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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 17151. |
How could i find root of any number? |
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Answer» By Factorisation Method -:-b ± √(b² - 4ac)/2aBy middle term splitting method By two method; 1)factorisation2)discriminant |
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| 17152. |
How will i get maximum numbers in class10th exams |
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Answer» For maths you should more and more practice Your basic concepts should be first clear and also make notes this may help u for fast and quick revision By studying ?? |
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| 17153. |
The diagram shows how the ant a 7-pointed star |
| Answer» Are you here for study purpose or for proposal ? | |
| 17154. |
1+Tan²ø= |
| Answer» Sec²∅ | |
| 17155. |
Differentiate with respect to x x^2/route 4- x^2 |
| Answer» | |
| 17156. |
Show that the cube of positive integer is of the form 6q+r , where q is an integer and r=0,1,2,3,4,5 |
| Answer» Let a be an arbitrary positive integer. Then, by Euclid’s division algorithm, corresponding to the positive integers ‘a’ and 6, there exist non-negative integers\xa0and r such that a = 6 q + r, where, 0 < r < 6Hence, the cube of a positive integer of the form 6q + r,q is an integer and r = 0,1,2, 3, 4,5 is also of the forms 6m, 6m + 1, 6m + 2, 6m + 3,6m + 4 and 6m + 5 i.e.,6m + r. | |
| 17157. |
Find the HCF and LCM of 101and 151 |
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Answer» A N S W E RGiven two numbers are\xa0101\xa0and\xa0151101, 151 doesn\'t any common primeSo, LCM is\xa0101 × 151=15 , 251\xa0HCL of\xa0101\xa0&\xa0151\xa0is\xa01. |
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| 17158. |
7x-2y/xy = 5 .....(i)8x+7y/xy=15 ....(ii) |
| Answer» i)7x-2y/xy =5=7x/xy - 2y/xy =5=7/y - 2/x =5ii)8x+7y/xy =15=8x/xy+7y/xy=15=8/y+7/x=15Let 1/x=p and 1/y=q then by substituting these values we get, 7q-2p=5 and 8q+7p=15By eliminating,q=1 and p=1; We know that 1/x=p and 1/y =q then by putting values of q and p we get x=1 and y =1. | |
| 17159. |
Durry suther on five questions |
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| 17160. |
Can I get the question paper of the year 2017 |
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Answer» Ya I also have same problem Yes |
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| 17161. |
solve for x find k 3 is a solution of 3x + (k-3)x+9=0\u200b |
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Answer» Find the cubic of polynomial given number as zeroes If x = 3then 3x + (k-3)x+9=0\u200b3(3) +( k - 3)3\xa0+ 9 =09 + 3k - 9 + 9 =03k = -9k =-9/3 = -3\xa0 |
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| 17162. |
Is there any topic which is fully deleted in construction chapter??? |
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Answer» Construction of similar triangle No No bro No |
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| 17163. |
X2 +24+144 |
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Answer» Question is wrong either incomplete 84 Hi |
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| 17164. |
What is the never between 0 and 1 |
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Answer» Infact their are many numbers 7.6 is the number which is never between 0&1. |
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| 17165. |
Class 10 tignomatry formula |
| Answer» •sin θ = Opposite Side/Hypotenuse•cos θ = Adjacent Side/Hypotenuse•tan θ = Opposite Side/Adjacent Side•sec θ = Hypotenuse/Adjacent Side•cosec θ = Hypotenuse/Opposite Side•cot θ = Adjacent Side/Opposite Side•cosec θ = 1/sin θ•sec θ = 1/cos θ•cot θ = 1/tan θ•sin θ = 1/cosec θ•cos θ = 1/sec θ•tan θ = 1/cot θ | |
| 17166. |
Class 10 maths ch 15 formula |
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Answer» Gando 1) Probability =( No. of the favourable outcomes)÷ (number of all possible outcomes). 2) Probability of event,P(E) + Probability of an event not happening, P(Ē) = 1 |
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| 17167. |
Determine if the points (1,5)(2,3)(-2,-11) are colinear |
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Answer» Re............... |
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| 17168. |
Find the area of sector whose radius 2 cm? |
| Answer» Angel kitna h | |
| 17169. |
what is the hcf of 29700 and 30240 |
| Answer» Factors the number,LCM is the least common multiple,Therefore, LCM of 30240 and 29700 using prime factorisation method is 1663200. | |
| 17170. |
What is the formula used to find the zeros or roots of a quadratic polynomial |
