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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 17751. |
O is the centre of the circle,PQ is a tangent at A.If angle PAB=58°,find angle ABQ AND Angle AQB. |
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Answer» Ya ya ????? Oh ...good ???????? RiGht Yee mein bhi ye he likhne wali thi ? No study only HOLI so let\'s play HOLI???? |
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| 17752. |
Sin(90_80) |
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Answer» Sin 10 Cos 80 Cos 80 Cos 80 Cos 10 |
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| 17753. |
1÷ tantheta+cottheta × 1÷ 1+ sintheta + 1÷ 1- sintheta |
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Answer» 2 cot theta+ 1 Hmmm? Ooooo Mr sudhanshu shekhar Rajvansh vats Cool Aap ka real name Hmm??? Hmm Let\'s play HOLI??? Aaaj no study only holi??? |
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| 17754. |
09878996656+6688888_678956(3466+866688_7899) |
| Answer» What is this | |
| 17755. |
What is the perimeter of sector? |
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Answer» l+2r Theta / 360 +2 pie × r +2r 2pi r 0/360 + 2r |
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| 17756. |
16th term of sn=2n+3n |
| Answer» 80 | |
| 17757. |
Math pura syllabus abhi kaise khatma kare plz give me easy tips ?and give formula all chapter |
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Answer» Name the website nancy Friends outcomes of democracy chapter ho Gaya ? Yes you was right and take help from website also and video Don\'t know ,ek hi rasta hai practice and sample paper |
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| 17758. |
All of you are vains |
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| 17759. |
√1296 |
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Answer» 36 36 36 36 36 36 |
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| 17760. |
datesheet |
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Answer» Or,see your admit card? See fast on internet ???? |
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| 17761. |
If sin0 + sin20 = 1. Prove that cos20 + cos40 =1 |
| Answer» sin0=1-sin20sin0=cos20now LHS= cos20 +cos40 cos20+(cos20)2 cos20+sin20=1 =RHS | |
| 17762. |
Root2 ,root8 ,root18, root32............ ? Is a ap or not? |
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Answer» Yes it is an a.p. In ap...D= root2 Yes it is an apEvery have a common difference of √2 √2, 2√2. ,3√2.... Yes |
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| 17763. |
If tan theta + sin theta =m and tan theta -sin theta =n show that m^2-n^2 = 4 root mn |
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Answer» Hii U can see in rd sharma Sorry Which state u are That also u don\'t know ah Very very simple |
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| 17764. |
If secA-tanA=root3-2 then prove that 1-sinA/1+sinA=7-4root 3 |
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| 17765. |
Tan¥=a/x then find the value of x/root a^2+x^ |
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| 17766. |
Is stamp on the photo on the admit card is very important???? |
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Answer» Yes sayad nhi. kyu?? Yes Yes Pata nahi |
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| 17767. |
Question is sum and product of zeros of poly. X3+x2-3x-3 are 0 and 3. Find all zeros. |
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Answer» Ohhhhhhh. Thanks. can give answers Dividing X2-3 by the polynomial we get an equationX+1 so the other zero of polynomial is -1 (x-3)(x-0)=X2-3x+0Now by dividing X2-3x by X3+X2-3x 2 min Plz tell me ans. Make another polynomial with the help of sum &pro. Kx^2-Sx+P then divide it with the given polynomial What happen. |
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| 17768. |
How can we name a triangle after proving similaryy |
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Answer» I hope you got it? Start with the part which is same example:- ABC~DEF in which angleA =angleD.....and so on |
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| 17769. |
Plz give answers. |
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Answer» Ok I sloved it .... iss app possible ni h X,y,z are in a.p. then find ( x+y-z) (y+z-x) ask questions |
