - 1 ) \\frac { 1 } { m n } {/tex}{tex}\\left[ \\because a = \\frac { 1 } { m n } = d \\right]{/tex}= {tex}\\frac { 1 } { m n } + \\frac { mn } { m n } - \\frac { 1 } { m n }{/tex}= 1
10363.

6877*6674

Answer» ????
10364.

In what ratio does the point (-4,6) divide the line segment joing the point A(-6,10) andB(3,-8)?

Answer» M1:M2= 2:7.
2:7
10365.

Who doesn\'t like trigonometric proofs?

Answer» I love it
I love it
I don\'t like
I like
I like
10366.

Assalamualaikum koi hai ?????

Answer»
10367.

Hye. ??

Answer» zyan143
Meko nhi mili...
tu hai kon superman. ????
Harsh...apni brainly id batana plss
Meko 4
ajj chocolate mili kise ko??
Hi
Hello
Hi
10368.

What is natural no.

Answer» No. Start from 1 and used for counting
10369.

Sorry { ishi }...??. Messege nhi jaa raha hai ...

Answer»
10370.

2-(5)

Answer» -3
-3
10371.

Who is TAKLU in history?

Answer» gandhi the gangstar
ha
Angreegi varnmala ka 21 va letter
u u u uuuu
?????
What is u
u
To ro kyo rha h
Gandhi?
Sabhi news dog app download kre
10372.

If tsa of cylinder =462 csa=154 find volume?

Answer» Let r cm be the radius of the base and h cm be the height of the cylinder. Then, total surface area of cylinder {tex}= 2\\pi r(r + h){/tex}Curved surface area of cylinder {tex}= 2\\pi rh{/tex}We have,Curved surface area = {tex}\\frac{1}{3}{/tex}(Total surface area) = {tex}\\frac{1}{3}{/tex}{tex}\\times{/tex}\xa0{tex}462 cm^2 = 154 cm^2\xa0{/tex}{tex}\\Rightarrow{/tex}{tex}2\\pi rh = 154{/tex}Also, {tex}2\\pi rh + 2\\pi r^2 = 462 {/tex}{tex}\\Rightarrow{/tex}154 + 2{tex}\\pi{/tex}{tex}r^2 = 462{/tex}{tex}\\Rightarrow{/tex}2{tex}\\pi{/tex}{tex}r^2 = 462 - 154 = 308 cm^2{/tex}2 {tex}\\times{/tex}{tex}\\frac{22}{7}{/tex}{tex}\\times{/tex}{tex}r^2 = 308\xa0{/tex}{tex}\\Rightarrow{/tex}r2 ={tex}\\frac{308 \\times 7}{2 \\times22}{/tex} = 72{tex}\\Rightarrow{/tex}\xa0{tex}r = 7 cm{/tex}Again 2{tex}\\pi{/tex}rh = 154 {tex}\\Rightarrow{/tex}\xa02{tex}\\times{/tex}{tex}\\frac{22}{7}{/tex}{tex}\\times{/tex}7{tex}\\times{/tex}{tex}h = 154{/tex}{tex}\\Rightarrow{/tex}\xa0h = {tex}\\frac{154}{2 \\times22}{/tex}={tex}\\frac{7}{2}{/tex}cmVolume of the cylinder = {tex}\\pi{/tex}r2h = {tex}\\frac{22}{7}{/tex}{tex}\\times{/tex}\xa07 {tex}\\times{/tex}\xa07 {tex}\\times{/tex}\xa0{tex}\\frac{7}{2}{/tex}\xa0{tex}= 539 cm^3{/tex}
10373.

Prove that area theorem

Answer» See in ncert
10374.

Write the form in which every odd integer can be written taking t as variable

Answer»
10375.

33-30=?????????

Answer» Follow bodmas
33=30 hence prove?????????????
How..??
No its write answer is 30
It\'s may be something...bocoz you tells wrong answer yourself....??
3. ????
10376.

Any body have maths ncert question?

Answer»
10377.

Derive volume,tsa,csa of frustum of cone?

Answer»
10378.

Prove Pythagoras theoram

Answer» Refer to ncert
See in NCERT
10379.

Old members kha gye. ??Yha toh sab new new log hi lag rhe hai?? ???

Answer» Hlo????
I guess they r studing....;-)
10380.

Hye Guys. ????

Answer» Hello learners..?
Hello,?
Hii
Hey
10381.

Important question isme jo diya hua h kya usse hi question aayegaa?

Answer» aisa nahi kar sakte
Maybe if possible learn kar lo na kya jata hai....?
May..be but learn kar lo...very important..
Don\'t know
10382.

How we revision for maths for final exam from which book

Answer» if you read NCERT only then you can obviously get more than 80 but if you read it carefully if you solve all problems carefully
Only NCERT
10383.

Find values of k such that xsq.+Kx+64 and xsq-8x+k have equal roots

Answer» 16
-8
10384.

Prove 1=2

Answer» Yes devil pls tell me how it is proved
Yes plz
May i tell you
Then give u and ur friends 100 marks
Made by me and my friends
I can
????
In 3 steps
10385.

Kkk

Answer» , ?????????
???
10386.

Bye u all....?

Answer» Byeeeeee✋✋☺?
Okk...bye
Are yar main to subah se hi hun. ...now it\'s study time. ...meeting you at 3:30am
Bye
Bhai...itne jaldi
Bye???
10387.

If I not gain 70%to80%than

Answer» Always ??
Why you think negative before exam aur aise to padne k liye itni books h kis kis me se padogi Isley first NCERT then other ok.. And it totally depend upon ur hard work and self confidence... ????
?
10388.

Solve : root x +y=7 and root y+ x=11 find the value of x and y

Answer» No
No minus nhi plus hoga
No minus nhi plus hai
Dono sides squaring kro...Equations will be...x-y=49x+y=121
Sorry i can\'t
?????????
Solve it
10389.

Anyone remember me???

Answer» Hmmmmm
Yaaa
yes
10390.

what is (a+b)3 = ?

Answer» 3a+3b
a³+b³+3a²b+3ab²
10391.

Shalupurohit

Answer» Or shalurRajpurohit
Id on brainy meri
Kya h ye
On brainly
10392.

How to change sinA into other trigonometric ratios

Answer» Tips batao
Value vala nahi hai sinA ko in terms of other trigonometric ratios mein change karna hai
Refer to ncert
Sin A ki value kya hai?
10393.

Without using Trigonometric Table evaluate, tan7.tan23.tan60.tan67.tan83+cot54/tan36+sin20.sec70-2.

Answer» 2
Wrong question sec 68 nhi hoga
10394.

What is the value of 3tan2 26degree - 3 cosec2 64 degree

Answer» 3
10395.

Cos²(45°+∅)+cos²(45°-∅)__________________________=1Tan(60°+∅) tan(30°-∅)

Answer»
10396.

Cos4-sin4

Answer»
10397.

marking scheme of math cbse

Answer» What
10398.

If cosA- sinA =1 then prove that cosA +sinA =-+1

Answer»
10399.

Triangle chapter theoms

Answer» Prefer videos of this app
10400.

What is tringle

Answer» Don\'t joke here