InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1101. |
9m, 9m+1,9m+8 |
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| 1102. |
What is coding ?dekho yeh question coput. Ka hai par usko koi padata nahi iss liye math pe ????? |
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Answer» Coding is the process of using programming laguage to get a computer to behave how you want it to. Mujhe com. Ache se aati h Mast waise humko halka halka ata hai ?? |
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| 1103. |
Solve the following pair of equations:1)4/x+3y =8;6/x-4y=-5 |
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| 1104. |
If x is less than y and y is greater than z into 2 relation |
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| 1105. |
What is the definition of |
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Answer» Please write your question clearly.....? ????? |
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| 1106. |
Find the value of P for which the numbers 2P-1 ,3P+1, 11, are in AP. Hence find the number |
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Answer» FORMULA :If the numbers a, b and c are in AP, thenb - a = c - b=> 2b = a + cSOLUTION :The given three numbers (2p - 1), (3p + 1) and 11 are in AP.Then,2(3p + 1) = (2p - 1) + 11=> 6p + 2 = 2p - 1 + 11=> 6p + 2 = 2p + 10=> 6p - 2p = 10 - 2=> 4p = 8=> p = 8/4=> p = 2So, the value of p is 2.Then, the given numbers be(2×2 - 1), (3×2 + 1) and 11i.e., 3, 7 and 11.So, we get an Arithmetic progression 3, 7, 11. P=2 3,7,11?? |
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| 1107. |
In a root of the equation ×2+bx+c=o is gour times the other, then prove that 4b2=25c |
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| 1108. |
Write a quadratic polynomials , the sum a\'d protect of zeroes are 3and -2 respectively |
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Answer» Alpha+beta= 3Alpha*beta= -2 (given)Quad poly= x^2- (alpha+beta)x+(alpha*beta)=x^2- 3x -2 Let alpha (A)=3 Bita (B)=-2Formula=x²-(A+B)x+AB =X²-(3-2)x+3×(-2) =X²-(3x-2x)-6 =X²-x-6 Solved__ |
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| 1109. |
Find a quadractic polynomials whose zeroes are root 3+1and root 3-1 |
| Answer» X²-(A+B)x+ABX²-{(√3+1)+(√3-1)}x+(√3+1)(√3-1)X²-(2+√2)x+2Solved | |
| 1110. |
find a quadratic polynomials whose zeroes are 2/3 and -7/3 |
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Answer» 3x^2-2x-7 Inme likha nhi jata mobile me? Science k puch |
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| 1111. |
solved paper from cbse class 10th chapter 1,2,3,4,5 |
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| 1112. |
6a2-3-7a |
| Answer» 6a²+2a-9a-3 => 2a(3a+1)-3(3a+1) => (3a+1)(2a-3) => a=-1/3 or 3/2 | |
| 1113. |
√10/√2-√3+√20-10√3 |
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| 1114. |
Anyone have 2020 class 10 board exam questions paper maths basic |
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| 1115. |
8+8 |
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Answer» 16 16plus korne se or 88plus ko hata do 16 16 16 |
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| 1116. |
Please aap koi cbse ka 2020 ke mid term ka syllabus bata do |
| Answer» Subject please? | |
| 1117. |
Find the value of 3Sin2 20® - 2Tan2 45® + 2Sin2 70® |
| Answer» 3sin²20°-2tan²45°+2sin²70°=3sin²20°-2×(tan45°)²+2{sin(90°×1)-20°}²=3sin²20°-2×(1)²+2cos²20°=3sin²20°+ 2cos²20° | |
| 1118. |
By substitution method 1. x+y=14, x-y=4 |
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Answer» x+y=14----------------- (1)x-y=4----------------(2)From 2 x=4+y Substituting value of x in equation 14+y+y=144+2y=142y=14-42y=10y=10/2y=5As x+y=14 x+5=14x=14-5x= 9x=9y=4 x+y=14 ......... (i)x-y=4 .......... (ii)Adding (i) and (ii)2x = 18x = 18/2 = 9Put x = 9 in (i)9 + y = 14y = 14 - 9y = 5 |
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| 1119. |
Write the condition to be satisfied by q so that a rational number p/q has a terminating expression. |
| Answer» Q is of the form 2 raised to n multiplied by 5 raise to m and m and n are non negative | |
| 1120. |
Lockdown kaisa chal raha hai friends |
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Answer» Mera toh bahaut krab....what about you☺️ Nhi saare frnds ki yaad aa rhi h.. Mt poocho ... aapka kaisa chal rha h |
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| 1121. |
Prove that 1+root2 is irrational[detailed answer and correct answer] |
| Answer» See in books of mathematics | |
| 1122. |
Solve the following pair of linear equationspx+qy=p-qqx-py=p+q |
| Answer» Please answer | |
| 1123. |
prove that the 0/0=2 |
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Answer» Bro 0/0 is infinity, not 2 So, it is not possible to prove that........Question is not valid solution from LHS let (100-100)/(100-100) = ( 10^2-10^2)/10(10-10) = ( 10+10)(10-10)/10(10-10). {a^2-b^2=(a+b) (a-b )} = 20/10 = 2 RHS prove |
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| 1124. |
prove that sin^[email\xa0protected]+cos^[email\xa0protected] =1 |
| Answer» solution= from LHS = sin^[email\xa0protected]+cos^[email\xa0protected] = (p/h)^2+(b/h)^2 = (p/h×p/h)+(b/h×b/h) = p^2/h^2+b^2/h^2 = p^2+b^2/h^2 = h^2/h^ =1 RHS prove | |
| 1125. |
prove that pythagorus theorem i |
| Answer» H2 = P2 + B2 | |
| 1126. |
What is the rationale number |