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| 17770. |
If x,y,z are in a.p.then what is the value of (x+y-z) (y+z-x).. |
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Answer» Ohhh. x, y and z are in the AP.So, 2y = x + zx = 2y - z .......(1) (x + y - z)(y + z - x) .......(2)Substituting (1) in (2)[(2y - z) + y - z][y + z - (2y - z)]= (2y - z + y - z)(y + z - 2y + z)= (3y - 2z)(2z - y)= 6yz - 3y2 - 4z2 + 2yz= 8yx - 3y2 - 4z2 I HOPE YOU GOT IT!!!!!!!!!!!!!!!!!!! I have asked question. Yes |
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| 17771. |
Solve for x and y .mx+ny=m+n.m(1/m- n - 1/m+n)x + n (1/n-m - 1/m+n)y = 2m/m+n |
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| 17772. |
IF p is a prime number then prove that under root 3 P is irrational |
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| 17773. |
What is the area of a phone rectangle |
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| 17774. |
Find the quadratic polynomial where sum and product of the zeros are a and 1/a |
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Answer» ax sq. - ax + 1 X sq.-ax+1/a |
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| 17775. |
Q) ✓2x + ✓3y =0.....(1) ✓3x + ✓8y =0......(2) Solve this full solve answer I want |
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| 17776. |
If one zero of quadratic polynomial x2-x-(2+2k) is -4, find the value of k. |
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Answer» Yep K=9 |
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| 17777. |
What is the formula of area of triangle with specific angle |
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Answer» Hii..samb I/2 r square sin theta For isosclese triangle with equal angles of X degree and equal sides of R cm( R^2 sinX )/2 Use herons formula Area of triangle - 1/2 base×hieght |
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| 17778. |
215÷0.2 |
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Answer» 1075 1075 1075 1075 |
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| 17779. |
Tan0=1/root3 find value of sin (90-0) |
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Answer» Sin 90-30=cos 60? Sin 90 - 30 = sin 60= √3/2 tan = 1/ root 3Sin (90 - 30 )= 2 root 3 / 2 60 or 30 |
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| 17780. |
3xsqure+2root5-5=0 wheather the quadratic equation has real roots and if so find the roots |
| Answer» The given equation is {tex} 3 x ^ { 2 } + 2 \\sqrt { 5 } x - 5 = 0{/tex}Here, a = 3, b =\xa0{tex}2 \\sqrt { 5 }{/tex} and, c = -5{tex}\\therefore{/tex}\xa0D = b2 - 4ac = ({tex}2 \\sqrt { 5 }{/tex})2 - 4\xa0{tex}\\times{/tex} 3 {tex}\\times{/tex}\xa0- 5 = 20 + 60 = 80 > 0So, the given equation has real roots, and are given by{tex}\\alpha = \\frac { - b + \\sqrt { D } } { 2 a } = \\frac { - 2 \\sqrt { 5 } + \\sqrt { 80 } } { 2 \\times 3 } = \\frac { - 2 \\sqrt { 5 } + 4 \\sqrt { 5 } } { 6 } = \\frac { 2 \\sqrt { 5 } } { 6 } = \\frac { \\sqrt { 5 } } { 3 }{/tex}and,\xa0{tex}\\beta = \\frac { - b - \\sqrt { D } } { 2 a } = \\frac { - 2 \\sqrt { 5 } - \\sqrt { 80 } } { 2 \\times 3 } = \\frac { - 2 \\sqrt { 5 } - 4 \\sqrt { 5 } } { 6 } = - \\sqrt { 5 }{/tex} | |
| 17781. |
What is the volume of frustum |
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Answer» 1/3 pie(r2+R2+r×R ) ×h I/3pie h (r×r + R×R +r×R) |
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| 17782. |
Campsite Number???? |
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Answer» ??? Composite |
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| 17783. |
Anyone here who say i got 90% above in 10th board |
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Answer» Ah pucho I will Ek questio puchu tere se Mee also Got Meeeee |
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| 17784. |
at what time we have to reach examination hall? |
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Answer» Before ten Before ten because exam will start at ten thirty |
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| 17785. |
Draw a triangle ABC with side BC 7cm angle b 45 degree angle A 105 Degree |
| Answer» It\'s not possible to draw triangle here | |
| 17786. |
Pie is a rational or irrational |
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Answer» Is irrational number because pie ia in fraction form so it is accurate Irrational |
