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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 20751. |
What is the formula of area of Triangle according to coordinate geometry? |
| Answer» 1/2 [x1(y2-y3)+X2(y3-y1)+x3(y1-y2)] | |
| 20752. |
How to prove uderroot 3.5 is irrational number |
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| 20753. |
What is important to draw ogive ? |
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| 20754. |
How much percent is require to take PCM in class 11??? |
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| 20755. |
All mathematics identities |
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| 20756. |
I want all mensurational formula for surface area and volume... of class 10th |
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Answer» revision notes in app Refer to RD Sharma pg no.16.1-16.3 |
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| 20757. |
Find the area of traigle whose vertices are (2,3) (-1,0) (2,-4) |
| Answer» 1/2{x1(y2-y3)+x2(y3-y1)+x3(y1-y2)} | |
| 20758. |
a3 - b3 |
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Answer» He is asking a cube - b cube What is this What |
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| 20759. |
Any que from rd sharma will be ask in the exam or not |
| Answer» No | |
| 20760. |
last min minute revision. how much time to each chapter?? please |
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Answer» thankuu all friends Chaho to 1 minutes main revise ho jayaega samjha agar tughe study karne ka mann hai to nhi to last 1 hour mai bhi kuch nhi kar sakta tu isliye mann lagake study karoo acchi acchi study ki video dekho time pass mat karoo study karne k liye inspiration chahiye to sandeep maheshwari ka power of focus vala video dekho YouTube GO pe dekho data bhi bach jata hai 10 minutes ka video YOUTUBE GO 1 ya 2 MB mai dikhata hai to khoob study karoo exam se mat daroo Yeh to ek opportunity hai jindagi bahoot badi hai isme infinite opportunity hai to bs Yeh socho ki mughe kuch banna hai uske liye mughe study karna hai apni energy ko waste nhi karna hai apne mind ko sahi direction dena hai . I will give big chapter 1-1.5hrs and smallwe as accordingly I also had Min 30 |
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| 20761. |
Establish the relation between coefficient and zeros of the quadratic polynomials. |
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| 20762. |
show that the points (7,3),(3,0),(0,4)and (4,-1) are the vertices of a rhombus. |
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Answer» Yes, but by distance formula Op. Side equal prove krke diagonal equal prove karo |
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| 20763. |
Ans my question very fast |
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| 20764. |
What is the common difference of an ap in which a21-a7 84 |
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Answer» A+20d Monika its 20 there not 10 Correct answer is 21 and i solve it downwards with my name monika sain8 a21-a7=84a21 = a+10d _ (1)a7 =a+6d _ (2)(1) - (2) = 84a + 10d - a - 6d = 84By above equation we obtained4d = 84Then d = 2121 is correct answer A21-A7=84A+20d-(A+6d)=8414d=84d=6 What is the. Question I cannot understand so plz told clearly 6 |
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| 20765. |
Hello everyone are u all prepare for our last xam |
| Answer» | |
| 20766. |
How to use section formula |
| Answer» It is used when In question a line is divide into any ratio for ex-4:5 so here 4 is m and 5 is n | |
| 20767. |
If x=3one root of the x²-2kx-6=0 |
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Answer» K = 1/2By putting value of s in eq 3×3-2×k×3-6 =09-6-6k =03-6k =0K= 1/2 |
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| 20768. |
What is the formula of (a ➕ b) ka Hall squre |
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Answer» a²+2ab+b² A square +_2ab +b square |
