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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 19351. |
Sample paper 1 ques 0 |
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| 19352. |
Kya kisi ke pass maths ki 2019 ke sple papers hein ?? |
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Answer» Thamks friends.. You can see in the cbse.nic .in . Ki site pr maths ka marking scheme ok Ansh Aap mycbsegide aap par dekh sakte hai Check out this app for sample paper woth solution in mathematics section. Kya tum uske sample paper 1 ke question 6 section A ka solution bata sakte ho plz. Yes |
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| 19353. |
Find the least number which when divided by 15,20 and 25 leaves remainder 2, 7 and 12 respectively. |
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Answer» 13 Its answer is 287 plzz tell me that it is 100%true So sorry nice trial but it os wrong 1 |
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| 19354. |
Chapter wise waitag |
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| 19355. |
Find HCF of 65 and 117 and express it in the form 65m + 117n |
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Answer» HCF = 1313 = 65m + 117nFrom [ 1] ,13 = 65 - 52 x 1From [2] ,52 = 117 - 65 x 1 ----> [3]Hence ,13 = 65 - [ 117 - 65 x 1 ] ------> from [3]= 65 x 2 - 117= 65 x 2 + 117 x [-1 ]m = 2n = -1 HCF = 1313 = 65m + 117nFrom [ 1] ,13 = 65 - 52 x 1From [2] ,52 = 117 - 65 x 1 ----> [3]Hence ,13 = 65 - [ 117 - 65 x 1 ] ------> from [3]= 65 x 2 - 117= 65 x 2 + 117 x [-1 ]m = 2n = -1Read more on Brainly.in - https://brainly.in/question/1192640#readmore |
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| 19356. |
Formula a2 b2 |
| Answer» Plz explain ur question a bit more ...... | |
| 19357. |
The 17th term of an AP exceeds its 10th term by 7. Find the common difference. |
| Answer» a17th = a10th +7a+(17-1)d=a+(10-1)d+7a+16d=a+9d+7a+16d-a-9d=77d=7d=7/7d=1 | |
| 19358. |
How many polynomial |
| Answer» 3 | |
| 19359. |
1/a^-bc + 1/b^-ca + 1/c^-ab |
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| 19360. |
Formula of (a+b) whole square |
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Answer» a2 + b2 + 2ab a2+b2+2ab (a + b)2 = a2 + 2ab + b2 |
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| 19361. |
On Monday, we r going to face the king of Subjects THE MATHS |
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Answer» Which school Oh nice I m from New Delhi Neha Beti frm where r u? I am from kerala , TrisshurWhere r u guys from? Matlab Our post mid term exam starts on 12-12-2018 |
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| 19362. |
" Sweet thooth may leads tooth decay "explain why?????? |
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Answer» Tnku Sweet tooth may cause tooth decay because when we eat something sweet it lowers the pH of our mouth it turns it acidic due to the formation of acid it corrodes our teeth which causes the tooth decay. For prevention you may use a base like toothpaste. |
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| 19363. |
Prime fractorization of 7429 |
| Answer» 17×19×23 | |
| 19364. |
Find the value of 2 Tangent 30 degree / 1 + tangent square 30 degree |
| Answer» 2√3/3 | |
| 19365. |
Find the value of 2tan 30/1+tan² 30 |
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Answer» Sorry root 3 by2 Sorry 2root3 divided by 9 Bro correct answer is 1 2 x 1/√3/1+(1/3)sqare= 2√3/3 |
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| 19366. |
Formula of Sn find |
| Answer» Sn=n÷2 (2a+(n-1)d | |
| 19367. |
D is a point on the side BC of a ∆ABC such that angle ADC= angle BAC. Show that CA square= CB.CD . |
| Answer» Please tell the answer? | |
| 19368. |
Kya maths me do paper h means standard level or higher level plz reply. |
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Answer» No, it is from next year Shayad ab cancel ho gaye |
