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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 13101. |
The sum of perimeter is 216 then find sides |
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Answer» .... perimeter of rectangle OF which figure ? Triangle square etc ! |
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| 13102. |
Hey guys how much you have prepared till now |
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Answer» 4 half of the syllabus |
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| 13103. |
Is optional exercise of mathematics ncert important?? |
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Answer» Yaa it\'s much and more important ok better to do that exercise ok No |
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| 13104. |
√1488= |
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Answer» 38.57 approx Plz answer how to get any square or cube root |
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| 13105. |
Guys Sin 120 ki value kaise find karte hain . Please bata do??? |
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Answer» Sin(120)=sin(90+30)=cos30 Iski value nahi hoti ???? |
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| 13106. |
1 cm cube is = to how many liter |
| Answer» 1/1000 | |
| 13107. |
Sorry...ncert exercise |
| Answer» | |
| 13108. |
Kitne chapter hue sabke |
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Answer» Full Ok meri to sari book ho gayi or desk work bhi 4 Only 12 chapters |
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| 13109. |
Agar real no.s hard lag rhi h toh uski meet kaafi hhh?? |
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| 13110. |
In a eluilateral ? ABC P is any point in interior such that AP^2=PB ^2 +PC^2 find angle BPC |
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| 13111. |
Is anybody from Jaipur? |
| Answer» | |
| 13112. |
Find hcf of196 and 38220. Hence find the LCD |
| Answer» Are yar ncert me 1.1 exervise dekhlo same type ka sum hai | |
| 13113. |
How to remember formula of:- cross multiplication method to solve linear equation? |
| Answer» | |
| 13114. |
Trigonomentry formulas |
| Answer» SinA=OPPO/HYPOCosA=Adj/HYPOtanA=OPPO/AdjCosecA=HYPO/OPPO(1/SinA)SecA=HYPO/Adj (1/cosA)CotA=Adj/OPPO(1/tanA) | |
| 13115. |
What is the area of right angled triangle? |
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Answer» Area of right triangle=1/2*breadth*Width 1/2×base×perpendicular 1/2×base×height 1/2 x base x heigh5 |
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| 13116. |
Formula of segment of circle |
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Answer» 0/360×πr2 ø/360×πr^(2) ø= given angle |
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| 13117. |
P proof that root 5 is rational |
| Answer» It is irrational | |
| 13118. |
all the formula of book |
| Answer» | |
| 13119. |
Kis kisko maths bahut hard lag rahe hain? |
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Answer» Bhut aasan hhh....just practice and only practice.... Maths is so easy subject Not me. Mujhe to simple lgi maths...... |
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| 13120. |
Is optional in NCERT math book ask in class 10 board exam |
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Answer» I should have some time. So, I think u know the perfect ans right. Tumhara ans thik hai but not much perfect. optional is very important they ask every year Kya hoga perfect ans nhi hai. Aditya aapka ans Mene likh dia last question ka nicha likha hai. no No, hamare mam ne mana kar de thi |
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| 13121. |
How do we find lcm |
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Answer» Factorization Ex. 4&8 = 4=2*28=2*2*2LCM : 2*2*2 = 8We take highest Coman factors. By prime factorization. |
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| 13122. |
Angle1=angle2 and triangle NSQ=MTR ( congruence |
| Answer» Your que. is incomplete | |
| 13123. |
Converse Of Pythagoras Theorem Full Proof |
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| 13124. |
Hello sir /mam value of sin 120 |
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Answer» Sin 120° = Cos 30° = (√3)/2 And there is no sir/mam every one you talk was 10 class student |/3/2 Cos 30° |
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| 13125. |
Derivation of volume of frustum of cone???? |
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Answer» U need not study dis See rd Sharma book no need of derivation Se r.d.sharmaThis not need for exam No need for derivation |
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| 13126. |
What is gharaphical mathed |
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Answer» eq.* Solving linear ek. with the help of graph |
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| 13127. |
(1+cot²theta)Sin²theta=1 |
| Answer» (1+cot^2theta)=cosec^2theta &cosec^2theta × sin^2theta=1 Hence proved | |
| 13128. |
Can we use segment formula given in Rd Sharma |
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| 13129. |
Modal paper |
| Answer» Net pe search kar milige | |
| 13130. |
Is it necessary to learn all the ratios of trigonometry?? |
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Answer» Take bit and copy in exam?? Yess it is necessary to learn all ratio Yes No Plz tell me... Yes |
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| 13131. |
X-3y-7=03x-3y-15=0 |
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Answer» x=4 ,y= -1 x=-4. y=-11/3 |
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| 13132. |
How to make pendiculer |
