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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 15051. |
Why is radius of circle is perpendicular to tengent |
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| 15052. |
Two composite number |
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Answer» 4,6 4,9 10 and 12 6,8 |
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| 15053. |
Prove pythagoreas theorm |
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Answer» Pythagoras TheoremStatement: In a right angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.\xa0Given: A right triangle ABC right angled at B.To prove: AC2\xa0= AB2\xa0+ BC2Construction: Draw BD\xa0ACProof :We know that: If a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse, then triangles on both sides of the perpendicular are similar to the whole triangle and to each other.ADB\xa0ABCSo,\xa0(Sides are proportional)Or, AD.AC = AB2\xa0... (1)Also,\xa0BDC\xa0ABCSo,\xa0Or, CD. AC = BC2\xa0... (2)Adding (1) and (2),AD. AC + CD. AC = AB2\xa0+ BC2AC (AD + CD) = AB2\xa0+ BC2AC.AC = AB2\xa0+ BC2AC2\xa0= AB2\xa0+ BC2Hence Proved. It\'s given in ncert on page no. 145. ( theorem 6.8) In a right angled traingle, hypotenuse square is equal to the sum of perpendicular square and base square. Prefer ncert book |
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| 15054. |
2p+1 |
| Answer» ??? | |
| 15055. |
19990897654321 |
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Answer» Are you all in 10 That was a time pass Is that your roll no for board hii myank ye kya he |
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| 15056. |
If ap is 3:1 |
| Answer» What is the question?? ? | |
| 15057. |
Math Basics questions in 2020 board exam |
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Answer» See previous paper Like a previous year question paper... |
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| 15058. |
The center of a circle is ( x-2,x-1).findx if the circle passes through (2,-2)and(8,-2). |
| Answer» Given that, a circle passes through points ( 2, -2 ) and ( 8, -2 ).This implies that the circle\'s outer circumference passes through these points.We know that, the distance from circle to any point on the circumference is equal to each other as it is called as radius.So distance between both the points from the center is equal.So calculating distance from center for point ( 2, -2 ) we get,=> √ ( x + 2 - 2 )² + ( x - 1 - ( -2 ) )² = Radius=> √ ( x + 0 )² + ( x - 1 + 2 )² = Radius=> √ x² + ( x + 1 )² = Radius ... ( 1 )Now calculating the distance between Center to ( 8, -2 ) we get,=> √ ( x + 2 - 8 )² + ( x - 1 - ( -2 ) )² = Radius=> √ ( x - 6 )² + ( x - 1 + 2 )² = Radius=> √ ( x - 6 )² + ( x + 1 )² = Radius ... ( 2 )Equating the LHS of ( 1 ) and ( 2 ) we get,=> √ x² + ( x + 1 )² = √ ( x - 6 )² + ( x + 1 )²Squaring on both sides, we cancel the roots. Hence we get,=> x² + ( x + 1 )² = ( x - 6 )² + ( x + 1 )²( x + 1 )² gets cancelled and we get,=> x² = ( x - 6 )²=> x² = x² - 12x + 36=> x² - x² + 12x = 36=> 12x = 36=> x = 36 / 12 = 3Hence the value of x is 3.Centre coordinates: ( 3 + 2, 3 - 1 )=> Centre Coordinates: ( 5, 2 )Read more on Brainly.in - https://brainly.in/question/6595393#readmore | |
| 15059. |
sin 1.sin 2.sin 3................sin 179 |
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Answer» I am sorry I had made a mistake 0As it will include sin 90 . Sin 90 is 0 and anything multiplied by 0 becomes0. Plz give solution 1 |
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| 15060. |
What is real root |
| Answer» A real root is a solution to an equation which is also a real number. | |
| 15061. |
5.2 question 2 |
| Answer» U want how to solve or only tick the mcq | |
| 15062. |
Find the 453root |
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Answer» Let we asume that √3 is rational i.e it can be qritten as a/b. √3=a/b(where a and b are co prime ). squaring on both sides. (√3)square=(a/b) square. 3= a square/b square. 3b square=a square______(1). 3 divides a square so 3 divides a also. a=3c_____________(2). from 1 and 2 equation. 3c square=3b square 3c square=b square. __________(3) 3divides b square so 3 divides b also. from 2 and 3 wquation it is proved that 3 is a common factor of a and b,which is a contradiction of our assumption this is due ti our wrong assumption .Si √3 is irrational number Prove that √3 is irrational |
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| 15063. |
If the first three terms of an A.P. are b,c,2b,then find the ratio and of b and c... |
