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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 18801. |
If one zero of the polynomials (a2+a)x2+13x+6a is reciprocal of the other find a? |
| Answer» Let {tex} \\alpha{/tex}\xa0and\xa0{tex} \\frac { 1 } { \\alpha }{/tex} be the zeros of\xa0(a2\xa0+ 9)x2\xa0+ 13x\xa0+ 6a.Then, we have{tex} \\alpha \\times \\frac { 1 } { \\alpha } = \\frac { 6 a } { a ^ { 2 } + 9 }{/tex}⇒\xa01 =\xa0{tex} \\frac { 6 a } { a ^ { 2 } + 9 }{/tex}⇒\xa0a2\xa0+ 9 = 6a⇒ a2 - 6a + 9 = 0⇒\xa0a2\xa0- 3a - 3a + 9 = 0⇒\xa0a(a - 3) - 3(a - 3) = 0⇒\xa0(a - 3) (a - 3) = 0⇒\xa0(a - 3)2\xa0= 0⇒\xa0a - 3 = 0⇒ a = 3So, the value of a in given polynomial is 3. | |
| 18802. |
sinA + 2cosA = 1(given), then prove that 2sinA - cosA = 2 |
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Answer» I have solved Google kro.... |
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| 18803. |
Hi I friend |
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Answer» Hi... Shipra Hi hlo |
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| 18804. |
(-1)°= ??? |
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Answer» Hmm,bs 0 nhi To 1 hoga hi...??????? Abe to 2nd bar me likha tha na Answer 0 hoga..??? Sorry.... 0 to...n Kuch bhi?? ??? 1 -1 to the power 0 =??? Kya??? |
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| 18805. |
Duff r |
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Answer» Wahi toh Kise bol rhe ho |
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| 18806. |
√sec square theta + cosec square theta = tan theta + cot theta |
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| 18807. |
If sin theta = a square - b square/a square + b square find 1+ tan theta cos theta |
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| 18808. |
2+(2-6) |
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Answer» -2 -2 -2 |
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| 18809. |
85==159 |
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| 18810. |
What is modal frequency |
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Answer» Mariya you know me Highest frequency |
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| 18811. |
If AD and PM are medians of ∆ABC and ∆PQR, respectively where ∆ABC~∆PQR, prove that AB/PQ=AD/PM. |
| Answer» See NCERT book chapter 06 | |
| 18812. |
Solve for x and ybx + ay + a + b = 0,bx -- ay + 2ab = 0 |
| Answer» So easy use elimination method | |
| 18813. |
(x+2),(X+3),(X+9) ar in ap solve for x |
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| 18814. |
What is speciation |
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Answer» Development of one more species from existing Origin of new species from pre existing species is called speciation |
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| 18815. |
(1+sin theta +cos theta)^2=2(1+cos theta)(1-sin theta) |
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| 18816. |
What is total surface area |
| Answer» All surface area including lateral and both sided up amd down areas. | |
| 18817. |
Give me some tips to score good marks in maths ?????Plzz guys |
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Answer» Thanks for ur all suggestions 2 everyone It may help me ??? Entry late kro magar....great kro.... Study it without taking any tension and don\'t think that u are weak in this sub Just finish your whole Ncert and do atleast 8 to 9 sample papers |
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| 18818. |
a (5,1)b( x, 7) c( 8,2) are three points such that ab=2ac find x please tell |
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| 18819. |
What is 1 plus 1 |
| Answer» 2 | |
| 18820. |
If the adjoining figure is a sector of a circle and radius10.5 cm.Find the perimeter of the sector. |
