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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 20601. |
Solve for x : 1/ 2a + b +2x = 1/2a + 1/b + 1/2x , x I\'d not equal to 0 |
| Answer» X=-a, x=-b/2 | |
| 20602. |
Where we will get HOTs question from each chapter? |
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Answer» Together with mathematics From x am idea or question bank of oswal mathematics |
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| 20603. |
New syllabus of mathematics |
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| 20604. |
How to solve cross multiplication |
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Answer» Language means..easy way to learn formula according to your understanding Formula learn kr lo...co bhi apni language me |
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| 20605. |
This time , again cgpa follow in class 10 check the news . |
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Answer» On Google? Wht |
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| 20606. |
For mulaes |
| Answer» ?????~???~~~~~ | |
| 20607. |
ABC Is an isosceles triangle right angled at C. Prove that AB-2AC |
| Answer» | |
| 20608. |
Maths Fear Is Never Ends Till The World Will Survive???? |
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Answer» But I love maths??? Ya?? Ya true...!! ???? |
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| 20609. |
X2-x-4 |
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| 20610. |
if AD is perpendicularBC prove that ABsquare+CDsquare=BDsquare+ACsquare |
| Answer» Do you know about Pythagoras Theorem Pythagoras theorem if you if you know then you can solve this question very very easily | |
| 20611. |
formula to find last term in AP |
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Answer» Tn - last terma - first term d- difference between two APn- no of terms in Ap FormulaTn=a+(n-1)d L-(n-1)×d |
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| 20612. |
Is thr anyone solving guide |
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Answer» Yes Ncert is sufficient |
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| 20613. |
Which is the important chapter for class x cbsc board exam |
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Answer» Sirf chapter ka Naam yaad karlo important hai Trigonometry and triangle Some questions are important All? |
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| 20614. |
Sphere of radius 5cm is cut 2cm find tsa of 2 parts together in terms of pie |
| Answer» It is very important question | |
| 20615. |
How to find square root of 2.7 |
| Answer» | |
| 20616. |
What is the answer of 3rd Q of ex 5.4 |
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Answer» If came then what willnhappen Ur wish... But we can practice other sums instead of this optional exercise which I am told would not be asked.... No negative result of doing this once Must see one time No need to do this optional exercise 385 is Ans Isi app me hai wha se dekh le |
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| 20617. |
What is volume of frustum? |
| Answer» Volume of the frustum of the cone=πh/3[R^2 +r^2+Rr] cubic units | |
| 20618. |
1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1×0 +1 |
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Answer» 1 Because ×0 means 0 and +1= 1 16 16 How it is equal to 1..?? 1 1 16 |
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| 20619. |
Solve _ +_+_=30 (1,3,5,7,9,11,13,15 ) u can also repeat the no. |
| Answer» from which chapter it is... | |
| 20620. |
If the Mth term of an AP be 1/n and Nth term be 1/m then show that its MNth term is 1 |
| Answer» Chill dude no hard questions at this time so close to final exam | |
| 20621. |
Find the sum of 2,7,12,...to10 terms |
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Answer» 245 245 245 |
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| 20622. |
Draw a line segment and divide it internally in ratio 2:3 |
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Answer» Draw aline segment. make an acute angle. mark 5 arcs of equal length and follow the process of making parallel lines on A3 and A5. Line segment ki length?? |
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| 20623. |
Is is diagonal of parallelogram bisect each other |
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Answer» Are koi nai Thnx Yes |
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| 20624. |
Missing frequency statistics |
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Answer» Just put it in the formula with + k and solve it K ki value find karne wali |
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| 20625. |
2x + 3y=7,(a+b+1)x+(a+2b+2)y=4(a+b)+1 |
| Answer» If infinite number of solutions,{tex}\\frac{{{a_1}}}{{{a_2}}} = \\frac{{{b_1}}}{{{b_2}}} = \\frac{{{c_1}}}{{{c_2}}}{/tex}or {tex}\\frac{2}{{a + b + 1}} = \\frac{3}{{a + 2b + 2}} = \\frac{7}{{4a + 4b + 1}}{/tex}If\xa0{tex}\\frac{2}{{a + b + 1}} = \\frac{3}{{a + 2b + 2}}{/tex}{tex}\\Rightarrow{/tex} a - b = 1and if {tex}\\frac{3}{{a + 2b + 2}} = \\frac{7}{{4a + 4b + 1}}{/tex}{tex}\\Rightarrow{/tex} 5a - 2b = 11On solving we get,a = 3 and b = 2 | |
| 20626. |
Find the coordinates of the centriod of a triangle whose vertices are x1,y1 x2 y2 x3,y3 . |
| Answer» [(x1 + x2 + x3)/3 , (y1 + y2 + y3)/3] | |
| 20627. |
Construct the quadratic equation whose roots are √3 and 3√3 |
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Answer» X^2-(alfa+beta)x+alfa×beta K(x²-4√3x+9) |
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| 20628. |