| Answer» I myself got the answer....Here is it ..........The common difference between the terms would always be equal....i.e. =a2-a1=a3-a2 =c-b=2b-c =2c=3b =b/c=2/3Hence the ratio isb:c=2:3..... | |
| 15064. |
Square root of 100 |
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Answer» 10 10 its very commmon question The answer is 10 10 10 10 √100=10 |
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| 15065. |
What is the formula of section |
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Answer» Do u want section formula or area of sector formula Thita/360×πr2 |
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| 15066. |
Ex 7.3 qno 3 |
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| 15067. |
Iog2 |
| Answer» 0.301 | |
| 15068. |
Any two similar figures are congruent true or false |
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Answer» False This statement is false becauseCONGRUENT SHAPES are\xa0figures\xa0with the same size and shape. The lengths of the sides and the measures of the angles are identical. They\'re exact copies, even if one is oriented differently.\xa0SIMILAR SHAPES are\xa0figures\xa0with the same shape but not\xa0always\xa0the same size. No False |
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| 15069. |
3xsquare minus square root6 minus 4 |
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Answer» -1 -1...because (3)^2-(√6)^2-4 = 9-6-4= 9-10=-1 |
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| 15070. |
Solve x square - 3 x minus 10 by completing square method |
| Answer» x=5 or x=-2 | |
| 15071. |
Find the coordintes of the points of trisection of the line segment joining (4,-1) and (-2,-3). |
| Answer» (2,-5/3);(0,-7/3) | |
| 15072. |
ABC is a right angled Triangle at c then the value of sec(a+b)is |
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Answer» It is not defined Infinity |
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| 15073. |
Prove that sinA(1+tanA)+cosA(1+cotA)=secA+cosecA |
| Answer» Step-by-step explanation:/*By\xa0Trigonometric\xa0identity:sin²A+cos²A\xa0=\xa01\xa0*/Therefore, | |
| 15074. |
Find the Hcf of 135and225 |
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Answer» HCF is 45 225=135*1+90135=90*1+4590=45*2+0HCF=45 |
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| 15075. |
Is misclineous exercise in syllabus for board exam |
| Answer» Nope.Buddy | |
| 15076. |
Check whether (5,-2),(6,4)and(7,-2)are the vertices of an isoceles triangle |
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Answer» √37 LetA ( 5 , -2)B (6 , 4)C ( 7 , -2)\xa0Length of each sides\xa0AB = BC = √37Hence verified that these vertices are of an isosceles triangles |
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| 15077. |
Value of cos30 |
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Answer» Root3÷2 √3/2 √3/2 |
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| 15078. |
Yadi cot A = 8 ho to sin A or sec A ka man gyat kijiye |
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Answer» SinA=1/3 and secA=3/8 Can u plz check ur ques. again !!!because I\'ve seen the same ques in ncert book ch-8 exercise-8.1 ques 4 in which " 15cotA =8 " is given.......and you\'ve wrote only cotA =8 in ques........... |
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| 15079. |
How to solve 4x^2+13x-450=0 by splitting the middle term? |
| Answer» Can\'t be done because it has no real roots | |
| 15080. |
Find x and y if vertices of llgm are (1,2) (4,y) (x,6) (3,5) |
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Answer» Here, x=6 and y =3 Step-by-step explanation:Let ABCD is a parallelogram with vertices (1,2) ; (4,y) ; (x,6) ; (3,5) respectively.As we know thatThe mid-points of two diagonals must be same.So, we will apply\xa0"Mid point rule":Mid point of AC is given byMid point of BD is given byNow, Mid point of AC = Mid point of BDHence, The value of x = 6 and y = 3. |
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| 15081. |
Basic maths me sbse jyada question kis chapter se aayenge? |
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Answer» You can get the idea on how the questions will come in board exams:Click on the below link to get the sample paper issued by CBSE :Basic paper:http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsBasic_SQP.pdfStandard paper:http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsStandard_SQP.pdf Trigonometery se 12 marks ka question aayega There is very least difference between basic and standard you will not get any long questions in basic else everything is same Ncert book |
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| 15082. |
