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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 18351. |
The sum of frist \'n\' even numbers is hiven by the relation Sn=n(n+1).find \'n\' if the sum is 420 |
| Answer» n(n + 1) = 420 ...Given{tex}\\Rightarrow n ^ { 2 } + n = 420{/tex}{tex}\\Rightarrow n ^ { 2 } + n - 420 = 0{/tex}Comparing with An2 + Bn + C = 0, we getA = 1, B = 1, C = -420Using the quadratic formula, {tex}n = \\frac { - B \\pm \\sqrt { B ^ { 2 } - 4 A C } } { 2 A }{/tex}we get {tex}\\Rightarrow \\frac { - 1 \\pm \\sqrt { 1 + 1680 } } { 2 } = \\frac { - 1 \\pm \\sqrt { 1681 } } { 2 }{/tex}{tex}= \\frac { - 1 \\pm 41 } { 2 } = \\frac { - 1 + 41 } { 2 } , \\frac { - 1 - 41 } { 2 } = 20 , - 21{/tex}n = -21 is in admissible as n is the number of terms.{tex}\\therefore n = 20{/tex}Hence, the required value of n is 20. | |
| 18352. |
If tan theta + cos theta =2 then find tan^2 theta + cot ^2 theta = ? |
| Answer» 2 | |
| 18353. |
Koi two brain id do |
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Answer» U motivate me about maths n I also motivate u for social ☺☺ Apn ne baat ki thi na .. Hey vidhan...sorry but I don\'t remember you Hii pragya ..Bhul gaye kya ?? SPragya....itna brainly ID ke liye tadap kyu |
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| 18354. |
Megha mene tumhari vo wali id add kri h |
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| 18355. |
How to unblock |
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Answer» Hum jo answer diye hai..usme maths ka sabse upar wala answer dekho Id search krk msg pe jao.... Unblock k option ayega Where? |
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| 18356. |
Hi nikita |
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Answer» Mai abhi bhi use delete kiya h Brainly id dena Hello |
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| 18357. |
Qurbinate gemeatery |
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Answer» Oh sorry Good night |
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| 18358. |
Are you giving or not |
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Answer» ??? are u crack? Kiss what? |
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| 18359. |
Hi arohi |
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| 18360. |
AB koi questions nhi pooch rha toh.... r king off... and ishan onnn????? |
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Answer» Kya nhi dekhe 304 Yes niki... nhi dekhe behna ji Koi baat nahi...followers dekhe ? King I think your name is ishan Nhi yaar.. paise nhi hqi..??? Bhaiya ji....aaj party nahi karoge Mtlb |
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| 18361. |
Aaj sabhi innocent se bache kaha gaye ??? |
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Answer» Also good I\'m fine ...what abt u How are you pragya I am here Okay....hi all Yhi hai Hii |
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| 18362. |
Pythagorus theorom |
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Answer» Yes L ki jgh P kr dena (H) ²=(p)²+(B)² H2 = B2 + L2 |
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| 18363. |
Cbse Blue Print 2018 |
| Answer» Check marking scheme here :\xa0https://mycbseguide.com/cbse-syllabus.html | |
| 18364. |
Hli guys koi hai ... |
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Answer» Hii Hii |
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| 18365. |
Shriya I am deleting this app bye |
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Answer» Tell me you are money or not Biiiiii |
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| 18366. |
Shriya or Shanaya |
| Answer» Shriya | |
| 18367. |
Bye.... To all ?ly frnds ? ???time ? |
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Answer» I will send uh : hii inbox dear What\'s urs?? Brainly id please Biii Bye |
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| 18368. |
Formula of square |
