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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 20551. |
Where to use centroid formula and mid point formula |
| Answer» | |
| 20552. |
Does we have to solve RD in this preparation leave to score good marks |
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Answer» Thanks guyz Rd preparation needs minimum 2 -3 months time to get perfect but as you know our exam is before two days .so i suggest you to only do ncert I thnk u shuld solve the smple paper..... It\'s not compulsory but it have some important questions which are helpful |
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| 20553. |
If a + b is equal to 90 degree and secant a is equal to 5 by 3 then find the value of cos b |
| Answer» 4/5 | |
| 20554. |
If x=a sin theta , y= b cos theta then determine the value of b^2 x^2+a^2 y^2 |
| Answer» x/a=sin theta and y/b= cos theta.. Now after squaring both sides we get x^2/a^2= sin^2 theta and y^2/b^2= cos^2. Now add both the equations. Then you\'ll get the value of b^2 x^2+ a^2 y^2 as sin^2 theta+cos^2 theta which is 1 | |
| 20555. |
Sin 18*/cos 72* |
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Answer» 1 is answer How Hi Your right answer 1 |
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| 20556. |
Chapter 1 exercise 1.3 1st question ncert |
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Answer» Abe tu padhna chor de Ave ✓5 irrational number hai tu prove nahi karna janta Kya re kaamene aese bolego Isi app me hai wha se dekh le |
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| 20557. |
Solve by completaion of square methods:2x2 + 4x -8 =0 |
| Answer» X=2 and 1 | |
| 20558. |
Any important question fr triangles frnds |
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| 20559. |
2x+y=2 what will the value of x and y |
| Answer» X=1 and y=0 | |
| 20560. |
What is Euclid algorithm |
| Answer» It is a process based on Euclid division lemme . In fact, division algorithm is a technique to compute HCF of two natural number | |
| 20561. |
Cos theta -sin theta ×cos theta -sin theta = cos theta sin theta |
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| 20562. |
If the zeros of the polynomial x3-3x2+x+1 |
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| 20563. |
Hey isss saal cgpa hoga na frnds |
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Answer» Nhi yrr cgpa hoga abhi malum padha hai 10 ka aur 12 ka percentage hoga percentage Noo only precentage |
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| 20564. |
Hey foram have u completed maths?? |
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| 20565. |
If sec + tan =p,prove that sin =p^2-1/p^2+1 |
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Answer» Bye No sorry check rd Is it in identities, n solve it See RD Sharma of Chapter trigonometric ratio |
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| 20566. |
in ch real no. solve route 2,5,7,3 is irrational |
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Answer» See ncert solution of this app Hiiiiii |
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| 20567. |
Explain why (17*5*11*3*2+2*11)is a composite number |
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Answer» 11(17*5*11*3*2+2)11*5612Hence 2 factors i.e. 1,2,4 etc Becuz it has more than 2 factors Do it please Na yrr na ho paayega mujhse ?? Answer it |
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| 20568. |
Sinx+1/n=7 |
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| 20569. |
Show that the following system of equations has a unique solution : 3x+5y=12,5x+3y=4 |
| Answer» Here a1/a2 is not = to b1/b2 | |
| 20570. |
Sec - sin*sec =1 |
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| 20571. |
Explain example 6 of chapter 15 |
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Answer» 15 nai ata Kya nhi samajh aa rha h aapko ??? |
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| 20572. |
Is fit marks get added in the result? |
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Answer» No Have u prepared for exam Han ji |
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| 20573. |
How many percentage r u expecting |
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Answer» So why u expect this Its not nice khushi Nice? Mine 85+ I am also sure my percentage will be 90+ I am sure...it will not fall below 90%.. |
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| 20574. |
What is division algorithm |
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Answer» You know Hindi Han ji...south ki hu Bagi ji South k ho Ur most welcome..☺☺ Thanks A series of well defined steps which gives a procedure for solving of problem |
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| 20575. |
Let the mathematics exm be easy..... |
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Answer» I wish..we would clouse our eyes and write the exm...it should be too easy Hope so...that exam will be easy.. Too easy |
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| 20576. |
What about oswaal question bank |
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Answer» Me to Useful Ya good luck i hope it would work पढ़ते दिन बीत जायगा Its...goood even i will use same.. |
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| 20577. |
should i sleep now or not |
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Answer» It depends how your syllabus is left If u r totally prepared ..then u can take rest...otherwise it is better to study.. जा के सो जा ज्यादा पढे ग तो दिमाग घिस जायगा ok Nooo...study. |
