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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 20351. |
Hello guy\'s..... ???? |
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Answer» Ue report kya likha aa rha h hrr msge me Hii. ? |
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| 20352. |
Is their is re-test in 10 class 2017-18? |
| Answer» No i think so | |
| 20353. |
Oswal ke papers kha pr available h..net pr to iske solutiona h questions to h hi ni |
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Answer» Ghjjnbbn Oo gud than extra krna h to rohit bhi best h sculs m bhi kraii h Ni fr b...thoda sa extra ho jaega to tensn free.....or the thing is that i have complted my ncert Ncert prr focus kroo bss aram se markss aege? |
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| 20354. |
Formele of 12 chaptet |
| Answer» Book m h | |
| 20355. |
SA identities |
| Answer» | |
| 20356. |
For what value of K for which points (1,2) ,(k,-2) and (-5,6) are collinear. |
| Answer» 1÷k=2÷-22=-2kK=-1 k÷-5=-2÷62k=-30K=-15 | |
| 20357. |
Ncrt exampler is Good |
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Answer» Ya I was right Yes 80 percent are Q coming from ncert I m just new in 10th or example r important of all chaptr Sorry but I don\'t know. I can\'t understand which. Questions is important from ncrt exampler Yes |
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| 20358. |
Which chapters are very inportant to do and to get good marks plz tell me |
| Answer» Algebra and geometry is important | |
| 20359. |
Is oswal sample papers are good for preparation of boards |
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Answer» Ek bhi question ni aaegaa oswaal se I guess yes |
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| 20360. |
A survey was conducted by a group of student as a part o |
| Answer» | |
| 20361. |
Kitni revision KAR li |
| Answer» 7 chapters ho gaye | |
| 20362. |
How to prepare chapter 6??? |
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Answer» Do all the ques from this app\'s imp ques Revise all theorems |
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| 20363. |
Use Euclid division method |
| Answer» | |
| 20364. |
What is double answer in A.P. |
| Answer» When \'n\'gives two values, both hve to b justified | |
| 20365. |
Find the coordinate of the point on y - axis which is nearest to |
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Answer» Upper wala banana hai Here x=0 and find coordinate of y |
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| 20366. |
Tan A =12sina cosa =1 |
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| 20367. |
In triangle ABC AD/AC=DE/AB and anlge ADE=angle DAE then prove that AB =BC |
| Answer» | |
| 20368. |
EveryonE ready for maThs exam |
| Answer» No | |
| 20369. |
iriririr |
| Answer» What is this ?? | |
| 20370. |
In triangle abc ax is perpendicular to BC and y is a mid point then prove that ab2=+ay2bc2/4-bc. Xy |
| Answer» | |
| 20371. |
In what ratio does the line x-y-2=0divide the line segment joining the points A (3,-1) and B (8,9). |
| Answer» 2:3 | |
| 20372. |
sanskrit ka xam kitne ka hai |
| Answer» 80 | |
| 20373. |
optional exercises are very important .. |
| Answer» | |
| 20374. |
Result will come in cgpa or percentage of cbse 10 board?? |
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Answer» % In %age Percentage In both |
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| 20375. |
Will the optional questions in mathematics come in board exams |
| Answer» Yes. Ofcourse | |
| 20376. |
Please explain (Q.22) of chapter 15. |
| Answer» | |
| 20377. |
Kitne chapter ho gaye abhi tak? |
| Answer» 2000 chapter | |
| 20378. |
Is \'Steps Of Construction\' necessary to write ?? |
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Answer» Depends on marks Thank you Yes it is necessary. |
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| 20379. |