What is the HCF of smallest composite number and prime number |
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Answer» 2 1 and 2 1 |
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| 20629. |
Construct the quadratic equation whose roots are /3 and 3/3 |
| Answer» Sum = 4√3. Product = 9. x^2-Sx+P = x2-4√3x+9 | |
| 20630. |
x+y=2(a-b)x+(a+b)y=1 |
| Answer» X=2a+2b-1/2b,y=2b-2a+1/2b | |
| 20631. |
sir private ko assessment milegi |
| Answer» | |
| 20632. |
0 is which number |
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Answer» Whole No. H Rational number I guess it is whole number |
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| 20633. |
Root 3 plus 1 divided by root 3 - 1 |
| Answer» | |
| 20634. |
CosA/1+sinA +1+sinA/cosA |
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Answer» 2secA 2secA |
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| 20635. |
Divide AB=7cm in 3:4 internally |
| Answer» 67 | |
| 20636. |
If the perimeter of sector of radius 5.6cm is 17.2 ,find the area of the sector |
| Answer» Find length of arc then area | |
| 20637. |
Find hcf 52 & 117 & express in the form 52x+117y |
| Answer» | |
| 20638. |
Given a =3, n=8, s=192,find D |
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Answer» 6 I hope u will understand Sn=8/2(2×3+(8-1)×d192=4(6+7d)192=24+28d192-24=28d168=28dd=168/28d=6 28 D= 6 |
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| 20639. |
If sec theta minus tan theta is equal to 4 then find the value of cosec theta |
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| 20640. |
should i start an extrabook or do sample papers ?? |
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Answer» I will say don\'t touch the sample papers solve only ncert because in all the exams 95% questions were from ncert 4 sample papers will be enough???? ok Sample papers Sample paper agr NCERT ho gai h thn.. Sample papers Sample papers please tell |
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| 20641. |
7/75 is terminating or non - terminating with solution |
| Answer» 7/75=7/5×5×3Denominater is not in the form of 2^n×5^mSo 7/75 is non terminating but recurring | |
| 20642. |
If sin 65/cos32 so find sinA +cosB - 2tan^π |
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| 20643. |
Formula of minor segment and major sector |
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| 20644. |
A number when divided by 53 gives 33 as quotient and 19 as remainder. Find the nunber |
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Answer» 1768 is the no. And we can obtain this no. By the following rule:Dividend = Divisor × Quotient + Remainder 1768 is the required no. |
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| 20645. |
All the best for your maths exam |
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Answer» Sme2 u oll Same to all Thanks |
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| 20646. |
Chapter 13 is difficult or easy |
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Answer» Ya it is difficult Who said it is easy don\'t be so smart ok. It is Based on formula and understanding of the figure. If u know all the formula only then u will be able to do it. For me it\'s very easy.Main concept is to understand figure Easy Little bit difficult for me.. For me it is difficult |
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| 20647. |
Math mee bhi optional unit h kya agar h toh batana kon se h |
| Answer» last exercises of some chapters are optional open ncert and see | |
| 20648. |
Optional krna compulsory hai kya |
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Answer» Yes No |
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| 20649. |
In the given figure PA,QB and RC aer perpendicular to AC. Prove that 1/x+/1z=1/y. |
| Answer» In the given figure we have\xa0{tex}P A \\perp A C{/tex}\xa0and\xa0{tex}Q B \\perp A C{/tex}.{tex}\\Rightarrow Q B \\| P A{/tex}In {tex}\\triangle PAC{/tex}\xa0and\xa0{tex}\\triangle Q B C{/tex}, we have\xa0{tex}\\angle QCB= \\angle PCA{/tex} ( Common )\xa0\xa0{tex}\\angle QBC= \\angle PAC{/tex} ( both are 90o\xa0).So by AA similarity rule ,\xa0{tex}\\triangle Q B C \\sim \\triangle P A C{/tex}.{tex}\\therefore \\frac { Q B } { P A } = \\frac { B C } { A C }{/tex}{tex}\\Rightarrow \\frac { z } { x } = \\frac { b } { a + b }{/tex}. .....................................(i) [by the property of similar triangles]In\xa0{tex}\\triangle RAC{/tex} ,\xa0{tex}Q B \\| R C{/tex}.So,\xa0{tex}\\triangle Q B A \\sim \\triangle R C A{/tex}.{tex}\\therefore \\frac { Q B } { R C } = \\frac { A B } { A C }{/tex}{tex}\\Rightarrow \\frac { z } { y } = \\frac { a } { a + b }{/tex}. .....................................(ii) [by the property of similar triangles]Form (i) and (ii), we obtain{tex}\\frac { z } { x } + \\frac { z } { y }{/tex}{tex}= \\left( \\frac { b } { a + b } + \\frac { a } { a + b } \\right) = 1{/tex}{tex}\\Rightarrow \\quad \\frac { z } { x } + \\frac { z } { y } = 1{/tex}{tex}\\Rightarrow \\frac { 1 } { x } + \\frac { 1 } { y } = \\frac { 1 } { z }{/tex}or {tex}\\frac { 1 } { x } + \\frac { 1 } { y } = \\frac { 1 } { z }{/tex}.Hence proved. | |
| 20650. |
When to use which methods of mean out of 3 methods |
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Answer» For ques. which has small digits eg. till 50, use direct......For big no. than 50 like till 100, use assumed mean method.......For very big no. like more than 100, use step deviation method. It is given in the question which methood will use.. |
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