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Answer» Number which can be written in the form of p/q where p and q are integers and q does not equal to 0. Any number that can be written in p/q form or in a fractional form is called a rational number |
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| 1127. |
Find quadratic equation, if o and q are roots of the equation x^2-px+q=0 when p=1 and q=-2 |
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| 1128. |
X= -b+√b^2-4ac/2a |
| Answer» This is the quadratic formula to find the value of x. | |
| 1129. |
Check whether,6n can end with the digit 0 for any natural number n. |
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Answer» No, because first of all u can write 6n =2×3. you know that the digit can be possible end of zero that condition is necessary = (2×5). U can see clearly here this is not that co dition form solution: no 6^0=1 6^1=6 6^2=36 6^3=216 |
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| 1130. |
(1+cot²theta)sin²theta |
| Answer» ( 1+cot ² @ = cosec ²@ ) sin ² @ (Cosec ² @ = 1/sin ²@ ) sin ²@ = 1 is your answer | |
| 1131. |
For every integer m every even integer is of the form? |
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Answer» 2m For some integer m, every even integer is of the form. Solution : We know that, even integers are 2,4,6… So, it can be written in the form of 2m. |
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| 1132. |
If 112=q×6+r ,then the possible value of r are: ? |
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Answer» Option (b) They have asked the possibilitys of the value r right. Not value of r and q.If u need options:-a)0,1,2,3.b)0,1,2,3,4,5.c)2,3,5.d)1,2,3. q=19 ,r=2 Since, b=6 :. r=5 r=8 |
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| 1133. |
Hi gm friends |
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Answer» Hi gud morning ?? Good morning nisha? Good morning? Good morning nisha....☺️ Very fresh good morning ? nisha |
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| 1134. |
Decimal expansion of (32/30) |
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Answer» Non terminating but repeating It is a non terminating and repeating decimal |
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| 1135. |
Sum of the areas of two square |
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| 1136. |
Distance formula in co-ordinate geometry |
| Answer» √(x2–x1)²+(y2–y1)=AB | |
| 1137. |
2x+3y=7(a-b)x+(a+b)y=3a+b-2 |
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| 1138. |
whad do yau mean by euclid divsion leema |
| Answer» For a pair of given positive integers ‘a’ and ‘b’, there exist unique integers ‘q’ and ‘r’ such thata=bq+r where\xa00≤r | |
| 1139. |
find two consecutive positive integers,sum of whose squares is 365 |
| Answer» let the no. be x and x+1 then we have x²+(x+1)²=365\xa02x²+2x-364=0x²+x-182=0x²+14x-13x-182=0(x+14)(x-13)=0That gives x=13 Avoiding negative valueone number is 13 and other one 14.\xa0 | |
| 1140. |
Prove that 5 + √3 is an irrational number |
| Answer» Let us assume that\xa05\xa0+√3 is rational.Let ,\xa05 +√3 = r , where "r" is rational5 + r =\xa0√3Here,LHS is purely rational.But,on the other hand ,RHS is irrational.This leads to a contradiction.Hence,5+√3 is irrational\xa0.\xa0 | |
| 1141. |
3x-5y-4=0 and 9x=2y+7 |
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Answer» 3x-5y=4---------(1)9x-2y=7---------(2)from Equation (2) we get,9x-2y=7 9x=7+2yx=7+2y/9putting the value of x in equation (1)3x-5y=43×(7+2y/9)-5y=47+2y/3-5y=4 7+2y-15y =4________ 3 7-13y=. 4/1______ 3cross multiplication7-13y=12-13y=12-7-13y=513y =-5y=-5/13putting the value of y in eqution (3)x =7+2y/9x=[7+2×(-5/13)]×1/9x=[7-10/13]×1/9x=[91-10/13] ×1/9x=81/13×1/9x=9/13hence x=9/13and y-5/13 3X - 5Y = 4----------(1)9X - 2Y = 7-------------(2)From EQUATION (1) we get,3X - 5Y = 43X = 4+5YX = 4+5Y/3 -------------(3)Putting the value of X in equation (2)9X - 2Y = 79 × (4+5Y/3) - 2Y = 73(4+5Y) - 2Y = 712 + 15Y - 2Y = 713Y = 7 -1213Y = -5Y = -5/13Putting the value of X in equation (3)X = 4+5Y/3 => 3 + 5 × -5/13 = 3 - 25/13 /3X = 39 - 25/13/3 = 14/13/3 => 14/13 × 1/3 => 14/9\xa0 y=5/17 and x=43/51 |
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| 1142. |
Sets chapter |
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| 1143. |
うぁた石フォrムーアオフむlちpぃかちおn |
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Answer» Not able to understand.. Unable to understand this language........????? What is this ??? のおね |
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| 1144. |
When cbse realese new slaybuss?for 2021 10th |
| Answer» After 3 july | |
| 1145. |
If the zeroes of the polynomial xcube -3xsquare +x-1 are s/t , s and st , then the value of s is |
| Answer» the required value of a is 1 and that of b is ±√2. | |
| 1146. |
18,15 1/2,13,..,. ,-47 find the numbers of terms in each of the following APS |
| Answer» here a=18 l=-47 d=2 1/2 l= a+[n-1]dnow find n | |
| 1147. |
Which numbers lying between 1 and 100? |
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| 1148. |
How many times management did give incentive to Sundaram |
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| 1149. |
Trigonometry chapter |
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Answer» Available in this app ans |
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| 1150. |
Find the zeroes of x²-x-2 |
| Answer» x²-2x+x-2x(x-2)1(x-2)(x-2)(x+1)x-2=0x=2x+1=0x=(-1) | |