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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 12751. |
Hsgggghh |
| Answer» Hhihml | |
| 12752. |
Bhaiyo pass hone wlae ch bata do |
| Answer» 3 ,4,6,8,14,15 | |
| 12753. |
2×9 |
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Answer» Oohh teetly itna to sab ko pate hai LOL 18 u don\'t know it 8096523 |
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| 12754. |
Given that OA=3cm, OB=4cm angleAOB=90°. AC=12cm&BC=13cm prove that angleCAB=90° . |
| Answer» Find AB using Pythagoras theorem, AB = 5cm, in triangle ABC, AC = 12, BC = 13, AB = 5 cm, BC is longest side, verify Sqr (AB) + Sqr (AC) = Sqr (BC), it proves triangle ABC is right angle triangle and angle opposite to BC is 90 , that is angle CAB = 90 | |
| 12755. |
Ch =11 exercise 11.2,question no.6...how to draw BD perpendicular from B toAC???plz tell me .... |
| Answer» | |
| 12756. |
Can anyone tell me how to draw a perpendicular line from an angle???? Plzzz help me |
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Answer» Take more than half from the angle and draw an arc from both the sides and join it *say Plzz art me |
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| 12757. |
Nszvkhxcb |
| Answer» | |
| 12758. |
Find the probability of getting 53 Friday in a leap year |
| Answer» 2/7 | |
| 12759. |
Math all chapter formula |
| Answer» LOL | |
| 12760. |
Find the quadratic polynomial whose two zero are /2+3 and/2-3 ? |
| Answer» x²-6x+5 | |
| 12761. |
find the quadratic polynomial whose zeroesvvvvv are 2 and -6 |
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Answer» X^2+4x-12 K(x-2)(x+6)=0, simplify and represent in std form.. K can take any value.. That means there are infinite quadratic equations having zeros 2 and -6 |
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| 12762. |
In fig 15.82 find the area of shaded region |
| Answer» 126 | |
| 12763. |
preperation done? |
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Answer» Hlo priyanshi No |
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| 12764. |
What is formula of buoyancy |
| Answer» {tex}F _ { b } = \\rho \\mathrm { gV } = \\rho \\mathrm { gh } \\mathrm { A }{/tex}Fb\xa0= buoyant force of a liquid acting on an object (N)ρ\xa0= density of the liquid(kg/m3)g\xa0= gravitational acceleration(9.80 m/s2)V\xa0= volume of liquid displaced (m3\xa0or liters, where 1 m3\xa0= 1000 L)h\xa0= height of water displaced by a floating object(m)A\xa0= surface area of a floating object(m2) | |
| 12765. |
Formulaa of( a+b)3 |
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Answer» Formula is wrong a^3+b^3+3a^2b+3ab^2 |
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| 12766. |
What is the probability of ENCYCLOPEDIA |
| Answer» O probability Okkkkkkkkk | |
| 12767. |
Let cosA+sinA = root2cosA.show that cosA-sinA=root2 sinA |
| Answer» Sqr(cos A+sinA)=sqr( /2 *cosA)Sqr(cosA)+2sinAcosA+sqr(sinA)=2*sqr(cosA)2 sinA cosA = 2*sqr(cosA) -1Now, sqr(cosA - sinA) = sqr(cosA) - 2sin A cos A + sqr(sinA).... = 1 - ( 2 Sqr (cos A ) - 1).... = 2 - 2 Sqr (cos A) .... = 2 ( 1- Sqr (cos A) ).... = 2 Sqr (sin A) Taking Sqr root on both side, we can prove desired.. | |
| 12768. |
In height and distance how can we know to use sin or cos?? |
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Answer» Nikita me tumse pucch rhi hu Ankit ne jo likha vo such h kya |
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| 12769. |
show that any positive odd integers is of the form 6q+1,or 6q+3,or 6q+5 where q is some integer. |
| Answer» Any positive integer can be written in form a=bq+r, if we assume b=6 then r is greater than or equal to 0 and less than 6. Then a can be written in form a=6q+0, a=6q+1, a=6q+2, a=6q+3, a=6q+4, a=6q+5. Out of these a=6q, a=6q+2 and a=6q+4 can be written as multiple of 2, hence these forms represents even numbers.. Naturally other forms, which can not be written as multiple of 2 are representing odd numbers.. | |
| 12770. |
Using the formula sin(A-B) = sinA cosB - cosA sinB, find the value of sin15. |
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Answer» Sin 15= sin(60-45)=sin 60 cos 45- cos 60 sin 45= √3/2 x 1/√2- 1/2 x1/√2= (√3-1)/2√2 Sin 15= sin (45-30) = sin 45.cos 30 - cos 45.sin30 = 1/root 2 × root 3/2 - 1/root 2 × 1/2 = root 3/ 2 root 2 - 1/2 root 2 = root 3 -1/ 2 root 2 Root 6 /4 |
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| 12771. |
Answers with solution |
| Answer» | |
| 12772. |
Height of triangle formula |
| Answer» For equilateral triangle it is √3/2×a | |
| 12773. |
Find t sum of first 22 term of an A.p in which d=7 and 22nd term is 149 |
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Answer» 1661 is sn 1661 |
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| 12774. |
Yeh toh pakka hai |
| Answer» God kre by luck ncert he aaye | |
| 12775. |
80% questions on ncert based |
| Answer» Kl pta chl jayega | |
| 12776. |
4tan=3 |
| Answer» Tan =3/4 Using Pythagoras theorem find the hypotenuse | |
| 12777. |
Please give me your exam quetion peper of 2017-18 |
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Answer» Kal deduga ???? very funny |
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| 12778. |
What is the HCF of smallest prime no. And composite no., |
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Answer» 2 Question** 2 ye queation to achi tarah se rat gya h?? 2 2 Ksjhhdhddhshjsjssjjsjsjs |
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| 12779. |
Plz give me last tips for mathematics,?? |
