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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 19201. |
A vertical tower stands on a horizontal plane and is surmounted by |
| Answer» Half question | |
| 19202. |
Prove phythagores theorem |
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Answer» See in ncert (H) ²=(p)²+(B)² |
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| 19203. |
Whole square root 1 minus sin A /1 +sin A equal to sec A-tanA |
| Answer» Sahi se likh | |
| 19204. |
Find the(hcf×lcm)for the numbers 100 and 190 |
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Answer» 19000 because lcm×hcf=product of numbers # hcf Haf - 10Lcm - 900 |
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| 19205. |
sec45= |
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Answer» =1÷cos45 =1÷1÷root2 =root2 Are 1 likhe to sb 1 likhe or Root 2 likhe to sb Root 2 ye kya bt hua Ya..root2 is right..sorry I think root2 One is wrong... root 2 Root2 Root 2 1 1 1 |
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| 19206. |
sample paper by cbse |
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Answer» Yess U can got it here .... |
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| 19207. |
Cos^2x-sin^2x=cos^2x-sin^2x(1-sin^2xcos^2x) |
| Answer» | |
| 19208. |
Sin A/ sin 2 A + cos A/ 1+ cos 2A =secA |
| Answer» Jante h but bhej nhi skte | |
| 19209. |
Prove that Cos A - sin A + 1 whole up on cos A + sin A - 1 = tan A + sin A |
| Answer» | |
| 19210. |
express the simplest form of 1.8 |
| Answer» 9\\5 | |
| 19211. |
Show that one and only one of the number n,n+2or n+4 is divisible by 3 |
| Answer» U can put the value of n as 1,2 ,3 and then ineach case it leave a remainder only in one case it will fully divisible by 3 | |
| 19212. |
Where should I get chapterwise last 10 years solved question paper? |
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Answer» Vendantu.com Visit my cbse guide Gogle |
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| 19213. |
Solve for x:1/a+1/b+1/x =1/a+b+x |
| Answer» Given,{tex}\\frac { 1 } { ( a + b + x ) } = \\frac { 1 } { a } + \\frac { 1 } { b } + \\frac { 1 } { x }{/tex}{tex}\\Rightarrow \\quad \\frac { 1 } { ( a + b + x ) } - \\frac { 1 } { x } = \\frac { 1 } { a } + \\frac { 1 } { b } \\Rightarrow \\frac { x - ( a + b + x ) } { x ( a + b + x ) } = \\frac { b + a } { a b }{/tex}{tex}\\Rightarrow \\quad \\frac { - ( a + b ) } { x ( a + b + x ) } = \\frac { ( a + b ) } { a b }{/tex}On dividing both sides by (a+b){tex}\\Rightarrow \\quad \\frac { - 1 } { x ( a + b + x ) } = \\frac { 1 } { a b }{/tex}Now cross multiply{tex}\\Rightarrow{/tex}\xa0x(a + b + x) = -ab\xa0{tex}\\Rightarrow{/tex}\xa0x2 + ax + bx + ab = 0{tex}\\Rightarrow{/tex}\xa0x(x +a) + b(x +a) = 0{tex}\\Rightarrow{/tex}\xa0(x\xa0+ a) (x + b) = 0{tex}\\Rightarrow{/tex}\xa0x + a = 0 or x + b = 0{tex}\\Rightarrow{/tex}\xa0x = -a or x = -b.Therefore, -a and -b\xa0are the roots of the equation. | |
| 19214. |
Are Angles in alternate segments are equal ??Plzzz explain! |
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Answer» But how segments can be parallel in a circle Yes but both segments should be parallel to each other Alternate interior angles are equal |
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| 19215. |
If Tan A + Sin A = m and Tan A - Sin A = n, then show that - m^2 - n^2 = under root mn x 4 |
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Answer» ?????? Put the values and solve urself |
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| 19216. |
Two tangents PA and PB are drawn to a circle with centre o from an external point p ..prove that |
| Answer» Suppose OP intersects AB at C.In triangles PAC and PBC, we havePA = PB\xa0[{tex} \\because{/tex}\xa0Tangents from an external point are equal]{tex}\\angle A P C = \\angle B P C{/tex}\xa0[{tex}\\because{/tex}\xa0PA and PB\xa0are equally inclined to\xa0O P]and, PC = PC [Common]So, by SAS-criterion of similarity, we obtain{tex}\\Delta P A C \\cong \\Delta P B C{/tex}{tex}\\Rightarrow{/tex}\xa0AC = BC and\xa0{tex}\\angle A C P = \\angle B C P{/tex}But, {tex}\\angle A C P + \\angle B C P{/tex}= 180°{tex}\\therefore \\quad \\angle A C P = \\angle B C P{/tex}= 90°Hence,\xa0{tex} O P \\perp A B{/tex} | |
