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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 14701. |
Write all prime nos.lying between 1 to20 |
| Answer» 2,3,5,7,11,13,17,19 | |
| 14702. |
Write the odd consecutive numbers |
| Answer» 1,3,5,7,9,... | |
| 14703. |
Class 10 maths rd sharma |
| Answer» Which question | |
| 14704. |
(√3+1) = |
| Answer» ◆√3=1.73 ◆√3+1= 1.73+1= 2.73 | |
| 14705. |
find the first term of the AP whose common difference is 8 and fifth term is 0 |
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Answer» Here, d=8a_5=> a+4d=0 => a+4*8=0 => a+32=0 => a=-32.Therefore,1st term is -32 -32 -32 -32 -32 |
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| 14706. |
Perimeter of a sector= |
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Answer» Theta/360*πr^2 Pie r^2into theta/360° Perimeter of minor sector = 2r + (2πr×theta)/360°. |
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| 14707. |
Sin90+Cos60=? |
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Answer» 1 +1/2=2+1/2=3/2 3/2 1+ 1/2 = 3/2 1+1/2=3/2 |
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| 14708. |
Use euclid division algorithim to find the h.c.f of 441,567,693 |
| Answer» HCF= 63. | |
| 14709. |
Find the HCF of 168 and 126 |
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Answer» 168=2*2*2*7*3126=2*7*3*3Therefore, hcf=2*7*3 =42. 168=2×2×2×3×7 and 126=2×3×3×7 ,.....then the hcf becomes 2×3×7=42 |
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| 14710. |
Does the polynomial x2 + 2 have any zeros ? If so find them |
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Answer» x^2 +2= (x+√2)(x±√2). x= -√2 , x= -√2 -1 -1 Yes |
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| 14711. |
The perimeter of a right triangle is 60cm . Its hypotenuse is 25cm . Find the area of triangle |
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Answer» Perimeter of right traingle = 60 => hypotenuse+ base + height = 60 => 25 + base + height = 60 => base + height = 35 ........(1) . Now, area of traingle = 1/2 × base × height. From eqn (1) , area of traingle = 1/2 × 35 = 17.5 cm square. Answer kaise aaya.....explain kro n thora 17.5 cm square. |
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| 14712. |
Can any one provide me this year basic maths sample paper solution? |
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Answer» You can brought online educart book with basic sample papers of 2o20 But I am unable to post the pdf file of solutions Yes |
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| 14713. |
Sample paper 9 of class 10 |
| Answer» Ji mere pas hai science ka 9class ka u like ka | |
| 14714. |
What is the formula of (a+b)^2 |
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Answer» a^2+b^2+2ab a^2+b^2+2ab |
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| 14715. |
One card is drawn from a well shuffled deck of52 cards the probability that it is black queen is |
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Answer» 1/26 total no of cards =52total no of black queen=2therefore probability of a getting a black queen = total no of possible outcomes/total no of outcomes =2/52 or 1/26 [ANSWER] 1/26. |
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| 14716. |
Cos^4A - Cos^2 = sin^4 - sin^2A |
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Answer» Thanks brother Cos ^4 A - cos ^2 A = (cos^2 A)^2 - cos^2 A = cos^2 A (cos ^2 A - 1) = - cos^2 A(1-cos^2A) =- cos^2 A * sin^2 A =- (1- sin^2 A)*sin^2 A = (sin^2 A - 1)*sin^2 A = sin^4 A - sin^2 AHence, proved |
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| 14717. |
In polynomial exercise 2.2 how 3x2-x_4=12x2 |
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Answer» The zeroes are 4/3 and -1.The relation between zeroes and coefficient are α+β=4/3+(-1)=-1/3=-(coefficient of x) /(coefficient of x^2)αβ=4/3*(-1)=-4/3=(constant term)/(coefficient of x^2). The zeroes are 4/3 and -1.Relation between zeroes and coefficient are α+β=4/3+(-1)=-(coefficient of x) / (coefficient of x^2)αβ=4/3*(-1)=(constant term) /coefficient of x^2) Puchna kya chahte ho bhai aap??? |
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| 14718. |
Ho to draw instructions |
| Answer» instructions nhii constructions hota h?? | |
| 14719. |
BPT. Theorem |
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Answer» If a line is drawn parallel to one side of triangle to intersect the other two sides in distinct point the other two side are divider in the same ratio Basic Proportionality Theorem was first stated by Thales, a Greek mathematician. ... Basic Proportionality Theorem (can be abbreviated as BPT) states that, if a line is parallel to a side of a triangle which intersects the other sides into two distinct points, then the line divides those sides in proportion. If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct point s,the other two sides are divided in the same ratio. |
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| 14720. |
Kisi ne maths or sci ka new pattern of question paper dekha h plz batoo n |
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Answer» Check the sample papers.... Plz tell me about this sis Hmm dekha hai.. |
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| 14721. |
Find the mean of first five prime numbers? |
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Answer» 5.6 5.6 First five prime numbers are 2, 3, 5, 7 and 11.The mean or the average formula is = Sum/no. = (2 + 3 + 5 + 7 +11)/5 = 5.6. Sorry 2 2.5 |
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| 14722. |
