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16701.

96+63

Answer» 159
16702.

Plz anwer my question plz

Answer»
16703.

Prove trigonometry questions

Answer» TanA+SecA-1/TanA-SecA+1=1+SinA/CosA
16704.

If cos tetta -4sin teeta =2 cos tetta+ sin tetta, find tan teeta.

Answer»
16705.

x+2y=32x-y=4

Answer» From 1 eq..X+2y=3X=-2y-32......-2x-y=4-2(2y-3)-y-4=0-4y-6-y-4=05y-10=0y=10/5y=2Puting in thirdX=-2y-3X=-2(2)-3X=-4-3X=-7
16706.

(K+4) (k+1)x+1=0

Answer» This question is incomplete
16707.

Which is the most important chapter of class 10 in maths

Answer» trigonometry
Trigonometry
Trigonometry
Ch.15,14 ,1,2,5,3 the and tenometry are the most important chapters
Trigonometry i guess
16708.

X2+6x+8=0

Answer» x^2+6x+8=0x^2+2x+4x+8x(x+2)+4(x+2)(x+2)(x+4)therefore -2&-4 are zeros of the polynomial
16709.

An=9-5n

Answer» Plz tell full question What we have to find in this question
16710.

3(2x+1/3x_1)_2(3x_1/2x+1)=5

Answer»
16711.

Prove that√8 is a irrational?

Answer» Let us assume that √8\xa0is rational.That is, we can find integers a and b (≠0) such that\xa0a and b are co-prime{tex}\\style{font-family:Arial}{\\begin{array}{l}\\sqrt8=\\frac ab\\\\b\\sqrt8=a\\\\on\\;squaring\\;both\\;sides\\;we\\;get\\\\8b^2=a^2\\end{array}}{/tex}Therefore, a2 is divisible by 8,\xa0it follows that a is also divisible by 8.So, we can write a = 8c for some integer c.Substituting for a, we get 8b2 = 64c2, that is, b\u200b\u200b\u200b\u200b\u200b\u200b2\xa0= 8c2This means that b2 is divisible by 8, and so b is also divisible by 8\xa0Therefore, a and b have at least 8\xa0as a common factor.But this contradicts the fact that a and b are co-prime.This contradiction has arisen because of our incorrect assumption that √8\xa0is rational.So, we conclude that √8\xa0is irrational.
Firsty let root 8 is rational Then root8/1=p/q(p and q r coprime anf q is not equal to 0)Then cross multiplication then we obtainP=root8qSquare on both sideP2=(root8q)2Then we obtain P2=8q2 because root se square cancel ho jaygaThen we can say that p2 divide 8exactly and p will also divide 8 exaclty Then by euclid division lemmaP=8q+0Then square on both sideP2=(8q)2 Then put the value of p2 8q2=64q28q2=8(8q2)Then 8 se 8 cancel ho jaygaThenq2=8q2Then we can say that q2 will divide 8 exactly and q will divide exactly Then the common factor of p and p is 8 then it is contraduction to our supposition. So, our supposition is wrong . Hence root 8 is irrational no.
16712.

If sec theta +tan theta =m; & sec theta× tan theta =n; find the value of √mn

Answer» Given: (sec{tex}\\theta{/tex}\xa0+ tan{tex}\\theta{/tex}) = m and (sec{tex}\\theta{/tex}\xa0- tan{tex}\\theta{/tex}) = n,LHS = mn = (sec{tex}\\theta{/tex}\xa0+ tan{tex}\\theta{/tex})(sec{tex}\\theta{/tex}\xa0- tan{tex}\\theta{/tex})= sec2{tex}\\theta{/tex}\xa0- tan2{tex}\\theta{/tex}\xa0= 1 = RHS [{tex}\\because{/tex}\xa0sec2{tex}\\theta{/tex}\xa0- tan2{tex}\\theta{/tex}\xa0= 1]{tex}\\therefore \\sqrt {mn} = 1{/tex}
16713.

x-4/x-5+x-4/x-5=10/3 solve the quadratic equation by factorisation

Answer» {tex}\\frac{x-4}{x-5}+\\frac{x-6}{x-7}=\\frac{10}{3}{/tex}, x\xa0{tex}\\neq{/tex}\xa05, 7{tex}\\Rightarrow \\frac{(x-4)(x-7)+(x-6)(x-5)}{(x-5)(x-7)}=\\frac{10}{3}{/tex}{tex}=\\frac{x^{2}-11 x+28+x^{2}-11 x+30}{x^{2}-12 x+35}=\\frac{10}{3}{/tex}{tex}\\Rightarrow{/tex}\xa03[2x2 - 22x + 58] = 10[x2 - 12x + 35]{tex}\\Rightarrow{/tex}\xa06x2 - 66x + 174 = 10x2 - 120x + 350{tex}\\Rightarrow{/tex}\xa04x2 - 54x + 176 = 0{tex}\\Rightarrow{/tex}\xa02x2 - 27x + 88 = 0{tex}\\Rightarrow{/tex}\xa02x2 - 16x - 11x + 88 = 0{tex}\\Rightarrow{/tex}\xa02x(x - 8)\xa0-11(x - 8)\xa0= 0{tex}\\Rightarrow{/tex}\xa0(2x - 11) (x - 8) = 0{tex}\\Rightarrow{/tex}\xa0x =\xa0{tex}\\frac{{11}}{2}{/tex},\xa08
16714.

solve by facterisation

Answer»
16715.

