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| 14101. |
Marking scheme of all the chapters for standard math |
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| 14102. |
5 x square - 136 X + 384 equal to zero |
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Answer» X=24 or 3.2 x = 16/5 or 24.. |
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| 14103. |
prove 2 is irrational |
| Answer» Let us assume √2 is rational number.a rational number can be written into he form of p/q√2=p/qp=√2qSquaring on both sidesp²=2q²__________(1).·.2 divides p² then 2 also divides p.·.p is an even numberLet p=2a (definition of even number,\'a\' is positive integer)Put p=2a in eq (1)p²=2q²(2a)²=2q²4a²=2q²q²=2a².·.2 divides q² then 2 also divides qBoth p and q have 2 as common factor.But this contradicts the fact that p and q are co primes or integers.Our supposition is false.·.√2 is an irrational number. | |
| 14104. |
The perimeter of right triangle is 60cm. Its hypotenuse is 25 cm. Find the area of the triangle |
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Answer» Area = s(s-h)Area = 30(30-25) = 30*5 = 150 Area of triangle=150 Perimeter of that triangle = 60cmthe measure of hypotaneous = 25cmthen the rest sides must measure = 60-25= 35let one side be xthen, thw measure of the third side must be 35 - xusing pythagoras theorem(25)^2 =(x)22 + (35-x)2625 = x2 + x2 - 70x + 1225x2 + x2 - 70x + 1225 = 625x2 + x2 - 70x + 1225 -625 = 02 x2 - 70x + 600 = 02x2 - 40x - 30 x + 600= 02x (x-20) -30 ( x - 20) = 0(x-20)(2x-30)=0x -20 = 0x = 202x -30 =02x =30x = 15so,one of the side measure either 20 cm 15 cmif one side measure 20cm then the other must measure 35 -20 = 15cmand if it measured 15 cm then the other side measure 35-15 = 20 cmso,we will get 20cm and 15 cm as our remaining sides.one of then will be height and the other misy be the base,now apply the formula of area of triangle i.e(1/2) (height)(base)= (1/2 )(20)(15)= 150 cm2so, the area of that triangle will be 150 cm2.\xa0 |
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| 14105. |
If 4tan k= 3 evalute (4sink - cosk+ 1)/(4sink+cosk-1) |
| Answer» 143/25 | |
| 14106. |
If A and B are acute angles and sinA=cosB, then find the value of A+B |
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Answer» 90 90 9,0 SinA=cosBCos(90-A)=cosB90-A=BA+B=90 |
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| 14107. |
Find the value of theata if cos theata /1-sin theata +cos theta /1-sin theata =4 |
| Answer» 60 | |
| 14108. |
The mid point of the line segment joining the point(-5,7) and (-1,3) is |
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Answer» -3,5 Using mid point formula ,that is , coordinates of mid point of a line segment with end points (x1 , y1) and (x2 , y2) are=> ( (x1 + x2 )/ 2 , (y1 + y2)/2 )therefore , using above formula ,=> mid point of (-5,7) and (-1,3) is=> x- coordinate = [-1+(-5)]/2 = = -6/2 = -3and y coordinate = (7+3)/2 = 5=> coordinates are (-3 , 5 ) (-3,5)... |
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| 14109. |
Trigonometry solution |
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Answer» Ken question ka To ye app kis ke liye hai |
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| 14110. |
2x+4y=18 |
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| 14111. |
If Sn denotes the sum of n terms of an AP, then S12-S11 is the________ term of the AP. |
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Answer» Coz an=sn -s(n-1) a12 |
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| 14112. |
