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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 16701. |
96+63 |
| Answer» 159 | |
| 16702. |
Plz anwer my question plz |
| Answer» | |
| 16703. |
Prove trigonometry questions |
| Answer» TanA+SecA-1/TanA-SecA+1=1+SinA/CosA | |
| 16704. |
If cos tetta -4sin teeta =2 cos tetta+ sin tetta, find tan teeta. |
| Answer» | |
| 16705. |
x+2y=32x-y=4 |
| Answer» From 1 eq..X+2y=3X=-2y-32......-2x-y=4-2(2y-3)-y-4=0-4y-6-y-4=05y-10=0y=10/5y=2Puting in thirdX=-2y-3X=-2(2)-3X=-4-3X=-7 | |
| 16706. |
(K+4) (k+1)x+1=0 |
| Answer» This question is incomplete | |
| 16707. |
Which is the most important chapter of class 10 in maths |
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Answer» trigonometry Trigonometry Trigonometry Ch.15,14 ,1,2,5,3 the and tenometry are the most important chapters Trigonometry i guess |
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| 16708. |
X2+6x+8=0 |
| Answer» x^2+6x+8=0x^2+2x+4x+8x(x+2)+4(x+2)(x+2)(x+4)therefore -2&-4 are zeros of the polynomial | |
| 16709. |
An=9-5n |
| Answer» Plz tell full question What we have to find in this question | |
| 16710. |
3(2x+1/3x_1)_2(3x_1/2x+1)=5 |
| Answer» | |
| 16711. |
Prove that√8 is a irrational? |
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Answer» Let us assume that Firsty let root 8 is rational Then root8/1=p/q(p and q r coprime anf q is not equal to 0)Then cross multiplication then we obtainP=root8qSquare on both sideP2=(root8q)2Then we obtain P2=8q2 because root se square cancel ho jaygaThen we can say that p2 divide 8exactly and p will also divide 8 exaclty Then by euclid division lemmaP=8q+0Then square on both sideP2=(8q)2 Then put the value of p2 8q2=64q28q2=8(8q2)Then 8 se 8 cancel ho jaygaThenq2=8q2Then we can say that q2 will divide 8 exactly and q will divide exactly Then the common factor of p and p is 8 then it is contraduction to our supposition. So, our supposition is wrong . Hence root 8 is irrational no. |
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| 16712. |
If sec theta +tan theta =m; & sec theta× tan theta =n; find the value of √mn |
| Answer» Given: (sec{tex}\\theta{/tex}\xa0+ tan{tex}\\theta{/tex}) = m and (sec{tex}\\theta{/tex}\xa0- tan{tex}\\theta{/tex}) = n,LHS = mn = (sec{tex}\\theta{/tex}\xa0+ tan{tex}\\theta{/tex})(sec{tex}\\theta{/tex}\xa0- tan{tex}\\theta{/tex})= sec2{tex}\\theta{/tex}\xa0- tan2{tex}\\theta{/tex}\xa0= 1 = RHS [{tex}\\because{/tex}\xa0sec2{tex}\\theta{/tex}\xa0- tan2{tex}\\theta{/tex}\xa0= 1]{tex}\\therefore \\sqrt {mn} = 1{/tex} | |
| 16713. |
x-4/x-5+x-4/x-5=10/3 solve the quadratic equation by factorisation |
| Answer» {tex}\\frac{x-4}{x-5}+\\frac{x-6}{x-7}=\\frac{10}{3}{/tex}, x\xa0{tex}\\neq{/tex}\xa05, 7{tex}\\Rightarrow \\frac{(x-4)(x-7)+(x-6)(x-5)}{(x-5)(x-7)}=\\frac{10}{3}{/tex}{tex}=\\frac{x^{2}-11 x+28+x^{2}-11 x+30}{x^{2}-12 x+35}=\\frac{10}{3}{/tex}{tex}\\Rightarrow{/tex}\xa03[2x2 - 22x + 58] = 10[x2 - 12x + 35]{tex}\\Rightarrow{/tex}\xa06x2 - 66x + 174 = 10x2 - 120x + 350{tex}\\Rightarrow{/tex}\xa04x2 - 54x + 176 = 0{tex}\\Rightarrow{/tex}\xa02x2 - 27x + 88 = 0{tex}\\Rightarrow{/tex}\xa02x2 - 16x - 11x + 88 = 0{tex}\\Rightarrow{/tex}\xa02x(x - 8)\xa0-11(x - 8)\xa0= 0{tex}\\Rightarrow{/tex}\xa0(2x - 11) (x - 8) = 0{tex}\\Rightarrow{/tex}\xa0x =\xa0{tex}\\frac{{11}}{2}{/tex},\xa08 | |
| 16714. |
solve by facterisation |
| Answer» | |
| 16715. |
If sin 2A =2sinA then find value of A |
| Answer» 2sinA=(90°-A)2A=90°-A2A+A=90°3A=90A=90÷3A=30 | |
| 16716. |
How many two digits no.are divisible by 3 from ch 5 |
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Answer» 30 So the ap will be 12,15,18.......99An=99 ,a=12 d=15-12=3An=a+(n-1)d99=12+(n-1)399=12+3n-399=9-3n99-9=3n90=3n90÷3=n30=n There r 30 no.which r divisible by 3 |
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| 16717. |