If sin 2A =2sinA then find value of A

Answer» 2sinA=(90°-A)2A=90°-A2A+A=90°3A=90A=90÷3A=30
16716.

How many two digits no.are divisible by 3 from ch 5

Answer» 30
So the ap will be 12,15,18.......99An=99 ,a=12 d=15-12=3An=a+(n-1)d99=12+(n-1)399=12+3n-399=9-3n99-9=3n90=3n90÷3=n30=n There r 30 no.which r divisible by 3
16717.

The length of equal side of an isosceles triangle is 20m ,angle between them is 45 .calculate area

Answer»
16718.

Alfa Bita gama ka mtlb

Answer» Alfa beta particles and gamma rays r the 3 most forms of radiations emitted by unstable and radioactive isotops. All three were nmed by newzeland-born scientists nm3d Ernest Ratherfordin the eary part of 20th century. All 3 are radioactivity potentially dangerous to human health although different considerations apply in each case
16719.

Prove square root of 5 is irrational

Answer» To prove that\xa0√5 is irrational number\xa0Let us assume that\xa0√5 is rational\xa0Then\xa0√5 =\xa0\xa0(a and b are co primes, with only 1 common factor and b≠0)\xa0⇒\xa0√5 =\xa0\xa0(cross multiply)\xa0⇒ a =\xa0√5b\xa0⇒ a² = 5b² ------->\xa0α⇒ 5/a²\xa0(by theorem if p divides q then p can also divide q²)\xa0⇒ 5/a ----> 1\xa0⇒ a = 5c\xa0(squaring on both sides)\xa0⇒ a² = 25c² ---->\xa0β\xa0From equations\xa0α and\xa0β\xa0⇒ 5b² = 25c²⇒ b² = 5c²\xa0⇒ 5/b²\xa0(again by theorem)\xa0⇒ 5/b-------> 2\xa0we know that a and b are co-primes having only 1 common factor but from 1 and 2 we can that it is wrong.\xa0This contradiction arises because we assumed that\xa0√5 is a rational number\xa0∴ our assumption is wrong\xa0∴\xa0√5 is irrational number\xa0
16720.

culculate tha mean of tha following frequency distribution.

Answer» Which frequency table
16721.

√5+√5+........

Answer»
16722.

Chapter 3 ,6question 3

Answer»
16723.

I cant understand substitution method and cross multiplication method plss help me

Answer»
16724.

Where is Rd Sharma ?

Answer» In book store
16725.

How to do substitution method

Answer» With the help of formula
16726.

Drew 60 degree Acute angle without protracktor

Answer» With compus you can make
16727.

Ex. 9.1que.14

Answer» BQ=58root3m
16728.

If tan A =5/12,fand the value of sec A

Answer» SecA=13/12
16729.

2(2×4)+7(22-66)

Answer» sorry - 292.
2 (2×4)+7 (22-66) . =2×8+7×(-44). =16-308. =282.
2(2×4)+7(22-66)= 2(8) + 7 (-44)= 16 - 308= -292
16730.

√6+√6+√6+......

Answer» 3√6 is wrong...
How?
3√6
16731.

Which chapter is main for final examination

Answer»
16732.

Give 5 5 equation of subsitution method and elimination methos

Answer»
16733.

Find the quadratic polynomial whose zero are (5+2√3) and(5-2√3)

Answer» x^2-10x+13
16734.

Solve the pair of linear equation by the substitution method 3x_y=3;9x_3y=9

Answer» From the equation (1),y=(3x-3)Substituting this value of y in (2),9x-3(3x-3)=99x-9x+9=99=9
16735.

3 x square minus x minus 2 is equal to zero solve this by using the method of completing the square

Answer» 3x^2-x-2=0Dividing the equation by 3X^2-x/3 -2/3=0X^2-x/3+1/36=2/3+1/36 {adding 1/36 on both side}(X-1/6)^2=25/36X-1/6=5/6X=5/6+1/6X=1
16736.

find A is a tan 2A= cot (A-24)

Answer» Tan 2A= cot(A_24)Cot(90-2A)= cot(A-24)Cot se cot cut jayga then next step90-2A=A-2490+24=A+2A144=3A144÷3=A38=A
16737.