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| 13133. |
Can we use segment formula which is given in Rd sharmA |
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Answer» What was the segment formula Really Yes |
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| 13134. |
Is ncert is sufficient for maths exam 10 class ??? |
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Answer» Sssss It is sufficient to get only 50-60 marks Just "sufficient" |
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| 13135. |
Abhi tak Kitne chapter ho gaye ? |
| Answer» First 5 and coordinate geo. (ncert,evergreen,rd sharma) | |
| 13136. |
Draw the graphs of the following equations 2x_y=2 and 4x+3y=24 |
| Answer» Given equations,\xa0{tex}2 x - y - 2 = 0{/tex}{tex}4x + 3y - 24 = 0{/tex}{tex}y + 4 = 0{/tex}We have, {tex}2x - y - 2 = 0{/tex} or\xa0{tex}x = {{y+2}\\over2} {/tex}When y = 0, we have\xa0{tex}x = {{0+2}\\over2} = 1{/tex}When x = 0, we have y = -2.Thus, we obtain the following table giving coordinates of two point on the line represented by the equation\xa0{tex}2x - y - 2 = 0{/tex}\xa0and its graph is shown below.\tx10y0-2\tNow we have,\xa0{tex}\\begin{array}{l}4x+3y-24=0\\Rightarrow y=\\frac{24-4x}3\\\\\\end{array}{/tex}When y = 0, we have x = 6When x = 0, we have y = 8Thus, we obtain the following table giving coordinates of two points on the line represented by the equation {tex}4x + 3y - 24 = 0{/tex}\xa0and its graph\xa0is shown below.\tx60y08\tAlso we have {tex}y + 4 = 0{/tex}Clearly, y = - 4 for every value of x.So, let E(2, -4) and F(0, -4) be two points on the line represented by y + 4 = 0. Plotting these points on the same graph and drawing a line passing through them, we obtain the graph of the line represented by the equation y + 4 = 0 as shown in Figure.From Fig.\xa0we have\xa0{tex}\\begin{array}{l}\\bigtriangleup PQR\\\\\\end{array}{/tex}\xa0having vertices P(3,4), Q(-1,-4) and R(9, -4).\xa0Also,\xa0PM = 8 and QR = 10.{tex}\\therefore \\quad \\text { Area of } \\triangle P Q R = \\frac { 1 } { 2 } ( \\text { Base } \\times \\text { Height } ){/tex}{tex}\\Rightarrow \\quad \\text { Area of } \\triangle P Q R = \\frac { 1 } { 2 } ( Q R \\times P M ) = \\frac { 1 } { 2 } ( 10 \\times 8 )sq.\\ units{/tex}{tex}\\Rightarrow \\quad \\text { Area of } \\triangle P Q R = 40 \\mathrm { sq } .units.{/tex} | |
| 13137. |
Suno aagr ch 14 me ogive or missing frequency me choice aaye to kon sa kro ge |
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Answer» Why ogive Hi Ogive Ogive |
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| 13138. |
Find the mean direct methods |
| Answer» Mean = €fixi/ €fi | |
| 13139. |
(3+√5)cube ×(3-√5) cube |
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Answer» 64 Identity |
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| 13140. |
how much time is required for revising ap from ncert plz tell |
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Answer» Only 2-3 hours???? 2 to 3 hours R u prepared Then ok For revising, if anybody not prepared then it take enough time What only 3-4 hours priyanka ????? If you do all the questions from NCERT then 2 or 3 days 3 to 4 hour 1-2 days will be enough |
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| 13141. |
ABCD and AEFG are squares. Prove that AG/ AF = AC/AD. (II) TRIANGLE ACF SIMILAR TRIANGLE ADG |
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Answer» I have figure.. .how to attach ?? Need diagram |
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| 13142. |
is our 10 class result come in percent or cgp |
| Answer» Both r provide d | |
| 13143. |
I heard that from 2018 class 10 syllabus will half |
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Answer» Yaah...I also heard... !! Hope so it was right |
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| 13144. |
Who studied mathematics NCERT full book |
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Answer» Me Me too Me.... |
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| 13145. |
What does angles in corresponding segments of a circle means? |
| Answer» It is not in our syllabus | |
| 13146. |
Important questions of circles |
| Answer» You can solve all the question of NCERT book than you score more and more marks | |
| 13147. |
We should have to do optional exercises in mathematics or not |
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Answer» ofcourse if u want good rank. If u do so, u will get nice marks On your choice |
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| 13148. |
Agar pre board Main kum no. Hai to kya |
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Answer» Ohhh sorry Neeche kisi ne pre board likha h Preboard nhi board ka bol rha hu |
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| 13149. |
Check whether 6n can end with the digit 0 for any natural number |
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Answer» If the no. 6 n for any n end with digit zero if the no. divisible by,5 .that is the prime factorisation contain 5 but this is not possible because 6n=(2×3)n.the prime factorisation of 6 n = 2 and 3 not 5 so there is no natural no. n for which 6 n end with digit zero 6n has 2 and 3 as it\'s factors. So it can\'t be written in the form of 2m5n. So it can\'t end with zero. |
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| 13150. |
Yaar sahi sahi batao n.a. class 11 April se hai ki bhi ???? |
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Answer» Really Arre ye toh tumhare upar hai tum jaha bhi admission loge waha ke timing se start hoga na |
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