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| 19369. |
Which of these is the odd one out.2012,2010,2008,2004 |
| Answer» 2010.....bcz its not a leap year. | |
| 19370. |
Sin60+cos60+tan45=cot30 It is true or not |
| Answer» True | |
| 19371. |
Write the trigonometric ratio of sin A in terms of cot A |
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Answer» Sin²A + Cos²A =1 .. so Sin²A =1-Cos²A SinA=√1-Cos²A.. Cot A = Cos A/ SinACotA= CosA/ √1-Cos²A. Bhai mai bhi Bansal hu Matlab |
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| 19372. |
Yrr plzz if someone is online plzz help me in my question |
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Answer» But how i give this answer ayushi Yes I know that But I want its answer This question is not in ncert My question is that Solve the following quadratic equation for X X ki power 2 -2aX -(4b ki power 2 -ki power 2 )=0 Yes what is ur question Bolo What |
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| 19373. |
hiiiii mehak kha ho |
| Answer» nhi ho kya mehak | |
| 19374. |
Explain theorem 10. 1And 10.2 |
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| 19375. |
sinA-cosA+1÷sinA+cosA-1=cos÷1-sinA |
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| 19376. |
Two stations due south of a leaning tower |
| Answer» Let AB be the leaning tower and let C and D be two given stations at distances a and b respectively from the foot A of the tower.Let AE = x and BE = hIn\xa0{tex} \\triangle A E B,{/tex}\xa0we have{tex} \\tan \\theta = \\frac { B E } { A E }{/tex}{tex} \\Rightarrow \\quad \\tan \\theta = \\frac { h } { x }{/tex}{tex} \\Rightarrow \\quad x = h \\cot \\theta{/tex}\xa0.......(i)In {tex} \\Delta C E B,{/tex}\xa0we have{tex} \\tan \\alpha = \\frac { B E } { C E }{/tex}{tex} \\Rightarrow \\quad \\tan \\alpha = \\frac { h } { a + x }{/tex}{tex} \\Rightarrow \\quad a + x = h \\cot \\alpha{/tex}{tex} \\Rightarrow \\quad x = h \\cot \\alpha - a{/tex}.........(ii)In\xa0{tex} \\Delta D E B,{/tex}\xa0we have{tex} \\tan \\beta = \\frac { B E } { D E }{/tex}{tex} \\Rightarrow \\quad \\tan \\beta = \\frac { h } { b + x }{/tex}{tex} \\Rightarrow \\quad b + x = h \\cot \\beta{/tex}{tex} \\Rightarrow \\quad x = h \\cot \\beta - b{/tex}\xa0...........(iii)On equating the values of x obtained from equations (i) and (ii), we have{tex} h \\cot \\theta = h \\cot \\alpha - a{/tex}{tex} \\Rightarrow \\quad h ( \\cot \\alpha - \\cot \\theta ) = a{/tex}{tex} \\Rightarrow \\quad h = \\frac { a } { \\cot \\alpha - \\cot \\theta }{/tex} .........(iv)On equating the values of x obtained from equations (i) and (iii), we get{tex} h \\cot \\theta = h \\cot \\beta - b{/tex}{tex} \\Rightarrow \\quad h ( \\cot \\beta - \\cot \\theta ) = b{/tex}{tex} \\Rightarrow \\quad h = \\frac { b } { \\cot \\beta - \\cot \\theta }{/tex} .........(v)Equating the values of h from equations (iv) and (v), we get{tex} \\frac { a } { \\cot \\alpha - \\cot \\theta } = \\frac { b } { \\cot \\beta - \\cot \\theta }{/tex}{tex} \\Rightarrow \\quad a ( \\cot \\beta - a \\cot \\theta ) = b ( \\cot \\alpha - \\cot \\theta ){/tex}{tex} \\Rightarrow \\quad ( b - a ) \\cot \\theta = b \\cot \\alpha - a \\cot \\beta{/tex}{tex} \\Rightarrow \\quad \\cot \\theta = \\frac { b \\cot \\alpha - a \\cot \\beta } { b - a }{/tex} | |
| 19377. |
a+b =c |
| Answer» prove karna h kya | |
| 19378. |
(k-1)x2+kx+1 is-3,the value of k is plese give me only answer |
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Answer» -2/3 -1 hami bata data h -2/3 hoga answer yar kisi ko pata v h ya nahi nahi h pata answer to bolo please fastely give me answer only answer not a full solution |
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| 19379. |
Write the nature of the product of rational and irational number. |
| Answer» Its irrational | |
| 19380. |
Prove that SinA/cotA+cosecA=2+sinA/cotA-cosecA |
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| 19381. |
