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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 15801. |
Given that sin(A+B)=sinA cosB+coAsinB ,find the value of sin 75°. |
| Answer» According to question we have sin (A+B) = sin A cos B + cos A sin B, we need to\xa0find the value of\xa0{tex}\\sin 75 ^ { \\circ }{/tex}.Putting\xa0{tex}A = 45 ^ { \\circ }{/tex}\xa0and\xa0{tex}B = 30 ^ { \\circ }{/tex}\xa0in sin (A+B) = sin A cos B + cos A sin B,we get{tex}\\sin \\left( 45 ^ { \\circ } + 30 ^ { \\circ } \\right){/tex}\xa0{tex}= \\sin 45 ^ { \\circ } \\cos 30 ^ { \\circ } + \\cos 45 ^ { \\circ } \\sin 30 ^ { \\circ }{/tex}{tex}\\Rightarrow \\sin 75 ^ { \\circ }{/tex}{tex}= \\frac { 1 } { \\sqrt { 2 } } \\times \\frac { \\sqrt { 3 } } { 2 } + \\frac { 1 } { \\sqrt { 2 } } \\times \\frac { 1 } { 2 }{/tex}{tex}= \\frac { \\sqrt { 3 } } { 2 \\sqrt { 2 } } + \\frac { 1 } { 2 \\sqrt { 2 } }{/tex}{tex}= \\frac { \\sqrt { 3 } + 1 } { 2 \\sqrt { 2 } }{/tex} | |
| 15802. |
If sin A =9/41,comput3 cos A and tan A |
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Answer» SinA=1/cos =41/9 Given,\xa0{tex}\\angle{/tex}B =\xa090°.Let BC = 9 and AC = 41sin A{tex}= \\frac { \\text { Perpendicular } } { \\text { Hypotenuse } } = \\frac { \\mathrm { BC } } { \\mathrm { AC } } = \\frac { 9 } { 41 }{/tex}By Pythagoras\' theorem, we haveAC2\xa0= AB2 + BC2{tex}\\Rightarrow{/tex}AB2= AC2\xa0- BC2= 412\xa0- 92\xa0= 1681 - 81\xa0= 1600{tex}\\Rightarrow AB = 40{/tex}{tex}\\cos A = \\frac { \\text { Base } } { \\text { Hypotenuse } } = \\frac { A B } { A C } = \\frac { 40 } { 41 }{/tex}{tex}\\tan A = \\frac { \\text { Perpendicular } } { \\text { Base } } = \\frac { B C } { A B } = \\frac { 9 } { 40 }{/tex} |
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| 15803. |
If 2,6,10,14,18......form an A.P. 5hen its nth term is |
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| 15804. |
If the sum of a1+a2=50 for an A.P. Find the value of a1+a2+..... +a10? |
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| 15805. |
Ncert chapter 6 ka example 7 of class 10th |
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| 15806. |
R.s aggarwal class10th exercise 4B ka question no: 14 solve |
| Answer» In rs aggarwal hint box the solution is given | |
| 15807. |
Give me a centroid formula i ch 7 |
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Answer» {(x1+x2+x3)÷3, (y1+y2+y3)÷3} (x1+x2+x3)÷3 x1+x2+X3 |
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| 15808. |
The sum of n terms of an AP is (5n²—3n).find the Ap and hence its 10th trem |
| Answer» S1=5(1)^2-3(1)=2=a1=aS2=5(2)^2-3(2)=14=a1+a2a2=14-2=12d=12-2=10A.P is 2, 12, 22.......a10=2+9(10)=92 | |
| 15809. |
The tem. of normal human body is 37c .In fahrenheite scale this temp.is |
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Answer» 98.6 degree fahrenheit 98.6 98.6 degree Fahrenheit 98.6 degree Fahrenheit 98.6 degree 98.6c |
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| 15810. |
If x=4-root 15 the find the value of (x+1÷x) |
| Answer» Using BODMASSx+1/x so here x=4root15Therefore first X/1.4root15 /1=4root15Now 4root15 + x4root15 + 4root15 = 8root15 | |
| 15811. |
show that (cosecA-cotA) ² =1+cotA/1-cotA |
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| 15812. |
1 CBSE paper |
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| 15813. |
Chapter 8.1 |
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| 15814. |
What is the formula of cos70 |
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| 15815. |
7*15+8*20+9*25........tnTn=? |
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| 15816. |
Express the trigonometry ratios sin A, secA,and tan A in term of cot A? |
| Answer» CotA =1/tanACotA=1/sinA×secA | |
| 15817. |
What is Euclids algorithm? and explain with examples. |
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Answer» Continued from above ...Where a=bq+r Euclid algorithm is a method to compute the hcf of two given positive Integers. |
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| 15818. |
Using the formula,cos A=√1+cos2A/2, find the value of cos 30°,it being given that cos 60°=1/2 |
| Answer» Given formula : cos A =\xa0{tex}\\sqrt{1}{/tex}\xa0+\xa0{tex}\\frac {cos2A}{2}{/tex}Also, cos60 = {tex}\\frac {1}{2}{/tex}Required to find : cos30Now,Let A = 30o, 2A = 60ocosA =\xa0{tex}\\sqrt{1}{/tex}\xa0+ {tex}\\frac {cos2A}{2}{/tex}cos30=\xa0{tex}\\sqrt{( } 1+1 / 2) / 2{/tex}cos30 =\xa0{tex}\\sqrt{( } 3 / 2) / 2{/tex}cos30 =\xa0{tex}\\sqrt {(\\frac {3}{4})} =\\sqrt \\frac {3}{2}{/tex}\xa0Therefore,\xa0{tex}\\cos 30=\\frac{\\sqrt{3}}{2}{/tex} | |
| 15819. |
express all trigonometrric ratios as cot |
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Answer» Tan=1/cot1+cot²=cosec²cot=_/`cosec²-1 Tan=1/cot |
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| 15820. |
If cot=3/4 show that √sec-cosec/sec+cosec=1/√7 |
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| 15821. |
Use euclid algorithm to find hcf of 1190 and 1445 Express in form of 1190m + 1445n |
| Answer» Sorry shayd misundrestanding ho gyi.. | |
| 15822. |
X^2 - 6x + 3 =0 solve this by completing square. |
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| 15823. |
Basic maths syllabus |