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| 20769. |
Show that a×a,b×b,c×c are in A.P .if 1/b+c,1/c+a,1/a+b are in A.P |
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| 20770. |
Step deviation method |
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| 20771. |
Which section will attempt in board exam of math firstly ??? |
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Answer» D As ur wish..... Section D Start with those section which you know ? |
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| 20772. |
Weightage of each chapter in boards |
| Answer» UnitTitleWeightage1Number System062Algebra203Co-ordinate Geometry064Geometry155Trigonometry12 6Mensuration10 7Statistics And Probability11Total Marks80MarksNo. of Questions1 Mark62 Marks63 Marks104 Marks8Total30 | |
| 20773. |
Optional exercise karni h |
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Answer» No If u want u can |
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| 20774. |
Prove that sin(1+tan)+cos(1+cot)=sec +cosec |
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| 20775. |
How many questions will be asked from ncert? |
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Answer» Really???????Then it\'s ok??? Confirm (with same values from ncert). Of 65to 72 marks |
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| 20776. |
Derivation of nth term of an ap |
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| 20777. |
Heron \'s formula? |
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Answer» s=a+b+c/2area=√s(s-a)(s-b)(s-c) S=a+b+c÷2 _____________Area=/S(s-a)(s-b)(s-c) |
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| 20778. |
What is the theorem of chapter 10 circle |
| Answer» Look ncert dere r 2 theorems. | |
| 20779. |
Formule of ch 13 |
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| 20780. |
tan5tan25tan65tan85 |
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Answer» 1 1 1 Ans-1 |
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| 20781. |
1 litre is how much 1cm cube |
| Answer» 1 litre = 1000 cm cube | |
| 20782. |
solve for x: x^2+1/2x-1 |
| Answer» the value of x are-- 1+root2 and 1- root2 | |
| 20783. |
How to find lcm of 510 and 92 |
| Answer» 2×2×3×5×17×23=23460 is lcm | |
| 20784. |
Can answer of mode can come in approx |
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Answer» Yes depends if it is Coming in points. No |
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| 20785. |
If sinA=1\\2 ,find the value of 2 secA\\1+ tan²A |
| Answer» √3 | |
| 20786. |
Tangentc ÷sinc |
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Answer» Sorry it\'s sec C Cos C |
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| 20787. |
Find zeroes of p(x) = abx2 + ( b2 - ac)x - bc |
| Answer» We have,f(x) = abx2 + (b2 - ac)x - bc= abx2 + b2x - acx - bc= bx(ax + b ) - c(ax + b)= (ax + b) (bx - c)Now r(x)=0 if\xa0ax+b=0 or bx-c=0{tex}\\style{font-family:Arial}{\\begin{array}{l}\\style{font-size:12px}{\\mathrm i}\\style{font-size:12px}.\\style{font-size:12px}{\\mathrm e}\\style{font-size:12px}.\\style{font-size:12px}\\;\\style{font-size:12px}{\\mathrm x}\\style{font-size:12px}=\\style{font-size:12px}-\\frac{\\style{font-size:12px}{\\mathrm b}}{\\style{font-size:12px}{\\mathrm a}}\\style{font-size:12px}\\;\\style{font-size:12px}{\\mathrm{or}}\\style{font-size:12px}\\;\\style{font-size:12px}{\\mathrm x}\\style{font-size:12px}=\\frac{\\style{font-size:12px}{\\mathrm c}}{\\style{font-size:12px}{\\mathrm b}}\\\\\\end{array}}{/tex}Thus, the zeroes of f(x) are :\xa0{tex}\\style{font-family:Arial}{\\style{font-size:12px}{\\mathrm\\alpha}\\style{font-size:12px}=\\style{font-size:12px}-\\frac{\\style{font-size:12px}{\\mathrm b}}{\\style{font-size:12px}{\\mathrm a}}\\style{font-size:12px}\\;\\style{font-size:12px}{\\mathrm{and}}\\style{font-size:12px}\\;\\style{font-size:12px}{\\mathrm\\beta}\\style{font-size:12px}=\\frac{\\style{font-size:12px}{\\mathrm c}}{\\style{font-size:12px}{\\mathrm b}}}{/tex} | |