| 19217. |
Find the number of natural numbers between 101 and 999 which are divisible by both 2 and 5 |
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Answer» 89 natural numberexplanation:- no. divisible by 2&5 must be divisible by 10 Form an AP of natural number present between 101 & 999AP = 110, 120, 130,............, 990from the AP we concluded a = 110d= 10nth term of the AP = 990a+(n-1)d=990110+(n-1)10=990(n-1)10=990-110(n-1)= 880/10n-1=88n=88+1n=89natural number present between 101 & 109 = 89 99 |
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| 19218. |
3x*3x+(k-1)x+9=0,then k=? |
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| 19219. |
What is theodolite???? Don\'t use Google please ?????? |
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Answer» Azeeb hai yaar mere phone me google hai hi naa unistall mar diya. Utsav phir Google kr diya Yarr????? Used in rocket launching and meteorology Ut is an instrument used to measure angles of planes.such as in meteorology and rocket launch. Instrument A instrument used for measuring angles |
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| 19220. |
How to study before the day of board exams |
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Answer» Puti jese Boy Girl ho ya boy. Ha ab to krta hi aaya hu ab bhi krunga hi Acchi baat hai aise he kero. Top keroge M krta hu ji Exam se phale kon study kerta hai Vo toh sirf revision time hota Khu khu khi. Khi.. Eyes se |
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| 19221. |
What is composite no. |
| Answer» No which have more than two factors. | |
| 19222. |
73839 |
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Answer» Mtlb kya hai iska 88228 ? |
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| 19223. |
Prove that root is irrational |
| Answer» Give me your root no... | |
| 19224. |
Find the value of m so that the quadratic equatiom mx(x-7)+49=0 has two roots. |
| Answer» {tex}mx(x - 7) +49 = 0{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}mx^2 - 7mx + 49 = 0{/tex}Here a = m, b = -7m, c = 49{tex}\\Rightarrow{/tex}\xa0{tex}D = b^2 - 4ac{/tex}For equal roots, D = 0{tex}\\Rightarrow{/tex}\xa00 = (-7m)2 - 4 {tex}\\times{/tex}\xa0m {tex}\\times{/tex}\xa049{tex}\\Rightarrow{/tex}\xa0{tex}0 = 49m^2 - 196m{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}49m^2 - 196m = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}7m(7m - 28) = 0{/tex}{tex}\\Rightarrow{/tex}\xa07m = 0 or 7m - 28 = 0{tex}\\Rightarrow{/tex}\xa0m = 0 or m =\xa0{tex}\\frac{28}{7}{/tex}\xa0= 4but m\xa0{tex}\\ne{/tex}\xa00 [{tex}\\because{/tex}In quadratic a\xa0{tex}\\ne{/tex}\xa00]{tex}\\therefore{/tex}\xa0m = 4 | |
| 19225. |
User submission question answer sheet |
| Answer» | |
| 19226. |
Square root finding |
| Answer» | |
| 19227. |
find a point on x axis which is equidistant from (6,3) and (3,0) |
| Answer» If point is on x axis that\'s mean y=0 and now it is given that point is equidistant from both these point there fore by mid point formula 6+3/2=9/2 hence x is 9/2 and y is 0 | |
| 19228. |
Anyone having hots qiestions of Arithmetic Progression... ??? |
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Answer» Yaa.. Questions chahiye ? ?? *questions |
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| 19229. |
all formula related to maths of 10th class |
| Answer» Check revision notes for formulae :\xa0https://mycbseguide.com/cbse-revision-notes.html | |
| 19230. |
What is photochemical reaction? |
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Answer» Reactions that are done in the presence of sunlight. That r done by reaction in light |
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| 19231. |
Phir exams ka formulaAnyone can answer r |