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Answer» Ncert All chapters of ncert..only questions will be little bit easy |
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| 15824. |
Rachnaye |
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| 15825. |
Finally Deepu kuch bolo |
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| 15826. |
Deepu we can be. Ha ya na me answer dena |
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| 15827. |
Hello deepu don\'t be sad |
| Answer» Electrolytic induction is a theory given by micheal farraday which states about the amount of product formed at the electrodes after passing a fixed amount of current | |
| 15828. |
What is the use of trignomentry in our daily life?? |
| Answer» Wit the help of trigonometry we can find height of tower building with shadow Trigonometry is use to calculate distance between stars and planets | |
| 15829. |
Can anyone suggest me some tips for the trignometory chapter?? (Especially EX - 8.4) |
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Answer» Bpt therom Break all the trigonometry ratio |
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| 15830. |
If the mean of the following distribution is 91find the missing frequencies |
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| 15831. |
The 2nd ,31st and the last term of an ap are 31 |
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| 15832. |
Which term of the AP 24,21,1,15.......is first negative term? |
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| 15833. |
Xi fi1-3 143-5 165-7 47-9 29-11 2Solve karo |
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| 15834. |
Find the ap whose firsr term is 6 |
| Answer» Common difference is not their. | |
| 15835. |
Basic math class x |
| Answer» Paper corrected by school teachers only | |
| 15836. |
Pai value |
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Answer» 22/7 or 3.14 3.14 22/7 |
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| 15837. |
Please give me all the formula of trigonometry identities |
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Answer» Bhai Youtube pe Dear sir ka trigonometry formula wala video dekh lo pura yaad ho jaye ga Sin^2+cos^2=1Sec^2-tan^2=1Cosec^2-cot^2=1 |
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| 15838. |
Please give me All the formula and identities of trignometry |
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Answer» Its very to right all the formulaes U go on this app, select maths , select ch:-Trigo and then , go to Notes.All the formula r there .?? Srry , I cant wrrite all the formulas here .Its very touhgh for me P/H .B/HP/B.Or u may learn like :-PBP / HHB ::--Papa (P) Bidhi (B) Piyoge (P) ,Ha (H) Ha (H) Beta (B).??????? Ok |
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| 15839. |
find all the zeros of 2x4-3x3-5x2+9x-3 if it is given that two of its zeroes are root3 and root -3 |
| Answer» Product of zeroes is -9 then EW. Is. x2-9 . Now divide the equation. By x2-9 . REDULT equal to zero and find the two new zeries | |
| 15840. |
find all the zeros of 2x4-3x3-5x2+9x-3 if it is given that two of its zeroes are 3 and -3 |
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| 15841. |
Has any one taken basic maths in class 10??? |
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Answer» If u want to take biology then u should choose basic and if u want to take maths then u should choose standard I have doubt wht is difference between basic and standard maths No ??medical and u ? Med Nope Deepu what sub are u going to take in. 11 No Yes |
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| 15842. |
11th 12th mein kon P.E lera aur kon I.P lera bathao.. |
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| 15843. |
Diffination of triangle |
| Answer» A polygon of three line side is triangle | |
| 15844. |
Find the value of (sin square 33 degrees +sin square 58 degree) |
| Answer» Sin square 33 degree+sin square58degreesin square(90-58)+sin square 58 cosec sqare 58 +sin square 581/sin square 58+ sin square 581 answer | |
| 15845. |
Find the value of (sin33°+ sin57°) |
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Answer» Because sin^2 (90-57)+cos^2(57)=1(as sinsquare theta + cos square theta =1) 1 |
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| 15846. |
Thals theorem |
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Answer» See theoram 6.1 0r 6.6 Trignomatry |
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| 15847. |
HCF of 144 and 180 is in the from of 13m-3 find m |
| Answer» Hcf of 144,180=1613m-13=16Then 13m=16+1313m=29m=29\\13m=2.23 answer | |
| 15848. |
What is 2x3 |
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Answer» 6 You dont no this 6 Hey pk, plz What happen bro.... 6 6 |
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| 15849. |
Find the value of tan1 tan2 tan3 .................tan89 |
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Answer» tan45 which is equal to 1 tan45 |
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| 15850. |
Divide polynomials 3x square -11x+10 divided by 3x-5 |
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Answer» Hey...bhai ache se bat kar kabhi einstein bhi fail hua karte the.... X-2 is the answer |
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