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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11801. |
Dareviation of area of segment |
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| 11802. |
find the value of k so that they have equal to 2 X square + kx + 3 equal to zero |
| Answer» 2x2 + kx +3=0We know that quadratic equation has two equal roots only when the value of discriminant is equal to zero.Comparing equation 2x 2 +kx +3=0 with general quadratic equation ax2 + bx + c =0, we get a = 2, b = k and c = 3Discriminant = b2 − 4ac = k2 - 4(2)(3) = k2 -24Putting discriminant equal to zerok2 - 24 = 0 ⇒ k2 = 24{tex}\\Rightarrow k = \\pm \\sqrt { 24 } = \\pm 2 \\sqrt { 6 } \\Rightarrow k = 2 \\sqrt { 6 } , - 2 \\sqrt { 6 }{/tex} | |
| 11803. |
Cos2theta plus tan2theta - 1 upon sin2theat equal to tan2theat |
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| 11804. |
Which are the important questions of polynomial ? |
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| 11805. |
What is the hcf of 098876 |
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| 11806. |
Question no. 14 of exercise 6.3 of ncert book |
| Answer» Check NCERT solutions here:\xa0https://mycbseguide.com/ncert-solutions.html | |
| 11807. |
In which time I study math and how to make it strong that I should get good marks |
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Answer» You should study whenever you like.From my point of view it should be SUNDAY.The whole sunday must be given to maths You should do maths always Mainly do math in morning with peaceful |
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| 11808. |
We take R.H.S in trigonometry to prove L.H.S , yes or not |
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Answer» No it is not correct.First we have to solve L.H.S till we get the R.H.S Yes we can proved. |
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| 11809. |
x3-7x-170 |
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| 11810. |
Abc is a triangle in which ad is a median then find the value of x |
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| 11811. |
Centre |
| Answer» Centre is\xa0the point that is equally distant from every point on the circumference of a circle or sphere | |
| 11812. |
Determine the conditions of the root of an equation ax^2+bx+c is differ by 2 |
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| 11813. |
Syllabus for sa a 1 |
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Answer» Ch 1 to 10 Chapter 1,2,3,4,5,6,10,14,7 |
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| 11814. |
How do squre all number find |
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| 11815. |
How do lern trigonometry formolaus |
| Answer» LAL/KKA where L=Perpandicular,A=Base,k=Hypotenyies. sine=L/K. Where= perpandicular/hypotenyies | |
| 11816. |
X square - 3 x minus 10 equals to zero |
| Answer» x2-3x-10=0x2-5x+2x-10=0x(x-5)+2(x-5)=0(x+2) (x-5)=0either x+2=0, x=-2or x-5=0,x=5 | |
| 11817. |
What is the formula of sum of zeros |
| Answer» sum of zeros= -b/a | |
| 11818. |
What is the quadratic equation |
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Answer» An equation of the form axsquare+ bx + c =0where is a,b,c are real numbers and a not equal to zero is called a quadratic equation in X In equation highlest exponent on variable is 2 this is equation called quadratic equation |
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| 11819. |
Polynomial |
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| 11820. |
Can the number 6n, being a natural number, end with the digit 5? Give reason. |
| Answer» No because its factors are 2n and 3n | |
| 11821. |
Exam idea questions chapter trigonometry |
| Answer» Tan2A/tan2A-1 when added with cosec2A/sec2A-cosec2A will be 1/1-2cot2A | |
| 11822. |
799 between 8567 |
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| 11823. |
Write an equation where sum of roots is 5 and product of the roots is -6. |
| Answer» For writing Quadratic equation formula is as follow{tex}x^2-(sum \\ of\\ the\\ roots) +(product\\ of\\ the\\ roots){/tex}hence, equation is\xa0{tex}x^2-5x-6{/tex}. | |
| 11824. |
Quardic equation me question read ker ke kase equation banaye |
| Answer» Phle que. Ko read krne ke bd samjo wo que. Kya bolana cha rha h or uske liye thoda sense bhi lagao.... | |
| 11825. |
(Cosec+cot) =m and cosec-cot =n,show that men=1 |
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Answer» (CosecA+cotA) =m and (cosecA-cotA) =nIn question given to prove men=1 that is wrongHere Actual\xa0{tex}m\\times n=1{/tex}proof:{tex}m\\times n{/tex}{tex}\\implies (CosecA+cotA) (cosecA-cotA) {/tex}{tex}\\implies (cosec^2A-cot^2A) =1{/tex} ({tex}because\\ cosec^2A =1+cot^2A{/tex})\xa0 Coordinates\xa0are distances or angles, represented by numbers, that uniquely identify points on surfaces of two dimensions (2D) or in space of three dimensions\xa0Coordinates is also used in graph to show value of X and Y axis. |