Write the condition that roots of the equation ax^2+x+b=0 are equal. |
| Answer» If b²- 4ac = 0 ...i.e D=0 | |
| 20380. |
Sin(A+B)=siA+sin true/fall |
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Answer» False Sin(A+B)= sinA+sinB is true but Sin(A+B)= sinA+sin is false False Falls Falsr |
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| 20381. |
If first ,second ,last term of ap are a,b,2a,then find its sum |
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Answer» 3ab/2(b-a) 3ab/2 (b-a). |
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| 20382. |
when will 11th class start |
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Answer» Around April 15 I think from June |
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| 20383. |
find the centre of the circle passing through the points (6,-6)(3,-7)(3,3) |
| Answer» Let\xa0A → (6, –6), B\xa0→ (3, –7) and C\xa0→ (3, 3).Let the centre of the circle be I(x, y)Then, IA = IB = IC [By definition of a circle]{tex}\\Rightarrow{/tex} IA2 = IB2 = IC2{tex}\\Rightarrow{/tex} (x - 6)2 + (y + 6)2 = (x - 3)2 + (y + 7)2 = (x - 3)2 + (y - 3)2Taking first two, we get(x - 6)2 + (y + 6)2 = (x - 3)2 + (y + 7)2{tex}\\Rightarrow{/tex} x2 - 12x + 36 + y2 + 12y + 36 = x2 - 6x + 9 + y2 + 14y + 49{tex}\\Rightarrow{/tex} 6x + 2y = 14{tex}\\Rightarrow{/tex} 3x + y = 7 ......(1) ....[Dividing throughout by 2]Taking last two, we get(x - 3)2 + (y + 7)2 = (x - 3)2 + (y - 3)2{tex}\\Rightarrow{/tex} (y + 7)2 = (y - 3)2{tex}\\Rightarrow{/tex} (y + 7) = {tex}\\pm{/tex}(y-3)taking +e sign, we gety + 7 = y - 3{tex}\\Rightarrow{/tex} 7 = -3which is impossibleTaking -ve sign, we gety + 7 = -(y - 3){tex}\\Rightarrow{/tex} y + 7 = -y + 3{tex}\\Rightarrow{/tex} 2y = -4{tex}\\Rightarrow y = \\frac{{ - 4}}{2} = - 2{/tex}Putting y = -2 in equation (1), we get{tex}\\Rightarrow{/tex} 3x - 2 = 7{tex}\\Rightarrow{/tex} 3x = 9{tex}\\Rightarrow{/tex} x = 3Thus, I {tex}\\rightarrow{/tex} (3, -2)Hence, the centre of the circle is (3, -2). | |
| 20384. |
What is dharacharya sutra? |
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Answer» Quadratic formula is -b+-√d/2a But it\'s about general knowledge Yes I know Oh sorry It means quadric formula Excuse me wake up ab math ka xam hai |
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| 20385. |
Maths sabka kitna padh ke hua |
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Answer» 8 chap 3 chapter Same pinch 5 chap |
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| 20386. |
Prove that 1/√2 is a irrational number. |
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Answer» It is so much easy Don\'t worry about it Let us prove to the contrary that √3 is irrational u can prove by this process easily |
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| 20387. |
For any positive integer n ,prove that n3 -n is divisible by 6 |
| Answer» n3\xa0- n = n (n2\xa0- 1) = n (n - 1) (n + 1)\xa0Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2.∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer.If n = 3p, then n is divisible by 3.If n = 3p + 1, then n – 1 = 3p + 1 –1 = 3p is divisible by 3.If n = 3p + 2, then n + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1) is divisible by 3.So, we can say that one of the numbers among n, n – 1 and n + 1 is always divisible by 3.⇒ n (n – 1) (n + 1) is divisible by 3.\xa0Similarly, whenever a number is divided by 2, the remainder obtained is 0 or 1.∴ n = 2q or 2q + 1, where q is some integer.If n = 2q, then n is divisible by 2.If n = 2q + 1, then n – 1 = 2q + 1 – 1 = 2q is divisible by 2 and n + 1 = 2q + 1 + 1 = 2q + 2 = 2 (q + 1) is divisible by 2.So, we can say that one of the numbers among n, n – 1 and n + 1 is always divisible by 2.⇒ n (n – 1) (n + 1) is divisible by 2.Since, n (n – 1) (n + 1) is divisible by 2 and 3.∴ n (n-1) (n+1) = n3\xa0- n is divisible by 6.( If a number is divisible by both 2 and 3 , then it is divisible by 6) | |
| 20388. |
