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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 16601. |
How we can find sin formula? By any numbers. |
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| 16602. |
Find the area of the red part in give figure |
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Answer» Where is the given figure????? figure? |
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| 16603. |
Is tan2 A and tan and A same |
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| 16604. |
Given that hcf (306,657)=9 . Find lcm (306,657). |
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Answer» 22338 by formula hcf* lcm= product of two numbers. Since, LCM(a,b) * HCF(a,b) = a*b Let LCM (306,657) = x So, x * 9 = 306 * 657x = 24538 |
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| 16605. |
Whose paper is there tomorrow? |
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Answer» My ? My |
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| 16606. |
Information of maths basic standard at paper in 2019 and 2020 |
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Answer» So we can select the any part of maths In the exam of 2020 it is found that maths will be divided in two parts.First standard and second basic for standard maths book willcremain same as I have listened and for basic some chapters will silent . |
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| 16607. |
Find the hcf of 135 and 225 by using Euclid s division algorithm |
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Answer» 45 225=135×1+90135=90×1+4590=45×2+0HCF=45 |
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| 16608. |
What is the formula of a2 +b2 |
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Answer» (a+b)2-2ab (A+B)(A-B) 2(a+b) a²+b²+2ab |
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| 16609. |
Very inportant question chapter 7 14. 15 |
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| 16610. |
1+7 |
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Answer» 8 8 7 |
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| 16611. |
Find using distributivity ( 9/16 × 4/ 12) + ( 9/ 16 × -3 / 9) |
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Answer» (a×b)+ (a×c)= a(b+c)Solution : 9/16{4/12+(-3/9)} =. 9/16 (1/3-1/3) =. 9/16× 0 = 0 13/16 9/16{4/12+(-3/9) |
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| 16612. |
Prove that √2 is irrational number? |
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Answer» Prove that 0 is a irrational Let us assume √2 is rational number.a rational number can be written into he form of p/q√2=p/qp=√2qSquaring on both sidesp²=2q²__________(1).·.2 divides p² then 2 also divides p.·.p is an even numberLet p=2a (definition of even number,\'a\' is positive integer)Put p=2a in eq (1)p²=2q²(2a)²=2q²4a²=2q²q²=2a².·.2 divides q² then 2 also divides qBoth p and q have 2 as common factor.But this contradicts the fact that p and q are co primes or integers.Our supposition is false.·.√2 is an irrational number.\xa0 Proof:let us assume √2 is an rational number.Therfore,√2=p/q where p and q are coprime and q is not equal to 0P= √2qSquaring on both sides,(P)square=(√2)squarePsquare=2squareTherefore,qsquare =psquare/2Psquare is divisible by 2P is also divisible by 2. {Equation 1}Let p=2k where k is some constant√2q=2kSquaring on both sides,√2qsquare=2ksquareKsquare=qsquare/2Therefore,qsquare is divisible by 2q is also divisible by 2. {Equation 2}From equation 1 and 2,P and q divides by 2 other than 1This is contradictory to our assumption that p and q are co primesTherefore, √2 is a irrational number see R.S Aggrawal example |
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| 16613. |
2/3. 1/32x - x. = 28 |
| Answer» ,check your statement | |
| 16614. |
x(2x+1)(x-2)(2x-3)=63 |
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Answer» 1+1+1+1+1=5 Multiply all terms by 2 and then add or subtract and then answer =63 then find value of x multiply and find the value of x |
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| 16615. |
What should be added to the polynomial 3 xrace to4-6 xrace2+4 |