Find x if -4 +(-1) +2 +........+x =437

Answer» (-4) + (-1) + 2 + 5 + ---- + x = 437.Now,-1 - (-4) = -1 + 4 = 32 - (-1) = 2 +\xa01 = 35 - 2 = 3Thus, this forms an A.P. with a = -4, d = 3,l = xLet their be n terms in this A.P.Then,Sn\xa0=\xa0{tex}\\frac { n } { 2 } [ 2 a + ( n - 1 ) d ] {/tex}{tex}\\Rightarrow 437 = \\frac { n } { 2 } [ 2 \\times ( - 4 ) + ( n - 1 ) \\times 3 ]{/tex}{tex}\\Rightarrow{/tex}\xa0874 = n[-8 + 3n - 3]{tex}\\Rightarrow{/tex}874 = n[3n - 11]{tex}\\Rightarrow{/tex}874 = 3n2\xa0- 11n{tex}\\Rightarrow{/tex}3n2\xa0- 11n - 874 = 0{tex}\\Rightarrow{/tex}3n2\xa0- 57n + 46n - 874 = 0{tex}\\Rightarrow{/tex}3n(n - 19) + 46(n - 19) = 0{tex}\\Rightarrow{/tex}3n + 46 = 0 or n = 19{tex}\\Rightarrow n = - \\frac { 46 } { 3 }{/tex}\xa0or n\xa0= 19Numbers of terms cannot be negative or fraction.{tex}\\Rightarrow{/tex}\xa0n = 19Now, Sn\xa0=\xa0{tex}\\frac { n } { 2 } [ a + l ]{/tex}{tex}\\Rightarrow 437 = \\frac { 19 } { 2 } [ - 4 + x ]{/tex}{tex}\\Rightarrow - 4 + x = \\frac { 437 \\times 2 } { 19 }{/tex}{tex}\\Rightarrow - 4 + x = 46{/tex}{tex}\\Rightarrow x = 50{/tex}
16738.

How many terms of the A.P -15, -11, -7, ....... are needed to make the sum 744 ?

Answer» a=-15, d=-11+15=4 , Sn=744Sn=n/2{2a+(n-1)d} , n/2{-30+(n-1)4}=744 ,n/2(-30+4n-4)=744 ,n(-34+4n)=1488 ,4n^2-34n-1488=0 ,2n^2-17n-744=0 ,2n^2-48n+31n-744=0 ,2n(n-24)+31(n-24)=0 ,(n-24)(2n+31)=0. ,n=24 or n=-31/2(which is not possible). Hence,n=24
24 terms.
16739.

An A.P consists of 60 terms. If the first and last term is 7 and 125 respectively. Find 32 term

Answer» we have,a=7an=125 and n=60 d=? And a32=? Solution an=a+(n-1)d125=7+(60-1)d125=7+59d 125-7=59d118=59d ;d=2 a32 =a+31d a32=7+31.2a32= 69
16740.

x-7y-7=03x-3y-15=0

Answer» y = -1/3 x= 14/3
16741.

Tantheta+sintheta/tantheta-sintheta=sectheta+1/sectheta-1

Answer»
16742.

hcf of 356

Answer» Is the answer 89
16743.

Find the smallest no. Which leaves the remainder8,20 when divided by 34 and 46

Answer» I more question is there in which i facing problem can u answer that question
Thanq i understand
Plz give answer in detail if u don\'t have any problem
First,add the given nos with the remainders 42=7*2*3 66=11*2*3LCM=7×2×11×3=462
16744.

The length of the diagonals of a rhombus are 24 cm and 10 cm find the side of a

Answer» Let ABCD be the rhombus where AC = 10 cm and BD = 24 cm.Let AC and BD intersect each other at O.Now, diagonals of rhombus bisect each other at right angles.Thus, we haveAO = 1/2 AC = 1/2 (10) = 5 cm andBO = 1/2 BD = 1/2 (24) = 12 cmSince AOB is a right angled triangle, by Pythagoras theorem, we haveAB2 = AO2 + BO2AB2 = 52 + 122 = 25 + 144 = 169Hence, AB = 13Thus, length of each side of rhombus is 13 cm.
16745.

(6)-+(6)

Answer» Surely 0
0
0
Answer is zero and you are zero as well
0
16746.

Sir maths syllabus

Answer» Check syllabus here : https://mycbseguide.com/cbse-syllabus.html
16747.

A=10 D=10Find the fourth term,??

Answer» a=10 & d=10 , nth term= a+(n-1)d ,4th term= 10+(4-1)10=10+(3)10=10+30=40
16748.

If x=3 is one root of the quadratic equations x2-2kx-6=0 then find the value of k.

Answer» p(x)=x²-2kx-6=0, p(3)=3²-2×k×3-6=0, =9-6k-6=0, =3-6k=0, =6k=3, =k=3/6, =k=½Therefore, the value of k is ½.
K=1/2
The equation is x square - 2kx - 6
16749.

22/7 is irrational

Answer» yes , because it is a form of p/q where p and q are integers and q not equal to 0.
yes it is rational no because it written in the form of p by q
It\'s rational but pie is irrational
It is rational but the real value of 22/7 is πand πis irrational............
It is in the form of p/q where q not equal to 0
It is rational
16750.

Resolve the graph by 4x-y=12,4x+y=12shade the area between the two lines and the x axis

Answer»