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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 14651. |
2xsquare+3xsquare |
| Answer» 5xsquare | |
| 14652. |
Which sample paper is best for maths,sst and sci.??? |
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Answer» Bye shreyu bestu...? Bye..adu bestie..? Hmm...? Ha..sunday tha..? Oh...aapko date bhi yaad h...mujhe to ni yaad tha..bas itna yaad h ki shayad sunday tha..?? Oh..ha..13 ko..kal mujhe or apko baat krte hue 1 month ho jayega..?? Vo to bahut pehle hi rakha tha...vaise mast h..? ? All the best for ur pre board ....ankesh bro. ?? Maine bhi name rakha..adu bestie..? Thanku...? Bht accha h ...adu bestie...? Hello shreyu bestie...new name kaisa h...shreyu...? Beatie or bestie...? Hello..aadya bestie..? Hii..beatie ji Hello to all Oh...mai January me lungi...? Xamidea ? ham bhi 2-3 din pahle hi liya... Ok bro...vaise maine abhi tak liya ni h...? Hello sis I agree sis.....because i prefer both Hello bro, shreya and ankesh ji...☺ Me fine.. I think Oswaal...? Mai theek hi hu ji..aap kaise ho.. Hello shreya g kaise ho... Ji..dekha maine..mere pass vidya ke h.. I suggest Arihant Hamne dekha bro.... |
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| 14653. |
X+5=2X-9. X=? |
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Answer» X =14 X=14 X + 5 = 2X - 9x -2x = -9 - 5-x = -14x = 14 X=14 |
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| 14654. |
X+5=2X-9 x = ? |
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Answer» X=14 X=14 |
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| 14655. |
Prove root 3 irritational |
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Answer» Let us assume that √3 is a rational number.then, as we know a rational number should be in the form of p/qwhere p and q are co- prime number.So, √3 = p/q { where p and q are co- prime}√3q = pNow, by squaring both the sidewe get,(√3q)² = p²3q² = p² ........ ( i )So, if 3 is the factor of p²then, 3 is also a factor of p ..... ( ii )=> Let p = 3m { where m is any integer }squaring both sidesp² = (3m)²p² = 9m²putting the value of p² in equation ( i )3q² = p²3q² = 9m²q² = 3m²So,if 3 is factor of q²then, 3 is also factor of qSince 3 is factor of p & q bothSo, our assumption that p & q are co- prime is wrongHence,. √3 is an irrational number. Let |
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| 14656. |
2x2+2x-365=0 |
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Answer» 180.5 180.5 180.5 |
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| 14657. |
x2+x-p(p+1) find roots |
| Answer» | |
| 14658. |
5-3 |
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Answer» 1+1 2 -2 2 100-98?? 2 |
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| 14659. |
The value of√ √6+√6+√6+.....is |
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Answer» 6 |
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| 14660. |
if theso seventh term of A.P. is |
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Answer» An=a+6difference(d) An=a+6d |
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| 14661. |
Derive the formula for tha frustum of a cone |
| Answer» Read ncert | |
| 14662. |
If 10,k,-2 are in AP then find the value of k |
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Answer» K= 10+(-2)/2. 8-2/2=4 K-10=-2-kK+k=-2+102k=8K=4 An = a +(n-1)d => -2 = 10+(3-1)×(k-10) => -2 = 10+2k-20 => -2 +10 = 2k =>k =8/2 => k = 4. 4 K-10=-2-k. || 2k=8. || K=4 |
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| 14663. |
14 chpter |
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Answer» Statistics Do ch 14 from this app Its very easily explained in the Cbse guide |
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| 14664. |
If sin^2A=3sinA×cosA ,prove that tanA=1or1/2 |
| Answer» Bro tanA should be equal to 3 | |
| 14665. |
sample paper are very different comparing to last year why |
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Answer» Bcz of chnged pttrn..and also acc. to basic nd standard.. The pattern has changed |
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| 14666. |
Value of ™ |
| Answer» Munna bbhukha lahi thi kya jo addha se jada andra ho gaya .Take care again during writing .Best of luck for your board examintion | |
| 14667. |
All sample paper solved of 2020 |
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Answer» Yes Theorem 6.1 and 6.2 |
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| 14668. |
All sample paper solved of 2019 |
| Answer» | |
| 14669. |
sin2A=2sinA is true when A |
| Answer» 2sinAcosA = 2sinACosA=1cosA = cos0A = 0 | |
| 14670. |
If the PA and PQ are tangent from an outside point P such that PA=15cm and |
| Answer» PQ is also 15cm | |
| 14671. |
9x⅔-+89y⅝*987z¾ find x y z if x=89, y=64,z=524 |
| Answer» | |
| 14672. |
Frnds ...aap log 10th ke baad...optional me kyon sa subject choice kroge |
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Answer» Maths... Ok I will choose maths with additional biology |
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| 14673. |
X 2x 8x |
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Answer» X(1×2×8) x in common =16x Kay h yeh?? |
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| 14674. |
What is distance between two parallel tangents of a circle of radius 4cm |
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Answer» 8cm 8 |