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| 11826. |
Prove that; sin-cos+2/sin+cos-1=1/(sec-tan) |
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| 11827. |
Question. 7 of chapter 7.l |
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| 11828. |
If sin A equal cos A then find the value of 2 tan A plus cos square A |
| Answer» {tex}SinA=CosA{/tex}(given){tex}\\implies{SinA\\over CosA}=1{/tex}{tex}\\implies TanA=1{/tex}but\xa0{tex}TanA={perpendicular\\over Base}{/tex}so perpendicular=1and Base=1Hypotaneous={tex}\\sqrt {1^2+1^2} =\\sqrt 2{/tex}we required value of\xa0{tex}2TanA+Cos^2A{/tex}{tex}\\implies 2\\times 1+{1\\over \\sqrt2}{/tex}{tex}\\implies { {2\\sqrt 2+1}\\over \\sqrt 2}{/tex}by rationalization{tex}\\implies {{4+\\sqrt 2}\\over2}{/tex} | |
| 11829. |
In triangleabc angle b is equal to 90 and angle acb is equal to 30 find length of ac bc |
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| 11830. |
Sa1 syllabus |
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| 11831. |
It is compulsory to complete previous 10 years question paper |
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| 11832. |
the value of tan5*tan10*tan15*tan20*...*tan85 |
| Answer» 1 | |
| 11833. |
sin(90-0) tan(90-0)÷sec(90-0)cos=cos |
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| 11834. |
Why are you not provide maths exercise |
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| 11835. |
What is trigometry |
| Answer» trigonometry is a branch of mathematics which deals with the measurement of angle &side of a triangle. The word trigonometry is derived from three Greek word trio means three, gonna means angle,metron means measure. Trigonometry is the study of relationship between the side &angle of a triangle. | |
| 11836. |
Tricks to learn Trigonometry |
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| 11837. |
(x+1)(x+2)(x+3)(x+4)-8=0 |
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| 11838. |
If 2^0=1. Then why 0^0 not equal to 1 |
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| 11839. |
2√16×4 |
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Answer» Root 16 is equal to 4 . The 2,4 and 4 are in multiplication . Therefore ans. Is 32 32 32 |
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| 11840. |
Subautusion method |
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| 11841. |
दिघात सूत्र |
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| 11842. |
Arithmetic proportion |
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| 11843. |
Divide the no. 50 in this way that the difference will be one |
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| 11844. |
Sec+tan +1÷tan-sec+1=cos÷1-sin |
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| 11845. |
What is the LCM of 22 |
| Answer» LCM of 22 is 2 × 11.Ok | |
| 11846. |
Is 68 a term of the A.P. 7 ,10 ,13 ,....................? |
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Answer» Use formula of nth term=a+(n-1) d68=7+(n-1) 361/3+1=nhere we look n is fractional but n can\'t be fractional so 68 is not a term of above series No |
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| 11847. |
1+1= |
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Answer» 2 2 2 2 |
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| 11848. |
Rs agrawal |
| Answer» Rs contain all the ncert solution in their example | |
| 11849. |
O is the centre of the circle,PQ is a tangent to the circle at A . If |
| Answer» Join OA.\xa0clearly, OA {tex}\\perp{/tex}\xa0PAQ.{tex}\\therefore{/tex}\xa0{tex}\\angle{/tex}OAP = 90°{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}1 + 58° = 90°{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}1 = 90° - 58° = 32°In {tex}\\triangle{/tex}BOA,OA = OB. [radius of circle]\xa0Now,\xa0{tex}\\angle{/tex}PAB={tex}\\angle {/tex}ARB={tex}58^\\circ{/tex}[alternate\xa0angles are equal]{tex}\\angle{/tex}ABQ = 32° [as AO=OB,angles opposite to them must be equal]{tex}\\angle{/tex}PAB + {tex}\\angle{/tex}BAQ = 180°{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}BAQ = 180° - 58°= 122°In {tex}\\triangle{/tex}ABQ,{tex}\\angle{/tex}ABQ + {tex}\\angle{/tex}BAQ + {tex}\\angle{/tex}AQB = 180°\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}{tex}AQB = 180° - 122° - 32° = 26°{/tex} | |
| 11850. |
Which term of AP . 121, 117 ,113, ....... is its first negative term? |
| Answer» Given: 121, 117, 113, .......Here a = 121, d = 117 - 121 = 4Now, an = a + (n - 1)d= 121 + (n - 1) (-4) = 121 - 4n + 4 = 125 - 4nFor the first negative term, an < 0{tex} \\Rightarrow 125 - 4n < 0 \\Rightarrow 125 < 4n \\Rightarrow \\frac{{125}}{4} < n{/tex}{tex} \\Rightarrow 31\\frac{1}{4} < n{/tex}n is an integer and {tex}n > 31\\frac{1}{4}{/tex}.Hence, the first negative term is 32nd term | |