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Answer» Tq ms.jingar and utkarsh ha vo exercise 13.3 k 8,9 questiok kr lena aurthode bhut frustum k question kr lena sare formulae pd lena and all the best Do ncert *chapter Surface area and volume....chalter13 prepare the chapter which you think u can do now For which do u want tips |
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| 12780. |
Guys? Do all the question will be based on ncert? |
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Answer» No about 50 percent can come from ncert but about 75 percent of the paper is based on ncert No |
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| 12781. |
Find the value of k for which the polynomial 2x^3+9x^2-x-k is exactly divisible by 2x+3 |
| Answer» K=15 | |
| 12782. |
check whether 6n can be end with digit 0 for any natural number N |
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Answer» No, because 6 is not the factor of both 2 &5 ??? It need 2^n×5^n then only it will end No |
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| 12783. |
Prove sin30°=1/2 geometrically |
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Answer» It is there in ncert pg no.183 Nisha..... |
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| 12784. |
For what value of K will K+9 2k-1 and 2k+7 are consecutive terms of an Ap. |
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Answer» 2k-1-k-9=2k+7-2k+1=k-10=8k=18 K=18 |
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| 12785. |
Perimeter of sector, perimeter of arc? |
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Answer» No one (Theta/180°)×πr + 2r Anybody whose center in school DAV |
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| 12786. |
Hey there! How many of you have done their preparation for tomorrow? |
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Answer» Meee......?? But tomorrow is both good or bad day Great Meee? Fully done |
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| 12787. |
1÷2+23 |
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Answer» i think the correct ans is 23.5 because according to bodmas rule when 1 is divided by 2 the ans will be 0.5 and then added to 23 so the correct ans is23.5 u can also calculate this in calculator???? 25 |
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| 12788. |
Who have confidence that he or she get above 70 in maths |
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Answer» I also have Me Bss na aveee |
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| 12789. |
Kon kon si book se pade |
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Answer» Red sharma or rs aagarwal now u should refer only ncert Tne pafliye Hai Sari ki sari book pad le last paper Ncert hii enough hh Abhi yaad aa ra ha h koi orr book uthana |
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| 12790. |
Find the points on the x axis which is equidistant from 2, - 5 and minus 2, 9 |
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Answer» 2,0 Bhi example 5 dekh |
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| 12791. |
Form a quadratic polynomial one of whose zeroes is 2+ √3and the sum of the zeroes is 4 |
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Answer» x^2-4x+3 X^2-4X+1 |
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| 12792. |
It is possible to divide a line segment in the ratio square root of2+1:square root of2-1 |
| Answer» | |
| 12793. |
What is a consonant. |
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Answer» A basic speech sound in which the breath is at least partly obstructed and which can be combined with a vowel to form a syllable.....it is called consonant Number present in with variable |
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| 12794. |
Prove that tangent drawn at the end of diameter of a circle are parell to each other |
| Answer» Nai prove krna h..? | |
| 12795. |
How to find all trigonometric ratios of (A) in terms of (sec A) |
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Answer» Value of sac A will be given.. Than you can easily find by making a triangle.. All The Best for exam ????? Dimag se...?? |
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| 12796. |
Prove that the points (2,-2),(-2,1)and(5,2) are the vertices of a right angled triangle |
| Answer» use the Pythagoras theorem and uae distance formula | |
| 12797. |
When fail in 1 subject to kya hota hai. |
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Answer» Dukh se jyada principle ki n parents ki daat Sunni padti h??? Dobara dena pdega ussi subject ka ppaper Dukh hota hau?? |
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| 12798. |
Is ncert sufficient for boards paper |
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Answer» Abe bahut tension hai Almost math will come from NCERT Yess kyo kii mostly paper ncert m se hi aae h bss base clear hoo? |
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| 12799. |
How to clacukate the area enclosed by two concentric circles..? |
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Answer» We have to ...because area of circle is pie× radius radius Ok...Khushi..thnx...bt....we have to add pie value or not Area of bigger circle - area of smaller circle |
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| 12800. |
If sinA=3÷4√5 then calculate cosA |
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Answer» root of 71/4root5 9/4√5 |
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