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Answer» *Given a function of the form\xa0f(x)=ax2+bx+c, one can find the zeroes of the function (that is, where\xa0f(x)=0) by using\xa0the quadratic formula:\xa0x=−b±√b2−4ac2a.If the discriminant\xa0b2−4ac\xa0is less than zero, these roots will be complex or imaginary, and if the discriminant is greater than or equal to 0. these roots will be real.The use of\xa0±\xa0informs us that there are two solutions here; one where we are subtracting\xa0√b2−4ac, and one where we are adding it.*For a step by step example, assume the function\xa0f(x)=x2−7x+10. Here\xa0a=1,b=−7,c=10.\xa0If we set\xa0f(x)=0, then the values of x for which\xa0f(x)=0, that is to say the\xa0roots\xa0of\xa0f(x), would be determined by the quadratic formula:\xa0x=−(−7)±√(−7)2−4(1)(10)2(1)=7±√49−402=7±√92=7±32. Thus, our roots will be at\xa0x=7+32\xa0and\xa0x=7−32\xa0or\xa0x=5\xa0and\xa0x=2.On the graph of the function, we would see that the parabola crosses the x-axis at\xa0x=2\xa0and\xa0x=5. First split the middle term and get factors of the given polynomial. Next to it put the factors equal to the value of zero. Then you will get the zeroes of the polynomial. You can also verify your answer using verification method. |
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| 17171. |
in figure abcd is a trapezium in which ab parallel ef parallel dc. the length of ae |
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| 17172. |
What is the symbol used to denote irrational numbers |
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Answer» Hello The symbol used to denote irrational number is Q Hii Sandhya.......... |
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| 17173. |
Maths ma unit 6 of class 10 ma exersice 6.3 board ma ayagee |
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Answer» Hi Nahi Yes... hanji ayegee Yes |
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| 17174. |
(x+a)(x+b)=? |
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Answer» X²+(a+b)-2ab (X+a)(X+b)=X^2+(a+b)X+(ab) |
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| 17175. |
A brooch is made with silver in the form of circle with dia |
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| 17176. |
2tan30/1-tan²30 |
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Answer» 2×1/√3/1-(1/√3) ² solve krna ok Ans √3 |
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| 17177. |
please guys help me in my revision of ch 8 and 10 of maths |
| Answer» If u have already completed ur NCERT BOOK...and u want revise any chapter then firstly solve all the example, exercise questions , and solve sample paper, previous year paper of that chapter after this I hope u are ready for testing these chapter..... | |
| 17178. |
Exercise 4.1 question 2 |
| Answer» Exercise 4.1 question 4 | |
| 17179. |
What number should be added to -4/7 to get 5/9? |
| Answer» Solution: Let number be added is x -4/7 + x = 5/9x= 5/9 + 4/7 = (35+36) upon 63 i.e. = 35+36/63 =71/63Hence, required number is 71/63 | |
| 17180. |
Mai abhi 2+2=5 hota h prove kr deti hu .......bcz mujhe us time koi argent kaam h let\'s starting.. |
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Answer» No I waste my time to this question from 2 days .. ???? ??✌️????✌️????????? Btaiye ki kahan rule break hua h or mera tarika pasand aaya ho to thnks ka button jaroor press Krna.... I know how you solved it, you have solved it by mistake 0=0 (as we all know)..If write it as 20-20 =25-25 (I didn\'t see any problem in this statement)Then,If we write 20-20 as (4×5)-(4×5) there is no problem.... similarly we write 25-25 as (5×5)-(5×5). ....then if we take 4 in L.H.S as a common digit. And take 5-5 in bracket..... similarly we take 5 in R.H.S as a common digit...and take 5-5 in bracket.... And in both the sides L.H.S AND R.H.S. we have to see that (5-5) in common then we cut it ..Now we have to see 4=5and we also write it as 2+2=5. ??????????????????MENE KR DIYA JAISA MENE KAHA THA KI MENE RULE TODA H MATHS KA TO PLZZ BTAYIA KO MENE RULE KAHAM TODA H IS PURE QUESTION MEI ...??☺️?? ???????MENE KR DIYA ???? |
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| 17181. |
Express sec theta in terms of cos theta |
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Answer» Scff Sec theta= 1/cos theta |
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| 17182. |
if cosec theta=3x and cot theta=3/x, then find the value of (x²-1/x²) |
| Answer» Cot^2 theta + 1 = cosec^2 theta(3/x)^2 + 1 = (3x)^29/x^2 + 1= 9x^29/x^2 - 9x^2 = -19(1/x^2 - x^2) = -13(1/x^2 - x^2) = -1/3Therefore, 3(x^2 - 1/x^2) = 1/3 | |
| 17183. |
2 cos ^2 30 -1 |
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| 17184. |
3/5 x^2 - 2/3x +1 = 0 |
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| 17185. |
(x6 y-3 / x-2 y3 ) 1/2 ÷ ( x-1 y2 / x3 y-2 ) 1/3 = x se y v then find the value of a + b |
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| 17186. |
Chapter 8 ex 8.4 questions no 1 2 |