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Answer» Side×side Side×side |
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| 18369. |
Shriya what happened |
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Answer» But number tho dethi nhi I like u I decide you but you don\'t like me Decide me or her Tum ne hi tho miluja number nhi dya |
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| 18370. |
How we find third cordinate of third vertex of right angle triangle |
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| 18371. |
Show that Square of every positive integer is in the form of 3m,3m+1. |
| Answer» By Euclid’s division algorithma = bq + r, where 0 ≤ r ≤ bPut b = 3a = 3q + r, where 0 ≤ r ≤ 3If r = 0, then a = 3qIf r = 1, then a = 3q + 1If r = 2, then a = 3q + 2Now, (3q)2\xa0= 9q2= 3 × 3q2= 3m, where m is some integer(3q + 1)2\xa0= (3q)2\xa0+ 2(3q)(1) + (1)2= 9q2\xa0+ 6q + 1= 3(3q2\xa0+ 2q) + 1= 3m + 1, where m is some integer(3q + 2)2\xa0= (3q)2\xa0+ 2(3q)(2) + (2)2= 9q2\xa0+ 12q + 4= 9q2\xa0+ 12q + 4= 3(3q2\xa0+ 4q + 1) + 1= 3m + 1, where m is some integerHence the square of any positive integer is of the form 3m, or 3m +1But not of the form 3m + 2 | |
| 18372. |
Tan^A= |
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| 18373. |
How to teach triknomatrik |
| Answer» It\'s trigonometry | |
| 18374. |
Solve the following questions2cos^x +root2 since =2 |
| Answer» Why | |
| 18375. |
Bolo na |
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Answer» Ho.... No? No Shanaya is searching u Are you money Kya bolo |
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| 18376. |
Sn=2nsquare + 3n find it nth term |
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| 18377. |
Find the perpendicular distance of(10,12)from y-axis |
| Answer» 10 units | |
| 18378. |
2u-7v=-1; 4u3v=14Solve this by using cross multiplication method. |
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| 18379. |
Cos90-tan60 |
| Answer» 0-1/root 3 | |
| 18380. |
Prove that an = a(n-1)d |
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Answer» Thanks brooo Let a1, a2,a3,.... be an ap where a is first term and d is common differenceFirst term =aSecond term a2= a+ d=a+(2-1)d Third a3= (a+d)+d =a+(3-1)dtherefore an= a+(n-1)d |
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| 18381. |
Solve 1÷(a+b+c)=1÷a+1÷b+1÷c if a+b is not equal to zero |
| Answer» The most easiest question of maths | |
| 18382. |
Ohh harsh name change again? |
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| 18383. |
135 225 |
| Answer» ???? | |
| 18384. |
In the given figure DE//AQ and DF//AR.Prove that EF//QR |
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Answer» Bss ayse mere.... lol ????esa kyu pucha???? Harsh tm 10th me hi ho na from* where r u feo |
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| 18385. |
Ajj sb busy hai koi hi bhi ni bola mujhe??? |
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Answer» LUv nahi HARSH Hi rohan Mujse baat karo Bdiya aur tum mr.luv kapoor Hi kse ho Hii hy dear. ?? |
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| 18386. |
How to make the class intervals equal for calculating the median. Class 10?? |
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| 18387. |
Should i prefer NCERT examplar for boards ? |
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Answer» Nice ? Js focus on ncert main ? nd do previous years question paper |
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| 18388. |
8x+5y=93x+2y=4 |
