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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1001. |
1/2 x3-5x2-11x-3 |
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Answer» 24.5 Don\'t know Goggle ka lo |
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| 1002. |
2 cube each of volume 64cm3 are joined end to end . Find the surface area of the resulting cuboid |
| Answer» Given, volume of each cube is 64 cm³..........⇒s³=64..........⇒s=∛64..... ...⇒s=4 cm............When two cubes are joined , ............the length of the resulting cuboid(l) = side + side = 4+4 = 8 cm..........its breadth(b) = side = 4cm...........And its height(h) = side = 4cm..........Total surface area of a cuboid = 2(lb+bh+hl)...........⇒TSA=2[(8)(4)+(4)(4)+(4)(8)].......⇒TSA=2(32+16+32).........⇒TSA = 2(80)........⇒TSA = 160 cm²..........∴ The surface area of the resulting cuboid is 160 cm.......... | |
| 1003. |
Number of zeroes in the product of 5×10*40*50*55*65*125*80 by (2nth×5) method |
| Answer» the answer is 9 zeros.as the product is 89375000000000hope it helps uu. ....... | |
| 1004. |
If A=[2,3,4,5]then write the relation R on A where R=[(a, b) :a+b=6] |
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Answer» Is this is a question of class 10th ? This question is correctly wrong Hm Good question. ? |
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| 1005. |
2¢4{4•√} |
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| 1006. |
In tha wold SCHOOL what is tha percentage of tha latter O? |
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Answer» Shayd aapko mile huaa hai O = 33.33% The percent of letter O in the word of school is 33.33% .... the percent of letter O.....Hence O is 33.33% of word SCHOOL. Aapka question repeat kro What ? |
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| 1007. |
What is the syllabus of CBSE board 2020-21 |
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Answer» You can get the syllabus in Google .... And one thing 30 % of syllabus is reduced.... 30 persent reduce hoga syllabus go and upload from Google if u have internet connection |
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| 1008. |
Not meet h axis meet only y axis |
| Answer» Can you repeat your question properly ..... | |
| 1009. |
11 th term of ap -3,-1/2,2........ Is ( Tanmy aapke question ka answer) |
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Answer» I am using only WhatsApp In insta can you follow me ?? dramebaaz_cool__girl Yes Hey do you use any social media app?? An=a+(n-1)d........n=11 ........... a=-3 ......... d=5/2........hence 11th term =-3+(11-1)*5/2 =22....( hope this answer helped...)? |
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| 1010. |
1/a+1/b+1/x= |
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Answer» QUESTION:\xa0Solve; 1/a+b+x=1/a+1/b+1/xAnswer:1/(a+b+x)=1/a + 1/b + 1/x1/(a+b+x) -1/x = 1/a + 1/bx-(a+b+x)/x(a+b+x) = a+b/ ab-1(a+b) /x(a+b+x) = a+b/ ab-1(a+b)/(a+b) = x(a+b+x)/ab-1=x(a+b+x) / ab-ab= (a+b)x + x2so, x2\xa0+ (a+b)x +ab = 0now, A = 1, B=(a+b) C= ab..so, D = B2\xa0- 4AC =(a+b)2\xa0- 4ab = (a-b)2so, x = (-B + root D)/2A and (-B-root D)/2A = -a-b+a-b /2*1 and -a-b-a+b /2*1 = -2b/1 and -2a /1so,x = -2b or -2a . Don\'t know |
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| 1011. |
11th term of ap: -3,-1/2,2...,is |
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Answer» ? Hoooo....... Asude Nahi mahit Sang patkan |
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| 1012. |
123*4 |
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Answer» 492 502 Hiiii ? Prachi ?p.a.p What ?? |
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| 1013. |
What comes firstEgg or Hen |
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Answer» I am also agreed to the answer that egg comes first Egg.because a dinosaur lays the egg and from that egg one chick comes out... According to one scientific theory egg |
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| 1014. |
Evaluate 2sin^2 30° tan 60°-3cos^2 60°sec^2 30° |
| Answer» sin 30°=1/2=>sin^2 30°=1/4cos 45°=1/root 2=>cos^2 45°=1/2tan 60°=root 3=>tan ^2 60°=3So, 2 sin ^2 30°-3cos^2 45° +tan^2 60°=>2(1/4)-3(1/2)+3=>1/2-3/2+3=>(1-3+6)/2=>4/2=>2 | |
| 1015. |
x+2y=-12x-3y=12By cross multiplication |
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Answer» Prachi tamarkar The given equations are:\xa0x + 2y + 1 = 0 …….(i)\xa02x – 3y – 12 = 0 …….(ii) |
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| 1016. |
Prime factorisation of 2s raise to 2-(1+2 root 2)s+root 2 |
| Answer» I love you | |
| 1017. |
poda narri |
| Answer» What ?????? | |
| 1018. |
Find the 7th term A.P 3 ,7 ,10 |
