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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 15451. |
Ncert book se board exam mein kitna percent aata hai |
| Answer» 60% | |
| 15452. |
2/5-3 is irrational . Prove it where /5 os irrational |
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Answer» Find HCF of the following number by using Euclid division lemma A-144&198B-155&1385 5-√3=a\\b5-a/b =√3We get √3=5-a/b5b-b/b5-a/b irrationalSo 5-√3 is irrational |
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| 15453. |
H9 |
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| 15454. |
Can you explain the condition required for a unique solution of a equation |
| Answer» Condition for Unique Solution to Linear EquationsA system of linear equations ax + by + c = 0 and dx + ey + g = 0 will have a unique solution if the two lines represented by the equations ax + by + c = 0 and dx + ey + g = 0 intersect at a point. i.e., if the two lines are neither parallel nor coincident. | |
| 15455. |
If cosecA-cotA=4/5, then prove that cosecA=41/40. |
| Answer» (cosecA - cotA)^2={4/5}^2, cosecA^2 +cotA^2 - 2coseccot= 16/25, 1+cotA^2 +cotA^2 - 2cosA/sinA^2 = 16/25, 1 + (2cos^A - 2cosA)/sin^2A = 16/25, 1 +{-2cosA(-cosA +1)}/sin^2A = 16/25, 1+{-2cosA(1- cosA)}/(1-cosA)(1+cosA), 1+{-2cosA}/(1+cosA)=16/25, (1+cosA-2cosA)/(1+cosA)=16/25, (1-cosA)/(1+cosA)=16/25, on cross multiplying rhs and Lsh,( 25 -25cosA = 16 +16cosA),( 9 = 41cosA),( cosA =9/41),(cos= adj side/hypot),(So, here using Pythagoras theorem we get perpendicular=40,hypotenuse=41& base= 9),cosecA=hypot/perpendicular, (cosecA = 41/40) hence proved It take long time to solve it on mobile by using keypad so please do likes ? | |
| 15456. |
draw tangents from an external point without using the center of that circle |
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| 15457. |
Find hcf and lcm of 404 and 96 and verify that hcf× lcm product of the two given numbers |
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| 15458. |
Factorise x 4 + x cube + x square + x |
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| 15459. |
What is height and distance |
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| 15460. |
6.3 ka 10 question |
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| 15461. |
A tv reporter was given a task to prepare a report on the rainfall of the city dispur |
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| 15462. |
If the ratio of the length of a pole and its shadow is 1:1 then find the angle of elevation of sun. |
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Answer» 45 tan45 |
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| 15463. |
Do metals react with oxygen only when they are burned? |
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Answer» No, Metal also react with oxyzen and make metaloxide No this is not true Nopes No |
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| 15464. |
Exercise 8.2 question no. 3 |
| Answer» Tan(a+b)=√3Tan (a+b)=tan60SoA+B=60 1Similarly A-B=30 2By adding 1 ,22A=90A=45,B=15 | |
| 15465. |
Find the value of p for which the numbers 2p-1,3p+1,11are in ap.hence,find the numbers |
| Answer» 2p+1-(3p+1)=11-(3p+1). 2p+1-3p-1=11-3p-1. -p=10-3p. -p+3p=10. 2p=10. p=5 | |
| 15466. |
Prove that sec(1-sinA)(secA+tanA)=1 |
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| 15467. |
In an equilateral triangles its two vertices A(0,0)and B(3,√3). Find its third vertex . |
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| 15468. |
The length of the diagonals of a rhombus are 16cm and 12cm. Find the length of side of the rhombus |
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Answer» Let side of shape be x Digonal Of rhombus is 16 and 12cm diagonal bisect at 90So half of digonals are 8cm and 6cm By using Pythagoras theorem X squre =16squre + 12squre X squre =256 + 244X =Side of rhombus = 10cm 10 |
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| 15469. |
Hii, good evening everyone......Is anyone online?? |