| 20788. |
If tan theta + sin theta =m and tan theta- sin theta = n prove that m square - n square = 4(mn)1/2 |
| Answer» Given, {tex}\\tan \\theta + \\sin \\theta = m{/tex} and {tex}\\tan \\theta - \\sin \\theta = n{/tex}L.H.S =\xa0{tex}m^{2}-n^{2}{/tex}{tex}=(tan\\theta+sin\\theta)^{2}-(tan\\theta-sin\\theta)^{2}{/tex}{tex}=tan^{2}\\theta+sin^{2}\\theta+2tan\\theta sin\\theta-[tan^{2}\\theta+sin^{2}\\theta-2tan\\theta sin\\theta]{/tex}{tex}=tan^{2}\\theta+sin^{2}\\theta+2tan\\theta sin\\theta-tan^{2}\\theta-sin^{2}\\theta+2tan\\theta sin\\theta{/tex}{tex}=4tan\\theta sin\\theta{/tex}R.H.S = 4{tex}\\sqrt{mn}{/tex}{tex}=4\\sqrt{(tan\\theta+sin\\theta)(tan\\theta-sin\\theta)}{/tex}{tex}=4\\sqrt{tan^{2}\\theta-sin^{2}\\theta}{/tex}{tex}=4\\sqrt{\\frac{sin^{2}\\theta}{cos^{2}\\theta}-sin^{2}\\theta}{/tex}{tex}=4\\sqrt{\\frac{sin^{2}\\theta-sin^{2}\\theta cos^{2}\\theta}{cos^{2}\\theta}}{/tex}{tex}=\\frac{4}{cos\\theta}\\sqrt{sin^{2}\\theta-sin^{2}\\theta cos^{2}\\theta}{/tex}{tex}=\\frac{4}{cos\\theta}\\sqrt{sin^{2}\\theta (1-cos^{2}\\theta)}{/tex}{tex}=\\frac{4}{cos\\theta} \\times sin\\theta \\times \\sqrt{sin^{2}\\theta}{/tex}{tex}=4tan\\theta sin\\theta{/tex}Hence, L.H.S = R.H.S | |
| 20789. |
In given figure AB||DC and BD||EF p. T DC² =CF×AC |
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| 20790. |
Show that n2+n+1 is not divisible by 5 for any n , where n is natural number |
| Answer» Because the prime factor of the equation the 5is not come | |
| 20791. |
Paper will be tough or easy |
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Answer» Easy No idea...worried? Ager sab ata hai to easy or nhi to tough |
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| 20792. |
In the figure o is the center of the circle |
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Answer» Its okay Nhi you are wrong in my book there is p as a center Bahut sahi Haa bhai |
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| 20793. |
What is the realation of sin cos tan |
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Answer» Tan=sin/cos ,sin=tan×cos ,cos=sin/tan ?? Sin÷cos = tan |
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| 20794. |
???Which is our next paper and on which date??? |
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Answer» I may answer some of ur questions Tomorrow...28.ko Toh 10 may time pass kerne aye ho ??? Waise me 11th class me hu. Nd I that for just kidding 2 ko sanskrit Last exam hai 28 ko Ager baad may dene ka mood hai toh compartment wala bhe de Dena |
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| 20795. |
CosA - SinA + 1÷ CosA + SinA - 1 = CosecA + CotA ??? |
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Answer» Thanks Divide numerator and denominator by sinA OR By rationalize method u can solve this but first one is better than other |
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| 20796. |
Maths mein question kaise solve karenge A to D ya D to A plzz tell i am very confuse about this. |
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Answer» Thanks to all .......☺☺☺ Section C than section D,A,B?? A se d becoz some small questions ko easyly fresh mind se solve kr sakte h Jaise kerna hai Vaise kero.. Jo section Acche se aata ho do it first.. |
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| 20797. |
if x=3 is one root of the quadratic equipment x²-2k-6=0 then find the value of k |
| Answer» K=3/2 | |
| 20798. |
Maths paper hindi midium 2010 bord Exam |
| Answer» Get last year papers here :\xa0https://mycbseguide.com/cbse-question-papers.html | |
| 20799. |
what is the hcf of smallest prime and composite no |
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Answer» Hcf of 4 nd 2 is 2 3 2 Bye bye 2 |
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| 20800. |
If 7sin square A + 3cos square A = 4 show that tanA= 1/√3 |
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