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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 16151. |
An A.P. consists of 43 terms if the sum of five middle most terms is 195 then the sum of the a.p. is |
| Answer» answer | |
| 16152. |
Class 7th |
| Answer» ???????? | |
| 16153. |
Rs aggarwal math book class 10 exercise 11 question 16 |
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| 16154. |
Yarr practical exam ka centre khud ka schoo hi hoga ya kisi dushre school me venue hoga....????? |
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Answer» 12th walo ka dusre school me 10th walo ka khud k school m Iske baare me nhi pta on exam centre I am sure perfectly sure okkk Are you sure..i am little bit confused about it??? Dushro k school me hoga bro.... |
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| 16155. |
What types of standard math I dont understand |
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| 16156. |
How to solve throrem 6.6 of triangle chapter with full process |
| Answer» Search on internet in Google | |
| 16157. |
How to prove theorem 6.6 of triangle chapter |
| Answer» Prefer rs agarwal | |
| 16158. |
Find the value of k for which the quadratic equation 2 |
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| 16159. |
solve y+5=65 |
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Answer» Board me aisa question nahi ayega Jo mere shaan me khilaf ho Y=65-5Y=60 60 y + 5 = 65y = 65 - 5y = 60 60 |
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| 16160. |
What should i choose?Standard math or Basic math to go in "science B group"? |
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Answer» Will i be able to take science biology by basic math!?? You can choose whatever you want according to waht you will opt in +1 Basic maths Because agr ap ne standard nahi liya toh ap ko bio bhi nahi milegi ? Standard maths |
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| 16161. |
Determine if the point (1,5),(2,3)and (-2,-11) are collinear. |
| Answer» orUsing the Distance Formula ,\xa01st and 2nd distance ,=>\xa0=>\xa0=>2nd and 3rd ,=>=>=>1st and 3rd point .=>=>=>so ,Ist and 2nd + 2nd and 3rd = 1st and 3rd is law of collinearity ,Lets check ,5+ 212 = 256217 not equal 256\xa0Hence ,It does not satisfy the condition , Hence they are not collinear . | |
| 16162. |
Find all the integers from 100 to 550, which are not divisible by 9? |
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Answer» The answer is 48 bro. Say thanks to your genius Ykdkxjt5inc epFC HR3y4uhhethd The sum of all integers between 100 and 550, which are divisible by 9 is 16425.Step-by-step explanation:Integers between 100 and 550, which are divisible by 9 are 108, 117, 126 , ....... 549Here, a = 108, d = 9, an(l) = 549By using the formula ,an = a + (n - 1)d549 = 108 + (n -1)9549 - 108 = 9(n -1)441 = 9(n -1)n -1 = 441/9n -1 = 49n = 49 + 1 n = 50By using the formula ,Sum of nth terms , Sn = n/2 [a + l]⇒ S50 = 50/2 (a + l)⇒ S50 = 25 (108 + 549)⇒ S50 = 25 × 657⇒ S50 = 16425Hence, the sum of all integers between 100 and 550, which are divisible by 9 is 16425 |
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| 16163. |
Diff between standard maths and basic maths |
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Answer» Thanks mr Gaurav seth Two levels of Mathematics in class 10\tThe two levels of Examination will be held in the subject of Mathematics in the Board examination for Class X in the year 2020 and the same shall not be applicable to the internal assessment in class X.\tThere shall not be two levels of Assessment/Examination for class IX.\tFirst level would be the same as the existing one, and the other would be an easier level.\tThe nomenclature for the two Examinations will be; Mathematics-Standard for the existing level of examination, and Mathematics-Basic for the easier level of examination.\tThe syllabus, class room teaching and internal assessment for both the levels of examination would remain the same; so that the students get an opportunity to study the whole range of topics throughout the year and are able to decide upon the level of Board examination depending upon their aptitude and abilities.\tThe Standard level will be meant for students who wish to opt for Mathematics at Sr. Secondary level and the Basic level would be for students not keen to pursue Mathematics at higher levels.\tA student will have the right to choose between the two levels of Examination at the time of submission of List of Candidates (LoC) by the affiliated school to the Board online.\tIn case student fails at any level of Mathematics, he/she can appear at the compartment examination as per norms of the Board. The student failed in Mathematics-standard will have the\xa0option\xa0to sit in the\xa0compartmental exam of Mathematics-Basic in place of Mathematics-Standard again.\tA student who qualifies the Mathematics-Basic, shall be given an option to appear in Mathematics-Standard at the time of Compartment exams as per norms of the Board, in case he/she changes his/her mind to pursue Mathematics at Senior Secondary level. |