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| 16616. |
If 2x=secA, 2/x= tanA. Find 2(x^2-1/x^2) |
| Answer» We know thatsec2A - tan2A = 1{tex}\\Rightarrow ( 2 x ) ^ { 2 } - \\left( \\frac { 2 } { x } \\right) ^ { 2 }{/tex}\xa0= 1{tex}\\Rightarrow 4 x ^ { 2 } - \\frac { 4 } { x ^ { 2 } }{/tex}\xa0= 1{tex}\\Rightarrow 4 \\left( x ^ { 2 } - \\frac { 1 } { x ^ { 2 } } \\right){/tex}\xa0= 1{tex}\\Rightarrow \\left( x ^ { 2 } - \\frac { 1 } { x ^ { 2 } } \\right) = \\frac { 1 } { 4 }{/tex} | |
| 16617. |
Is anyone\'s rich here please give me 800 rupees its urgent |
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| 16618. |
The HCF of a and b is ? |
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Answer» It\'s lcmHcf is 1 Ab |
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| 16619. |
Kya aap logon ne aaj ka test diya maths ka |
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Answer» Ya Ya Yees |
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| 16620. |
solve the equation 2x+3y=52x-3y=6 |
| Answer» By adding eqn 1and 2 we get 4x=11 thenx=11\\4 | |
| 16621. |
If sinA+cosA=m and secA+cosecA=n than prove that n(m+1)(m-1)=2m |
| Answer» Please answer this question | |
| 16622. |
If sec A - tan A=4, THEN PROVE THAT cos A= 8/16 |
| Answer» Now, sec A - tan A = 4........(i)We know that(sec A - tan A)(sec A + tan A) = 1{tex}\\Rightarrow{/tex}\xa04(secA + tanA) = 1{tex}\\Rightarrow{/tex}\xa0secA + tanA = {tex}\\frac{1}{4}{/tex}\xa0.......(ii)Adding\xa0(i) and (ii) we get,2 secA =\xa0{tex}\\frac{{17}}{4}{/tex}{tex}\\Rightarrow{/tex}\xa0secA =\xa0{tex}\\frac{{17}}{8}{/tex}{tex}\\Rightarrow{/tex}\xa0cosA = {tex}\\frac{8}{{17}}{/tex} | |
| 16623. |
If polynomial x4 |
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| 16624. |
Please give me trigonometric formula |
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Answer» Make a chart of formula and daily minimum 1 time revice it make a project like a creating formula and keep it in document file |
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| 16625. |
(X+Y) whole square |
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Answer» Gauri? (x+y)²=x²+2xy+y² X |
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| 16626. |
Show that any positive odd integer is of the form 6q+1 6q+2 6q+3 or 6q+5 q where q is some integers |
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Answer» Thkk let b= 6 r = 0,1,2,3,4,5 |
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| 16627. |
Find the value k so that quadratic equation 3x^2-kx+38=0 has equal roots |
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Answer» In this question we put formula of alpha +beta =-b/a3=k/39=k No your answer is wrong K^2-4×3×38=0=k^2-456=0=k^2=456=k=+-456^1÷2 |
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| 16628. |
Chapter 9 ex.9.1 ques.2 |
| Answer» Sorry i am not solving this chapter | |
| 16629. |
5*3=? |
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Answer» 15 Its 15 15/- 15 15 15 |
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| 16630. |
What is algorithm. |
| Answer» Algorithm is\xa0a set of rules to be followed in calculations or other problem-solving operations, especially by a computer. | |
| 16631. |
AP 3‚15‚27‚39… will be 120 more than its 21st term. |
| Answer» Here we are having a=3and d=15-3=12Let nth term Tn =T21+120so a+(n-1)d = a+20d+120or (n-1){tex}\\times{/tex}12 = 20 {tex}\\times{/tex} 12+12012n -12 = 240+12012n = 372{tex}\\style{font-size:12px}{\\text{n=}\\frac{372}{12}=31}{/tex}Hence, 31st term is the required term. | |
| 16632. |
Solution of 4+2y-4=0 |
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Answer» y=0 y=0 4+2y=42y=4-4=02y=0Y=-2 2y=4-4 2y=0Y =0 0 |
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| 16633. |
Xsquare -88x+125 , find the zeros of quadratic polynomial |
| Answer» Trinomial can not be factored | |
| 16634. |
What is the square root of 13.62 |
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Answer» 3.6905284174 3.69 (aprrox).... |
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| 16635. |
x2-88x+125 |
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Answer» Do it by middle term splitting Both positive |
