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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11001. |
a²+a²=a²+a² is given a=1Prove that 1=2 |
| Answer» Both sides are equal .So we can take LHS and RHS as b .☺.\'. A=b .a squared =ab a squared - b squared = ab squared - b sqaured . (a-b) (a+b) = b (a-b).a+b = b .B+b =b 2b = b .Hence .... 2=1 proved .. | |
| 11002. |
Euclid\'s division lemma |
| Answer» a= bq+r =0 | |
| 11003. |
1+cot2/(1+cosec) = cosec |
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| 11004. |
FIND THE ROOT OF THE FOLLOWING EQUSTION: X+1/X=3,X=0 |
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| 11005. |
guide r d shrma |
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| 11006. |
The sum of a number and its reciprocal is 10/3.Find the number. |
| Answer» let the no. is\xa0{tex}x{/tex}reciprocal of\xa0{tex}x is \\frac1x{/tex}A.T.Q.{tex}x + \\frac1x=\\frac{10}3{/tex}{tex}\\implies{(x^2+1)\\over x}={10 \\over 3}{/tex}{tex}\\implies 3x^2+3=10x{/tex}{tex}\\implies 3x^2-10x+3=0{/tex}{tex}\\implies 3x^2-9x-x+3=0{/tex}{tex}\\implies 3x(x-3)-1(x-3)=0{/tex}{tex}\\implies (x-3)(3x-1)=0{/tex}{tex}\\implies x=3 \\;or\\;{1\\over3}{/tex}\xa0 | |
| 11007. |
Sec x =(y+1)/4y then prove that sec x +tan x = 2y or 1/2y |
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| 11008. |
Find the 25th term of the A.P. -5, -5/2, 0, 5/2 |
| Answer» The given Arithmetic progression is\xa0{tex} - 5 , \\frac { - 5 } { 2 } , 0 , \\frac { 5 } { 2 } ,{/tex}.....Its first term a = -5 and common difference d =\xa0{tex}\\left( \\frac { 5 } { 2 } - 0 \\right) = \\frac { 5 } { 2 }.{/tex}Therefore,\xa0a = -5 and\xa0{tex}d = \\frac { 5 } { 2 }.{/tex}{tex}\\Rightarrow{/tex}\xa0T25 = a + (25-1)d{tex}= a + 24 d \\\\= ( - 5 ) + \\left( 24 \\times \\frac { 5 } { 2 } \\right)\\\\ = - 5 + 60 = 55.{/tex}Hence, 25th term = 55. | |
| 11009. |
How to learn formula in esay way |
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Answer» By solving many questions related to that formula. By learning about their valencies |
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| 11010. |
Exact definition of real numbers |
| Answer» combination of rational and irrational number is called real number | |
| 11011. |
rs aggarwal 10( E) 62 no. solution please help me friends |
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| 11012. |
√2×2= |
| Answer» 2√2 | |
| 11013. |
12+14 |
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Answer» 26. 26 Bchdyfhxhfjcvcj hdlwhvwgxgwbnhztnaf zjq 4th zcbge evfv |
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| 11014. |
If sin(Q+34)=cosQ and Q+34 is an acute angle then Q=? |
| Answer» sin(Q+34) = cosQSin(Q+34 = sin(90-Q) Q +34 = 90-Q 2Q = 90-34 2Q = 56 Q = 56/2 Q= 28 | |
| 11015. |
SinO+cosO |
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Answer» How it\'s possible Sin 0 + Cos 0\xa0= 0 +1 = 1 |
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| 11016. |
If sin a =3/5, find cos a |
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Answer» Sin a= 3/5=p/h and b=✓h×h-p×p =✓25-9=4 So, cos a= b/h =4/5 {tex}sin \\ a =\xa0{3\\over 5}{/tex}we know,\xa0{tex}sin ^2\\theta + cos^2\\theta = 1 {/tex}So,\xa0{tex}cos \\ a = \\sqrt {1-sin^2a}{/tex}{tex}cos \\ a = \\sqrt {1- ({3\\over 5})^2}{/tex}{tex}=> cos \\ a = \\sqrt {1- {9\\over 25}}{/tex}{tex}=> cos \\ a = \\sqrt {16\\over 25}{/tex}{tex}=> cos \\ a = {4\\over 5}{/tex} Sin a =3/5 P/H Cos a = B/H =H(SQUARE) =B(SQUARE) +P(SQUARE) =5(SQUARE)=B(SQUARE) +3(SQUARE) =25=B(SQUARE) +9=25-9= 16 B(SQUARE)B=4 COS a =b/h = 4/5. |
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| 11017. |
The fourth root of 89 - 28√10 |
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| 11018. |
The roots of the equation |
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| 11019. |
Which term of A. P 21,42,63 ------ is 120 |
| Answer» Tn = a +(n-1)d120 = 21+ (n-1)21 120 -21 = (n-1)2199÷21 = (n-1)4.7 =(n-1)5 = n-1n = 5+1n = 6 | |
| 11020. |
Plz give me all formula s of coordinate geometry |
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| 11021. |
calculate the hcf of 3cube×5and3square×5square |
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| 11022. |
B |
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| 11023. |
Prove that root three is irrational |
| Answer» Use contradict method for proving | |
| 11024. |
FX = 2 X square + 7 x + 12 |
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| 11025. |
Which book should I practise for maths class10 |