| Answer» To convert the given trigonometric ratios in terms of cot functions, use trigonometric formulasWe know that,cosec2A\xa0– cot2A = 1cosec2A = 1\xa0+ cot2ASince cosec function is the inverse of sin function, it is written as1/sin2A = 1\xa0+ cot2ANow, rearrange the terms, it becomessin2A = 1/(1+cot2A)Now, take square roots on both sides, we getsin A = ±1/(√(1+cot2A)The above equation defines the sin function in terms of cot functionNow, to express sec function in terms of cot function, use this formulasin2A = 1/ (1+cot2A)Now, represent the sin function as cos function1 – cos2A = 1/ (1+cot2A)Rearrange the terms,cos2A = 1 – 1/(1+cot2A)⇒cos2A =\xa0(1-1+cot2A)/(1+cot2A)Since sec function is the inverse of cos function,⇒ 1/sec2A = cot2A/(1+cot2A)Take the reciprocal and square roots on both sides, we get⇒ sec A = ±√ (1+cot2A)/cotANow, to express tan function in terms of cot functiontan A = sin A/cos A and cot A = cos A/sin ASince cot function is the inverse of tan function, it is rewritten astan A = 1/cot A | |
| 17187. |
(ii) 11th term of the AP: -3,-1/2 ,2,...,is? |
| Answer» 17 | |
| 17188. |
di is that deviation of xi from assumed mean a. |
| Answer» Yes | |
| 17189. |
Cbse 10th standard chapter 11 exercise 11. 2 question no. 1and2 |
| Answer» | |
| 17190. |
Which of the following is a polynomial ?(i)X^2+2X^1/3+4(ii)X+1/X(iii)X^-1+X^2(iv)ax^2+bx+c |
| Answer» | |
| 17191. |
Formula for sum and product of roots in a quadratic polynomial |
| Answer» Middle term factorization | |
| 17192. |
Find the zerors of the given polynomial X^2+3X+2 |
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Answer» 2x²+3x+2=02x²+4x-1x+2=02x(x+2)-1(x+2)=0(X+2) (2x-1)=0X=-2 & x=1/2 X^2+x+2x+2x(x+1)+2(x+1)(x+1)(x+2)x = -1,-2 |
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| 17193. |
9^x - 2^(x+1/2) = 2^(x+3/2) - 3^(2x-1) |
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| 17194. |
Rs Aggarwal solution class 10 CBSE |
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Answer» Chapter????? Chapter ??????? |
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| 17195. |
Maths solutions class 10 CBSE RS Aggarwal |
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Answer» Ji chapter btane ka kasht kree Chapter ????? |
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| 17196. |
prove that 7-2√3 is an irrational number |
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Answer» Thanks Question:- (7-2√3)Solution:- Let us assume that (7-2√3) is a rational number.Therefore we can write in the form of p/q. Where p and q are co- prime numbers.7-2√3=p/q7-p/q=2√37q-p/q=2√37q-p/2q=√3√3=7q-p/2qSince, we know that √3 is an irrational number .Hence our assumption is wrong 7q-p/q or 7-2√3 is an irrational number.. Hence Proved.....I hope now your doubt is clear?? |
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| 17197. |
Prove that 7-2√3 is an irrational |
| Answer» https://images.app.goo.gl/eJK1UnZKtYo2NaEA6 | |
| 17198. |
All trigonometry ratio and formula |
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Answer» Trigonometry formula Sin=Oppo/hypo Cos=adj/hypo Tan=Oppo/adj Cosec=hypo/Oppo Sec=Hypo/adj Cot=Adj/Oppo Sin=1/cosec Cos=1/sec Tan= sin/cos Cot= cos Trigonometry formulaSin=Oppo/hypoCos=adj/hypoTan=Oppo/adjCosec=hypo/OppoSec=Hypo/adjCot=Adj/OppoSin=1/cosecCos=1/secTan= sin/cosCot= cos/sin |
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| 17199. |
CSA of a cylinder |
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Answer» 2πrh 2πrh 2 π r h + 2 π r 2 2 \\pi rh + 2 \\pi r^{2} 2πrh+2πr2. the CSA of a cylinder will be:\xa02*π*R*H Curved Surface Area-\xa0The curved surface area is defined as the area of only curved surface, leaving the circular top and base.Formula for calculating the Curved Surface Area (C.S.A.)-Consider a cylinder having a height ‘h’ and base radius ‘r’.The curved surface area of a cylinder is given as-C.S.A.=\xa0 |
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| 17200. |
Height and distance link |
| Answer» Height is the measurement of an object in the vertical direction and distance is the measurement of an object from a particular point in the horizontal direction. If we imagine a line connecting the point of observation to the topmost point of the object then the horizontal line, vertical line and the imaginary line will form a triangle.Observe the figure. Consider the observer to be at point C. The height of the object is shown by line AB. The distance of the object from the observer is given by line BC. The object may or may not be perpendicular to the ground. Line AC represents the Line of Sight when the observer is observing the topmost point of the object. Angle\xa0α represents the angle of elevation and Angle\xa0β represents the angle of depression.Using trigonometry, if we are provided with any of the two quantities that may be a side or an angle, we can calculate all the rest of the quantities. By the law of alternate angles, the angle of elevation and angle of depression are consequently equal in magnitude (α =\xa0β). Tan\xa0α is equal to the ratio of the height and distance.You can be provided with any two of the following information:\tThe distance of the object from the observer\tThe height of the object\tAngle at which the observer views the topmost point of the object (angle of elevation)\tThe angle at\xa0which the observer views the object when the observer is on top of a tower/building (angle of depression) | |