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| 16636. |
Find the least no. Which is divisible by all no. From 1 to 10 |
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Answer» 520 1 |
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| 16637. |
Trisection of the line segment joining (4,-1) and (-2,-3) |
| Answer» Let P and Q be the points of trisection as shown belowThen, AP : PB = 1 : 2and AQ : QB = 2 : 1\t\tHere,\xa0{tex}\\frac{m_{1}}{m_{2}}=\\frac{1}{2},{/tex}\xa0A(x1, y1) = (2, -3) and B(x2, y2) = (4, -1)\tFor internally,\xa0{tex}P=\\left(\\frac{m_{1} x_{2}+m_{2} x_{1}}{m_{1}+m_{2}}, \\frac{m_{1} y_{2}+m_{2} y_{1}}{m_{1}+m_{2}}\\right){/tex}\t{tex}\\Rightarrow \\quad P=\\left(\\frac{1 \\times 4+2 \\times 2}{1+2}, \\frac{1 \\times(-1)+2 \\times(-3)}{1+2}\\right){/tex}\t{tex}\\Rightarrow \\quad P=\\left(\\frac{4+4}{3}, \\frac{-1-6}{3}\\right) \\Rightarrow P=\\left(\\frac{8}{3}, \\frac{-7}{3}\\right){/tex}\tHere,\xa0{tex}\\frac{m_{1}}{m_{2}}=\\frac{2}{1}{/tex}, A(x1, y1) = (2, -3)\tand B(x2, y2) = (4, -1)\tFor internally,\xa0{tex}Q=\\left(\\frac{m_{1} x_{2}+m_{2} x_{1}}{m_{1}+m_{2}}, \\frac{m_{1} y_{2}+m_{2} y_{1}}{m_{1}+m_{2}}\\right){/tex}\t\t{tex}\\Rightarrow \\quad Q=\\left(\\frac{2 \\times 4+1 \\times 2}{2+1}, \\frac{2 \\times(-1)+1 \\times(-3)}{2+1}\\right){/tex}\t{tex}\\Rightarrow \\quad Q=\\left(\\frac{8+2}{3}, \\frac{-2-3}{3}\\right) \\Rightarrow Q=\\left(\\frac{10}{3}, \\frac{-5}{3}\\right){/tex} | |
| 16638. |
If 5 cos theta =4 .find the value of sin theta -2 cos theta/ tan theta - cot theta |
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| 16639. |
3tan square theta -1 =0 |
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| 16640. |
O.2x+0.3y=1.30.4x+0.5y=2.3 |
| Answer» 0.2x\xa0+ 0.3y\xa0= 1.3 ...\xa0(i)0.4x\xa0+ 0.5y\xa0= 2.3 ...\xa0(ii)Solving equation\xa0(i), we get0.2x\xa0= 1.3 – 0.3yDividing by 0.2, we getx\xa0= 1.3/0.2 - 0.3/0.2x\xa0= 6.5 – 1.5\xa0yPutting the value in equation\xa0(ii), we get0.4x\xa0+ 0.5y\xa0= 2.3(6.5 – 1.5y) ×\xa00.4x\xa0+ 0.5y\xa0= 2.32.6 – 0.6y\xa0+ 0.5y\xa0= 2.3-0.1y\xa0= 2.3 – 2.6y\xa0= -0.3/-0.1y\xa0= 3Putting this value in equation\xa0(i)\xa0we get x\xa0= 2\tx\xa0= 2 and\xa0y\xa0= 3\t | |
| 16641. |
Can you give me questions of previous board examination from chapter 1,2,3 and 4 |
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| 16642. |
What is new sample paper of maths 2019-20 |
| Answer» Oswal sample paper will be launch in October | |
| 16643. |
Can u send the new pattern paper for practice of both levels,standard and basics |
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Answer» You can check the question paper pattern in syllabus here :\xa0https://mycbseguide.com/cbse-syllabus.html 20 marks of MCQ carring 1 marks each and remaining are of 2,3 and 5 marks Yes |
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| 16644. |
Find the product of zeroes of x-3x=10 |
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Answer» -10 is the product of zero. The product of zeroes will be -10 |
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| 16645. |
The value of Q |
| Answer» Q=power of electron | |
| 16646. |
Method of completing the square |
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| 16647. |
Probability activity |
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| 16648. |
Kya India match Har gya? |
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Answer» Hnn India match har gyii....? Dhoni k wajah se This is used for studies not for matches Haa Ha bhai 18 run se Kiske karn Hara? Haaaa |
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| 16649. |
Chapter 5 AP formula |
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Answer» a2=a+da3=a+2d When first term(a) and common difference (d) is given then the formula is an=a+(n-1)d |
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| 16650. |
What is the formulA of mean mode |
| Answer» The\xa0formula\xa0to find the sample\xa0mean\xa0is: = ( Σ xi\xa0) / nThe mode is the value that occurs the most often in a data set, and the range is the difference between the highest and lowest values in a data set. | |