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| 16164. |
Ap logo ne kon si maths li hai standard? or basic? |
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Answer» In language of maths the art of solving questions is much harder than making questions.:-Rohan Stark I have taken Standard because I am going take PCMB in science on class 11.What about you???;) Standard.....? Standard Standard Tum konse class m ho Standard Oo Basic Maths |
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| 16165. |
5x-4y+8=07x+6y-9=0 |
| Answer» 5 x - 4 y - 8 = 07 x + 6 y - 9 = 0Here, a1= 5, b1\xa0= -4, c1= 8a2= 7, b2= 6, c2\xa0= 9We see that\xa0{tex}\\frac { a _ { 1 } } { a _ { 2 } } \\neq \\frac { b _ { 1 } } { b _ { 2 } }{/tex}Hence, the lines representing the given pair of linear equations intersect at the point and the equations are consistent having unique solution. | |
| 16166. |
Hii guys which math you decided basic or stander |
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Answer» Maths is my favourite subject so I decided to read standard maths Guys why choose standerd Soory Standard Standard Standard Standard standard Standard and what about u |
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| 16167. |
The sum of two consecutive number is 11and their reciprocals is 11/28. Find the number? |
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Answer» Ok Given that - The sum of two numbers is 11 and the sum of their reciprocal is 11/28.Let the numbers be x and y respectively.Sum of numbers is 11.⇒ x + y = 11.... (i)⇒ y = 11 - x .... (ii)Sum of reciprocals is 11/28.⇒ .... (iii)Now, on solving (iii), Putting the value of (i) and (ii) here, we get - Hence, the required numbers are 7 and 4. |
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| 16168. |
The curved surface area of right cicular cone of height is 24 cm and base diameter 14 cm is |
| Answer» 2πrh2×22/7×7×2444×241056 | |
| 16169. |
What is the solution of Questions 6 and 7 of exercise 6.5 |
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| 16170. |
Evaluate tan5.tan25,tan65.tan85 |
| Answer» 1 | |
| 16171. |
The perimeter of two similar triangles ABC and PQR are 32cm. respectively. If PQ=12cm , find AB. |
| Answer» According to question it is given that triangles ABC and PQR are similar.Also, perimeter of ∆ ABC = 32 & Perimeter of ∆ PQR = 24Therefore,{tex}\\frac { \\text { Perimeter } ( \\triangle A B C ) } { \\text {Perimeter } ( \\triangle P Q R ) }{/tex}{tex}= \\frac { A B } { P Q }{/tex}{tex}\\Rightarrow \\frac { 32 } { 24 } = \\frac { A B } { 12 }{/tex}{tex}\\Rightarrow A B = \\frac { 32 \\times 12 } { 24 }{/tex}= 16 cm | |
| 16172. |
Evaluate:Sin^2 63°+ sin^2 27° ÷ cos^2 17°+cos^2 73° |
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Answer» Thank u..☺ First of all I would make it clear thatSin(90-a)= cos a.So, sin^2 63°would be cos^2 17°and cos^2 17°=sin^2 73°In the expression given in the question,(Cos^2 17°+sin^2 17°)/(sin^2 73°+cos^2 73)Since sin^2 a+cos^2 a=1, it would become 1/1=1Hence, the answer is 1. Plz ans.. |
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| 16173. |
If p and q are two prime number then what is thir hcf |
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Answer» 1 1 pq is their hcf |
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| 16174. |
Check whether6^n can end with the digit \'0\' for any natural number n. |
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Answer» 6^n=(2×3)n since fraction of this number is 2and 3 not 2 and 5.Therefore, 6^n cannot ends with zero for any natural no. n No |
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| 16175. |
When we get basic mathematics sample papee |
| Answer» After sometime..... | |
| 16176. |
Can you help me ? In math what is good and why? Standard math or basic math |
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Answer» Standard is good but if you going to opt medical then you can choose basic.... I know standard math is very significant in future but i have to go in medical categoriesSo please tell me ,will it be good to choose basic Standard math is good because it has many options in future....... |
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| 16177. |
Kya 10th class mein 2020 mein jo math ka paper Hoga usme method of completing the square aayega |
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Answer» Thank you krupa hogi aapke No no.... No Yes No |
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| 16178. |
Do elimination of trignometry ask in board |
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| 16179. |
In which school you study |
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Answer» Aps suratgarh L. B. S sec 3 rk puram new Delhi |
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| 16180. |