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| 17787. |
Ex 4.3 question-2 |
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| 17788. |
(k+4)x2+(k+1)x+1=0 |
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Answer» And prakash your answer is 7 and -5 5 and -3 are the zeroes (k+9)*2+(k+1)*+1=0 |
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| 17789. |
U will start solving maths from section A or D |
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Answer» Section D Will u leave place to solve section A,B.C if u solve from D At middle No Ya but we can finish it in very less time Sec a takes more time than other sections But section A will be little tricky Sec d First C and D and then B and A Section A |
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| 17790. |
30,28,27.......find its first negative term |
| Answer» Here, the given A.P. is\xa030,28,27.......a = 30d = 28 - 30 = -2The general term of A.P. isan\xa0= a + (n - 1)dLet nth term is negative,a + (n - 1)d < 030 + (n - 1)(-2) < 030 - 2n + 2 < 032 < 2n16 < nHence, the 17th term is first negative term. | |
| 17791. |
Kya sabke exam apne school me hoyenge ya sabhi doosre school me jayenge? Exam check kon karega? |
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Answer» Doosre school mein or check doosre school ke teachers Dusre school me jayenge? Dusre school mein jayege Doosre schl mein |
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| 17792. |
How % are you expecting?Well i am expecting from 82% to 93%? |
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Answer» Meri 75 ageye to me party du sabko.... 93-97% Above 93% 90-95% Mera v above 95 % Don\'t know but I will give my best ? My 75% v aa jaye to bahut hai Above 95 ??? Above 95 . |
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| 17793. |
A cosec A 1 1 cos A sin A |
| Answer» Kya hai ye.. ?? | |
| 17794. |
Optional exercise is come in board exam |
| Answer» Pls prepare for it it may come | |
| 17795. |
1/2x+b+2x=1/2a+1/b+1/2x solve for x |
| Answer» {tex}\\frac{1}{2a + b + 2x}{/tex}\xa0=\xa0{tex}\\frac{1}{2a}{/tex}\xa0+\xa0{tex}\\frac{1}{b}{/tex}\xa0+\xa0{tex}\\frac{1}{2x}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{1}{2a + b + 2x}{/tex}\xa0-\xa0{tex}\\frac{1}{2x}{/tex}\xa0=\xa0{tex}\\frac{1}{2a}{/tex}\xa0+\xa0{tex}\\frac{1}{b}{/tex}\xa0{tex}\\Rightarrow{/tex}{tex}\\frac { 2 x - 2 a - b - 2 x } { ( 2 a + b + 2 x ) ( 2 x ) }{/tex}\xa0=\xa0{tex}\\frac{b + 2a}{2a \\times b}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\frac { - ( 2 a + b ) } { ( 2 a + b + 2 x ) 2 x }{/tex}\xa0=\xa0{tex}\\frac{b + 2a}{2ab}{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac { - 1 } { 4 a x + 2 b x + 4 x ^ { 2 } }{/tex}\xa0=\xa0{tex}\\frac{1}{2ab}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}4x^2 + 2bx + 4ax = -2ab{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}4x^2 + 2bx + 4ax + 2ab = 0{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}2x(2x + b) + 2a(2x + b) = 0{/tex}{tex}\\Rightarrow{/tex}\xa0(2x + b)(2x + 2a) = 0{tex}\\Rightarrow{/tex}\xa0x = -{tex}\\frac{b}{2}{/tex} or x = -a | |
| 17796. |
If sin theta - cos theta=0 0 |
| Answer» Wt | |
| 17797. |
12x2-27x-0 |
| Answer» O | |
| 17798. |
How many maltipels of seven between 0 to 200 |
| Answer» 28 | |
| 17799. |
What is octate rule |
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Answer» Ohh tu to Kunal h Nahi Nahi koi baat nahk sorry answer Dena nai late ho gaya The octet rule or the electronic theory of chemical bonding was developed by Kossel and Lewis. According to this rule, atoms can combine either by transfer of valence electrons from one atom to another or by sharing their valence electrons in order to attain the nearest noble gas configuration by having an octet in their valence shell. Mujhe koi toh help kaar do.... iss Jessica se baat karne mein It refers to the tendency of atoms to prefer to have 8 electrons in the valence shell Koi hai ya phir sab so gye??? |
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| 17800. |
Pawan |
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Answer» Ek hi time m aa jayega Mere Lego Yaisha name kewal ek hi hai Photo kaun Si hai Ok my id is --> Bravishi kumar Ya Id du |
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