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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 10801. |
Find the sum of first 100 positive integer |
| Answer» Sn\xa0=\xa0{tex}\\frac { n } { 2 } [ a + l ]{/tex}{tex}\\Rightarrow{/tex}\xa0S100\xa0=\xa0{tex}\\frac { 1000 } { 2 }{/tex}[{tex}1 + 100] = 50050{/tex} | |
| 10802. |
prove that 0/0=2 |
| Answer» | |
| 10803. |
A +B A_B |
| Answer» | |
| 10804. |
(a+b) (a-b)= |
| Answer» a^2-b^2 i.e. a square- b square | |
| 10805. |
If m=4,n=8 then find (1),2m+n |
| Answer» 16 | |
| 10806. |
30a°+6b°=5c° |
| Answer» | |
| 10807. |
(a+b)x + (a-b)y =a + b(a-b)x + (a+b) =a + b |
| Answer» | |
| 10808. |
Sin30° Sin²60°+3Cos60° tan45°=2Sec²45°-cosec²90° ? Prove that |
| Answer» | |
| 10809. |
2+2÷2 |
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Answer» 3 2+(2÷2)=3 3 A/c to Bodmas firstly divide then add 3 1 3 3 |
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| 10810. |
Show that the quadrilateral whose vertices are (2,-1),(3,4),(-2,3),(-3,-2) is a rhombus |
| Answer» Let A(2, -1), B(3, 4), C(-2, 3) and D(-3, -2){tex}A B = \\sqrt { ( 3 - 2 ) ^ { 2 } + ( 4 + 1 ) ^ { 2 } } = \\sqrt { ( 1 ) ^ { 2 } + ( 5 ) ^ { 2 } } = \\sqrt { 1 + 25 } = \\sqrt { 26 }{/tex}{tex}B C = \\sqrt { ( - 2 - 3 ) ^ { 2 } + ( 3 - 4 ) ^ { 2 } } = \\sqrt { ( - 5 ) ^ { 2 } + ( - 1 ) ^ { 2 } } = \\sqrt { 25 + 1 } = \\sqrt { 26 }{/tex}{tex}C D = \\sqrt { ( - 3 + 2 ) ^ { 2 } + ( - 2 - 3 ) ^ { 2 } } = \\sqrt { ( - 1 ) ^ { 2 } + ( - 5 ) ^ { 2 } } = \\sqrt { 1 + 25 } = \\sqrt { 26 }{/tex}{tex}A D = \\sqrt { ( - 3 - 2 ) ^ { 2 } + ( - 2 + 1 ) ^ { 2 } } = \\sqrt { ( - 5 ) ^ { 2 } + ( - 1 ) ^ { 2 } } = \\sqrt { 25 + 1 } = \\sqrt { 26 }{/tex}Since AB = BC = CD = AD{tex}\\therefore{/tex}ABCD is a rhombus. | |
| 10811. |
LCM of 24 69 15o |
| Answer» 3oo | |
| 10812. |
Is it pepare to me board |
| Answer» | |
| 10813. |
What is appolonias theorum? |
| Answer» Apollonius\' theorem is a theorem relating the length of a median of a triangle to the lengths of its side. It states that "the sum of the squares of any two sides of any triangle equals twice the square on half the third side, together with twice the square on the median bisecting the third side".Specifically, in any triangle ABC, if AD is a median, then{tex} {\\displaystyle |AB|^{2}+|AC|^{2}=2(|AD|^{2}+|BD|^{2}).}{/tex}\xa0 | |
| 10814. |
Find the value of x -(6x-2)-(8x+4)=(2x+7)-(6x+2) |
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Answer» When you opn all the bracket you will get6x-2-8x-4=2x+7-6x-2-2x-6= -4x + 5-2x+4x=5+62x=11x=11/2 When you open all the bracket , you will find that 6x -2 -8x - 4 = 2x +7 - 6x +2. Then after solving this the answer is 11/2 I think that the question is wrong |
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| 10815. |
52 deck of cards has how many reds ace face kings blacks or other please |
| Answer» 52 deck of cards will have26 red cards4 aces12 face cards4 kings26 blacks | |
| 10816. |
X2+y2=61,x3-y3=91 |
| Answer» I want solution | |
| 10817. |
What is the probability of two friends have different birthday |
| Answer» 364 up0n 365 | |
| 10818. |
Tan(a+b)=Root3and and tan(a-b)=1/root3 find a and b |
| Answer» Tan(a+b)=60degree (since tan root3=60degree)Tan(a-b) =30degree (since tan 1/root3=30degree ) Now, a+b=60. --1a-b=30. --2 Using elimination method We get a=30 degree and b=15degree | |
| 10819. |
Qudt |
| Answer» | |
| 10820. |
M=tanA/tanB and N=sinA/sinB prove that m×m-1/n×n-1=cosA×cosA |
| Answer» | |