7cm,24cm,25cm |
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| 15083. |
Exercise 13.4 question answers |
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| 15084. |
Chpter13 Ex 13.1 quetion 4 |
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| 15085. |
What is formula of (a+b)2 |
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Answer» a^2+b^2+2ab A2+b2+2ab Sorry for this .... Sorry suhana g but ham log jo yek bar decide kar late use kabhi nahi badalte isiliya ham name nahi bata sakte.... a^2+2ab+b^2 a² + b² + 2ab. Kya yrr .....a^2+b^2+2ab (a+b)^2 = a^2+b^2+2ab |
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| 15086. |
Formula to find Area of triangle of class 10 |
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Answer» Right triangle?? 1/2× base × height 1÷2 ×base×corresponding altitude |
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| 15087. |
Vector |
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| 15088. |
All formula of chapter-13 |
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| 15089. |
Ex 8.2 maths answer |
| Answer» 1.1. 12. 23. 3root2-root6÷84. 43-24root3÷115. 67÷122.1.A2.D3.A4.C3. angleA=45°,angleB=15°4.1.False2.True3.False4.False5.True | |
| 15090. |
Prove that √5 is irrational number.if it is so,then prove 3+√5 is also a irrational number. |
| Answer» Let\'s prove this by the method of contradiction-Say,\xa0√5 is a rational number.\xa0∴ It can be expressed in the form p/q where p,q are co-prime integers.⇒√5=p/q⇒5=p²/q² {Squaring both the sides}⇒5q²=p² (1)⇒p² is a multiple of 5. {Euclid\'s Division Lemma}⇒p is also a multiple of 5. {Fundamental Theorm of arithmetic}⇒p=5m⇒p²=25m² (2)From equations (1) and (2), we get,5q²=25m²⇒q²=5m²⇒q² is a multiple of 5. {Euclid\'s Division Lemma}⇒q is a multiple of 5.{Fundamental Theorm of Arithmetic}Hence, p,q have a common factor 5. this contradicts that they are co-primes. Therefore, p/q is not a rational number. This proves that\xa0√5 is an irrational number.\xa0For you second query, as we\'ve proved\xa0√5 irrational. Therefore\xa0√5+3 is also irrational because sum of a rational and an irrational number is always an irrational number. | |
| 15091. |
If zeros of quadratic equation are resiprocal of eachother 3x²-10x+k .Thae find value of k. |
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Answer» 3 Given in the question the equation:3x² - 10x + k = 0suppose 1st root of this equation is rso as stated in the question, second root of this equation will be 1/rAdding the roots gives = −b/aMultiplying the roots gives = c/aa b c3x² - 10x + k = 0r x 1 / r = c / ar / r = k / 31 = k / 33 = k 3 |
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| 15092. |
Cot90+tan0 |
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Answer» 0BUT HOW Sorry for oo 0 O Aapne bataya nhi aapka question wrong tha ya right? Hello sahil ji 0 0 |
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| 15093. |
Area of two similar triangle |
| Answer» 22/7Rsquare | |
| 15094. |
The LCM of smallest two digit composit number and smallest composit number is a 44b 4c 20d 14 |
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Answer» LCM=20 Oops!??sorry 2 digit * Sahil...smallest digit composite number is 10 not 12. Smallest two digit composite number is 12.....smallest composite number is 4.So,their LCM will be 12 C) 20 |
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| 15095. |
The following frequency |
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| 15096. |
What is latest syllabus of class 10 every subject topic wise |
| Answer» What Qution | |
| 15097. |
At t minutes past 2pm the time needed by the minutes hand of a clock |
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| 15098. |
If the sum of first n terms of an ap is given by sn=2n²+n . Find its nth term |
| Answer» Put the value of n as 1 Then,Sn =3Then same as2,3 a=sn=1a2=S2-S1 and so onThen find the ap and find nth term by formula,an=a+(n-1)dHope this may help u | |
| 15099. |
Chapter 9of class 10 |
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Answer» What is the questions say claerly Which subject Write clear What chapter 9of class 10 ???? Height and distance Hllo |
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| 15100. |
Find the no. Of cubes of side 2cm which can be cut of side 6cm |
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Answer» 27 Volume of 6 cm cube = 6×6×6 = 216 cm cube. Volume of 2 cm cube = 8 cm cube. So, number of cubes = 216/8 = 27 . But how 27 cubes 27 cubes |
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