Volume of hemisphere is 4851/2 . Find curved surface area of hemisphere. |
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Answer» 693 The volume of hemisphere ={tex} \\dfrac{4851}{2} cm^{2}{/tex}To find, the curved surface area(CSA) of a hemisphere = ?We know that,The volume of a hemisphere {tex}=\\dfrac{2}{3} \\pi r^{3}{/tex}{tex}⇒\\dfrac{2}{3} \\times \\dfrac{22}{7} r^{3}=\\dfrac{4851}{2} cm^{2}{/tex}{tex}⇒ r^3=(4851\\times 7 \\times 3)/(2 \\times 2 \\times 22){/tex}{tex}⇒ r^3=\\dfrac{101871}{88}{/tex}{tex}⇒ r^3 = 1157.625{/tex}{tex}⇒ r^3 = \\dfrac{1157625}{100}{/tex}{tex}⇒ r^3 = (\\dfrac{105}{10})^{3} =10.5^{2}{/tex}⇒ r = 10.5 cm{tex}∴ The curved surface area(CSA) of a hemisphere =2\\pi r^{2}{/tex}{tex}= 2 \\times \\dfrac{22}{7} \\times 10.5 \\times 10.5{/tex}{tex}= 2 \\times 22 \\times 1.5 \\times 10.5cm^{2}{/tex}{tex}= 44 \\times 15.75cm^{2}{/tex}{tex}=693cm^2{/tex}Hence, the curved surface area(CSA) of a hemisphere ={tex}693cm^2.{/tex}\xa0 |
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| 14113. |
2√45/√5+3√20/√5 |
| Answer» 9 | |
| 14114. |
If two vertex of an equilateral triangle be 0, 0 and 3, under root 3 find the third vertex |
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| 14115. |
3x²-k(root over 3)x+4=0 ,has real real roots,then value of k will be |
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Answer» K^2=48 k=√48 K^_^ Hope it helps u both guys...?? => k=±4 K²=16 3k²=48 (√3k)²-4×3×4 =0 B²-4ac=0 Roots are equal , so d=0 By using the formula b²-4ac put the values And get the answer ... Actually i am not able to solve it fuuly but you ll get some idea of question ? |
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| 14116. |
√3+√5 prove it is a irrational number. |
| Answer» Let √3+√5 be a rational number.A rational number can be written in the form of p/q where p,q are integers.√3+√5 = p/q√3 = p/q-√5Squaring on both sides,(√3)² = (p/q-√5)²3 = p²/q²+√5²-2(p/q)(√5)√5×2p/q = p²/q²+5-3√5 = (p²+2q²)/q² × q/2p√5 = (p²+2q²)/2pqp,q are integers then (p²+2q²)/2pq is a rational number.Then √5 is also a rational number.But this contradicts the fact that √5 is an irrational number.So,our supposition is false.Therefore, √3+√5 is an irrational number. | |
| 14117. |
Sin²60°+2 tan45-cos²30° |
| Answer» Put the value of sin60,tan45,cos30 .......then....(√3/2)^2+2×1-(√3/2)^2.. ...........3/4+2-3/4..........here 3/4 and 3/4 get cancelled out.............hence ,,,2 is the right answer ? | |
| 14118. |
If secA + tanA = p then show that p2-1/p2+1 = sinA |
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| 14119. |
If sec∆ + tan∆ = p then show that p2-1 =sin∆. p2+1 |
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| 14120. |
draw tangent to the two circles from a given point outside the circle |
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Answer» step of construction likh kar bhejo Ye to bhut easy h one circle draw kro or bisector draw kro gir both side s circle ki side ko touch krte hue line draw kr do |
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| 14121. |
If Sin77 =x, then the value of Tan77 is |
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Answer» cos2 θ + sin2 θ = 1⇒ cos2 77° + sin2 77° = 1⇒ cos 2 77° = 1 – sin2 77°⇒ cos 77° = √(1 – sin2 77°)And Given that sin 77° = x⇒ cos 77° = √(1 – x2 )Tan77° = x/ √(1 – x2 ) X/cos |
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| 14122. |
if s16 = 236 and first term is 21 then find 23 th term |
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| 14123. |
Name on organism that grow by vegetative propagation? |