| 10821. |
3x-y=40 and x-2y=50 solve it by cross-multiplication |
| Answer» 8 | |
| 10822. |
Hcf 780,890 |
| Answer» 890= 780×1+110780= 110×7+10110=10×11+0*HCF=10 | |
| 10823. |
How to get good marks in maths? |
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Answer» Hard work ,more practice of solving problems By learning the formulas ! |
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| 10824. |
Squre of numbers up to 900 |
| Answer» | |
| 10825. |
Can you give me a trick for trigonometry |
| Answer» Prove:CotA -CosA/CotA + CosA=CosecA - 1/CosecA+1 | |
| 10826. |
Sin2A+cos2A=tan2A |
| Answer» | |
| 10827. |
(a+b)x-2by |
| Answer» | |
| 10828. |
²58896804+588 |
| Answer» | |
| 10829. |
Kay math Hindi me nhi ha |
| Answer» | |
| 10830. |
How to perform elimination method |
| Answer» | |
| 10831. |
A circle is inscribed in a triangle PQR with PQ=10cm,QR=8cm,and PR=12cm,find length of QM,RN andPL. |
| Answer» QM=3cm,RN=5cm PL=7cm | |
| 10832. |
How many polynomial will have ther zeroes as-2and5. |
| Answer» | |
| 10833. |
Evaluate: sin 62°/cos 28°- sec 42°/cosec 48° |
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Answer» =sin62°/sin62°- sec42°/sec42°=1-1=O Ans:-. O |
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| 10834. |
Prove that root 3 is an irrational number |
| Answer» Ncert ka example hi bhai khud dekh le | |
| 10835. |
When will we get new sample papers |
| Answer» | |
| 10836. |
Sin2Q + cos2Q = |
| Answer» 1 | |
| 10837. |
Find the missing no. 4,13,31,58______ |
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Answer» The answer is 94 because :--- The difference between 4 and 13 is 9. Then the difference between 13 and 31 is 18 . Then the difference between 31 and 58 is 27. As you can see the difference is a multiple of 9. So, the difference between the 58 and the required number will be 36. After adding 36 to 58, we get the number 94 94 |
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| 10838. |
Is there any problem which includes all the triangle theorem |
| Answer» No | |
| 10839. |
Sum of first n terms of an a.p.is 2nsquare +5n then find its n term |
| Answer» | |
| 10840. |
Difference between math and mathematics |
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Answer» Both are same veer g Same h bahi |
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| 10841. |
Prove that 9*underroot8 is an irrational |
| Answer» | |
| 10842. |
Prove that ,√5 is irrational |
| Answer» | |
| 10843. |
Cot equal to 15/8 then evalute (2+2sinthita)(1-sinthita)/(1+sinthita)(2-2costhita) |
| Answer» | |
| 10844. |
In figure OAB ~OCD. If AB = 8 cm, BO = 6. 4 cm , OC = 3. 5 cm and CD = 5cm, find the OA and DO |
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| 10845. |
Find the zeros of 3xsq-3under root2+1 |
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| 10846. |
When will new pattern of sample paper come |
| Answer» | |
| 10847. |
Find value of theata sin -cos |
| Answer» Tan theata | |
| 10848. |
Formula arthamatic mean |
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Answer» Arthmatic is the series of n numbers in which the difference between the two consecutive numbers is always equal ?????????????? x = fixi/fi. Adding sigma is compulsory A(n)=a+(n-1)d |
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| 10849. |
4.5.6-7.67 |
| Answer» | |
| 10850. |
Find the largest number which divides 969 and 2059 gives the remainder 9 and 11 respectively |
| Answer» 9 | |