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| 14201. |
Derive the formula of the CSA and the TSA of the frustum of cone |
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Answer» TAS=πl(r1+r2)+π(r2+r2) π(r1+r2) Cut a right circular cone with a plane parallel to the base of the cone, then the solid shape between the plane and the base of the cone is called the frustum of a cone.e.g. Flower pots have a shape as the frustum of a cone.The surface area and the volume of the frustum of a cone can be calculated using standard formulae.CSA of the frustum of a cone =\xa0πl( r1 + r2).where r1 = radius of the larger circular face of the frustum, r2 = radius of the smaller circular face of the frustum, and l = slant height of the frustum.l = h2+(r1-r2)2 and h is the height of the frustum.TSA of a frustum of a cone = πl(r1 + r2) + πr12 + πr22 |
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| 14202. |
If the line given by 3x +2ky=0 & 2x+5y+1 =0are parellel find value of k |
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Answer» 3/2=2k/54k=15K=15/4 a1/a2= b1/b2 |
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| 14203. |
Using eucluds divisio lemma find hcf of 455 and 42 |
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Answer» It is correct The Hcf of 455 and 42 is =7 Given numbers are 455 and 42Here, 455 > 42So, we divide 455 by 42By using Euclid’s division lemma, we get455 = 42 × 10 + 35Here, r = 35 ≠ 0.On taking 42 as dividend and 35 as the divisor and we apply Euclid’s division lemma, we get42 = 35 × 1 + 7Here, r = 7 ≠ 0So, on taking 35 as dividend and 7 as the divisor and again we apply Euclid’s division lemma, we get35 = 7 × 5 + 0The remainder has now become 0, so our procedure stops. Since the divisor at this last stage is 7, the HCF of 455 and 42 is 7. |
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| 14204. |
CBSE last 10 year question paper |
| Answer» Search on Google | |
| 14205. |
Lcm of two no is 1800 which of ghe following is not their hcf |
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| 14206. |
If x square +y square = 25xy then prove that 2log (x+y)=3 log3+logx+logy |
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| 14207. |
sin (45+A) -cos(45-A) is equal to........ |
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Answer» 0 Sin(45+A)-cos(45-A)=sin(45+A)-sin(90-45+A)=sin(45+A)-sin(45+A)=0 0 0 |
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| 14208. |
In maths class 10 ex. 14.1 ka 5 and 7 question batao do.... Plz |
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| 14209. |
Solve this by complete squaring method:-xsq +7x-18 =0 |
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| 14210. |
In maths I am not geeting statistics chap.?? |
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Answer» Go and search in youtube you will get all the sums with the right answers and in different languages also Write-maths chapter 14 sums answer and explanation ? It is the easiest after probability 14th chapterpage no 260 |
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| 14211. |
TSA OF FRUSTRUMLSA OF FRUSTRUMVOLUME OF FRUSTRUM FORMULAS |
| Answer» You will get them in the summary of this ch of ncert book | |
| 14212. |
In an ap if d,=4, n=3 an=10then a is |
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Answer» an=a+(n-1)d10=a+(3-1)410=a+2×410=a+810-8=a2=a By formula An=a+(n-1)dAn=10N=3D=4So by putting value in formula 10=a+(3-1)410=a+(2)410=a+8A=10-8A=10So the first term (a) is 10 an=a+(n-1)d10=a+(3-1)410=a+(2×4)10-8=aa=2 |
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| 14213. |
Xsin^2A+Ycos^2A=sinA×cosA and XsinA=YcosA . Prove that X^2+Y^2=1 |
| Answer» Bro X^2 +Y^2=0 not 1 | |
| 14214. |
Step deviation method. |
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Answer» A+sigmafu/sigma f×h where u=x-A/h Hi Sigma fixi/Sigma fi Yeah ye hui n ak\'sis wali baat.....bye sis ..take care -- Sad mt ho sis iss baar ekdm aache se.....aane do questions kaha se aayega 00 ++ Koi ni sis..keep practice.... # Kyo sis बेस्ट ऑफ लक बहन Ok ...pahle kaise huye - Acche se krna Pre board Mean = (a+Σf¡u¡/Σf¡)h......where h is the class interval Ya..... ... Time milega to Are thanks kyu help to kiaa hi ni ,, Kash hm bhi chote hote sis ki tarah Bht bada h lekin .hmmmm Bht lamba h sis baad me bataunga |
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| 14215. |
Standard maths kis book se padhe |
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Answer» ncert NCERT , RD and ncert exampler Not rd bcoz it\'s ques r very high level also based on 11th class so according to no rd Then ulike or Dk First ncert |
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| 14216. |
If Sin A = Cos(A-6degree), find the value of A |
| Answer» Cos (90-A ) =cos ( a -6) 90-a = a - 6 90 +6 = 2a 96 =2a A = 48 | |
| 14217. |
Proove that tan^2 A - Sin^ A = Tan^2 A × 1/Cosec^2 A |
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| 14218. |
Find 3 irrational number between 2 and 3 |
| Answer» 2.12112111211112......and 2.222341232......and 2.4565665666566666..... | |
| 14219. |
an=sn-s |
| Answer» Wht | |
| 14220. |
Find the sum of all multiples of u lying between 100 to 1000. |
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| 14221. |
What is the numbes distribution in 10th exam.unit wise number distribution.. |
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| 14222. |
If PA and PB are the tangents ti the circle with centre O such that angle APB =50 °find angle OAB |