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Answer» Bryophyllum Bryophyllum Bryophyllum leaf... |
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| 14124. |
Prove that root 5-2 is irrational |
| Answer» It can be done by the method of contradiction. | |
| 14125. |
Find the centre of the circle passing through the points(6,-6),(3,-7),(3,3) |
| Answer» If your question is"Find the centre of a circle passing through the points (6,-6), (3,-7) and (3,3)." than the solution is-Let A (6, –6), B (3, –7) and C (3, 3) be the points on the circle and the centre of the circle be P (h,\xa0k).∴\xa0PA = PB = PC (Radius of the circle) | |
| 14126. |
What is ap or sum of ap |
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| 14127. |
Root3 is irrational no .why |
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Answer» TMC By the method of contradiction Since Root 3 is an integer Kiddin expresws it in the form of a\\b where a and b are coprime U GEt tHe AnSwER Because it has√ |
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| 14128. |
Sin(A+B)= SinA.CosB + CosA.SinBFind Sin 75 degree. |
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Answer» kya ch ho raha hai messages mein. Ok bye?\u200d♂️?\u200d♂️?\u200d♂️ Heheheh century?? Mujhe v aapse baat krke accha laga .... bss ab exam acche se dena???? Thanx? Byeee Century?? Tumse baat krke acha lga? Ohh accha science???? Acche se tayiyari krna all the best..?? Arre nhi nhi aesa nhi haj thoda bhot to refreshment cata hai aur vese bhi frnds se baate krne mai tym waste kesa?? Sc- Science? Mene acha khasa time waste kr dia tumhara? Okay ab m jaa ri hu Sc?? Tab lekin sc fail ho jata aur hamm..... Kaash hum pillow k niche book rakhke sote aur saara osmosis se yaaad hota kitna achha hota????? Ha esa hi lg rha h?? Thori si hui thi Ohh lagta hai tapasya jari hai???? Baat hui thi aapki? Aadya morning m ayi thi Aadya kyu ni ayi aaj kal bina batay chali gyi thi? Smj gi smj syi?? Usse pehle blank hai usse fill krke samaj jao??????? Orry ??? Mtlb _orry ??? Ok ok sorry Face to serious wala hi tha isliye laga? Frshp m no sry ,no thank u? ???? M or serious???? Perspective mtlb wo story to yahi hai but unka charitr alag hai jesa aapko meri baato se samaj aaya hoga Class 1?inna acha brain ni h mera?? Alle seroius hogyi ... sorry?\u200d♂️?\u200d♂️ ? . Aapko yaad ek \'rabad\'(rubber) naam ka ch tha 1st claass mai? Mene jo perspective batay bade bhai sahab ka bilkul alag hai ch mai?? Class 4 ya 5 m tha,isliye yaad ni rha hoga? Ohh mujhe to yaad hi nhi?\u200d♂️ Okay dekhungi padhke Ksa boring ch tha. Baseless khani Lesson giving chapter hai pdke dekhna Wahi to bechara aur fur v chhote bhai ko daante the wo Thoda batao shayad yaad aajay Bhai 1st n bara bhai fail??? Ummm nah yaad ni Tumhe yaad h ek ch hua krta tha-kirmich ki gend Aur bechare ka chhota bhai 1st aata raha ?????? Itni buri haalat??? Aur 3 years fail hone k baad ch khatm?????? Humara Course B hai Oh achaa? Pure din padayi krte hai apni jagah se uthte tak nhi but fir v 3 years fail hote hai??? Hindi course B ka first ch hai usme bde bhai sahab hai Tumhari Haan A course Aapka hindi course A hai? Bde bhai sahab? Kayi bde bhai sahab ki tarah kaam hua to??????? ??? Aaj sab tapasya krne gye h esa lg ra h? ? Haan ok? Are isme bura maanne ki kya baat? Aaj kal tum phle se happy rhne lge ho?hamesha happy rhna? Agar m tumhe tum bulau toh bura toh ni manoge na Tum apni frnd ko jail bhejoge?buri baat aseem?? Sorry just kidding?? Mene hi report ki tb kayn bachaega? ???? Jail ho jate toh ankesh bro n shreya h na dm, bacha