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Answer» Common difference equal nhii hai 22 d1\xa0= 7 - 3 = 4And d2\xa0= 10 - 7 = 33 ,7 ,10 is not an A.P. आप क्या मुझे बबताये गई कि मै common difference क्या लु इसमे common difference अलग-अलग hai |
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| 1019. |
Prove that 1\\√2is irrational |
| Answer» To prove 1/√2 is irrational.............Let us assume that\xa0√2 is irrational\xa0..........1/√2 = p/q\xa0(where p and q are co prime)........q/p =\xa0√2.........q =\xa0√2p.......squaring both sides.........q² = 2p² .....................(1)By theorem\xa0......q is divisible by 2.......∴ q = 2c ( where c is an integer).......\xa0putting the value of q in equitation 1.......2p² = q² = 2c² =4c² ......p² =4c² /2 = 2c².....p²/2 = c²\xa0.....by theorem p is also divisible by 2.....But p and q are coprime........This is a contradiction which has arisen due to our wrong assumption....∴1/√2 is irrational | |
| 1020. |
Construct a quadrilateral ABCD in which AB equal to 3.8 cm equal to 4.5 cm |
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| 1021. |
Class 10Ex.12.2Q.12 |
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Answer» Check the weather following are quadratic equations 4x+8=0 The given details are,.......Percentage Rohit deposited in bank = 12% of total income.....Rohit deposited money during the year 1997 = Rs 1440......So, let us consider the total income of Rohit as Rs x......By calculating,......(x/100) × 12 = 1440....By cross multiplying......x = (1440×100)/22......= 12000.......∴ Rohit’s total income for the year 1997 is Rs 12000....... |
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| 1022. |
By elimination method solve8x -6=5y5y -3x=-7 |
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Answer» Now put the value of x in any of the 2 equations and then you will get the value of y 1) 8x-5y=6 and 2) 3x-5y=7 Now, subtract 2) from 1) You will get 5x=-1 so, x=-1/5 Elimination method apply karo and answer nikalo |
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| 1023. |
Who many ls are there in Exam |
| Answer» Don\'t know | |
| 1024. |
What\'s fundamental theoram of artimetic |
| Answer» This theorem also says that the prime factorisation of a natural number is unique, except for the order of its factors. For example 20 can be expressed as 2×2×5. Using this theorem the LCM and HCF of the given pair of positive integers can be calculated. | |
| 1025. |
In a triangle ABC angla a is 90 degree , side AB is 5m and side AC is 9m then find side BC ? |
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Answer» Root 106 we know that by phythagorar thm. we get,BC^2 = AC^2 + AB^2BC^2 = (9)^2 + (5)^2BC^2= 81 + 25BC^2 = 106BC = ROOT 106 AB=5m,AC=9mBy Pythagoras theorem, BC²=AB²+AC²=)BC=√5²+9²=)BC=√25+81=)BC=√106=)BC=10.3m |
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| 1026. |
The length of the diagonals of a rhombus are 16cm and 12cm find the length of side of rhombus |
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Answer» 7.6 m 10 cm We know that, the diagonals of a rhombus are perpendicular bisector of each other.Given, AC = 16 cm and BD = 12 cm [let]∴ AO = 8cm, SO = 6cmand ∠AOB = 90°In right angled ∠AOB, Answer is 10 cm 10 cm |
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| 1027. |
1 million = how many lakhs? |
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Answer» ?? 10,000,00 10 lakhs |
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| 1028. |
use Euclid\'s division algorithm to find the hcf of 441,567,693 |
| Answer» Euclid division lemma:-a=bq+rFirst find the HCF of 693 and 567,693=567(1)+126567=126(4)+63126=63(2)+0HCF of 693 and 567 is 63.Now find the HCF of 63 and 441,441=63(7)+0The HCF of 63 and 441 is 63.Therefore, the HCF of 441,567 and 693 is 63. | |
| 1029. |
What is the difference between code 30/1/1 and 30/2/1 in board paper? |
| Answer» | |
| 1030. |
Use Euclid division Lemma to show that cube of any positive integer is form of 99 + 19 + 8 |
| Answer» Q:\xa0Use Euclid\'s division lemma to show that the cube of any positive integer is of the form\xa09m,9m+1\xa0or\xa09m+8Let\xa0x\xa0be any positive integer. Then, it is of the form 3q\xa0or, 3q\xa0+ 1 or, 3q\xa0+ 2.So, we have the following cases :\xa0Case I :\xa0When\xa0x\xa0= 3q.then,\xa0x3\xa0= (3q)3\xa0= 27q3\xa0= 9 (3q3) = 9m, where\xa0m\xa0= 3q3.\xa0Case II :\xa0When\xa0x\xa0= 3q\xa0+ 1then,\xa0x3\xa0= (3q\xa0+ 1)3= 27q3\xa0+ 27q2\xa0+ 9q\xa0+ 1= 9\xa0q\xa0(3q2\xa0+ 3q\xa0+ 1) + 1= 9m\xa0+ 1, where\xa0m\xa0=\xa0q\xa0(3q2\xa0+ 3q\xa0+ 1)\xa0Case III.\xa0When\xa0x\xa0= 3q\xa0+ 2then,\xa0x3\xa0= (3q\xa0+ 2)3= 27\xa0q3\xa0+ 54q2\xa0+ 36q\xa0+ 8= 9q\xa0(3q2\xa0+ 6q\xa0+ 4) + 8= 9\xa0m\xa0+ 8, where\xa0m\xa0=\xa0q\xa0(3q2\xa0+ 6q\xa0+ 4)Hence,\xa0x3\xa0is either of the form 9\xa0m\xa0or 9\xa0m\xa0+ 1 or, 9\xa0m\xa0+ 8. | |