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| 14675. |
2/2=0 |
| Answer» Wooo what a question | |
| 14676. |
If ? ABC~ ? DEF BC=3cm and EF =4cm ar of triangle ABC=54cm square, then ar of ? DEF??? |
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Answer» 96cm 96 cm |
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| 14677. |
0/0=2 prove this |
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Answer» After 3rd line, there is.. (10-10)(10+10)/10(10-10) LHS = 0/0 => [(10)^2 - (10)^2]/ (100-100) => (10-10)(10+10)/ (100-100) => (10+10)/10 [since, (10-10) get cancelled by each other] => 20/10 => 2 = RHS Hence, it\'s prove...? |
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| 14678. |
Find hcf of 45 and56 |
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Answer» The factors of 45 are: 1, 3, 5, 9, 15, 45The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56Then the greatest common factor is 1. 1 10 |
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| 14679. |
Prove that (sin theta+1+cos theta)(sin theta-1+cos theta)(sec theta cosec theta)=2 |
| Answer» LHS={(sin Φ+cos Φ)+1}{(sin Φ+cos Φ)-1}(sec Φ*cosec Φ)={(sin Φ + cos Φ)^2 -1}(sec Φ*cosec Φ)=(sin^2Φ+cos^2Φ+2sinΦcosΦ-1)(secΦ*cosecΦ)=(2sinΦcosΦ)(1/cosΦsinΦ)=2=RHS | |
| 14680. |
HCF OF 2×5 and 2×5 |
| Answer» 10 | |
| 14681. |
101×102 |
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Answer» <10302> <10302blue> 101 × 102 = (100 + 1) 102= 100 (102) + 1(102)= 10200 + 102= 10302 10,302 10302 |
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| 14682. |
If secA=3/2 find 2cosA - tan^2A/sin^2A |
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Answer» 3 SecA=3/2=H/BBy Pythagoras theorem,H^2=P^2+B^29=P^2+4P^2=9-4P^2=5P=√5Therefore,According to the question,2*2/3-(√5/2)^2/(√5/3)4/3-(5/4)/(5/9)Now by taking LCM u can get the correcy answer! |
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| 14683. |
Empirical relation |
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Answer» 4.6 Empirical Relation Between Mean, Median And ModeA distribution in which the values of mean, median and mode coincide (i.e. mean = median = mode) is known as a symmetrical distribution. Conversely, when values of mean, median and mode are not equal the distribution is known as asymmetrical or skewed distribution. What?? |
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| 14684. |
Empirical relatio8 |
| Answer» Empirical relation for mode, median and mean is given by :-Mode = 3(median) _ 2(mode)Hope this will help you..... | |
| 14685. |
If the HCF of 65 and 117 is expressive in the form 65m - 117,the value of m is: |
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Answer» 2 65=13*5117=3*3*13Hcf of 65 and 117 is 13Since, 65m-117=13 =>m=130/65 Therefore, m = 2. |
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| 14686. |
What are the formula of quadrant |
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Answer» Pi r square upon 4 1/4 pi r square |
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| 14687. |
If acos theta -bsin theta =c ,prove that asin theta +bcos theta = √a2+ b2- c2 |
| Answer» | |
| 14688. |
Do someone knows the syllabus for FIITJEE talent reward exam 2019 |
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Answer» Delhi For which city |
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| 14689. |
The nth term of an A.P,then the sum of whose n terms is Sn,is |
| Answer» Given.....sn=snTo find ............anSince sn=sn an=an an=a+(n-1)d Also........ s(n)-s(n-1) ~it depends on the number of terms(n)????? | |
| 14690. |
Root 3 is equal to |
| Answer» 1.732 | |
| 14691. |
Find the area of quadrant of a circle whose circumference is 44 cm |
| Answer» 2πr=44r=7Q÷360×π×r×r90÷360×22÷7×49=77÷2=38.5 | |
| 14692. |
What about standard and basic maths?? |
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Answer» Thnxx In standard you can take pcm or pcb but in basic maths you can only take pcb and if you want to take non med in basic maths you have to give standard and basic both examination |
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| 14693. |
If sinA=1 then find cosA? |
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Answer» We know that,Sin^2A +Cos^2A=1So,1+Cos^2A=1 [putting sinA =1]Cos^2A=0CosA=0Hope this will help you..... 0 sin2A+cos2A =11 + cos2A = 1Cos2A = 1-1=0 |
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| 14694. |
if cars going to opposite direction then speed will be? |
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Answer» Relative speed = difference of their speed Negative Negative |
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| 14695. |
Volume of a frustum |
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Answer» Volume =1/3πh(r1{ Murk Volume of frustum = 1/3πh(R^2+r^2+Rh) |
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| 14696. |
If probability of occurrence of an event is P(A).Then which of the following is true |
| Answer» P(event) + P(not event) =1 | |
| 14697. |
2tan30/1-tansq30 |
| Answer» √3 is answer... | |
| 14698. |
x^2+5x +6=0 . Then find the value of x. |
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Answer» X2+(3+2)x+6=0X2+3x+2x+6=0X(X+3)+2(x+3)=0(x+2)(x+3)=0x+2=0/x+3=0x= -2/x= -3 ans x = -2 or -3. |
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| 14699. |
√2x^2 - 2x - √3 |
| Answer» | |
| 14700. |
If the sum of fit |
| Answer» | |