Define Pythagoras theorem by yourself |
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Answer» a²=b²+c². a=√b²+c² Yes bhi sahi hai but there are two ways to prove it one is very easy by method of a+b)12 Itni badi theorem yaha kahan se type kru Can u prove it In a right angle triangle the square of the long side (hypotenuse) is equal to the sum of the square two other sides. " a²=b²+c²" Yes Have u answered by yourself You are correct Square of hypotenuse is equal to sum of square of other two sides The square of hypotenuse is equal to the sum of square of rest two sides |
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| 20389. |
Blue print in maths |
| Answer» Check the syllabus of maths on the app itself.... U will get it... | |
| 20390. |
Find the roots of the quadratic equation x square + (a+b ÷ a+a÷a+b)x +1=0 |
| Answer» {tex}x ^ { 2 } + \\left( \\frac { a } { a + b } + \\frac { a + b } { a } \\right) x + 1 = 0{/tex}{tex}x ^ { 2 } + \\frac { a } { a + b } x + \\frac { a + b } { a } x + 1 = 0{/tex}{tex}x \\left( x + \\frac { a } { a + b } \\right) + \\frac { a + b } { a } \\left( x + \\frac { a } { a + b } \\right) = 0{/tex}{tex}\\left( x + \\frac { a } { a + b } \\right) \\left( x + \\frac { a + b } { a } \\right) = 0{/tex}{tex}\\therefore{/tex}\xa0{tex}x = \\frac { - a } { a + b } , \\frac { - ( a + b ) } { a }{/tex} | |
| 20391. |
If d is the HCF of 30,72 find the value of x and y satisfying d=30x+72y |
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Answer» But NYRA questn toh aapne galat likha hai Actually woh lcm hoga naa ki hcfAnswer hai x=0,y=5 HCF of 45 and 2745 = (27 x 1) + 1827 = (18 x 1) + 918 = (9 x 2) + 0 Therefore, HCF = 99 = 27 – (18 x 1) = 27 – [45 – (27 x 1)] x 1 [since 18 = 45 – (27 x 1)] = 27 – [45 x 1 – 27 x 1 x 1] = 27 – (45 x 1) + (27 x 1) = 27 + (27 x 1) – (45 x 1) = 27{1 + 1} – (45 x 1) = (27 x 2) – (45 x 1) HCF of 45 and 27 in the form of 27x + 45 is (27 x 2) + (45 x -1).Hence, the values of x and y are 2 and -1.Yeh tha iska ans let me try guys Yahi question maine bhi pucha tha par kisi ne ans nhi diya tha |
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| 20392. |
Given 15 cotA=8 = find sinA and secA |
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Answer» Sin A = 15/17 and sec A = 17/8 SinA=8/17,secA=17/8 Cot a =8/15=b/p therefore (h )^2=(15)^2+(8)^2.H=17, Sina=15/17,andsec a=8/17. |
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| 20393. |
formula of area of isosceles triangle when two sides and one angle is given |
| Answer» | |
| 20394. |
Classes 11 ki 11 April se start I kya |
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Answer» No idea sare school ka alag alag date hai school open hone ka..Mera school 16 april ko khul raha hai Katilo Wala Naam Kyu rkha h or Kuch ni milaa Hehe Niche wale ka ans dekho Kya hua? ???? For CBSE.... Other boards will start from june Yes 15000 April se |
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| 20395. |
Prove the (3-√5) is an irrational number |
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Answer» OKkkkkkkkk Kabhi book khol lia karo |
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| 20396. |
What is new blue print math cbse boards class 10th |
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Answer» Iska kya mtlb h??? Is app m h aap dekhlo. |
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| 20397. |
If n is an odd integer then show that n^2-1 is divisible by 8 |
| Answer» Let n = 8q+1,8q+3..... Now n square -1 so, 8q square -1 = 64q square + 16 q +1-1 result is 64 q square +16 q now take 8 comman from it and that comman 8 will be cancelled out by 8 in divide so it is divisible by 8 | |
| 20398. |
What sin a |
| Answer» | |
| 20399. |
A(a+b,b-a) and B(a-b, b+a) is equidistant from P(x,y) find a and b |
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| 20400. |
Find quotient and remainderP(x)=x^3-3x^2+4x+5, g(x)=x^2+1-x |
| Answer» Quotient is x-2Remainder is x+7 | |