| 1031. |
8+2rut2 |
| Answer» Finding the whole expression value the answer is 10.828 | |
| 1032. |
An9-5n |
| Answer» Question :\xa0Find the series if\xa0an\u200b=9−5nGivenan\u200b=9−5na1\u200b=9−5=4a2\u200b=9−10=−1a3\u200b=9−15=−6∴\xa0The series is\xa04,−1,−6,−11.... | |
| 1033. |
The sum of 2 numbers ia 1000 and difference between their square is 256000.find the numbera |
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Answer» Let’s assume the two numbers be x and y. And also assume that x is greater than or equal to y.\xa0So as per the question, we can write the sum of the two numbers as\xa0x + y = 1000 ……….. (i)\xa0Again it’s given that, the difference between the squares of the two numbers, thus writing it\xa0x2\xa0– y2\xa0= 256000⇒ (x + y) (x – y) = 256000⇒ 1000(x - y) = 256000\xa0⇒ x – y = 256000/1000\xa0⇒ x – y = 256 ………….. (ii)\xa0By solving (i) and (ii), we can find the two numbers\xa0On adding the equations (i) and (ii), we get;\xa0(x + y) + (x - y) = 1000 + 256\xa0⇒ x + y + x – y =1256\xa0⇒ 2x = 1256\xa0⇒ x = 1256/ 2\xa0⇒ x = 628\xa0Now, putting the value of x in equation (i), we get\xa0628 + y =1000\xa0⇒ y = 1000 – 628\xa0⇒ y = 372\xa0Hence, the two required numbers are 628 and 372. I love you |
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| 1034. |
x+12+ y−13= 8 ;x−13+ y+12= 9 |
| Answer» I love you | |
| 1035. |
Natural no. |
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Answer» All the counting numbers are called natural number. It os denoted by \'N\'Examples-1,2,3,4,..... Counting number are called natural number . These numbers are denoi by N=(1.2.3....) |
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| 1036. |
What are important question |
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Answer» Ok Which can come in exam and imp for lec In which chapter |
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| 1037. |
Hii sir i have doubt in math ex.3.5 (3 ) qq sir plzz u can explain it |
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Answer» Okkk it is available in aap I love you???????????? Plzz explain it sir |
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| 1038. |
I am wait to understand theorem 1.3 |
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| 1039. |
The pair of equation X=2 and Y=-3 HasNo solutionOne solutionInfinite many solutionTwo solution |
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| 1040. |
For any positive integer n prove that (n2-n) is divisible by 6 |
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| 1041. |
Solution of Rs Aggarwal exercise 4B |
| Answer» Pls tell the question Actually i am not having Rs Aggarwal | |
| 1042. |
May i know the chaptes of 1st term from NCERT Maths book. Please help me |
| Answer» Dont know yrr..sry.. | |
| 1043. |
10+10 |
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Answer» 20 20 1st class ka question h yrr ye Bhi nhi aata kya 20 20.. |
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| 1044. |
is minus roots are exists |
| Answer» Exists but those ar called complex number not real number | |
| 1045. |
1 upone 2 is rational no. |
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Answer» Yes................ Yes this is a rational no. Yes....it is a rational number because it of the p by q and p=1 is an integer and q=2 is a natural number |
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| 1046. |
Who is missing school ?????\u200d??\u200d??\u200d??\u200d? |
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Answer» It is a What is Trigonometry |
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| 1047. |
9 pe power4 minus 9 pe power3 =? |
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Answer» 9^4-9^3=9^4-3(using identity a^m-a^n=a^m-n)=9^1=9? 9^4–9^3= ? 1032 |
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| 1048. |
Find all zeroes of x⁴+4x²-2x²-12x+9 if 2 of its zeroes are 1and 1 |
| Answer» | |
| 1049. |
Good morning friends ??????????? |
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Answer» Good morning...have a good day to all..?? Fresh means ???? (sry) Good morning ?? Very fresh good morning ?? |
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| 1050. |
Solve the following pair of linear equations by substitution method : 3x + y -11=0 , x - y -1=0 |
| Answer» 3x + y -11=0........... (i)x - y -1=0x = y + 1 ............ (ii)Substitute (ii) in (i), we get3(y+ 1) + y - 11 =03y + 3 + y - 11 =04y - 8 =04y = 8y = 8/2 =4Put y = 4 in (ii) , we getx = y + 1x= 5\xa0 | |