I am founding difficulty to doing trignometry ex - 8.4 Question |
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Answer» 8.4 all questions Please write the question. Then ,i can do something for u |
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| 19382. |
What are sides proportinal |
| Answer» Corrosponding sides of two triangle are in the same ratio to other corrosponding sides .eg. ABC and PQR . sides are proportional . Then, AB/PQ=BC/QR=AC/ PR | |
| 19383. |
An AP consist of 50terms of which 3rd term is 12 and the last term is 106 . Find the 29th term |
| Answer» Let the first term be a and common difference be dTn=a+(n-1)dA/qa+2d=12---------1a+49d=106-------2With equation 1&2 we have; By changing signa+2d=12-a-49d=-106-47d=-94d=2Putting d value in eq 1a+2(2)=12a=12-4a=8Now; 28th term=a+27d =8+27(2) =8+54=62Hence; 28th term is 62 ansHope this will right . | |
| 19384. |
I am unable to solve graph from linear equations in two varibles give me some tips to solve it |
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Answer» Practice makes a man perfect..... Remember it Keeps practice and practice. Nothing else .......... |
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| 19385. |
What is arithmetic mean? |
| Answer» Arithmetic mean is\xa0the average of a set of numerical values, as calculated by adding them together and dividing by the number of terms in the set. | |
| 19386. |
Thels thorum |
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Answer» See in ncert textbook. Pata ni |
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| 19387. |
the radii of circular ends of a bucket of hight 24cm are15cm and 5cm find the area of curved surface |
| Answer» Curved surface area of frustum = πl(r1 +r2) 22/7*24(15+5)= 1496cm 2 | |
| 19388. |
If cot o =root 7 then evaluate cosec2o-sec2o/cosec2o+sec2o |
| Answer» Please answer it | |
| 19389. |
CBSE k 5 sampe paper किसने slove कर लिए hअगर किए है, तो mathematics k answers बताना |
| Answer» oyuuìoo | |
| 19390. |
In what ratio does the point (-4,6) divide the line segment joining the point A(-6,10)and B(3,-8) |
| Answer» Let (-4, 6) divide AB internally in the ratio k:1. Using the section formula, we get{tex}( - 4,6 ) = \\left( \\frac { 3 k - 6 } { k + 1 } , \\frac { - 8 k + 10 } { k + 1 } \\right){/tex}So,\xa0{tex}- 4 = \\frac { 3 k - 6 } { k + 1 }{/tex}i.e., -4k - 4 = 3k - 6i.e., 7k = 2i.e., k:1 = 2:7\xa0 | |
| 19391. |
If 1-tan2 θ= 30° then write the value of sin θ+ cos2 θ. |
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| 19392. |
Finde value sin90apon cos45+1upon cosec 30 |
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| 19393. |
Hi Bhawna Arya! |
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| 19394. |
Hi Bhawna Arya |
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| 19395. |
Solve for x: 1plus 4plus 7plus10 .......plus x is equal to287 |
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| 19396. |
Batao yar kaise karta ha pic upload |
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Answer» Ha Isase accha to fb aur istagram bolo n koi plzz... Fckmcbcdc....... |
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| 19397. |
Hiiii guys...aap logo ki hindi ki preparation ho gayi kya....☺☺☺☺☺☺☺☺☺☺☺ |
| Answer» nhi | |
| 19398. |
Ok bye guys.. |
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| 19399. |
Hi guys . |
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Answer» Ur nd my title...same All good M fine nd u?? Sonam what is same title How are you all Hlo Same title Hlo..varun Hiii |
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| 19400. |
Speak in English I don\'t know Hindi |
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Answer» My language is English and Malayalam not Hindi that\'s why Kal hindi me exam hai Fateh singh tusi punjabi oo..? Are you getting crazy? Kyo |
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