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Answer» For maths refer to 3 books:TextbookRd sharma bookMaths exemplar problems book Ncert and rs aggarwal. After that see new type of questions in rd sharma |
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| 11026. |
Find roots abx^2-(a+b)^2 (x-1) |
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| 11027. |
Quadratic equation |
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| 11028. |
Area of cuboid |
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Answer» The total suface area (TSA) of the cuboid is the sum of AREAS\xa0of its 6 faces and is given byTSA = 2(LB+BH+HL)Please remember surface area is the total area of all the faces of a 3D shape 2(lb+bh+lh) |
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| 11029. |
What is leema |
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| 11030. |
Find the value of Tan 15 using the formula Tan2 Q = 2 Tan Q /1-tan^2Q |
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| 11031. |
Solve the quadratic eqñ2x²+ax-a² |
| Answer» 2x2+ax-a2=02x2+2ax-ax - a2=02x(x+a) - a(x+a)=0(x+a) (x-a)=0x= - a or x = a | |
| 11032. |
√3x²-8x+4√3 solve by factorisation method |
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| 11033. |
X^2+16x+85 factories solve |
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| 11034. |
What is determinant |
| Answer» Is this discriminant? | |
| 11035. |
SinQ./1+cosQ +1+cosQ/sinQ. =2cosecQ |
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| 11036. |
ex. 8.4 ncert solutions in easy form |
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| 11037. |
Sample paper of class 10 new |
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| 11038. |
If ax²+bx+c is quadratic polynomial and zeroes of the polynomial are α&β. Find the value of. α³+β³? |
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| 11039. |
If i ask the que from rd sharna may i get the answeres |
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| 11040. |
Cards,probability |
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| 11041. |
Find the value of x,y if the distances of the point (x,y) from (-3,0) as well as from (3,0) are 4 |
| Answer» We have P(x, y), Q(-3, 0) and R(3, 0){tex}P Q = \\sqrt { ( x + 3 ) ^ { 2 } + ( y - 0 ) ^ { 2 } }{/tex}{tex}\\Rightarrow \\quad 4 = \\sqrt { x ^ { 2 } + 9 + 6 x + y ^ { 2 } }{/tex}Squaring both sides{tex}\\Rightarrow \\quad ( 4 ) ^ { 2 } = \\left( \\sqrt { x ^ { 2 } + 9 + 6 x + y ^ { 2 } } \\right) ^ { 2 }{/tex}{tex}\\Rightarrow{/tex}\xa016 = x2 + 9 + 6x + y2{tex}\\Rightarrow{/tex}x2 + y2 = 16 - 9 - 6x{tex}\\Rightarrow{/tex}x2 + y2 = 7 - 6x ...(i){tex}P R = \\sqrt { ( x - 3 ) ^ { 2 } + ( y - 0 ) ^ { 2 } }{/tex}\xa0{tex}\\Rightarrow{/tex}{tex}4 = \\sqrt { x ^ { 2 } + 9 - 6 x + y ^ { 2 } }{/tex}Squaring both sides{tex}( 4 ) ^ { 2 } = \\left( \\sqrt { x ^ { 2 } + 9 - 6 x + y ^ { 2 } } \\right) ^ { 2 }{/tex}{tex}\\Rightarrow{/tex}16 = x2 + 9 - 6x + y2{tex}\\Rightarrow{/tex}x2 + y2 - 16 - 9 + 6x ...(ii)Equating (i) and (ii)7 - 6x = 7 + 6x{tex}\\Rightarrow{/tex}7 - 7 = 6x + 6x{tex}\\Rightarrow{/tex}0 = 12x{tex}\\Rightarrow{/tex}x = 0Substituting the values of x = 0 in (ii)x2 + y2 = 7 + 6x0 + y2 = 7 + 6\xa0{tex}\\times{/tex}0y2\xa0= 7y =\xa0{tex}\\pm \\sqrt { 7 }{/tex} | |
| 11042. |
Prove that sin theta_cos theta+1÷sin theta+cos theta_1=cos theta÷1_sin theta |
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| 11043. |
If product of zeroes of the polynomial kx^2+41x+42 is7 then find the zeroes of the |
| Answer» Prodct=c/aSo, c/a=7c=42a=k7=42/kk=6 | |
| 11044. |
How many terms are in A.P.18,15.5,13....-4? |
| Answer» 9 | |
| 11045. |
If btan thita=a then again thita +bcos thita÷asin thita-bcos thita= what |
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| 11046. |
Solve the system of equation- bx/a_ay/b+a+b=0 |
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| 11047. |
How can i score well in maths |
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| 11048. |
Which book is best for reading |
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Answer» S.chand for science and R.D Sharma for maths and for exam preparation oswaal is the best RD Sharma and exam idea |
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| 11049. |
What do u mean by trignometry? |
| Answer» TRI means three:Gino means corner or sides:Metry means measurement so in one word measurement of triangles | |
| 11050. |
Cos |
| Answer» Adjacent by hypothesis | |