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Answer» First draw the diagonal if triangle find its length through which we can find the angle by putting sin then put the formula of perimeter sum of two side + pir Angle is not given on the question |
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| 18821. |
If tan theta +sin theta=m and tan theta-sin theta = n. ,show that m square - n square = 4 root mn |
| Answer» Given, {tex}\\tan \\theta + \\sin \\theta = m{/tex} and {tex}\\tan \\theta - \\sin \\theta = n{/tex}L.H.S =\xa0{tex}m^{2}-n^{2}{/tex}{tex}=(tan\\theta+sin\\theta)^{2}-(tan\\theta-sin\\theta)^{2}{/tex}{tex}=tan^{2}\\theta+sin^{2}\\theta+2tan\\theta sin\\theta-[tan^{2}\\theta+sin^{2}\\theta-2tan\\theta sin\\theta]{/tex}{tex}=tan^{2}\\theta+sin^{2}\\theta+2tan\\theta sin\\theta-tan^{2}\\theta-sin^{2}\\theta+2tan\\theta sin\\theta{/tex}{tex}=4tan\\theta sin\\theta{/tex}R.H.S = 4{tex}\\sqrt{mn}{/tex}{tex}=4\\sqrt{(tan\\theta+sin\\theta)(tan\\theta-sin\\theta)}{/tex}{tex}=4\\sqrt{tan^{2}\\theta-sin^{2}\\theta}{/tex}{tex}=4\\sqrt{\\frac{sin^{2}\\theta}{cos^{2}\\theta}-sin^{2}\\theta}{/tex}{tex}=4\\sqrt{\\frac{sin^{2}\\theta-sin^{2}\\theta cos^{2}\\theta}{cos^{2}\\theta}}{/tex}{tex}=\\frac{4}{cos\\theta}\\sqrt{sin^{2}\\theta-sin^{2}\\theta cos^{2}\\theta}{/tex}{tex}=\\frac{4}{cos\\theta}\\sqrt{sin^{2}\\theta (1-cos^{2}\\theta)}{/tex}{tex}=\\frac{4}{cos\\theta} \\times sin\\theta \\times \\sqrt{sin^{2}\\theta}{/tex}{tex}=4tan\\theta sin\\theta{/tex}Hence, L.H.S = R.H.S | |
| 18822. |
Proof Pythagoras Theron in brefly |
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Answer» What an English, Shakespeare would be so proud of you ???? You can broke my heart to give your name of bf who cheated you no me why you do wrong I do true love to you School gana ka leya ready hona ka rhi hu Byyy Ha Rihu |
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| 18823. |
What are zero |
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Answer» Ruhi in next chat read reasons ? 0 ? |
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| 18824. |
Show that the sequence log (a) ,log(ab) ,log(ab2) ,log(ab3).......is an AP..Find its nth term.. |
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Answer» Correct A2 -A1=A3-A2= b... |
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| 18825. |
In tringlePAB,PA=PB,and area of coordinate of A and B are (1,2) and (3,8) respectively. |
| Answer» PA =\xa0{tex}\\sqrt { ( 1 - x ) ^ { 2 } + ( 2 - y ) ^ { 2 } }{/tex}PB =\xa0{tex}\\sqrt { ( 3 - x ) ^ { 2 } + ( 8 - y ) ^ { 2 } }{/tex}{tex}\\therefore{/tex}\xa0PA = PBLet coordinates of P are (x, y){tex}\\Rightarrow{/tex}\xa0{tex} \\sqrt { ( 1 - x ) ^ { 2 } + ( 2 - y ) ^ { 2 } }{/tex}{tex}= \\sqrt { ( 3 - x ) ^ { 2 } + ( 8 - y ) ^ { 2 } }{/tex}Squaring on both sides,\xa0{tex}\\Rightarrow{/tex}\xa0{tex}(1 - x)^2 + (2 - y)^2 = (3 - x)^2 + (8 - y)^2{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}(1 - x)^2 - (3 - x)^2 = (8 - y)^2 - (2 - y)^2{/tex}{tex}\\Rightarrow{/tex}\xa0(1 - x - 3 + x) (1 - x + 3 - x) = (8 - y - 2 + y) (8 - y + 2 - y){tex}\\Rightarrow{/tex}- 2(4 - 2x) = 6(10 - 2y){tex}\\Rightarrow{/tex}\xa0{tex}- 2 \\times 2 ( 2 - x ) = 6 \\times 2 ( 5 - y ){/tex}- 2 + x = 15 - 3yx = 17 - 3y ...(i)Area of\xa0{tex}\\triangle{/tex}PAB = 10 sq units{tex}\\Rightarrow{/tex}\xa0{tex} \\frac { 1 } { 2 } | x ( 2 - 8 ) + 1 ( 8 - y ) + 3 ( y - 2 ) |{/tex}\xa0= 10{tex}\\Rightarrow{/tex}\xa0{tex}| - 6 x + 8 - y + 3 y - 6 |{/tex}\xa0= 20{tex}\\Rightarrow{/tex}\xa0{tex}| - 6 x + 2 y + 2 |{/tex}\xa0= 20{tex}\\Rightarrow{/tex}\xa0{tex}\xa0- 6x + 2y + 2 = 20 {/tex}or\xa0{tex}- 6x + 2y + 2 = -20{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}- 6(17 - 3y) + 2y + 2 = 20{/tex} or {tex}- 6(17 - 3y) + 2y + 2 = - 20 {/tex}...(ii){tex}\\Rightarrow{/tex}\xa0{tex}- 102 + 18y + 2y + 2 = 20{/tex} or\xa0{tex}- 102 + 18y + 2y + 2 = - 20{/tex}{tex}\\Rightarrow{/tex}\xa020y = 120 or 20y = 80y = 6 or y = 4When y = 6, equation (i) becomes x = 17 - 18 = - 1{tex}\\therefore{/tex}\xa0Point is (- 1, 6).When y = 4, equation (i) becomes x = 17 - 12 = 5{tex}\\therefore{/tex}\xa0Point is (5, 4). | |
