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18101.

How we know where i should use curved surface area and where total surface area

Answer» It will be asked total surface area......in question
Jb closed ya solid rhe koi bhi...jaise ki cylinder ya cube ya cuboid. ...... rhe tb total surface area use kro
Ya
Mostly used curved surface area....
18102.

Kunal ????????i luv u

Answer» Ooo
Yaa.... who is kunal here??
Wow... R u in relationship with him...
Who is kunal here
18103.

The sum of first n terms of an AP is given by Sn=2n^2 +3n.find the sixteenth term of the AP

Answer» Do want it\'s solution?
65
65
18104.

If an+1+bn+1by an+bn is the Am between a and b then find the value of n

Answer» it\'s 0
Are mera ans..shi hai.na????
H shi h
Nhi mai 10 se hu
Shi hai..na???).
Solved in only 2 min??
n = -1/2
Aap 11 se ho??
18105.

Which subject do you all like to study

Answer» Maths
Math and science
English
maths
Only maths
18106.

Volumes surface area

Answer»
18107.

Pythagoras theorm

Answer»
18108.

Will the change in NCERT SYLLABUS effect from 2018-19 or 2019-20??

Answer» I don\'t know
18109.

Sir i wnt the complete date sheet of 10th cbse board examination ...

Answer»
18110.

Hello riddhi are u here

Answer» Yes aa jao na plzzzz
??????
Absent h aaj
18111.

Hello riddhi me rah nahin saka chat Karne chalia aya???????????????????

Answer»
18112.

Sin _cos

Answer» 1
Hii
18113.

According to HRD minister will the NCERT Syllabus change from 2018-19 or from 2019-20?

Answer»
18114.

4+8-4(6)+8-2/2+68-60/10+25=?

Answer» Write or wrong...?
26. 8
18115.

Hii or RAM RAM

Answer» K baat koi koni kkk
18116.

Section formula ki derivation exam me a saktii h

Answer»
18117.

Has anybody latest blue print of Mathematics ?

Answer» Is app me bhi diya hua h
What is the marks weightage of Trigonometry?
Yess
18118.

construction nahi samaj me aa raha h

Answer»
18119.

How many Monday in an non leap year?

Answer» 53 Mondays
18120.

RAM RAM sb nnnnn

Answer»
18121.

Good morning hello everybody

Answer» Hello
Hey....
Hiii
18122.

How many formulas in surface area and volume

Answer» Soooooo manyyy
18
18123.

Bye my cuty riddhi I will back soon?

Answer»
18124.

Prove that sec power 4 teta - sec power 2 teta = tan power 4 teta + tan power 2

Answer» Sec² = tan² + 1.....Lhs=Sec⁴-sec²....=sec²( sec² - 1).....As sec² - 1= tan²......Lhs=sec²(tan²).....Lhs=(1 + tan²)(tan²)......Lhs=tan⁴ + tan²Hence proved
18125.

Hi darling

Answer»
18126.

Hlo guys kisi ko m yaad hu ya sab bhul gye

Answer» Aap batao
Fine
How r u guys
Hii
Hmme ...yaad ho aap...??
18127.

Find the value of k for which the point are collinear (7,-2), (5,1), (3,k).

Answer» Area = 0 use the area formula
K is 4
18128.

Find the valur of k in quadratic equation has equal roots

Answer» D= 0.
Roots equal hai to D=0 hoga. Bas D=b2-4ac formula use kar lo
Equation toh do
18129.

Roots of equation 3n^2-11n+2

Answer»
18130.

Find the root of equation x square + x -p(p+1)

Answer» Give me answer fast......
18131.

If the question is in no solution we will able to substitube the equation yes or no

Answer»
18132.

Cot^2A(secA-1)/1+sinA= sec^2A(1-sinA/1+sinA)

Answer»
18133.

(1-cos∅)²÷sin²∅

Answer»
18134.

Find the value of alpha beta Gama if alpha + gama= 2 beta

Answer» Cannot be determined
18135.

The ratio between the sum of two APs is (3m-18) : (7n-15) find the ratio of their 12th term