If the distance of P(x,y) from the point A(3,6)and B(-3,4)are equal , prove that 3x +y =5 |
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| 16181. |
(2x - 1) (x - 3) = (x+5) (x-1). |
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Answer» (2x-1) (x-3) = (x+5) (x-1)2x(x-3) -1(x-3) = x(x-1) +5(x-1)2x^2-6x-x+3 = x^2-x+5x-52x^2-7x+3 = x^2+4x-5x^2-11x+8 Albcels |
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| 16182. |
Prov that sin= sinr |
| Answer» Pleez type your question clearly..... | |
| 16183. |
If p(x,y) is any point on the line joining the points A(a,0) and B(0,b) then show that x/a+y/b=1 |
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| 16184. |
Prove thatSec^6A= tan^6A + 3tan^2Asec^2A + 1 |
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| 16185. |
If 15 cot a = 8 then the values of sin A and sec A are.? |
| Answer» CotA = 8/15 then cotA is B /P then. Find hypoteniu=17 sin A = p/h so is 15/17 and sec A is H /B then 17 /8 ans | |
| 16186. |
In a Ap :2,x,26.the value of x is |
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Answer» 2x = 2+262x = 28 X= 14 14 14 In AP, a2-a1=a3-a2So,. x-2=26-x 2x=28 x= 14 |
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| 16187. |
10 th class exercise 8.4 |
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| 16188. |
What are the syllabus of maths in half yearly exam |
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Answer» Kya 14 and 15 bhi h Chapter 1 to7 means Real number to coordinate geometry |
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| 16189. |
If the first 7 terms of an ap is 49 and first 17 term of an ap is 289 then find the n |
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Answer» 7 a7 = a + 6d = 49-------------(1)a17 = a + 16d = 289------------(2)Subtract (1) from (2) ; a + 6d = 49 a + 16d = 289(-) (-) (-) ————————— -10d. = -24010d = 240 : [ d = 24 ] Putting the value of d in (1) ;a + 6d = 49a + 6 × 24 = 49a + 144 = 49a = 49 - 144[ a = -95 ]An is not given in your question otherwise the formula of an is "a+(n-1)d"............ I think your question is incomplete |
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| 16190. |
If we opt for basic maths in cbse board exam , then can we take physics in class 11 ?? |
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Answer» No No you can n\'t take physics in 11th standard Yes u can take physics in class 11th but you cannot take maths as an extra subject also if you want so you have to appear in standard maths Ya sure Yes u can take physics in 11th No |
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| 16191. |
2{2x-1/x+3}-3{x+3/2x-1}=5 |
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| 16192. |
How to prove an Quadratic Equation using*competing the square method*? |
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| 16193. |
Cbse latest sample papers released ? |
| Answer» You can find it on my CBSE Guide | |
| 16194. |
Prove that sin70+cosec20/cos20+sec70 - 2cos70 .cosec20=0 |
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Answer» Please give me answer in brief.. 1+tan square |
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| 16195. |
How will we solve example 12 of chapter polynomial |
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| 16196. |
To make 6x2+5x=0 a prefect square, we need to add and substract............ |
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| 16197. |
If the angels of a trainge are in the ratio 1:2:6,determine the three angles |
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Answer» Let the angle be x 2x 6x and we know that sum of angle of triangle is 180. So x+2x+6x=180. 9x=180 x=180/9 x=20 so x=20,2x=2×20=40,6x=6×20=120 X,2x ,6x are the angles..as assumed.Now x+2x+6x =180Therefore 9x=180 x=20Now substituting the valye of x in assumption we get all three angles they are 20,40,120..Hope it helps u mate.. Let the angles be x,2x and 6x.Then, x+2x+6x=180 9x=180 x=20Therefore; angles are 20, 20×2=40, 20×6=120. |
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| 16198. |
What is difference between base maths n standard maths for 10std |
| Answer» If we Choose basic Math we will not able to take any stream related to math. But if we choose standard math we will able to take stream related to math. | |
| 16199. |
If nth term of an AP is 5-2n. what is the sum of n termt?? |
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Answer» n=1 5-2*1=3Similarly whenn=25-2*2=1n=35-2*3=-1 and so on...........This forms an AP =3,1,-1a=3 & d=-2 Sn =n/2[3+5-2n]=n/2[8-2n]=n/2*2(4-n)=n(4-n) N1=5-2(1)=3 ;n2 =5-2(2)=4 a=3;d=4-3 =1 sn=n/2(2a(n-1)d |
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| 16200. |
What is value of sin theeta |
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Answer» Of which degree As the degree of Sin Theta varies the value also varies, O.K. Degree? |
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