| 18826. |
root 6 plus root 6 till infinity is equal to |
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Answer» Ans.......x=n root 6 ∞√6 So easy Ya answer is 3 Ohhh srry yrrr darshana 2 and 3 # 2 and 3 higa First of all I\'m not Bro. I am sis Bro 3 shyd I am testing you I know this answer. Ley √6 be x .And ut will form quadratic equation ...try it |
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| 18827. |
Sin73 |
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| 18828. |
म |
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Answer» म kya Complete it bhai Ye kya hai Hey What\'s this???? ?? |
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| 18829. |
Guys,kya late night study important hai ek 10 class student ke liye? And justify ur answer |
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Answer» Par mujhe neend hi nahi aati. Soti hoo to teachers sapne mein aate Hain. Kabhi padhate Hain to scold kartein Hain. But mai to 2 baje tak padhti hu raat mein I agree with statement given by the guys My parents are also arguing with me to not study but l don\'t get a proper sleep 10:30 tak bus raat me agar din me padhte ho to nhi Nopes but getting up early is more beneficial Not soo |
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| 18830. |
3+3/3 |
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Answer» Two have them has the answer 2 I don\'t know how they get they are studying quiet different from us isn\'t it 4 answer because first devide 3/3 than add3+1=4 It\'s 4 4 4 Its 4answer 4is the answer No 4 2 2 I think 2 4 bhai 4 |
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| 18831. |
area ratio theroem |
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| 18832. |
How can i score good marks in maths |
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Answer» By doing saadhna in mathematics instead of practicing Learn some tricks to do questions Even me Yes i also want to know |
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| 18833. |
Date Sheet for Class 10 cbse 2018 |
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Answer» 5th march ko ITk ha Fifth exam on 28 March 2018 and maths exam Fourth exam on 22 March 2018 and Sst exam Third exam on 16 March 2018 and science exam 6 march to 28 march Second exam on 12 March 2018 and English exam Exam starts on 6 March 2018 and first exam is hindi 6th march to 2nd April Check on google |
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| 18834. |
Which govt. Is best.. Congress, Bjp? |
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Answer» Bjp For country development in defence while Congress is for development of corruption & decreasing the value of Indian currency in foreign countries Me from Udaipur Bjp Fdk?? Kon a fdk to Abohar se Ya uske aas pass Faridkot ke andar h na Mein पंजाब और राजस्थान के बार्डर se hu Kihne dubhna? Namita dub ke mar ja Nearly city Congress Moga is in punjab MOGa konsi city के पास h According to me Congress BJP Bjp |
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| 18835. |
Which govt. Is in ur state? |
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Answer» Aap Jo app ke hae Bjp (raj.) I am living in national territory Ur Kaunsi state |
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| 18836. |
State and prove Basic proportionality theorem. |
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Answer» Hello everyone Aap kaha se ho |
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| 18837. |
Write the polynomial whose zeroes are 2+ root3 and 2-root 3 |
| Answer» Xsquare-4x+1 | |
| 18838. |
Is ncert is suffecient for class10 board new pattern ? |
