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16451.

Maths chapter 6

Answer»
16452.

Kya sach me mathematics ka question paper ncert me se hota hai??

Answer» Together with sa aata hai questions
NooooFrom oswaal rd sharma and rs aggarwal
Mane suna h ki paper ncert m se aata h
Consa set tha?
Hme bhi yhi kaha geya tha ki paper ncert se hota hai..but it was wrong for maths..sara paper rd sharma se tha but haan sci ka ncert me se extra ques hi pooche gye the...sst me sb extra..not a single ncert ques was there?..
Maine is baar ke board exams diye the..aur maths ke paper me sirf 4 ques ncert se the..but unki statement change thi and rest of the paper was from rd sharma.
16453.

Sin Q = cos Q

Answer» sin30°= cos60°, sin60= cos30, sin90= cos0 ,sin45= cos45
16454.

1/cosC

Answer» Hi
sec c
16455.

Impotant question of maths

Answer» Hcf problems
16456.

x²+x+1. Factorize

Answer» It\'s irrational sum
16457.

199+0

Answer» 199
199
ask able question.Don\'t waste your time
199
16458.

More information

Answer» ??
16459.

182 factor

Answer» 182 = 2 x 7 x 13
183=2×7×13??
16460.

Can we replace maths with any other subject in cbse class10

Answer» Iron man what an ironic name. I real want to be interested but sir,it is not intersted in me thank you for you kind advice sir very very thank you
Ya we can replace
Yaa information technology
No my dear , feel interest math because math os a easy subject.
16461.

Can you Send me last year question paper of maths!!!

Answer» They r available on google
They are available on many websites..check it!!
Yes
16462.

Sum of first n terms of odd number nsquare,nsquare-1,nsquare+1,2n-1

Answer» 1....
16463.

An electrician has to repair an electric fault on a pole height 5cm

Answer» type full question which is to be find
16464.

Prove ABC is similar to POR if AB Equal to PO

Answer»
16465.

Prove that sq root 2+3/sq root 2 is a rational no

Answer»
16466.

To find hcf of quadratic equation

Answer» Lcm ×hcf = a×b
16467.

Can you provide 2019 bord question paper

Answer» You can get question papers here :\xa0https://mycbseguide.com/cbse-question-papers.html
But link was not open
16468.

Solve for x and y ax/b - by/a = a+b , ax- by= 2ab

Answer» The given equations may be written as{tex}a^2x - b^2y = a^2b + ab^2{/tex} ....... (i){tex}ax - by = 2ab{/tex} ......... (ii)Multiplying (ii) by b and subtracting the result from (i),\xa0{tex}(a^2\xa0- ab)x = a^2b - ab^2{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}(a^2\xa0- ab)x = b(a^2\xa0- ab){/tex}{tex}\\Rightarrow{/tex}{tex}x = b.{/tex}Putting {tex}x = b{/tex} in\xa0(ii), we get{tex}a b - b y = 2 a b {/tex}{tex}\\Rightarrow b y = - a b{/tex}{tex} \\Rightarrow y = \\frac { - a b } { b } = - a{/tex}Hence, x = b and y = -a.
16469.

write the first four terms of the following sequence: an= n^2-2n+1

Answer»
16470.

1+cot^2 alpha /1+cosec alpha =cosec alpha

Answer» Break down al the things in sin, cos
16471.

Prove that cos A - sin A+1\\ cos A+ sin A-1= cosec A + cotA

Answer»
16472.

Prove geometrically sin 60° =√3\\2

Answer»
16473.

If cosec =2, show that sin ( Cot+----------. )=2 1+cos.

Answer» please write qiestion clear
16474.

What are most important chapters

Answer» All chapters are important because board asks from all chapters
Trigonometry triangle
16475.

Ch-7 ka 7 no

Answer»
16476.

First term syllabus

Answer» Hme kya pta..it is upto to ur school..
Ch 1,2,3,4,5,6,7,14,15
Hello koi h kya answer dene ke liye
16477.

Find in change in percentage from first term to second term of Rs 80 , Rs 120

Answer» 50%
16478.

4 + 3y= 4X

Answer» 3
16479.

Sin square 48° + sin square 42° ÷ cosec square 51° - tan square 39°

Answer» 1
16480.