The length of equal side of an isosceles triangle is 20m ,angle between them is 45 .calculate area |
| Answer» | |
| 16718. |
Alfa Bita gama ka mtlb |
| Answer» Alfa beta particles and gamma rays r the 3 most forms of radiations emitted by unstable and radioactive isotops. All three were nmed by newzeland-born scientists nm3d Ernest Ratherfordin the eary part of 20th century. All 3 are radioactivity potentially dangerous to human health although different considerations apply in each case | |
| 16719. |
Prove square root of 5 is irrational |
| Answer» To prove that\xa0√5 is irrational number\xa0Let us assume that\xa0√5 is rational\xa0Then\xa0√5 =\xa0\xa0(a and b are co primes, with only 1 common factor and b≠0)\xa0⇒\xa0√5 =\xa0\xa0(cross multiply)\xa0⇒ a =\xa0√5b\xa0⇒ a² = 5b² ------->\xa0α⇒ 5/a²\xa0(by theorem if p divides q then p can also divide q²)\xa0⇒ 5/a ----> 1\xa0⇒ a = 5c\xa0(squaring on both sides)\xa0⇒ a² = 25c² ---->\xa0β\xa0From equations\xa0α and\xa0β\xa0⇒ 5b² = 25c²⇒ b² = 5c²\xa0⇒ 5/b²\xa0(again by theorem)\xa0⇒ 5/b-------> 2\xa0we know that a and b are co-primes having only 1 common factor but from 1 and 2 we can that it is wrong.\xa0This contradiction arises because we assumed that\xa0√5 is a rational number\xa0∴ our assumption is wrong\xa0∴\xa0√5 is irrational number\xa0 | |
| 16720. |
culculate tha mean of tha following frequency distribution. |
| Answer» Which frequency table | |
| 16721. |
√5+√5+........ |
| Answer» | |
| 16722. |
Chapter 3 ,6question 3 |
| Answer» | |
| 16723. |
I cant understand substitution method and cross multiplication method plss help me |
| Answer» | |
| 16724. |
Where is Rd Sharma ? |
| Answer» In book store | |
| 16725. |
How to do substitution method |
| Answer» With the help of formula | |
| 16726. |
Drew 60 degree Acute angle without protracktor |
| Answer» With compus you can make | |
| 16727. |
Ex. 9.1que.14 |
| Answer» BQ=58root3m | |
| 16728. |
If tan A =5/12,fand the value of sec A |
| Answer» SecA=13/12 | |
| 16729. |
2(2×4)+7(22-66) |
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Answer» sorry - 292. 2 (2×4)+7 (22-66) . =2×8+7×(-44). =16-308. =282. 2(2×4)+7(22-66)= 2(8) + 7 (-44)= 16 - 308= -292 |
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| 16730. |
√6+√6+√6+...... |
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Answer» 3√6 is wrong... How? 3√6 |
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| 16731. |
Which chapter is main for final examination |
| Answer» | |
| 16732. |
Give 5 5 equation of subsitution method and elimination methos |
| Answer» | |
| 16733. |
Find the quadratic polynomial whose zero are (5+2√3) and(5-2√3) |
| Answer» x^2-10x+13 | |
| 16734. |
Solve the pair of linear equation by the substitution method 3x_y=3;9x_3y=9 |
| Answer» From the equation (1),y=(3x-3)Substituting this value of y in (2),9x-3(3x-3)=99x-9x+9=99=9 | |
| 16735. |
3 x square minus x minus 2 is equal to zero solve this by using the method of completing the square |
| Answer» 3x^2-x-2=0Dividing the equation by 3X^2-x/3 -2/3=0X^2-x/3+1/36=2/3+1/36 {adding 1/36 on both side}(X-1/6)^2=25/36X-1/6=5/6X=5/6+1/6X=1 | |
| 16736. |
find A is a tan 2A= cot (A-24) |
| Answer» Tan 2A= cot(A_24)Cot(90-2A)= cot(A-24)Cot se cot cut jayga then next step90-2A=A-2490+24=A+2A144=3A144÷3=A38=A | |
| 16737. |
Find x if -4 +(-1) +2 +........+x =437 |