Find the roots of the quadric equation /2×"+7+/2=0 |
| Answer» Question kya h bhai aapka?? | |
| 14723. |
How many questions will ask from all chapters |
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Answer» Total no. of questions will be 30 It depends on marking scheme of chapters |
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| 14724. |
How many natural number between 120 to 500 which is divisible by 2 and 5 |
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Answer» Both of you have Wrong answer 500=120+5n-5500-120+5=5n385/5=n77= n 500 = 120+(n-1)* 2500=120+2n -2500-120+2= 2n382= 2nn=191H ence 191 no. divisible by 2 between 120to500 |
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| 14725. |
How many marks multiple choice queatians will come in board exam |
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Answer» 10 mcqs and 10 questions will include true false fill in the blanks or definition asking questions all 20 questions will carry 1 mark each 20 questions will be each of 1mark .....but I\'m not sure that all these will be mcqs or not....... 20 |
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| 14726. |
What is coprime factor |
| Answer» Two numbers are coprime if their highest common factor is 1. | |
| 14727. |
Important questions in triangle chapter |
| Answer» | |
| 14728. |
Give me some tips for math basic to pass in board exam |
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Answer» Do cbse guess paper 2019-20 Solve only ncert book but completely Practice more as practice makes a man perfect. Padho aur pass ho jao Just practice ncert properly.All exercises as well as examples.Need not to use any other book . |
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| 14729. |
Give relation between volume of cylinder and cone |
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Answer» Well done It is its one third part |
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| 14730. |
Express the following as ratio in the simplest form(c) 50 p to Rs 3 |
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Answer» 3 rs = 300 p50 pRatio = 50/300 = 5/30 = 1/6 1:6 First we convert 3rupees into paisa by multiplying ? then3×100=300 paisa50/300=1/6 |
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| 14731. |
Express the following as ratio |
| Answer» Kya express karu? | |
| 14732. |
How to slove trigonometric identies |
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Answer» turn the identities in simpler form i.e. Sin and Cos Only Practice |
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| 14733. |
The probability of getting a bad egg in a lot of 400 is 0.035 the number of bad eggs in the Lot is ? |
| Answer» 14 | |
| 14734. |
Th |
| Answer» | |
| 14735. |
The distance of the point (2,3)from the X-axis |
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Answer» 3 units 3 units |
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| 14736. |
Important question in exam all chapters |
| Answer» | |
| 14737. |
If tanA=cotB prove that A+B=90° |
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Answer» Cot(90- A)=CotB90= B+ A cot(90°-A)=cotB............90°-A=B......... therefore , A+B=90° |
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| 14738. |
Aerthmetic progreation |
| Answer» Arithmetic Progression | |
| 14739. |
2+7888 |
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Answer» 7890 7890 7890 bro 7900 2 + 7888 = 7890 |
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| 14740. |
Simplify 1+[1/2+1/3+1/6+(3/4-13)] |
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Answer» =1+[1/2+1/3+1/6+(3-52/4)=1+[1/2+1/3+1/6-49/4]=1+[3a+2+1/6-49/4]=1+[6/6-49/4]=1+[1-49/4]=1+[4-49/4]=1+[-45/4]=1-45/4=4-45/4=-41/4=-10.25 -10.25 |
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| 14741. |
Find value of k in 2x + 3y = 5 , 4x + ky = 10 |
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Answer» K= 6 1 |
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| 14742. |
Exercise 10.2 Questions 13 |
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Answer» Or solution h bhai kis ka Similarly, we can prove thatBOC + AOD = 180° Given: ABCD is a quadrilateral circumscribing a circle whose centre is O.To prove: (i) AOB + COD = (ii) BOC + AOD = Construction: Join OP, OQ, OR and OS.Proof: Since tangents from an external point to a circle are equal.AP = AS,BP = BQ ……….(i)CQ = CRDR = DSIn OBP and OBQ,OP = OQ [Radii of the same circle]OB = OB [Common]BP = BQ [From eq. (i)] OPB OBQ [By SSS congruence criterion] [By C.P.C.T.]Similarly, Since, the sum of all the angles round a point is equal to AOB + COD = Similarly, we can prove thatBOC + AOD = |
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| 14743. |
Exercise 10.1 Question 13 |
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Answer» Post galatisa ho gay There are only 4 questions in that exercise |
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| 14744. |
Ex 3.1 questions 1 ,2 ,3 |
| Answer» | |
| 14745. |
The upper limit of the median class in the given data is(questin from spq |
| Answer» | |
| 14746. |
How to teach circle concept? |
| Answer» | |
| 14747. |
Chapter 13 exercise 13.3 examples with solutions |
| Answer» | |
| 14748. |
Pichhle 5 sal ke sample paper |
| Answer» | |
| 14749. |
SecA+TanA=4 find sinA.cosA |
| Answer» SinA = 15/17 and cosA = 8/17 . So, sinA×cosA = 15/17×8/17 = 120/289. | |
| 14750. |
Volume of frastum H=20,R=14,r=7 |
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Answer» Surface area and volumes 7186.67 |
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