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Answer» Okk Armaan s fan r u a girl or a boy??Tell Plz Riya I have one request.. Don\'t write my full name here.. Call me Deep or Deepu, that sit.. Plz Oh, sorry Ankesh ? Bye ? Hii deepika Bye guys Deep baat ke blou ki itni zaldi to sec bhi ni badalta jitni zaldi tum naam change krti ho Hii . Hi Ankesh Hello deep Hey Ohhk.... Me from prayagraj Are????? New Delhi nd u? are* From where u have Oh Doctor? Thanks And your Wow!!!!! Nice!! Great!!!???? Ya Is ur dream IAS?? Wlc Thanks? Ok as your wish It\'s a secret.....so NO HINT !! ?? Plz give me some hint Ok Nope... Aditi Maybe... Can i guess I can\'t tell sorry.... Your name Yupp? U know me Hi hello.....how r u?? Hello Hi New Delhi Punjab aur aap?? So Riya, where r u from? Hmm.... It\'s ok Ohh...sorry for this mistake.....mujhe lga ap meri frnd wali riya gupta ho? Ok Secret means secret ? no one can know that secret except me!!!?? Nhi Ku?? Ap Riya Gupta hona?? It\'s a secret!? Aapka name?? Asoka name??? Hi Riya.. Hi |
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| 15470. |
If the vertices of an equilateral triangle are (0,0)and (3,0) find the third vertices |
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| 15471. |
Cosa-sina+1 |
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| 15472. |
The sum of the first n term of an Ap is 3n^2÷2+5n÷2.find its nth term and the 25th term |
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| 15473. |
Construction of similar triangle when scale factor is more than one |
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| 15474. |
Construction of similar triangle when scale factor is more than q |
| Answer» Hij | |
| 15475. |
???? न छेड़ मेरा वो किस्सा, बड़ी लम्बी कहानी है।। ...किसी गैर को क्या कहे जी अपनो की महेरबानी है☺☺☺? |
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Answer» ꧁⭕*KING*⭕๑▬๑꧂ ꧁⭕???????⭕๑▬๑꧂ |
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| 15476. |
If cos theta =sin theta then find the value of tan 6theta |
| Answer» =tan6theta.......= sin/cos*6.....=sin/sin*6.....=1*6.....=6..Ans:- | |
| 15477. |
If the first term of an AP are b, c and 2b then find the ratio of b and c |
| Answer» Step by Step explanation.a = b\xa0a2 = 2bd = c - dc = -c2b - 2c{tex}\\frac {c}{2c}{/tex}=\xa0{tex}\\frac {1}{2}{/tex} | |
| 15478. |
Find the point on the x axis which is equidistant from (2, - 5) and (- 2,9) |
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Answer» (0 , 2) Gst. Good ?⏰?? night frnds |
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| 15479. |
Chapter 6 exercise 6.2 question 6 |
| Answer» Plz write question | |
| 15480. |
If p,q are zeroes of polynomial f(x)=2x2-8x+3, find the value of p2+q2 |
| Answer» p+q=-(-8÷2)=4And pq=3÷2(p+q)^2=p^2+q^2+2pq4^2=p^2+q^2+2×3/216-3=p^2+q^2p^2+q^2=13 | |
| 15481. |
The distance of the point P(4,-3)from the origin is :a) 1Unit (b) 3 (c)5 (d) 7 |
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Answer» Its unit is five The given point is P (4, -3).Distance of point P from x-axis is -3 units.Distance of point P from y-axis is 4 units.Distance of point P from origin = OP, where O is the origin.From P draw line A perpendicular to x-axis.You can observe that OAP is a right angled triangle with OA = 4 units, AP = -3 units.So, using Pythagoras theorem,OP2 = 42 + (-3)2 = 25=> OP = 5 unitsHence, the distance of point P from origin is 5 units. 5unit |
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| 15482. |
Prove that underroot 2 is an irrational number |
| Answer» Let\xa0√2 be a rational number\xa0Therefore,\xa0√2= p/q [ p and q are in their least terms i.e., HCF of (p,q)=1 and q\xa0≠ 0On squaring both sides, we get\xa0 p²= 2q² ...(1)Clearly, 2 is a factor of 2q²⇒ 2 is a factor of p² [since, 2q²=p²]⇒ 2 is a factor of p\xa0Let p =2 m for all m ( where m is a positive integer)Squaring both sides, we get\xa0 p²= 4 m² ...(2)From (1) and (2), we get\xa0 2q² = 4m² ⇒ q²= 2m²Clearly, 2 is a factor of 2m²⇒ 2 is a factor of q² [since, q² = 2m²]⇒ 2 is a factor of q\xa0Thus, we see that both p and q have common factor 2 which is a contradiction that H.C.F. of (p,q)= 1 Therefore, Our supposition is wrongHence\xa0√2 is not a rational number i.e., irrational number. | |
| 15483. |
If secA+tan A=p Prove that sin A = psquare-1 divided by p square +1 |
| Answer» SecA+tanA=p ----------------------------(1)We know that,sec²A-tan²A=1or, (secA+tanA)(secA-tanA)=1or, p(secA-tanA)=1or, secA-tanA=1/p -----------------------(2)Adding (1) and (2) we get,2secA=p+1/por, secA=(p²+1)/2p∴, cosA=1/secA=2p/(p²+1)∴, sinA=√(1-cos²A)=√{1-4p²/(p²+1)²=√{(p²+1)²-4p²}/(p²+1)²=√(p⁴+2p²+1-4p²)/(p²+1)=√(p²-1)²/(p²+1)=(p²-1)/(p²+1) (Proved) | |