| Answer» The given pair of linear equations8x + 5y = 9 ...(1) ...(1)3x + 2y = 4 ...(2) ...(2)\tby substituting method\tFrom equation (2), 2y = 4 - 3x\t{tex}\\Rightarrow \\;y = \\frac{{4 - 3x}}{2}{/tex}\xa0...(3)\tSubstitute this value of y in equation (1), we get\t{tex}8x + 5\\left( {\\frac{{4 - 3x}}{2}} \\right) = 9{/tex}\t{tex}\\Rightarrow{/tex} 16x + 20 - 15x = 18\t{tex}\\Rightarrow{/tex} x + 20 = 18\t{tex}\\Rightarrow{/tex} x = 18 - 20\t{tex}\\Rightarrow{/tex} x = -2\tsubstituting this value of x in equation (3), we get\t{tex}y = \\frac{{4 - 3( - 2)}}{2} = \\frac{{4 + 6}}{2} = \\frac{{10}}{2} = 5{/tex}\tSo the solution of the given pair of linear equations is x = -2, y = 5.\tby cross-multiplication method\tLet us write the given pair of linear equation is\t8x + 5y - 9 = 0 ...(1)\t3x + 2y - 4 = 0 ...(2)\tTo solve the equation (1) and (2) by cross multiplication method,\twe draw the diagram below:\t\tThen,\t{tex}\\frac{x}{{(5)( - 4) - (2)( - 9)}} = \\frac{y}{{( - 9)(3) - ( - 4)(8)}}{/tex}{tex} = \\frac{1}{{(8)(2) - (3)(5)}}{/tex}\t{tex}= \\frac{x}{{ - 20 + 18}} = \\frac{y}{{ - 27 + 32}} = \\frac{1}{{16 - 15}}{/tex}\t{tex}\\Rightarrow \\frac{x}{{ - 2}} = \\frac{y}{5} = \\frac{1}{1}{/tex}\t{tex}\\Rightarrow{/tex} x = -2 and y = 5\tHence, the required solution of the given pair of linear equations is x = -2, y = 5.\tVerification : substituting x = -2, y = 5, we find that both the equation (1) and (2) are satisfied as shown below:\t8x + 5y = 8(-2) + 5(5) = -16 + 25 = 9\t3x + 2y = 3(-2) + 2(5) =- 6 + 10 = 4\tHence, the solution is correct. | |
| 18389. |
Find the coordinates of the point on y-axis which I nearest nearest to point (-2,5) |
| Answer» 0,5 | |
| 18390. |
Show that any positive odd integer is of the form 6q+1 or 6q+3 or 6q+5, where q is some integer. |
| Answer» It\'s very easy fist of all take b in place of 6 a positive integer | |
| 18391. |
Tati |
| Answer» | |
| 18392. |
If the perimeter and the area of a circle are numerically equal then find the radius of the circle. |
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Answer» Vaise thnx ki need nhi h ye mat kahiye? Ya thanks a lot? Is it helpful? 2#r=#rr r and pie cut then r is equal to 2 Let the radius of the circle be r units.Perimeter of the circle = 2πr unitsArea of the circle = πr2 sq unitsNumerical value of area of the circle = Numerical value of perimeter of circle So, πr2 = 2πr⇒ r = 2Thus, the radius of the circle is 2 units. Yes Can u show how ? 2 |
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| 18393. |
Kiya class 10th maths ke om liye ncert question enough hai??? |
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Answer» Ncert exampler is must Ni |
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| 18394. |
If 2 sin square theta - cos square theta = 2 then,find the value of theta |
| Answer» Given:\xa0{tex}2sin^2\\theta-cos^2\\theta=2{/tex}⇒\xa0{tex}2(1-cos^2\\theta)-cos^2\\theta=2{/tex}\xa0{tex}[\\because sin^2\\theta+cos^2\\theta=1]{/tex}⇒{tex}2-2cos^2\\theta-cos^2\\theta=2{/tex}{tex}\\Rightarrow 2-3cos^2\\theta=2{/tex}{tex}\\Rightarrow -3cos^2\\theta=2-2{/tex}⇒\xa0{tex}-3cos^2\\theta=0{/tex}{tex}\\Rightarrow cos^2\\theta=0{/tex}{tex}\\Rightarrow cos\\theta=0{/tex}{tex}\\Rightarrow cos\\theta=cos90°{/tex}{tex}\\Rightarrow \\theta=90°{/tex}\xa0 | |
| 18395. |
Proof of alternate segment theorm |
| Answer» See on Google, | |
| 18396. |
Tan30-sin60 |
| Answer» | |
| 18397. |
Ruthless King......303 ....hope you got it bhaiya ji |
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Answer» HmmmmToh dundiye unhe Hahahhahahhahahah...bhaiya ji smile??? Wahi mil jae toh baat hi kuch aur hoti Toh aapke bhaiyaji hain kahan?? Yeh humare bhaiya ji samajh gaye honge What is 303?? What is this? What is that 303 |
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| 18398. |
2 x minus 1divided by 4 x cube minus 8 x square + 8 x + 1 |
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| 18399. |
Hlo all and my bhaiya.... |
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Answer» Marjii. Tumhari marzipan.. Tumhe bhai banna hai ya frnd ? Jo bologe agey se wahi bolungi Mujhe bhul gayi kya.. Are waah ek aur bhai Hlo Pragya Haa bena bolo Kaise ho Hello pragya Hlo behna ji |
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| 18400. |
What is ARPANET |
| Answer» Advanced Research Project Agency Network | |