| Answer» (-4) + (-1) + 2 + 5 + ---- + x = 437.Now,-1 - (-4) = -1 + 4 = 32 - (-1) = 2 +\xa01 = 35 - 2 = 3Thus, this forms an A.P. with a = -4, d = 3,l = xLet their be n terms in this A.P.Then,Sn\xa0=\xa0{tex}\\frac { n } { 2 } [ 2 a + ( n - 1 ) d ] {/tex}{tex}\\Rightarrow 437 = \\frac { n } { 2 } [ 2 \\times ( - 4 ) + ( n - 1 ) \\times 3 ]{/tex}{tex}\\Rightarrow{/tex}\xa0874 = n[-8 + 3n - 3]{tex}\\Rightarrow{/tex}874 = n[3n - 11]{tex}\\Rightarrow{/tex}874 = 3n2\xa0- 11n{tex}\\Rightarrow{/tex}3n2\xa0- 11n - 874 = 0{tex}\\Rightarrow{/tex}3n2\xa0- 57n + 46n - 874 = 0{tex}\\Rightarrow{/tex}3n(n - 19) + 46(n - 19) = 0{tex}\\Rightarrow{/tex}3n + 46 = 0 or n = 19{tex}\\Rightarrow n = - \\frac { 46 } { 3 }{/tex}\xa0or n\xa0= 19Numbers of terms cannot be negative or fraction.{tex}\\Rightarrow{/tex}\xa0n = 19Now, Sn\xa0=\xa0{tex}\\frac { n } { 2 } [ a + l ]{/tex}{tex}\\Rightarrow 437 = \\frac { 19 } { 2 } [ - 4 + x ]{/tex}{tex}\\Rightarrow - 4 + x = \\frac { 437 \\times 2 } { 19 }{/tex}{tex}\\Rightarrow - 4 + x = 46{/tex}{tex}\\Rightarrow x = 50{/tex} | |
| 16738. |
How many terms of the A.P -15, -11, -7, ....... are needed to make the sum 744 ? |
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Answer» a=-15, d=-11+15=4 , Sn=744Sn=n/2{2a+(n-1)d} , n/2{-30+(n-1)4}=744 ,n/2(-30+4n-4)=744 ,n(-34+4n)=1488 ,4n^2-34n-1488=0 ,2n^2-17n-744=0 ,2n^2-48n+31n-744=0 ,2n(n-24)+31(n-24)=0 ,(n-24)(2n+31)=0. ,n=24 or n=-31/2(which is not possible). Hence,n=24 24 terms. |
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| 16739. |
An A.P consists of 60 terms. If the first and last term is 7 and 125 respectively. Find 32 term |
| Answer» we have,a=7an=125 and n=60 d=? And a32=? Solution an=a+(n-1)d125=7+(60-1)d125=7+59d 125-7=59d118=59d ;d=2 a32 =a+31d a32=7+31.2a32= 69 | |
| 16740. |
x-7y-7=03x-3y-15=0 |
| Answer» y = -1/3 x= 14/3 | |
| 16741. |
Tantheta+sintheta/tantheta-sintheta=sectheta+1/sectheta-1 |
| Answer» | |
| 16742. |
hcf of 356 |
| Answer» Is the answer 89 | |
| 16743. |
Find the smallest no. Which leaves the remainder8,20 when divided by 34 and 46 |
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Answer» I more question is there in which i facing problem can u answer that question Thanq i understand Plz give answer in detail if u don\'t have any problem First,add the given nos with the remainders 42=7*2*3 66=11*2*3LCM=7×2×11×3=462 |
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| 16744. |
The length of the diagonals of a rhombus are 24 cm and 10 cm find the side of a |
| Answer» Let ABCD be the rhombus where AC = 10 cm and BD = 24 cm.Let AC and BD intersect each other at O.Now, diagonals of rhombus bisect each other at right angles.Thus, we haveAO = 1/2 AC = 1/2 (10) = 5 cm andBO = 1/2 BD = 1/2 (24) = 12 cmSince AOB is a right angled triangle, by Pythagoras theorem, we haveAB2 = AO2 + BO2AB2 = 52 + 122 = 25 + 144 = 169Hence, AB = 13Thus, length of each side of rhombus is 13 cm. | |
| 16745. |
(6)-+(6) |
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Answer» Surely 0 0 0 Answer is zero and you are zero as well 0 |
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| 16746. |
Sir maths syllabus |
| Answer» Check syllabus here : https://mycbseguide.com/cbse-syllabus.html | |
| 16747. |
A=10 D=10Find the fourth term,?? |
| Answer» a=10 & d=10 , nth term= a+(n-1)d ,4th term= 10+(4-1)10=10+(3)10=10+30=40 | |
| 16748. |
If x=3 is one root of the quadratic equations x2-2kx-6=0 then find the value of k. |
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Answer» p(x)=x²-2kx-6=0, p(3)=3²-2×k×3-6=0, =9-6k-6=0, =3-6k=0, =6k=3, =k=3/6, =k=½Therefore, the value of k is ½. K=1/2 The equation is x square - 2kx - 6 |
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| 16749. |
22/7 is irrational |
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Answer» yes , because it is a form of p/q where p and q are integers and q not equal to 0. yes it is rational no because it written in the form of p by q It\'s rational but pie is irrational It is rational but the real value of 22/7 is πand πis irrational............ It is in the form of p/q where q not equal to 0 It is rational |
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| 16750. |
Resolve the graph by 4x-y=12,4x+y=12shade the area between the two lines and the x axis |
| Answer» | |