| 15484. |
Exercise 13 trigonmateric identities RS aggarwal solution |
| Answer» 1. sin2A+cos2A=12. 1+tan2A= sec2A 3. 1+cot2A= cosec2A | |
| 15485. |
If p = sec A- cosec A and q = sinA - cos then prove that p(q²-1) + 2q =0 |
| Answer» H de jh dg ni he tu hi ud dh ni is | |
| 15486. |
if 5 sin A + 7 cos A = 7, show that7 sin A-5 cos A = ± 5 |
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| 15487. |
Cos sq 67-sinsq23 |
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Answer» Cos^2 67- Sin^2 23Cos^2(90-23) - Sin^2 23Sin^2 23 -Sin^2 230 Hence proved... cos sq67 - sin sq23=cos sq(90-23) - sin sq23=sin sq23-sin sq23=0 Cos²a 67 - cos²(90 - 23).................. Cos²a67 - cos² 67................ 0 is the answer |
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| 15488. |
Hloooo |
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Answer» Excuse me!! Mere answers reply kro Maine kr diya answer polarity wala question h science wala me dekhiye Question kya h?? mera answer Sab gye ..!! Ok...bye.. Hello payal...? Hii. Shreya and ziddi ji.... ??? Kya question h apka..?? mera science wala question ka answer kisi ne nahi diya mujhe?????? Maine august mai join kiya h isko Jo marzi keh lo #pushkar Tum nayi ho kya yaha par acha ye app personal chat ke liye h kya Ziddi..??? Nhi... But itna ziddi kon hota hhh...... ??????? Hasne ki kya baat h Ziddi....?? |
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| 15489. |
Value of sin(90-1) |
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Answer» Cos 1 Cos A CosA.... Sin (90-A) = Cos A |
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| 15490. |
Important questions from chapters 1 2 3 4 5 8 for periodic test |
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| 15491. |
Choose any three numbers to solve this proble{. } +(. ) + (. ) =30And number is 1,3,7,9,11,13,15 |
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Answer» sry it\'s not 3,7,9answer is 9,7,15 3,7 ,9 We what tatal 30 not 31 13+9+9 |
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| 15492. |
How to read standard mathematics book |
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Answer» Hello bhai sun standard maths me NCERT Book k questions thode tede aayege don\'t take tension Hey bro..... Standard or basic me kuch fark nhi hhh bas itna hh unke liye normal question aaenge aur hmare liye question thode tough ho jaenge... Agar books ? ? janni hh to me sabse phle NCERT bollooongi because 70% issi me se atta hhh aur.. Vese r. D. Is best... For practice... ?????????? |
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| 15493. |
How to find the upper limit of the median class |
| Answer» First circle to the highest frequency when it\'s upper limit of the median class | |
| 15494. |
√567 |
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Answer» 23.82 23.82 36 |
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| 15495. |
How many tangent can a circle have |
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Answer» Infinite according to circle Infinite as my sperms are infinite Infinite tangets |
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| 15496. |
HCF of 385 and 100 1 |
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Answer» 385 =5×7×111001 =77×13The common in both is 77.So, the HCF of 385 and 1001 is 77. Thanks 1001=385 ×2+231385=231×1+154231=154×1+77154=77×2+0Hence 77 is the HCF of 1001 and 385 |
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| 15497. |
Find the middle term of the sequence formed by all the natural numbers from 9 to 95. |
| Answer» The middle terms of sequence from is 46 ,47 | |
| 15498. |
Find k for which the equation x square - kx-12=0 has two equal roots. |
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Answer» Please give full solution K=12/x |
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| 15499. |
The decimal expansion of 7/4 terminates after how many places of decimals?? |
| Answer» 2 | |
| 15500. |
The perimeter of a triangle with vertices (0,4),(0,0),(3,0) is ?? |
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Answer» First find length of each sides of ∆Let A( 4 , 0) B(0, 0) and C (0 , 3)use distance formula,AB =√(4²+0) =4BC= √(0+3²) = 3CA =√(4²+3²) =5now ,perimeter of ∆ = 3 + 4 + 5= 12 unit The perimeter of traingle is 12. |
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