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Answer» 25 degree OAB=130° |
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| 14223. |
Long division for 2x4-3x3-3x2+6x-2 by 22-2 |
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Answer» Thanks(1) Thanks(5) |
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| 14224. |
Solve the following equation by using factorisation method.4x^2_4ax+(a^2_b^2)=0 |
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Answer» Reply plzzz I think x^2 on the place of b^2..... |
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| 14225. |
Verify sin2 a +cos2a=1 |
| Answer» Sin2a + Cos2a = 1Sin2a+Sin(90-2a)=1Sin(90-2a+2a)=1Sin90=11=1 | |
| 14226. |
An ap 3,7,11,15,...?find the 95th term of an a.p |
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Answer» A=3,D=7minus3=4,N=95A95=3+(95minus1)=3+376A95=379 A=3,d=4,n=95An=a+(n-1)d A95= 3+(95-1)4A95=3+376A95=379 379 |
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| 14227. |
Zero of a polynomial graphically by this equation y=x^2-3x-4 |
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Answer» X=2 then y= -6 again.....so X=1 then y= -6 |
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| 14228. |
Kya hum standerd math ko basic math me convert es time me |
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Answer» Thanks (2) Are bhai etna mat dar???? Okk Aap school m teachers se puchiye..? |
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| 14229. |
If the 10th term of an AP is 52 and 17th term is 20 more than its 13th term, find the AP |
| Answer» a+9d=52a+16d=a+12d+20=> 4d=20 => d= 5a+9×5=52=>a=7The AP is 7,12,17,22,..... | |
| 14230. |
if the perimeter of a circle is equal to that of a square then the ratio of their areas is |
| Answer» Perimeter of circle=2πrPerimeter of square=4r(since,r=side of square)Ratio=2πr\\4r=π:2Ans::::. π:2 Most prolly not sure | |
| 14231. |
2x +5y -1 = 0 and 2x +3y-1 = 0 find by cross multiplication |
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| 14232. |
If one root of the equation (k-1)x^2-10x+3=0 is the reciprocal of the other,then the value of k is |
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| 14233. |
How to download mcq series for class 10?? |
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| 14234. |
Can i download pdf form |
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Answer» YA Hn ji iss app se kr skte ho! |
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| 14235. |
10x²+3x+12 midle term splitting |
| Answer» It has no solution because D is negative. | |
| 14236. |
165522+622888-32847+ |
| Answer» Thanks (3) | |
| 14237. |
The volume of a hemispher is 2425 1by2cm3 find its curved surface area |
| Answer» Thanks(4) | |
| 14238. |
What is the smallest number when divided by 35,56 and 91 leaving a remainder 7 in each case |
| Answer» The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 9135 = 5 x 756 = 2 x 2 x 2 x 791 = 7 x 13LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647. | |
| 14239. |
For a frequency distribution, Mode - Median =__________×(Median - Mean)A 1B 2C 3D 4 |
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Answer» Ek pahad ke sikhar se purve ki or do karmagat ke patharo ke avnaman kon 30 ka h or 45ka pahad ki hight kitni hogi sit Mean – Mode = 3 (Mean – Median) |
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| 14240. |
What is pononomil |
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Answer» Do u mean polynomial? What is this??Polynomial..?? I don\'t know |
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| 14241. |
If Cos theta + sin theta =√2cos theta.prove that cos theta -sin theta =√2sin theta |
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Answer» But pk vo toh prove krna hai na,so how can u bring rhs to lhs?? Sorry lhs ko rhs me transfer karns....jada easy hoga......sign ka problem na hoga. Bhai eq....(1)ka square kar do........then rhs ko lhs me la lo......and then add 2 sin^2 thete to both side. |
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| 14242. |
If tan theta + sin theta = m and tan |
| Answer» M-sin theta??? | |
| 14243. |
a SinQ - b CosQ =1 then find the value of a CosQ - b SinQ =? |
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| 14244. |
Sin square 63 +cos square 27 / cos square 17 + cos sqaure 73 |
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| 14245. |
3x + y = 3900X + 3y = 1300 represent it graphically |
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Answer» 3x+y=3900X=100,y=1200X=1200,y=300Draw it on graph.X+3y=1300X=100,y=1200X=1300,y=0Draw this alsoThen u can get ur answer. Let value of x be 0 & value of y be 0 then you can represent it graphically |
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| 14246. |
If x=1 then find the value of |
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Answer» Complete this ques. Complete the question plz |
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| 14247. |
Ex5.2 1q |
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| 14248. |
The solution of the eqution X-Y=-2 |
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| 14249. |
The value of sin60 cos30+sin30 cos60 is |
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Answer» =Cos(90-60)cos30+sin30sin(90-60)=cos30cos30+sin30sin30=cos²30+sin²30 =1. (sin²A+cos²A=1) 1 Yes sory my ans is wrong?its 1 1 0 |
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| 14250. |
Chapter 1all questions |
| Answer» Ncert ke solutions hai @learncbse.in pe check kar lo | |