lenge muje? Acha h thora tym toh h tumhare pas Ohh ktl! Jail ho jati to???? Tension* Lekin mera to sat ko hai zada nhi h tendion Sst insan hota toh m uska katl hi kar deti? ??smj gi Samaj gyi hogi kesa hu? Mera v sst ka paper hai agla Tum kse ho Sukhi mn mai pata hai kinni power hoti hai???? Fir tensed rehne ki zaryrat nhi ?? Rest toh leti hi rhti hu m? Relaxed rahega brain isse Agr 2 hrs pada to 30 min break aese Min* Mtlb 1 hr pada aur 15 mi break Mtlb Thoda rest v krlo boch bich mai Thanks... Sst ni pdhi jati yaar? Agr mai hua to aapke ques ka answer kr dunga Tension mt lo bss acche se pdlo accha hi hoga paper? All the best Ohh Kal sst k xm h,bht padne ko h Lagra tha lekin tensed kyu? Par aapne esa kyu pucha? Bas tensed hu Sad ni hu Thanx ki koi baat nhi Aap sad ho ? Thnx Hence , sin75 = (√3+1)/2√2 = √3/2√2 + 1/2√2 => 1/√2 × √3/2 + 1/√2 × 1/2 Putting sin45 = cos 45 = 1/√2 and cos30 =√3/2 => Sin45.cos30 + cos45.sin30 Sin75 = sin(45+30) |
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| 14129. |
Find the Number of terms in theA.P.1,3,5,....1001 |
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Answer» a=1 , d=2 , an=1001Using an=a+(n-1)d1001=1+(n-1)21001-1/2 = n-1500+1=nn=501 Use the formulq an=a+(n-1)d |
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| 14130. |
Find the LCM of 150 and 210 by prime factorisation |
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Answer» Find the prime factorization of 150. 150 = 2 × 3 × 5 × 5.Find the prime factorization of 210. 210 = 2 × 3 × 5 × 7.LCM = 2 × 3 × 5 × 5 × 7.LCM = 1050. 1050 |
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| 14131. |
Find the number of natural numbers between 102 and 998 which are divisible by 2 and 5 both |
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Answer» As the numbers are divisible by both 2 and 5,so their last digit will always be 0. hence the series are 110,120,130,....,990here a=110,d=10,an=990an=a+(n-1)d990=110+(n-1)10(n-1)10=880n-1=88n=88+1n=89.thus the number of natural numbers between 102 and 998 which are divisible by both 2 and 5 is 89.Read more on Brainly.in - https://brainly.in/question/12757639#readmore 80 natural no.s |
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| 14132. |
Solve the pair of linear equations, 2x+y=6 , 2x-y=-2 graphically |
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| 14133. |
cosecA + sinA = 2 To find sinA^2 + cosecA^2= |
| Answer» (CosecA + sinA ) = 2 Cosec^2A + sin^2A + 2cosecA×sinA = 4 [by squaring on both sides] Cosec^2 + sin^2 + 2×1/sin ×sin = 4 Cosec^2 + Sin^2 + 2 = 4 Cosec^2 + Sin^2 = 2.. | |
| 14134. |
SinA+1/cosA-1 |
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| 14135. |
what is trignometic |
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Answer» It is a branch of mathematic which deal with the study of relations between lengths of sides and angles of a right angle triangle. what is triangle chapter |
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| 14136. |
Prove that1+sinA+cosA÷1+sinA+cosA+1+sinA+cosA÷1+sinA+cosA=2cosecA |
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| 14137. |
In an ap 7:45 equal to -4 sum of n terms is equal to 64 find n |
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Answer» Agar answer mil jaye to share kar lena YaWhat is it What is 7:45 |
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| 14138. |
Kya ismein standard CBSE sample papers hain |
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Answer» Yup Yes Where are the no.s? Which of the following number have the non-terminating repeating decimals expansion |