30th term,A.P is 10,7,4

Answer» AP = 10 ,7,4 a = 10 ; d = 7-10=-3 and n = 30An = a+(n-1)d = 10+(30-1)-3 =10+29×(-3) =10-87 = -67 30th term og given AP is -67
16481.

In a ∆abc ,ad is bisector of angle a , meeting side BC at d If ad=5.6cm,bc=6cm & bd =12 cm ,find ac

Answer»
16482.

1-cos^theta=?

Answer» Sin^theta
16483.

If you hit a six I will be equal to a century

Answer» Chapter 5
16484.

how many of you get maths bore in class

Answer» no
Me
16485.

2x³+x²_5x+2;½‚1‚-2

Answer»
16486.

Please tell me which is the best sample paper for class 10

Answer» Evergreen
U solve the book ncert and ncert exampler both r best for exam the paper always come from ncert so u can solve ncert
Oswal
Arihant sample copy le lo market me easily mil zaygi
Oswall
16487.

4.4.4.4 side You any method you only used(+._.×.÷)you prove thatis=100

Answer»
16488.

What is the difference between zeroes and roots. ?

Answer» Zero of a polynomial is a solution to the polynomial equation, P(x) = 0 but Root of a polynomial is that value of x that makes the polynomial equal to 0.
Thanks sia and Raj kumar Mahato..
zeroes are the solution only for polynomial. But solutions are said to be roots if LHS=RHS means eqation. It is seen inQuadratic eqn.Thanks Mahi
16489.

Show that 5-root3 is a irrational number

Answer» We will solve this by contradiction method i.e.,\xa0Assume\xa0{tex}5 - \\sqrt { 3 } = \\frac { p } { q }{/tex}\xa0be a rational number.{tex}\\therefore 5 - \\frac { p } { q } = \\sqrt { 3 }{/tex}\xa0or\xa0{tex}\\frac { 5 q - p } { q } = \\sqrt { 3 }{/tex},Since p,q are integers, therefore\xa0{tex}\\frac { 5 q - p } { q }{/tex} is a rational number, which is a contradiction,since\xa0{tex}\\sqrt 3{/tex} is an irrational number.Therefore, our supposition is wrong and hence, 5 - {tex}\\sqrt 3{/tex}\xa0is irrational.
16490.

Fina a rational no between2 qnd 3

Answer» (2+3)/2i.e 5/2
16491.

Find the hcf by edl 315 and 225

Answer» 45
It cant be done because in this case always the smaller one will be devided by the greater ones
16492.

Ch 5 difnition

Answer» Quadritic formula is -b+√d/2 or
What do you mean by quadratic formula
16493.

75x²-766x+80Middle term factorisation

Answer»
16494.

5.2 apply formulas

Answer»
16495.

X+Y=5, 2x-3y=4 solve by elimination and substitution method

Answer» Thanks it really helped me
By elimination methodx + y =5 ……….(1)2x –3y = 4 ………(2)Multiplying equation (1) by 2, we obtain2x + 2y = 10 ………..(3)2x –3y = 4 ………(2)Subtracting equation (2) from equation (3), we obtain5y = 6y = 6/5Substituting the value in equation (1), we obtainx = 5 - (6/5) = 19/5So our answer is x = 19/5 and y = 6/5By substitution methodx + y =5 ……….(1)subtract y both side we getx = 5 - y ……..,(4)plug the value of x in equation second we get2(5 – y ) – 3y = 4-5y = - 6y = -6/-5 = 6/5Plug the value of y in equation 4 we getx = 5 – 6/5x = 19/5
16496.

All questions of roots of ch 4

Answer» Check NCERT Solutions here :\xa0https://mycbseguide.com/ncert-solutions.html
Thank u ??
16497.

Kisi sankhya or uske 2/3 ka anter 10 hai. Vo sankhya bataye

Answer» Let the no be x2/3of x=2x/3 A/Q x-2x/3=10i.e (3x-2x)/3=10i.e x=10×3i.e x=30
How?
30
16498.

Prove that 2√3/5 is irrational ?

Answer» Yes
16499.

576x square + 6336x + 17250

Answer»
16500.

How to make project for any chapter in maths on paper ?

Answer»