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Answer» Yes Awecose yes No |
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| 18839. |
What are you doing guys |
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Answer» Nikunj kumar see I just love my god and not anyone else aere gaire nathugaere ????????????? Tripiti sharma What Loving very well You Loving whom Padhai kro kal exam h Suno yashika it might sound funny but ek baat puchni thi Loving you nothing Nothing just talking to anyone |
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| 18840. |
In equilateral triangle ABC, D is a point on BC such that 3BD=BC. Prove that 9AD^2=7AB^2 |
| Answer» Given, {tex}\\triangle ABC{/tex}\xa0in which\xa0{tex}AB = BC = CA{/tex} and D is a point on BC such that BD ={tex}\\frac { 1 } { 3 }{/tex}BC.Prove: 9AD2 = 7AB2.Construction :Draw\xa0{tex}A L \\perp B C{/tex}\xa0Proof: In right triangles ALB and ALC, we have{tex}AB = AC {/tex}(given){tex}AL = AL {/tex}(common){tex}\\therefore \\triangle A L B \\cong \\triangle A L C{/tex}\xa0[by RHS axiom]So,\xa0{tex}BL = CL.{/tex}Thus, BD ={tex}\\frac { 1 } { 3 }{/tex}BC and BL ={tex}\\frac { 1 } { 2 }{/tex}BC.In\xa0{tex}\\triangle ALB{/tex},\xa0{tex}\\angle A L B = 90 ^ { \\circ }{/tex}By using pythagoras theorem, we get\xa0{tex}\\therefore{/tex}\xa0AB2 = AL2 + BL2 ...(i)In\xa0{tex}\\triangle ALD{/tex},\xa0{tex}\\angle A L D = 90 ^ { \\circ }{/tex}By using pythagoras theorem, we get\xa0{tex}\\therefore{/tex}\xa0AD2 = AL2 + DL2\xa0= AL2 + (BL - BD)2= AL2 + BL2 + BD2 -\xa0{tex}2 B L \\cdot B D{/tex}= (AL2 + BL2) + BD2 -\xa0{tex}2 B L \\cdot B D{/tex}= AB2 + BD2 -\xa0{tex}2 B L \\cdot B D{/tex}\xa0[using (i)]{tex}= B C ^ { 2 } + \\left( \\frac { 1 } { 3 } B C \\right) ^ { 2 } - 2 \\left( \\frac { 1 } { 2 } B C \\right) \\cdot \\frac { 1 } { 3 } B C{/tex}{tex}= B C ^ { 2 } + \\frac { 1 } { 9 } B C ^ { 2 } - \\frac { 1 } { 3 } B C ^ { 2 }{/tex}{tex}= \\frac { 7 } { 9 } B C ^ { 2 } = \\frac { 7 } { 9 } A B ^ { 2 }{/tex}\xa0[{tex}\\because{/tex}\xa0BC = AB]Therefore, 9AD2 = 7AB2. | |
| 18841. |
I have only 1 query |
| Answer» | |
| 18842. |
The surface area of a cube is equal to surface area of sphere, then find the ratio of their volumes. |
| Answer» 4/3 | |
| 18843. |
Tan teta minus cot teta divided by sin teta. Cos teta =tan square teta minus cot square teta |
| Answer» | |
| 18844. |
ABC is an isosceles triangle right angled at C.prove that AB |
| Answer» Complete ur question | |
| 18845. |
Sin6+cos6=4-3 (x2-1)2/4 |
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| 18846. |
What should I have to do for good marks |
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Answer» you should have just study for good marks For good mark you study deeply How? Who Nothing just focus on main marks gaining points or questions Concentrate in studies |
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| 18847. |
What is the sum of first n natural numbers |
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Answer» Brahman boy is correct Sorry N(n+1)/2 n/2 (n-1) |
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| 18848. |
Good news frnds! India has won the12th edition of ICC Under-19 cricket world cup2018. |
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Answer» Mujhe Sachin ki yaad aayi hai. Kya sixes,fours .yaad aate hai Doston, cricket mein kis cheez ki kami tum feel karte ho ?? Wah |
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| 18849. |
Itna easy kyo hai maths |
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Answer» Sweet toh me Kisi ke saath nhi hu.. but truth matters Yha to bhut sweet ban rhe ho ruthless....mujhe kya dushmani h Really??? Bocz tum accha pdti ho isliye Wah....??? |
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| 18850. |
Doston,cce pattern vs board pattern dono me se tum sabki kya raay hai |
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