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| 14139. |
If the distances of P(x,y) from A(5,1) and B(-1,5) are equal, then prove that 3x=2y. |
| Answer» Considering AZ = ZB, that means {tex}A Z^{2}=Z B^{2}{/tex}{tex}(x-5)^{2}+(y-1)^{2}=(x+1)^{2}+(y-5)^{2}{/tex}Squaring both the sides we get the factors and then simplifying them we get:{tex}x^{2}+25-10 x+y^{2}+1-2 y=x^{2}+1+2 x+y^{2}+25-10 y{/tex}12x = 8y3x = 2y Hence proved | |
| 14140. |
What is probability?? |
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Answer» Hlw? Hi Shirin?? Probablity is chapter 15 Probability means possible occurrence of chances out of total chances Probability of event= no. of favourable outcomes/ total no. of trials Probabilty means chances |
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| 14141. |
Find the distance of a point P(3,2) from the origin |
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Answer» {tex}Distance\\: from\\\\ \\:the \\:point \\:P(3,2)\\: and\\\\ \\:the \\:origin\\\\=5{/tex}Step-by-step explanation:{tex}\\boxed{Distance\\: from\\\\ \\:the \\:point \\:(x,y)\\: and\\\\ \\:the \\:origin\\: is\\: \\sqrt{x^{2}+y^{2}}}{/tex}{tex}Distance\\: from\\\\ \\:the \\:point \\:P(3,2)=(x,y)\\: and\\\\ \\:the \\:origin\\\\= \\sqrt{3^{2}+2^{2}}\\\\=\\sqrt{9+4}\\\\=\\sqrt{13}\\\\{/tex}Therefore,{tex}Distance\\: from\\\\ \\:the \\:point \\:P(3,2)\\: and\\\\ \\:the \\:origin\\\\=\\sqrt{13}{/tex}\xa0 Oe...kya yaha par time pass kar raha h kya....faltu ke question post kare h ....kya 10 th padhi bhi nahi h kya...?? |
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| 14142. |
Find all zeroes of the polynomial (2x⁴-9x³+5x²+3x-1) if two of its zeroes are (2+3)and(2-3) |
| Answer» Hi | |
| 14143. |
If sin theta equal a square minus b square / a square + b square find 1 + 10 theta into cos theta |
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| 14144. |
Prove that a rectangle circumscribing a circle is a square |
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| 14145. |
Triangle ABC has a median AD and AE perpendicular to BC then prove that AB2+AC2=2AD2+1/2BC2 |
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| 14146. |
What do you mean by polynomial |
| Answer» A polynomial is defined as an expression which contains two or more algebraic terms. It is made up of two terms namely Poly (meaning “many”) and Nominal (meaning “terms.”). Polynomials are composed of:\tConstants such as 1, 2, 3, etc.\tVariables such as g, h, x, y, etc.\tExponents such as 5 in x5 etc. | |
| 14147. |
Find the value of sin 30° geometrically |
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Answer» 1/2 1/2 |
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| 14148. |
What is the hcf of 225 & 009 |
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Answer» HCF=9 225=9*25+0So HCF=9 9 9 |
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| 14149. |
Given that sin theta +2 cos theta =1, then prove that 2 sin theta -cos theta =2 |
| Answer» Given that sin theta + 2 cos theta=1Cos theta = 1 - sin theta by 2. (-1)Now we need to prove that 2 sin theta - cos theta=2. (-2)Now put the value of equation 1 in eq 2 We have2 sin theta -(1 - sin theta by 2)=24 sin theta - 1 + sin theta by 2=24 sin theta + sin theta - 1 = 4Sin theta =1. Put the value of sin theta in 1 equationCos theta=1-1 by 2Cos theta=0Put the value in 2 equation2*1-0=22=2Hence proved | |
| 14150. |
Does anybody has maths lab activity 18 solved table and observation? |
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