Answer» For the first AP,Let first term=a1common difference=d1using formula:{tex}\\Longrightarrow \\mathrm { S } _ { \\mathrm { n } } = \\frac { \\mathrm { n } } { 2 } [ 2 \\mathrm { a } + ( \\mathrm { n } - 1 ) \\mathrm { d } ]{/tex}{tex}\\Longrightarrow \\left( \\mathrm { S } _ { \\mathrm { n } } \\right) _ { 1 } = \\frac { \\mathrm { n } } { 2 } \\left[ 2 \\mathrm { a } _ { 1 } + ( \\mathrm { n } - 1 ) \\mathrm { d } _ { 1 } \\right]{/tex}For 2nd AP.Given,\xa0{tex}\\Rightarrow{/tex}No. of terms=nLet,\xa0{tex}\\Rightarrow{/tex}first term=a2{tex}\\Rightarrow{/tex}common difference=d2Using formula:{tex}\\Longrightarrow \\mathrm { S } _ { \\mathrm { n } } = \\frac { \\mathrm { n } } { 2 } [ 2 \\mathrm { a } + ( \\mathrm { n } - 1 ) \\mathrm { d } ]{/tex}{tex}\\Longrightarrow \\left( \\mathrm { S } _ { \\mathrm { n } } \\right) _ { 2 } = \\frac { \\mathrm { n } } { 2 } \\left[ 2 \\mathrm { a } _ { 2 } + ( \\mathrm { n } - 1 ) \\mathrm { d } _ { 2 } \\right]{/tex}According to question :{tex}\\Longrightarrow \\frac { \\left( \\mathrm { S } _ { \\mathrm { n } } \\right) _ { 1 } } { \\left( \\mathrm { S } _ { \\mathrm { n } } \\right) _ { 2 } } = \\frac { 3 \\mathrm { n } + 8 } { 7 \\mathrm { n } + 15 }{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac { \\frac { n } { 2 } \\left[ 2 a _ { 1 } + ( n - 1 ) d _ { 1 } \\right] } { \\frac { n } { 2 } \\left[ 2 a _ { 2 } + ( n - 1 ) d _ { 2 } \\right] } = \\frac { 3 n + 8 } { 7 n + 15 }{/tex}Substitute n=23:{tex}\\Longrightarrow \\frac { 2 a _ { 1 } + ( 23 - 1 ) d _ { 1 } } { 2 a _ { 2 } + ( 23 - 1 ) d _ { 2 } } = \\frac { 3 \\times 23 + 8 } { 7 \\times 23 + 15 }{/tex}{tex}\\Longrightarrow \\frac { 2 \\mathrm { a } _ { 1 } + 22 \\mathrm { d } _ { 1 } } { 2 \\mathrm { a } _ { 2 } + 22 \\mathrm { d } _ { 2 } } = \\frac { 69 + 8 } { 161 + 15 }{/tex}{tex}\\Longrightarrow \\frac { 2 \\left( a _ { 1 } + 11 d _ { 1 } \\right) } { 2 \\left( a _ { 2 } + 11 d _ { 2 } \\right) } = \\frac { 77 } { 176 }{/tex}{tex}\\Longrightarrow \\frac { a _ { 1 } + ( 12 - 1 ) d _ { 1 } } { a _ { 2 } + ( 12 - 1 ) d _ { 2 } } = \\frac { 7 } { 16 }{/tex}{tex}\\Longrightarrow \\frac { \\left( T _ { 12 } \\right) _ { 1 } } { \\left( T _ { 12 } \\right) _ { 2 } } = \\frac { 7 } { 16 }{/tex}{tex}\\therefore{/tex}\xa0(T12)1 : (T12)2=7: 16.
18136.

x,y&z are AP . Show that (x+y-z)(y+z-x)

Answer» a2- a1 =a3-a2y-x=z-y2y-z=x Put value of x and solve them
18137.

TanA /1+secA - TanA/1-secA=2cosecA

Answer» Plz check d que...it should b + in middle
18138.

Find the mean of first prime numbers.

Answer»
18139.

Class 9Support material

Answer» ??????
18140.

In the adjoining figure AC is diameter of a circle

Answer» Given: AC is the diameter of a circle whose centre is O. AB and CD are parallel chords of the circle.To prove : AB = CDConstruction: Draw OP {tex}\\perp{/tex}\xa0AB and OQ\xa0{tex}\\perp{/tex}\xa0CDProof : In {tex}\\triangle{/tex}s OAP and OQCOA = OC |Radii of the same circle{tex}\\angle{/tex}OAB =\xa0{tex}\\angle{/tex}OCQ [Alt. {tex}\\angle{/tex}s]\xa0{tex}\\angle{/tex}OPA =\xa0{tex}\\angle{/tex}OQC [Each = 90o\xa0]\xa0{tex}\\therefore{/tex}\xa0{tex}\\triangle{/tex}OAP\xa0{tex}\\cong{/tex}\xa0{tex}\\triangle{/tex}OQC [AAS Axiom]{tex}\\therefore{/tex}\xa0OP = OQ [c.p.c.t]{tex}\\therefore{/tex}\xa0AB = CD[{tex}\\because{/tex}Chords of a circle which are equidistant from the centre are equal]
18141.

Tri

Answer»
18142.

Hello jitu r. U listening

Answer» Tomorrow when should we come.
Yes
18143.

Prove that the tangents

Answer»
18144.

is any body online

Answer» Tuj jese ladke sayd apni real bhn ki bhi respect nhi krte
Too mera munh me lele tabse sari ladkiyon ko preshan kar rha hai
Jyada mt bol
Ooo.... Bikari plz apni limit me rh
Jakar kutte se kiss le
Everybody is online.ek kiss de de
18145.

For what value of \'p\'are 2p+1 ,13,5p-3, 3consecutive terms of an AP.

Answer» I do this with formula 2b=(a+b)
P=4
Common difference formula
18146.

Sahi pakde ham Dj ba

Answer» MC khike..... Harsh tuu kha h
Nhi h cuty h
Tu kutti
Kamene kutteee ho tm
Hii aaru
Dj khade waali ridhi
18147.

Anyone want to be my girlfriend (conditions applied only for girls)

Answer» Ya
Nonsense
U r a girl or a boy
What Dj riddhi
Bhai to single hi rahega
What
Boluu mujhe sirf gaali aata h bolne sunna h to bolo
Dj aru.Dj ridhi
Deviyon kuchh bolo bhi
18148.

P(x)=(ax)square+bx+c. If a+b=c, then find of its one zeroes

Answer»
18149.

Any one is alive?

Answer» Hlo Mr hydrogen bomb ? remember me or not.....
O
Yepe
Nothing much
Oh really ....i m scared of u
Ya...I m a modern ghost....who do chatting
What\'s up
Oh seriously
Na
Ya I am alive alone ????
18150.

LOL baklol

Answer» real name se aana tu fir dek ?
DJ
Real name se aana
Chup rhhhh
Hai kon??????