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| 20578. |
How to do division |
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Answer» Its thought in 3rd std itself??? Hoo U dnt knw divinsion...r u really in 10th???? |
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| 20579. |
Is ncert enough to score 75+ |
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Answer» Look, ncert should be done first properly with example tjen u will be able to understand the question nd u will have idea of question .then u must do some sample paper, i think it will be enough Me to..im also using OSWAAL..will it help I am using oswaal will it work Ncert text book + ncert exempler is enough I dont think so Yes |
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| 20580. |
Aaaa |
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| 20581. |
If the distance between the points (4,k) and (1,0) is 5, then what can be the possible value of k? |
| Answer» 4 | |
| 20582. |
Tum saab abhi 10th class mai hua ho kya? |
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Answer» Hii Yessssd How was ur science exam OK nice Me to? Yes I am giving 10th board exams |
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| 20583. |
Maths me ncert book se related questions ayenge ya rd ke hard questions bhi a sakte hai |
| Answer» don\'t know anything can come | |
| 20584. |
how can i do fast and accurate calculation to save time in exam |
| Answer» U should practice? | |
| 20585. |
How much marks we have to score for passing in board exam ? |
| Answer» 15-25 | |
| 20586. |
Do we need to study Appendix 1 and Appendix 2 also ??? |
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Answer» No no Yes very important Noo all .. paper come from ncrt I think they\'re not important |
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| 20587. |
What I do I complete my ncrt textbook |
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Answer» Try exemplar Solve ques. papers of Ur previous exams..... they\'re also very important #ritu but I not have sample paper Solve sample papers |
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| 20588. |
How much of your course is left |
| Answer» 2 chapters r remaining | |
| 20589. |
If n = 23 × 34 × 54 × 7, write the number of consecutive zeroes in n, where n is anatural number. |
| Answer» No 0 | |
| 20590. |
How can we write in maths from proper way |
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| 20591. |
Please tell the way of finishing the course, 9 chapters are remaining? |
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Answer» Minimum 3hrs for the ch. like triangle How much time I should give to each chapter? Practice is the only way..... |
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| 20592. |
Solve 4x²+170x-450=0 |
| Answer» x= 5/2, -45 | |
| 20593. |
How to prepare fast |
| Answer» | |
| 20594. |
Polynomial q2 |
| Answer» Bas yar kitna padhoge so jayo | |
| 20595. |
Kitni tyari ho gyi sabki? |
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Answer» 2 chapters r remaining remaining 3 ch. r |
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| 20596. |
Can anyone explain me how to slove..quadratic equation by completing square method |
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Answer» Tq There are some steps to solve quadratic equation from completing square method:1. Divide whole equation from coefficient of x square.2. Multiply coefficient of X by 1/2nd add square of it on both sides.3. Take x square and square of its Coefficient in bracket like-(x plus minus square of coefficient), the sign between x square and square of Coefficient is determined by the sign of x cofficent.4. Take the third Coefficient to the other side.5. Now solve the other side by adding or subtracting them.6. Now take that whole square to the other side and make the square root,solve it.7. Buy that put both science positive and negative to solve the two sides. then you will get your answer . Don\'t waste your time their is no question related to this method |
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| 20597. |
24-4into6-:-3+8 |
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| 20598. |
Solve 2x+3y=11and2x-3y=-24and hence find the value of \'m,\'for which y=mx+3 |
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Answer» M=-1 M= -1 |
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| 20599. |
What is peobability |
| Answer» Its Probability | |
| 20600. |
[1+ cotA + tanA)(sinA- cosA)=sinA.tanA-cotA.cosA |
| Answer» L.H.S\xa0= (1 + cotA + tanA) (sinA - cosA)= sinA - cosA + cotA sinA - cotA cosA + sinA tanA - tanA cosA{tex}= \\sin A - \\cos A + \\frac{{\\cos A}}{{\\sin A}} \\times \\sin A - \\cot A\\cos A + \\sin A\\;\\tan A - \\frac{{\\sin A}}{{\\cos A}} \\times \\cos A{/tex}= sinA - cosA + cosA - cotA cosA + sinA tanA - sinA= sinA tanA - cotA cosA........(1)Now taking ;{tex}\\quad \\frac{{\\sec A}}{{\\cos e{c^2}A}} - \\frac{{\\cos ecA}}{{{{\\sec }^2}A}}{/tex}{tex} = \\frac{{\\frac{1}{{\\cos A}}}}{{\\frac{1}{{{{\\sin }^2}A}}}} - \\frac{{\\frac{1}{{\\sin A}}}}{{\\frac{1}{{{{\\cos }^2}A}}}}{/tex}{tex} = \\frac{{{{\\sin }^2}A}}{{\\cos A}} - \\frac{{{{\\cos }^2}A}}{{\\sin A}}{/tex}{tex} = \\sin A \\times \\frac{{\\sin A}}{{\\cos A}} - \\cos A \\times \\frac{{\\cos A}}{{\\sin A}}{/tex}{tex} = \\sin A \\times \\tan A - \\cos A \\times \\cot A{/tex}.......(2)From (1) & (2),(1 + cotA + tanA) (sinA - cosA) =\xa0{tex}\\frac { \\sec A } { cosec ^ { 2 } A } - \\frac { cosec A } { \\sec ^ { 2 } A }{/tex}\xa0= sinA.tanA - cosA.cotA\xa0Hence, Proved. | |