| Answer» | |
| 19232. |
1/sec a-1/coseca=1/cosec a-1/sea |
| Answer» | |
| 19233. |
Sin2A=2sinA is true when A=? |
| Answer» {tex}0^\\circ {/tex} | |
| 19234. |
How to calculate cube root by estimation method ? |
| Answer» U will opt maths or bio in 11th | |
| 19235. |
Is digital watch allowed in cbse boards |
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Answer» Never Nope I don\'t think so |
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| 19236. |
What is neuron |
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Answer» Neuron Largest cell |
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| 19237. |
A car has two wipers which do not overlap ea |
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Answer» Write full Que. ???? Half question |
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| 19238. |
What is weight of universe? |
| Answer» End of thinking capacity ?????? | |
| 19239. |
Probability of a spade or an ace |
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Answer» P (E)=no. of favourable outcomes /total no. of outcomes=13/52=1/4 16/52 |
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| 19240. |
In trigonometry is we can strat proveing eqation from R.H.S. |
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Answer» As u like Both are OK its ur choice which side is easy to modify You can...... As ur wish Your choice |
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| 19241. |
Tfd |
| Answer» | |
| 19242. |
A+B=90°, secA=5/3 then cosecA=? |
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Answer» No.,5/3 4/3 |
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| 19243. |
2x+5=0 x=? |
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Answer» -2.5 -5/2=x |
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| 19244. |
Find the value of k it the points A (2,3) B(4,k) and C (6,-3)are collinear. |
| Answer» Let the points A (2, 3), B{tex}\\left( {4,k} \\right){/tex} and C{tex}\\left( {6, - 3} \\right){/tex} be collinear.If the points are collinear then area of triangle ABC formed by these three points is 0.{tex}\\therefore {/tex}{tex}{\\text{ar}}\\left( {\\Delta {\\text{ABC}}} \\right) = \\frac{1}{2}\\left[ {{x_1}\\left( {{y_2} - {y_3}} \\right) + {x_2}\\left( {{y_3} - {y_1}} \\right) + {x_3}\\left( {{y_1} - {y_2}} \\right)} \\right]{/tex}= 0{tex} \\Rightarrow {/tex}{tex}\\frac{1}{2}\\left[ {2\\left( {k + 3} \\right) + 4\\left( { - 3 - 3} \\right) + 6\\left( {3 - k} \\right)} \\right] = 0{/tex}{tex} \\Rightarrow {/tex}{tex}\\left[ {2k + 6 - 24 + 18 - 6k} \\right] = 0{/tex}{tex} \\Rightarrow {/tex}{tex}\\left[ { - 4k} \\right] = 0{/tex}{tex} \\Rightarrow {/tex}{tex}k = 0{/tex} | |
| 19245. |
root questions |
| Answer» | |
| 19246. |
Yash scored 40 marks in a test getting 3 marks for each right answer and loosing 1 marks for |
| Answer» Let the number of right answers and wrong answers be x and y respectively.According to the question,{tex}3x - y = 40{/tex} ...(i){tex}4x - 2y = 50\u200b\u200b\u200b\u200b\u200b\u200b\u200b{/tex}{tex}\\Rightarrow{/tex}{tex}2x - y = 25{/tex} ...(ii)Subtracting equation (ii) from equation (i), we obtain:{tex}x = 15{/tex}Substituting the value of x in equation (ii), we obtain:{tex}30 - y = 25{/tex}{tex}y = 5{/tex}Thus, the number of right answers and the number of wrong answers is 15 and 5 respectively. Therefore the total number of questions is 20. | |
| 19247. |
sin^8x-cos^8x=(sin^2x-cos^2x)(1-2sin^2xcos^2x |
| Answer» hii beauty | |
| 19248. |
Find a relation between a and b sach that point (a, b) is equidistant from the points (8,3),2,7 |
| Answer» 12a - 8b + 20 = 0 | |
| 19249. |
In mathematics which sample paper is best |
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Answer» Arihant Upadhyaye and upadhyaye ya fir R.D.sharma is the best No yrr.... Oswaal is best U like ya fir exam idea |
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| 19250. |
Find the root of the quadratic equation √3Sq-2x-√3 |
| Answer» If u sure your question is currect | |